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1.

CH3CH2Cl + NaCN→X + Ni/H2→Y +acetic anhydride→Z,Z in the above reaction sequence is(a) CH3CH2CH2NHCOCH3(b) CH3CH2CH2NH2(c) CH3CH2CH2CONHCH3(d) CH3CH2CH2CONHCOCH3

Answer»

Correct option(a) CH3CH2CH2NHCOCH3

Explanation :

2.

Identify Aand predict the type of reaction.

Answer»

Correct option (d)

Explanation :

m-Bromoanisole gives only the respective meta substituted aniline. This is a substitution reaction which goes by an elimination-addition pathway.

3.

Consider the reaction,CH3CH2CH2Br+ NaCN→CH3CH2CH2CN + NaBrThis reaction will be the fastest in(a) ethanol(b) methanol(c) N, N' - dimethylformamide (DMF)(d) water

Answer»

Correct option(c) N, N' - dimethylformamide (DMF)

Explanation :

The reaction,

CH3CH2CH2Br+ NaCNCH3CH2CH2CN + NaBr

follows SN2 mechanism which is favoured by polaraprotic solvent i.e.. N, N' -dimethylformamide (DMF),

4.

For the following reactions :(A) CH3CH2CH2Br +KOH→CH3CH = CH2 + KBr + H2OWhich of the following statements is correct?(a) (A) is elimination, (B) and (C) are substitutionreactions.(b) (A) is substitution, (B) and (C) are addition reactions.(c) (A) and (B) are elimination reactions and (C) is addition reaction.(d) (A) is elimination, (B) is substitution and (C) is addition reaction

Answer»

Correct option(d) (A) is elimination, (B) is substitution and (C) is addition reaction

Explanation :

CH3CH2CH2Br +KOHCH3CH = CH2+ KBr + H2O

Saturated compound is converted into unsaturatedcompound by removal of group of atoms hence, itis an elimination reaction.

- Br group is replaced by - OH group hence, itis a substitution reaction.

Addition of Br2 converts an unsaturated compoundinto a saturated compound hence, it is an additionreaction.

5.

The compound I on treatment with Na gives B, and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C are in the order(a) C2H5OH, C2H6, C2H5Cl(b) C2H5OH, C2H5Cl, C2H5ONa(c) C2H5Cl, C2H6, C2H5OH(d) C2H5OH, C2H5ONa, C2H5Cl

Answer»

Correct option(d) C2H5OH, C2H5ONa, C2H5Cl

Explanation :

6.

Which of the following biphenyls is optically active?

Answer»

Correct option (d)

Explanation :

o-Substituted biphenyls are optically active as both the rings are not in one plane and their mirror images are non-superimposable.