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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
Select the incorrect statement from the following :A. Baldness is a sex limited traitB. Linkage is an exception to the principle of independent assortment in heredity.C. Galactosemia is an inborn error of metabolismD. Small population size results in random genetic drift in a population |
Answer» Correct Answer - 1 | |
202. |
Adventive embryony in Citrus is due toA. NucellusB. IntegumentsC. Zygotic embryoD. Fertilized egg |
Answer» Correct Answer - A | |
203. |
Cotyledons and testa respectively are edible parts inA. Cashew nut and litchiB. Groundnut and pomegranateC. Walnut and tamarindD. French bean and coconut |
Answer» Correct Answer - 2 | |
204. |
An example of a seed with endosperm perisperm and caruncle is Or Which one of the following is an endosperm seed Or In which of the following plants, cotyledons form the first pair of leaves.A. CastorB. CottonC. CoffeeD. Lily |
Answer» Correct Answer - 1 | |
205. |
Low `Ca^(+)` in the body fluid may be the cause ofA. TetanyB. AnaemiaC. Angina pectorisD. Gout |
Answer» Correct Answer - A | |
206. |
Which one of the follwing pairs of structures distinguishes a nerve cell from other types of cellA. Nucleus and mitochondriaB. Perikaryon and dendritesC. Vacuoles and fibresD. Flagellum and medullary sheath |
Answer» Correct Answer - B | |
207. |
In maize, hybrid vigour is exploited by:A. Inducing mutationsB. Inducing mutationsC. Crossing of two inbred parental linesD. Harvesting seeds from the most productive plants |
Answer» Correct Answer - C | |
208. |
In maize, hybrid vigour is exploited by:A. Bombarding the protoplast with DNAB. Crossing of two inbred parental linesC. Harvesting seeds from the most productive plantsD. Inducing mutations |
Answer» Correct Answer - B | |
209. |
In photosynthesis , energy from light reaction to dark reaction is transferred in the form ofA. ADPB. ATPC. RUDPD. Chlorophyll |
Answer» Correct Answer - B | |
210. |
The correct sequence of phases of cell cycle is :A. `G1toStoG_(2)toM`B. `M toG_(1)toG_(2)toS`C. `G_(1)toG_(2)toStoM`D. `StoG_(1)toG_(2)toM` |
Answer» Correct Answer - A | |
211. |
Which proves to be effective biological control for nematodal pathogens of plants?A. Gliocladium virensB. Paecilomyces lilacinusC. Pisolithus tinctoriusD. Pseudomonas cepacia |
Answer» Correct Answer - B | |
212. |
Select the correct group of biocontrol agents.A. Nostoc, Azospirillium, NucleopolyhedrovirusB. Bacillus thuringiensis, Tobacco mosaic virus, AphidsC. Trichoderma, Baculovirus, Bacillus thuringiensisD. Oscillatoria, Rhizobium, Trichoderma |
Answer» Correct Answer - C | |
213. |
An organic compound containing `C,H` and `N` have the percentage `40,13.33` and `46.67` respectively. Its empirical formula may be`:`A. `C_3H_13N_3`B. `CH_2N`C. `CH_4N`D. `CH_6N` |
Answer» Correct Answer - C | |
214. |
Standard enthalpy and standard entropy changes for the oxidation of ammonia at `298 K` are `-382.64 kJ mol^(-1)` and `-145.6 jK^(-1)mol^(-1)` respectively. Standard Gibbs energy change for the same reaction at `298 K` isA. `–339.3 "kJ mol"^(–1)`B. `–439.3 "kJ mol"^(–1)`C. `–523.2 "kJ mol"^(–1)`D. `–221.1 "kJ mol"^(–1)` |
Answer» Correct Answer - A | |
215. |
If the rate of the reaction is equal to the rate constant, the order of the reaction is |
Answer» Correct Answer - A | |
216. |
The molar heat capacity of water at constant pressure, C, is `75 JK^(-1) mol^(-1)`. When 1.0 kJ of heat is supplied to 100 g water which is free to expand, the increase in temperature of water is :A. 1.2 KB. 2.4 KC. 4.8 KD. 6.6 K |
Answer» Correct Answer - B | |
217. |
The number of unpaired electrons in a parmamagnetic diatomic molecule of an element with atomic number ` 16` is :A. 2B. 3C. 4D. 1 |
Answer» Correct Answer - A Element of At. No.=16 is sulphur,its diatomic molecule is like `0_(2)` Which have two unpaired `e^(-)` according to MOT. |
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218. |
Consider the reaction `RCHO + NH_(2)NH_(2) rarr R - CH = N NH_(2)` What sort of reaction is it?A. Free radical addition – elimination reactionB. Electrophilic substitution-elimination reactionC. Nucleophilic addition – elimination reactionD. Electrophilic addition – elimination reaction |
Answer» Correct Answer - C Nucleophilic addition – elimination reaction. |
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219. |
First product of the reaction between RCHO and `NH_(2) NH_(2)` :-A. `RCH = NNH_(2)`B. `RCH = NH`C. `RCH_(2)NH_(2)`D. `RCON_(2)` |
Answer» Correct Answer - A | |
220. |
Which of the following reagents convert the propene to `1`-propanol?A. `H_(2)O, H_(2) SO_(4)`B. `B_(2)H_(6), H_(2) O, OH^(-)`C. `Hg(Oac)_(2), NaBH_(4)//H_(2)O`D. `Aq.KOH` |
Answer» Correct Answer - B | |
221. |
In Friedal craft reaction Toluene can be prepared by:A. `C_(6)H_(6) + CH_(3) CI`B. `C_(6)H_(5)CI + CH_(4)`C. `C_(6)H_(6) CH_(2) CI_(2)`D. `C_(6)H_(6) + CH_(3) COCI` |
Answer» Correct Answer - A | |
222. |
Ethyl benzote can be prepared from benzoic acid by using:A. Ethyl alcoholB. Ethyl alcohol and dry HCIC. Ehtyl ChlorideD. Sodium ethoxide |
Answer» Correct Answer - B | |
223. |
The percentage of pyridine `(C_(5)H_(5)N)` that forms pyridinium ion `(C_(5)H_(5)N^(+)H)` in a 0.10 M aqueous pyridine solution (`K_(b)` for `C_(5)H_(5)N=1.7xx10^(-9)`) isA. 6.0E-5B. 0.00013C. 0.0077D. 0.016 |
Answer» Correct Answer - B `alpha=sqrt((K_(b))/(C))` ltBrgt `=sqrt((1.7xx10^(-9))/(0.1))` `=sqrt(1.7xx10^(-8))` `=1.3xx10^(-4)` `=1.3xx10^(-2)%` |
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224. |
In Angiosperms pollen tube liberate their male gametes into the :A. Central cellB. Antipodal cellsC. Egg cellD. Synergids |
Answer» Correct Answer - D | |
225. |
main funcation of lenticel isA. TranspirationB. GuttationC. Gaseous exchangeD. Bleeding |
Answer» Correct Answer - C | |
226. |
Stomata in grass leaf areA. RectangularB. Kidney shapedC. Dumb-bell shapedD. Barrel shaped |
Answer» Correct Answer - C Grass being a monocot, has Dumb-bell shaped stomata in their leaves. |
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227. |
The frequency of recombination between gene present on the same chromosome as a measure of the distance between genes was explained by:A. Sutton BoveriB. T.H. MorganC. Gregor J.MendelD. Alfred Sturtevant |
Answer» Correct Answer - D | |
228. |
Match the followmg hormones with the respective disease: `{:("(a) Insulin",,"(i) Addisons disease"),("(b) Thyroxin",,"(ii) Diabetes insipudus"),("(c) Corticoids",,"(iii) Acromegaly"),("(d) Growth Harmone",,"(v) Dianetes mellitus"):}` Select the correct optionA. `{:(,(a),(b),(c),(d)),((1),(ii),(iv),(i),"(iii)"):}`B. `{:(,(a),(b),(c),(d)),((2),(v),(i),(ii),"(iii)"):}`C. `{:(,(a),(b),(c),(d)),((3),(ii),(iv),(iii),"(i)"):}`D. `{:(,(a),(b),(c),(d)),((4),(v),(iv),(i),"(iii)"):}` |
Answer» Correct Answer - D | |
229. |
Which of the following factors is responbilble the formation of concentrated urine?A. Hydrostatic pressure during glomerular filtrationB. Low levels of antidiuretic hormone.C. Maintaining hyperosmolarity towards it medullary interstitium in the kidneysD. Secretion of erythropoietin Juxtaglomerular complex. |
Answer» Correct Answer - C | |
230. |
If a gas expands at constant temperature, it indicates thatA. kinetic energy of molecules remains the sameB. number of the molecules of gas increasesC. kinetic energy of molecules decreasesD. pressure of the gas increases |
Answer» Correct Answer - A The average translational KE of one molecule of an ideal gas is as follows : `K_(t)=(KE)/(N_(A))=(3//2RT)/(N_(A))=(3)/(2)KT` when `R//N_(A)`= Boltzmann constant `"i.e., "E_(t) prop T` Thus, at constant temperature KE of molecules remains same. |
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231. |
The dissociation equilibrium of a gas `AB_(2)` can be represented as `2AB_(2)(g)hArr 2AB(g)+B_(2)(g)` The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium contant `K_(p)` and total pressure p isA. `(2K_(p)//P)^(1//2)`B. `(K_(p)//P)`C. `(2K_(p)//P)`D. `(2K_(p)//P)^(1//3)` |
Answer» Correct Answer - D `underset(2(1-x))underset(2)(2AB_(2)(g))hArrunderset(2x)underset(0)(2AB(g))+underset(x)underset(0)(B_(2)(g))underset("at eq.")underset("initially")(.)` Total amount of moles at equilibrium `2=x(1-x)+2x+x=2+x` `K_(p)=([P_(AB)]^(2)[P_(B_(2))])/([P_(AB_(2))]^(2))` `K_(p)=([(2x)/(2+x)xxP]^(2)xx[(x)/(2+x)xxP])/([(2(1-x))/(2+x)xxP]^(2))` `K_(p)=((4x^(3))/(2+x)xxP)/(4(1-x)^(2))` `K_(p)=(4x^(3)xxP)/(2)xx(1)/(4)("As "1-x ~=1 and 2+x~=2)` `x=(8K_(p)//4P)^(1//3)=(2K_(p)//P)^(1//3)` |
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232. |
Tetradynamous stamens are found inA. CruciferaeB. MalvaceaeC. SolanaceaeD. Liliaceae |
Answer» Correct Answer - A | |
233. |
A point `Q` lies on the perpendicular bisector of an electrical dipole of dipole moment `p`, If the distance of `Q` from the dipole is `r` (much larger than the size of the dipole), then electric field at `Q` is proportional toA. `p^(2)andr^(-3)`B. `pandr^(-2)`C. `p^(-1)andr^(-2)`D. `pandr^(-3)` |
Answer» Correct Answer - D | |
234. |
Match the following organisms with respective characteristics: `{:("(a) Pila",,"(i) Flame cells"),("(b) Bombyx",,"(ii) Comb plates"),("(c) Pleurobrachia",,"(iii) Redula"),("(d) Taenia",,"(iv) Malpighian tubules"):}`A. `{:(,(a),(b),(c),(d)),((1),(iii),(ii),(iv),"(i)"):}`B. `{:(,(a),(b),(c),(d)),((2),(iii),(ii),(i),"(iv)"):}`C. `{:(,(a),(b),(c),(d)),((3),(iii),(iv),(ii),"(i)"):}`D. `{:(,(a),(b),(c),(d)),((4),(ii),(iv),(iii),"(i)"):}` |
Answer» Correct Answer - C | |
235. |
If `E_(cell)^(ɵ)` for a given reaction is negative, which gives the correct relationships for the values of `DeltaG^(ɵ)` and `K_(eq)`?A. `DeltaG^(@) gt 0 : K_(eq) lt 1`B. `DeltaG^(@) gt 0, K_(eq) gt 1`C. `DeltaG^(@) lt 0, K_(eq) gt 1`D. `DeltaG^(@) lt 0, K_(eq) lt 1` |
Answer» Correct Answer - A `DeltaG^(@)=-nFE^(@)` `E^(@)` is negative So `DeltaG^(@)=+ve` `DeltaG^(@)=-2.303RT" log "K` `thereforeK_(eq) lt1` |
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236. |
In calcium, fluoride having the florite structures. The coordination number for calcium ion `(Ca^(2+))` and fluoride ion `(F^(-))` areA. 4 and 2B. 6 and 6C. 8 and 4D. 4 and 8 |
Answer» Correct Answer - C `CaF_(2)` is a fluorite structure So, Co-ordination ratio `Ca^(+2)F` `8:4` |
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237. |
Which one of the following is a possibility for most of us in regards to breathing, by making a conscious effortA. The lungs can be made fully empty by forcefully breathings out all air from themB. One can breathe out air totally without oxygenC. One can breathe out air through Eustachian tubes by closing both the nose and the mouthD. one can consciously breathe in and breathe out by moving the diaphragm alone, without moving the ribs at all. |
Answer» Correct Answer - D | |
238. |
HIV that causes AIDS, first starts destroyingA. B-lymphocytesB. LeucocytesC. ThrombocytesD. Helper T-lymphocytes |
Answer» Correct Answer - D | |
239. |
In which one of the following sets of animals do all the four give birth to young onesA. Lion, Bat, Whale, OstrichB. Platypus, Penguin, Bat, HippopotamusC. Shrew, Bat, Cat, KiwiD. Kangaroo, Hedgehog, Dolphin, Loris |
Answer» Correct Answer - D | |
240. |
Which of the following is the pair of biofertilizersA. Azolla and BGAB. Nostoc and legumeC. Rhizobium and grassesD. Salmonella & E. Coli |
Answer» Correct Answer - A | |
241. |
Lead concentration of blood is considered alarming atA. 30 `mu`g/100 mlB. 4-6 `mu`g/100 mlC. 10 `mu`g/100 mlD. 20 `mu`g/100 ml |
Answer» Correct Answer - C | |
242. |
Given: (i) `Cu^(2+)+2e^(-) rarr Cu, E^(@) = 0.337 V` (ii) `Cu^(2+)+e^(-) rarr Cu^(+), E^(@) = 0.153 V` Electrode potential, `E^(@)` for the reaction, `Cu^(+)+e^(-) rarr Cu`, will beA. 0.38VB. 0.52VC. 0.90 VD. 0.30V |
Answer» Correct Answer - B `Cu^(2+) +2e^(-) to Cu` `E^(@) =0.337V ` `DeltaG=-nFE_("cell")^(@)` `=-2xx F xx 0.337` `=-0.674` `Cu^(2+) to Cu^(2+) +e^(-)` `E^(@) =-0.153V ` `Delta G=+1 xx F xx 0.153` Final ` Cu^(+) +e^(-) to Cu` `DeltaG=-0.52 V` `DeltaG=-nFE_("cell")^(@)` `E_("cell")^(@)=0.52V` |
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243. |
Which one of the following statements related to lanthanons is incorrect ?A. Europium shows +2 oxidation stateB. The basicity decreases as the ionic radius decreases from Pr to LuC. All the lanthanons are much more reactive than aluminiumD. Ce (+4) solutions are widely used as oxidizing agent in volumetric analysis |
Answer» Correct Answer - C The earlier number of lathenoide series are quiet reactive similar to calcium but with increasing atomic number they behave more like aluminium. |
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244. |
The central dogma of molecular genetics states that the genetic information flows fromA. Amino acids`to`proteins`to`DNAB. `DNA to `carbohydrates`to`proteinsC. `DNAtoRNAto`protiensD. `DNAtoRNAto`carbohydrates |
Answer» Correct Answer - C Central dogma model contains following steps: `DNA overset("transcript ion")toRNA overset("Translation")to`protiens |
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245. |
If the tension and diameter of a sonometer wire of fundamental frequency `n` are doubled and density is halved then its fundamental frequency will becomeA. `N/4`B. `sqrt2n`C. nD. `n/sqrt2` |
Answer» Correct Answer - C `n=1/"2l"sqrt(T/(pir^2rho))` `rho_1=rho/2, T^1=2T`and `D^1=2D` `r_1=2r` `n^1=1/"2l"sqrt((2T)/(pi(2r)^2rho/2))=1/"2l"sqrt((1)/(pir^2rho))=n` `rArr` No change |
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246. |
In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow `P = (a^(3)b^(2))/(cd) %` error in `P` isA. `14%`B. `10%`C. `7%`D. `4%` |
Answer» Correct Answer - A `P=(a^(3)b^(2))/(cd)` Error in `((DeltaP)/(P))=3((Deltaa)/(a))+2((Deltab)/(b))+((Deltac)/(c))+((Deltad)/(d))` `=3(1%)+2(2%)+3%+4%=14%` |
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247. |
In which of the following molecule. The internuclear distance will be maximum :A. CsIB. CsFC. LiFD. LiI |
Answer» Correct Answer - A | |
248. |
The chiral centre is absent in :A. `DCH_(2)-CH_(2)-CH_(2)-CI`B. `CH_(3)-CHD-CH_(2)-CI`C. `CH_(3)-CHCI-CH_(2)D`D. `CH_(3)-CHOH-CH_(2)-CH_(3)` |
Answer» Correct Answer - A | |
249. |
Number of isomers of `[Pt(NH_(3))_(4)][CuCI_(4)]` complex are :A. 2B. 3C. 4D. 5 |
Answer» Correct Answer - C | |
250. |
1% solution of other compound is isotonic with 5% sucrose (sugar) solution. Then molecular wt. of compound will be :A. 32.4B. 68.4C. 129.6D. 34.2 |
Answer» Correct Answer - B | |