InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
SI unit of acceleration isA. mB. m/sC. `m//s^(2)`D. s |
| Answer» Correct Answer - C | |
| 2. |
What is the SI unit of displacement ?A. LengthB. VelocityC. EnergyD. Acceleration |
| Answer» Correct Answer - A | |
| 3. |
The distance covered by a moving body is directly proportional to the square to the time. The acceleration of the body isA. IncreasesB. Remains constantC. Is zeroD. Decreases |
| Answer» Correct Answer - B | |
| 4. |
A boy standing on the top of a tower of height 54 ft. throws a packet with a speed of 20 ft/s directly aiming towards his friend standing on the ground at a distance of 72 ft from the foot of the tower. The packet falls short of the person on the ground by `x xx(16)/(3)` ft. The value of x is |
| Answer» Correct Answer - 9 | |
| 5. |
If the displacement of a particle is zero, then distance covered by itA. Must be zeroB. Must not be zeroC. Must be unityD. |
| Answer» Correct Answer - C | |
| 6. |
If distance coverd by a particle is zero , what can be its displacement ? |
| Answer» As the distance covered by the particle is zero. This implies that the particle is at rest or stationary. Hence, its displacement is also zero. | |
| 7. |
STATEMENT - 1 : If person walks in a straight line and never changes direction, then the distance and the displacement will have exactly the same magnitude. STATEMENT - 2 : The phrase '20 m, northwest' likely describe the distance for a motion. STATEMENT - 3 : The phrase '20 m, west' likely describes the displacement for a motionA. TFTB. TTFC. FTTD. TTT |
| Answer» Correct Answer - A | |
| 8. |
STATEMENT - 1 : Distance is a vector quantity and displacement is a scalar quantity. STATEMENT - 2 : A person makes a round - trip journey, finishing where she started. The displacement for the trip is 0 and the distance is some nonzero value. STATEMENT - 3 : A person starts at position A and finishes at position B. The distance for the trip is the length of the segment measured from A to B.A. TTTB. FTFC. FFFD. TFT |
| Answer» Correct Answer - B | |
| 9. |
STATEMENT - 1 : Acceleration of a car moving on a circular track of radius r with speed v , for the person sitting in the car is zero. and STATEMENT - 2 : In the frame of reference of a person sitting in a car, the car always remains at rest irrespective of its motion with respect to ground.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-8B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-8C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 10. |
If the velocity of an object is increasing and changing at a uniform rate then the acceleration of the object is `"(i) Positive (ii) Zero"` `" (iii) Negative (iv) Not defined"` |
| Answer» Correct Answer - Positive. | |
| 11. |
What is the difference between average velocity and instantaneous velocity? |
| Answer» Average velocity tell us how fast an object is moving in a given interval of time, whareas the instantaneous velocity gives the velocity of the object at a particular instant of time interval. | |
| 12. |
A boy moves 400 m towards north, 300 m towards west and again 400 m towards south. Calculate the displacement of the boy from the initial position. |
|
Answer» Correct Answer - 300 m (towards west). Hint : Displacement of an object is the shortest distance between its initial and final position. |
|
| 13. |
Explain with the help of an example, if the displacement of a particle is zero, then it is not necessary that the distance traversed by it is also zero. |
|
Answer» Correct Answer - When object comes back to its intial position displacement is zero but the distance traversed by the object is non-zero. Hint : It object comes back to its initial position its displacement is zero. |
|
| 14. |
The variation of velocity of a particle moving along a straight line is as shown in the figure given below. The distance travelled by the particle in 5 s is A. 60 mB. 30 mC. 40 mD. 50 m |
| Answer» Correct Answer - A | |
| 15. |
STATEMENT - 1 : Zero velocity of a particle does not mean zero acceleration. and STATEMENT - 2 : The moment at which velocity is zero, its rate of change may be non-zero.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-3B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-3C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 16. |
STATEMENT - 1 : The instantaneous velocity is always tangential to the path and STATEMENT - 2 : The slope of position-time graph represents the velocity.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - B | |
| 17. |
A particle moves along a circular path of radius R. The distance and displacement of a particle after one completer revolution isA. `0,2pir`B. `2pir, 0`C. `0,pi r`D. `pir, 0` |
| Answer» Correct Answer - B | |
| 18. |
If the object is moving with uniform velocity in a given interval of time, then the average speed and instantaneous velocity are equal, why? |
| Answer» As the object is moving with uniform velocity therefore velocity remains same hence, the average velocity is same as the instantaneous velocity. | |
| 19. |
STATEMENT - 1 : Distance travelled by a particle moving rectilinearly may not be equal to magnitude of displacement of the particle. and STATEMENT - 2 : Distance travelled is a scalar but displacement is a vector.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-2B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-2C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - B | |
| 20. |
What is the ratio of displacement to the path length traversed by an object, if the object comes back to its initial position? |
|
Answer» Correct Answer - Zero Hint : When object comes back to its initial position its displacement is zero. |
|
| 21. |
If the displacement of an object during its motion is 100 m in a time interval of 20 s, then calculate the average velocity of the object with which it was moving through out his journey. |
| Answer» Correct Answer - 5 m/s. | |
| 22. |
A car accelerates from rest at constant rate of `2ms^(-2)` for some time. Immediately after this, it retards at a constant rate of `4ms^(-2)` and comes to rest. The total time for which it remains in motion is 3 s. Taking the moment of start of motion as t = 0, answer the following questions. At t = 3 s, the speed of the car is zero. The time for which it increases its speed isA. 1 sB. 2 sC. 3 sD. 1.5 s |
| Answer» Correct Answer - B | |
| 23. |
A car accelerates from rest at constant rate of `2ms^(-2)` for some time. Immediately after this, it retards at a constant rate of `4ms^(-2)` and comes to rest. The total time for which it remains in motion is 3 s. Taking the moment of start of motion as t = 0, answer the following questions. Let t be a time instant greater than `t_(1)` but less than 3 s. The velocity at this time instant isA. `4(t-t_(1))`B. `2t_(1)+4(t-t_(1))`C. `2t_(1)-4(t-t_(1))`D. `4t` |
| Answer» Correct Answer - C | |
| 24. |
A car accelerates from rest at constant rate of `2ms^(-2)` for some time. Immediately after this, it retards at a constant rate of `4ms^(-2)` and comes to rest. The total time for which it remains in motion is 3 s. Taking the moment of start of motion as t = 0, answer the following questions. If the time of acceleration is `t_(1)`, then the speed of the car at `t=t_(1)` isA. `2t_(1)`B. `4t_(1)`C. `gt 2t_(1)`D. `lt 2t_(1)` |
| Answer» Correct Answer - A | |
| 25. |
What is the average velocity of the object during its course of motion, if its initial and final positions are same? |
|
Answer» Correct Answer - Zero. Hint : Displacement of object is zero in this situation. |
|
| 26. |
A ball is projected vertically up with speed 20 m/s. Take `g=10m//s^(2)`A. It covers a distance of 5 m in 2nd second of its motionB. The displacement in 2nd and 3rd second are equalC. The distance covered in 2nd and 3rd second are equalD. The average speed for first 4 seconds is zero |
| Answer» Correct Answer - A::C | |
| 27. |
A rocket is fired upwards such that its engine takes 10 s to explods fully. Its velocity- time graph is as shown in the figure. Acceleration due to gravity is `10m//s^(2)`. The total time for which the rocket moves upwards isA. 10 sB. 100 sC. 110 sD. 20 s |
| Answer» Correct Answer - C | |
| 28. |
A car accelerates from rest at constant rate of `2ms^(-2)` for some time. Immediately after this, it retards at a constant rate of `4ms^(-2)` and comes to rest. The total time for which it remains in motion is 3 s. Taking the moment of start of motion as t = 0, answer the following questions. What is the distance travelled by it during the time of decreasing speed ?A. 2 mB. 3 mC. 4 mD. 6 m |
| Answer» Correct Answer - A | |
| 29. |
How can you determine the displacement and the acceleration of an object from its velocity-time graph? |
| Answer» Displacement is given by the area under the velocity-time graph of the object and acceleration is given by the slope of velocity-time graph. | |
| 30. |
STATEMENT - 1 : Equation of motion `(v=u+at)` is applicable even if the acceleration is non-uniform. STATEMENT - 2 : The initial velocity of a body is u and its acceleration is ft where f is a constant and t is time. The displacement in time t is `(ut+(1)/(2)ft^(2))`. STATEMENT - 3 : The area enclosed by the a-t graph and time axis gives the change in velocity of the body.A. FFTB. TTFC. TTFD. FTT |
| Answer» Correct Answer - A | |
| 31. |
A body is thrown vertically upward with velocity u. The distance travelled by it in the `7^(th) and 8^(th)` seconds are equal. The displacement in `8^(th)` seconds is equal to (take `g=10m//s^(2)`)A. 5 mB. 10 mC. 2.5 mD. `(5)/(3)m` |
| Answer» Correct Answer - A | |
| 32. |
A car starts moving on a straight road. It makes the entire journey in three parts. The total time of journey is 25 s. For first part it accelerates at a constant rate `5m//s^(2)`. For second part it moves with a constant speed. For the third part it retards at constant rate `5m//s^(2)` to come to rest. If the average speed for entire journey is 20 m/s, time period of first part of journey isA. 5 sB. 20 sC. 15 sD. 10 s |
| Answer» Correct Answer - A | |
| 33. |
A car starts moving on a straight road. It makes the entire journey in three parts. The total time of journey is 25 s. For first part it accelerates at a constant rate `5m//s^(2)`. For second part it moves with a constant speed. For the third part it retards at constant rate `5m//s^(2)` to come to rest. Let `t_(1)` be the time for first part, `t_(2)` be the time for 2nd part then correct relation isA. `t_(2)=25-t_(1)`B. `t_(2)=25-2t_(1)`C. `2t_(2)=25-t_(1)`D. None of these |
| Answer» Correct Answer - B | |
| 34. |
A particle starts from rest. Its acceleration is varying with time as shown in the figure. When the particle comes to rest, its distance from its starting point is A. 20 mB. 24 mC. 36 mD. 14 m |
| Answer» Correct Answer - D | |
| 35. |
A car starts moving on a straight road. It makes the entire journey in three parts. The total time of journey is 25 s. For first part it accelerates at a constant rate `5m//s^(2)`. For second part it moves with a constant speed. For the third part it retards at constant rate `5m//s^(2)` to come to rest. The correct velocity-time graph isA. B. C. D. |
| Answer» Correct Answer - B | |
| 36. |
The acceleration a of a particle starting from rest varies with time according to relation, `a=alphat+beta`. Find the velocity of the particle at time instant t. Strategy : `a=(dv)/(dt)` |
|
Answer» Given that, `a=alphat+beta` `(dv)/(dt)=alphat+beta` `int_(0)^(v)dv=int_(0)^(t)(alphat+beta)dt=int_(0)^(t)alphatdt+int_(0)^(t)betadt` `(v)_(0)^(v)=alpha int_(0)^(t)tdt+beta int_(0)^(t)dt` `=alpha((t^(2))/(2))_(0)^(t)+beta(t)_(0)^(t)` `v=(alpha)/(2)t^(2)+betat` |
|
| 37. |
The velocity-time graph of a particle moving along a straight line is shown in the figure-given below The displacement of the particle in 5 second isA. 0.5 mB. 1 mC. 2 mD. 4 m |
| Answer» Correct Answer - D | |
| 38. |
The acceleration-time graph of a particle moving along a straight line is as shown in. At what time the particle acquires its initial velocity? .A. 12 sB. 5 sC. 8 sD. 16 s |
| Answer» Correct Answer - C | |
| 39. |
A stone is dropped from the top of a tower and travels 24.5 m in the last second of its journey. The height of the tower isA. 44.1 mB. 49 mC. 78.4 mD. 72 m |
| Answer» Correct Answer - A | |
| 40. |
A particle travels a distance of 20 m in the `7^(th)` seconds and 24 m in `9^(th)` second. How much distance shall it travel in the `15^(th)` second? |
|
Answer» Here, `s_(7)^(th)=20m,s_(9)^(th)=24m, s_(15)^(th)=?` Let initial velocity is u and acceleration is a. We know that, `s_(t)^(th)=u+(1)/(2)a(2t-1)` `therefore" "s_(7)^(th)=u+(1)/(2)a(2xx7-1)=20` `u+(1)/(2)a(2xx7-1)=20` `2u+13a=40" ...(i)"` `therefore" "S_(9)^(th)=u+(1)/(2)a(2xx9-1)=24` `u+(1)/(2)a(17)=24` `2u+17a=48" ...(ii)"` From equation (i) and (ii), `{:(2u+17a=48," ...(ii)"),(2u+13a=40," ...(i)"),(-" "-" "-,),(_,):}` `4a=8rArr a=(8)/(4)=2m//s^(2)` From equation (i) `2u+13(2)=40` `2u+26=40rArr 2u=40-26=14` `u=7m//s` Henec, `S_(15)^(th)=u+(1)/(2)a(15xx2-1)` `=7+(1)/(2)xx2(30-1)=7+29=36m` |
|
| 41. |
A particle starting from rest moves along a straight line with constant acceleration for this velocity displacement graph will have the form-A. B. C. D. |
| Answer» Correct Answer - B | |
| 42. |
A particle having initial velocity 4 m/s moves with a constant acceleration `1m//s^(2)` for a time interval of 10 second in straight line. Find the displacement of the particle in the last second and the distance travelled in 10 second. |
|
Answer» Here, `u=4m//s, a=1m//s^(2), s_(10)^(th)=?, s_(10)=?` As, `s_(10)^(th)=u+(1)/(2)a(2t-1)=4+(1)/(2)xx1(2xx10-1)=4+(1)/(2)xx19` `=4+9.5=13.5m` `s_(10)=ut+(1)/(2)at^(2)=4(10)+(1)/(2)xx1xx1(10)^(2)` `=40+(1)/(2)xx100=90m` |
|
| 43. |
A trolley moves down a slope from rest with constant acceleration. In the first second of its motion it travels 1.6 m. Its acceleration (in `m//s^(2)`) isA. `3.2`B. `1.6`C. `0.8`D. `2.4` |
| Answer» Correct Answer - A | |
| 44. |
A particle moves in a straight line with the velocity as shown in. At `t=0 ,x=-16 m`, . |
| Answer» Correct Answer - A::B::C::D | |
| 45. |
Which of the following is correct expression for the stopping distance of a vechicle? (symbols have their usual meaning)A. `s=(u^(2))/(2a)`B. `s=(2a)/(u^(2))`C. `s=(at^(2))/(2)`D. `s=ut` |
| Answer» Correct Answer - A | |
| 46. |
If the upward direction is taken as positive then, which of the following correctly shows the magnitude of acceleration due to gravity with its direction?A. `9.8m//s^(2)`B. `-9.8m//s^(2)`C. `10m//s^(2)`D. `-10m//s^(2)` |
| Answer» Correct Answer - B | |
| 47. |
A car is moving on a straight road covers one third of the distance with a speed of 20 km/h and the rest with a speed of 60 km/h. The average speed of the car isA. 40 km/hB. 50 km/hC. 36 km/hD. 55 km/h |
| Answer» Correct Answer - C | |
| 48. |
The ratio of velocity of two objects A and B is `1:3`. It the position-time graph of object A is inclined to time axis at `30^(@)`, then the position-time graph of object B is inclined to time axis atA. `0^(@)`B. `90^(@)`C. `30^(@)`D. `60^(@)` |
| Answer» Correct Answer - D | |
| 49. |
If speed of water in river is 4 m/s and speed of swimmer with respect to water is 3 m/s, then in which direction the swimmer must swim so that he will reach directly opposite end?A. `127^(@)` with direction of river flowB. `60^(@)` with direction of river flowC. `143^(@)` with direction of river flowD. Swimmer will never reach directly opposite end |
| Answer» Correct Answer - D | |
| 50. |
Ram covers a distance of 100 km with variable speed. During the first half of his journey his speed was 20 km/h and during the rest of his journey his speed was 40 km/h. Calculate the average speed of Ram during the whole course of his motion. |
|
Answer» `"Distance covered = 100 km"` `"Time taken by Ram to cover 50 km with speed 20 km/h "(t_(1))=(50)/(20)h=(5)/(2)h` `"Time taken by Ram to cover next 50 km "(t_(1))=(50)/(40)g=(5)/(4)h` `"Total time"=t_(1)+t_(2)=(5)/(2)+(5)/(4)=(10+5)/(4)=(15)/(4)h` `"Average speed"=("Total distance travelled")/("Total time taken to cover that distance")` `=(100)/(15)xx4=(80)/(3)=26.66km//h` |
|