InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
iodine rects with connentrated `HNO_(3)` to yield Y along with other products , the oxidation state of iodine in Y , is :A. 7B. 3C. 1D. 5 |
| Answer» Correct Answer - D | |
| 2. |
Bleaching action of `SO_(2)` is due to :A. its reducing natureB. its oxidising natureC. its acidic natureD. its both oxidising as well as reducing nature |
|
Answer» Correct Answer - A `SO_(2) + 2H_(2)O rarr H_(2)SO_(4) + 2H` coloured matter `underset("Oxidation")overset("Reduction")hArr` colourless matter |
|
| 3. |
Bleaching of a fabric cloth is done using A and excess of chlorine is removed using B.A and B are :A. `CaOCl_(2), Na_(2)SO_(3)`B. `Na_(2)S_(2)O_(3), CaOCl_(2)`C. `CaCl_(2), Na_(2)S_(2)O_(3)`D. `CaOCl_(2), Na_(2) S_(2)O_(3)` |
| Answer» Correct Answer - D | |
| 4. |
Platinum metal (Pt) dissolves in aqua-regia but not in concentrated HCl ot `HNO_(3)` becauseA. HCl oxidises Pt in the presence of `HNO_(3)`B. `HNO_(3)` reacts with HCl to form chlorine which attacks PtC. `HNO_(3)` oxidises Pt which is followed by formation of a chloro complexD. HCl and `HNO_(3)` together give `O_(2)` that oxidises Pt |
| Answer» Correct Answer - B | |
| 5. |
Why concentrated `H_(2)SO_(4)` can not be used for drying `H_(2)S`? |
| Answer» As hydrogen catches fire due to heat liberated when water is absorbed by acid | |
| 6. |
`PH_(3) ("anhydrous") + HBr ("anhydrous") rarr X`. Identify X ?A. `H_(3)BrO_(3)`B. `PH_(4)Br`C. `Br_(2)`D. `P_(4)` |
| Answer» Correct Answer - B | |
| 7. |
Anhydrous `CaCl_(2),P_(4)O_(10)` or concentrated `H_(2)SO_(4)` can not be used as drying agent for ammonia.Why ? |
|
Answer» Ammonia cannot be dried using `CaCl_(2), P_(2) O_(5)` or concentrated `H_(2)SO_(4)` because `NH_(3)` reacts with all of these. `{:(CaCl_(2) + 8NH_(3) rarr CaCl_(2).8NH_(3),P_(2)O_(5) + 6NH_(3) + 3H_(2)O rarr 2(NH_(4))_(3) PO_(4)),(H_(2) SO_(4) + 2NH_(3) rarr (NH_(4))_(2) SO_(4),CaO + H_(2)O rarr Ca(OH)_(2)):}` |
|
| 8. |
A gas is pale blue in colour on liquifaction, the colour arises from electronic transitions. This transition is forbidden in gaseous state. The gas does not burn but is a strong supported of combustion. Given the molar mass of this gas. |
| Answer» Correct Answer - `32, O_(2)` | |
| 9. |
Hydrogen peroxide oxidises `[Fe(CN)_(6)]^(4-)` to `[Fe(CN)_(6)]^(3-)` in acidic medium but reduces `[Fe(CN)_(6)]^(3-)` to `[Fe(CN)_(6)]^(4-)` in alkaline medium. The other products formed are, respectivelyA. `H_(2)O and (H_(2)O + O_(2))`B. `H_(2)O and (H_(2)O + OH^(-))`C. `(H_(2)O + O_(2)) and H_(2)O`D. `(H_(2) O + O_(2)) and (H_(2)O + OH^(-))` |
| Answer» Correct Answer - A | |
| 10. |
A gaseous substance dissolve in water giving a pale blue solution which decolouises `KMnO_(4)` and oxidises `Kl` to `l_(2)` in acidic medium :A. `N_(2)O_(5)`B. `NH_(3)`C. `N_(2)O_(3)`D. `HNO_(3)` |
|
Answer» Correct Answer - C `N_(2)O_(3) + H_(2)O rarr HNO_(2)` `2KMnO_(4) + 5KNO_(2) + 6HCl rarr 2MnCl_(2) + 5KNO_(3) + 3H_(2)O + 2KCl` `2Kl + 2HNO_(2) + 2HCl rarr 2H_(2)O + 2NO + 3KCl + I_(2)` |
|
| 11. |
Cold dilute nirtic acid would dissolved how many of the following without significant evolution of any gas: `Pb, Mg,Sb, Au, Ag,Fe, Mn, Sn,P_(4)` |
|
Answer» Correct Answer - 4 NO is evolved with Pb, Sb, Ag `P_(4)` `NH_(4)NO_(3)` is formed and no gas is evolved with Mg, Fe, Mn, Sn. No reaction with Au |
|
| 12. |
An unknown substance (P) functions as weak base in water. It produces silver mirror test. It reacts with dilute `HCl` to produce (Q) which turns blue litmus red (P) may be:A. `NH_(3)`B. `PH_(3)` is less basic than `NH_(3)`C. `NH_(2)OH`D. `HPO_(3)` |
| Answer» Correct Answer - C | |
| 13. |
Identify the pollutant gases largely responsible for the discoloured and lustreless nature of marble of the Taj Mahal.A. `SO_(2) and NO_(2)`B. `SO_(2) and O_(3)`C. `O_(3) and CO_(2)`D. `CO_(2) and NO_(2)` |
| Answer» Correct Answer - A | |
| 14. |
Which of the following set of combination is correct ?A. I, iv, SB. II, ii, QC. II, iii, QD. IV, iv, S |
| Answer» Correct Answer - C | |
| 15. |
The compound which has ionic nature in solid state isA. `PCl_(5)`B. `POCl_(3)`C. `P_(4)O_(10)`D. `PCl_(3)` |
|
Answer» Correct Answer - A `PCl_(5)` remains covalent in gas as well as in liquid phase but in solid exists as `[PCl_(4)]^(+) and [PCl_(6)]^(-)` |
|
| 16. |
Oxygen differs from the other elements of the group. Compounds of oxygen with metals are more ionic in nature and hydrogen bonding is more important for oxygen compounds. Oxygen is never more than divalent beacasue when it hs formed two covalent bonds, there are no low energy orbitals which can be used for form. further bonds. However, the elements S,Se,Te and Po have empty d- orbitals which may be used for bonding, and they can form four or six bonds by unpairing electrons. The higher oxidation states become less stable on decending the group. The bond between S and O, or Se and O, are much shorter than might be expected for a single bond owing to `rho pi - dpi` interaction between the p- orbital of oxygen and d- orbital of S or Se. Which one of the following orders represents the correct order for the properties indicated against them?A. `H_(2)O lt H_(2)S lt H_(2)Se lt H_(2)Te -` acidic characterB. `H_(2)O lt H_(2)S lt H_(2)Se lt H_(2)Te` - thermal stabilityC. `H_(2)S gt H_(2)Se lt H_(2)Te lt H_(2)O -` reducing characterD. `H_(2)S lt H_(2)Se lt H_(2)O lt H_(2)Te -` boiling point |
| Answer» Correct Answer - A | |
| 17. |
Oxygen differs from the other elements of the group. Compounds of oxygen with metals are more ionic in nature and hydrogen bonding is more important for oxygen compounds. Oxygen is never more than divalent beacasue when it hs formed two covalent bonds, there are no low energy orbitals which can be used for form. further bonds. However, the elements S,Se,Te and Po have empty d- orbitals which may be used for bonding, and they can form four or six bonds by unpairing electrons. The higher oxidation states become less stable on decending the group. The bond between S and O, or Se and O, are much shorter than might be expected for a single bond owing to `rho pi - dpi` interaction between the p- orbital of oxygen and d- orbital of S or Se. Which of the following statemet is incorrect ?A. Oxo-anions of sulphur have little tendency to polymerise compared with the phosphates and silicates.B. In pyrosulphurous acid `(H_(2)S_(2O_(5))`, the oxidation states of both the sulphur atoms are not same, they are +V and +IIIC. Concentrated `HNO_(3)` oxidises both sulphur and selenium to `H_(2)SO_(4) (+VI) and H_(2)SeO_(4) (+VI)` respectivelyD. Most metal oxides are ionic and basic in nature while non-metallic oxides are usually covalent and acidic in nature |
| Answer» Correct Answer - C | |
| 18. |
Inert pair effect plays an important role in the case ofA. PB. BiC. SbD. As |
| Answer» Correct Answer - B | |
| 19. |
The product formed in the reaction of `SOCl_2` (thionyl chloride) with white phosphorous is.A. `PCl_(3)`B. `SO_(2)Cl_(2)`C. `SCl_(2)`D. `POCl_(3)` |
| Answer» Correct Answer - A | |
| 20. |
A yellow coloured crystalline substance gave a colourless gas `X` on reaction with fluorine, which is thermally stable and has octahedral geometry. `X` can be |
| Answer» Correct Answer - `3 (a =1, b =2, c=1, d=3)` | |
| 21. |
A yellow coloured crystalline substance gave a colourless gas `X` on reaction with fluorine, which is thermally stable and has octahedral geometry. `X` can beA. `SF_(4)`B. `SF_(5)`C. `SF_(2)`D. `S_(2)F_(6)` |
| Answer» Correct Answer - B | |
| 22. |
Aqueous solution of `Na_(2)S_(2)O_(3)` on reaction with `CI_(2)`, givesA. `Na_(2)S_(2)O_(6)`B. `NaHSO_(4)`C. `NaCl`D. `NaOH` |
| Answer» Correct Answer - B | |
| 23. |
The product of the chemical reaction between `Na_(2)S_(2)O_(3)`, `Cl_(2)` and `H_(2)O` areA. `HCl + Na_(2)S`B. `HCl + NaHSO_(4)`C. `HCl + Na_(2)SO_(3)`D. `NaHClO_(3) + H_(2)O` |
| Answer» Correct Answer - B | |
| 24. |
In the above reaction (in Q.99) `Na_(2)S_(2)O_(4)` acts as aA. 2 electron reducing agentB. 1 electron reducing agentC. 3 electron reducing agentD. 4 electron reducing agent |
| Answer» Correct Answer - A | |
| 25. |
When sulphur is boiled with `Na_(2)SO_(3)` solution, the compound formed isA. sodium sulphideB. sodium sulphateC. sodium persulphateD. sodium thiosulphate |
| Answer» Correct Answer - D | |
| 26. |
How many of the following compounds are possible products when chlorine is passed through hypo solution (i) S (ii) HCl (iii) `Na_(2)S` (iv) `Na_(2)SO_(4)` (v) `Na_(2)S_(4)O_(6)` (vi) `HClO_(4)` |
| Answer» Correct Answer - 3(i, ii and iv) | |
| 27. |
The difference in the oxidation numbers of two types of sulphul atoms in `Na_(2)S_(4)O_(6)` is….. |
| Answer» Correct Answer - 5 | |
| 28. |
Ammonium nitrate decomposes on heating intoA. Ammonia and nitric acidB. Nitrous oxide and waterC. Nitrogen, hydrogne and ozoneD. Nitric oxide, nitrogen dioxide and hydrogen |
|
Answer» Correct Answer - B `NH_(4)NO_(3) overset(Delta)rarr N_(2)O + 2H_(2)O` |
|
| 29. |
Describe the changes which occur on heating sulphur |
| Answer» `S_(8) ("melt") underset(angle160^(@)C)overset(" at " 160^(@)C)hArr S_(8)` ring and diradical so formed polymerises to forms long chain polymerises to forms long chain polymer and viscocity starts to increase `overset("at " 200^(@)C)rarr` Viscosity further `uarr underset("boiling point")overset("at " 444^(@)C)rarr` Viscosity `darr` shorter chains and rings are formed `overset("at" 600^(@)C)rarr` in vapour state exist as `S_(2)` molecules (paramagnetic like `O_(2)`) | |
| 30. |
Out of following forms of sulphur which one is paramagnetic in nature and why ? `S_(8) , S_(6) and S_(2)` |
| Answer» Sulphur exist as `S_(2)` in vapour state which has two unpaired electrons in the anti-bonding `pi^(**)` obitals like `O_(2)` | |
| 31. |
Nitrogen exists as diatomic molecule and phosphorus as `P_(4)`. Why ?A. `N_(2)` has valence electrons only in bonding and nonbonding orbitals, while P has valence electrons in both bonding and antibonding orbitalsB. higher electronegativity of N favours formation of multiple bondsC. bigger size of P does not favour multiple bondsD. P has preference to adapt structures with small bond angles |
| Answer» Correct Answer - C | |
| 32. |
What happens when (A)`PCl_(5)` is heated. (B)`PCl_(5)` is reacted with heavy water. ( C)`H_(3)PO_(3)` is heated. |
|
Answer» (a) `PCl_(5) overset(Delta)rarrPCl_(3) + Cl_(2)`, (b) `PCl_(5) + D_(2)O overset(Delta)rarr POCl_(3) + 2 DCl`, (c) `4 H_(3) PO_(3) overset(Delta)rarr 3H_(3)PO_(4) + PH_(3)` |
|
| 33. |
`NO_(2)` can be prepared by heating :A. `NH_(4)NO_(3)`B. `NaNO_(3)`C. `Pb(NO_(3))_(2)`D. `KNO_(3)` |
| Answer» Correct Answer - C | |
| 34. |
How is `H_(2)S` prepared in laboratory ?A. `FeS + H_(2)SO_(4)`B. `FeSO_(4) + H_(2)SO_(4)`C. `FeS + HCl`D. Elemental `H_(2) +` elemental `S_(8)` |
| Answer» Correct Answer - A::C | |
| 35. |
Which of the following process(es) can given sulphur ?A. `H_(2)S` gas is passed through nitric acidB. `Cl_(2)` gas is passed into water saturated with hydrogen sulphideC. Hydrogen sulphide is passed through sodium bisulphate solutionD. `H_(2)S` gas is passed through acidified `KMnO_(4)` solution |
| Answer» Correct Answer - A::B::C::D | |
| 36. |
In which of the following reactions, hydrogen peroxide acts as an oxidizing agent ?A. `PbS + 4H_(2) O_(2) ? PbSO_(4) + 4H_(2)O`B. `2MnO_(4)^(-) + 3H_(2)O_(2) ? 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-)`C. `I_(2) + H_(2)O_(2) + 2OH^(-) ? 2I^(-) + 2H_(2)O_(2) + O_(2)`D. `HOCl + H_(2)O_(2) ? H_(3)O^(+) ? H_(3)O^(+) + Cl^(-) + O_(2)` |
| Answer» Correct Answer - A | |
| 37. |
The order of stability of halides of sulphur with different halogens isA. `I^(-) gt Br^(-) gt Cl^(-) gt F^(-)`B. `F^(-) gt Cl^(-) gt Br^(-) gt I^(-)`C. `Br^(-1) gt Cl^(-) gt I^(-) gt F^(-)`D. `F^(-) gt Cl^(-) gt I^(-) Br^(-)` |
| Answer» Correct Answer - B | |
| 38. |
The compound which can act as an oxidizing agent as well as reducing agent isA. `HNO_(2)`B. HlC. HCND. HCOOH |
| Answer» Correct Answer - A | |
| 39. |
The nitrogen atom may complete its octet in several ways. Which one is incorrect ?A. Electron gain to form the nitride Ion, `N^(3-)` e.g., `Li_(3)N`B. Formation of electron pair bonds e.g. `NH_(3) " or " NF_(3)` Azo compounds `(-N = N -)`C. Formation of electron - pair bonds with electron gain e.g., Amide ion `NH_(2^(-))` and imide ion `NH^(2-)`D. Formation of electron pair bonds with electron gain : `NH_(4^(+)), N_(2)H_(5)^(+), (C_(2)H_(5))_(4) N^(+)` |
| Answer» Correct Answer - D | |
| 40. |
Red phosphorus may be prepared from white phosphorus by :A. adding red colour to white phosphorusB. heating white phosphorus to red heatC. heating white phosphorus in inert atmosphere to `250^(@)C` or at low temperature in the presence of sun light.D. heating white phosphorus at high pressure and 473 k temperature |
| Answer» Correct Answer - C | |
| 41. |
White Phosphorus may be removed from red Phosphorus byA. sublimation under reduced pressureB. dissolving in waterC. dissolving in `CS_(2)`D. heating with an alkali solution |
| Answer» Correct Answer - A::C::D | |
| 42. |
Phosphorus is manufactred by heating in an electric furnace a mixture ofA. Bone ash and cokeB. Bone ash and silicaC. Bone ash, silica and cokeD. None of these |
|
Answer» Correct Answer - C `2Ca_(3) (PO_(4))_(2) ("from bone -ash") + 10C + 6SiO_(2) overset(Delta)rarr 6CaSiO_(3) + 10CO + P_(4)(s)` white phosphorus |
|
| 43. |
For per gram of reactant, the maximum quantity of `N_(2)` gas is produce in which of the following thermal decomposition reactions ? (Given : Atomic wt : `Cr = 52 u, Ba = 137 u)`A. `(NH_(4))_(2) Cr_(2)O_(7) (s) rarr N_(2)(g) + 4H_(2) O (g) + Cr_(2)O_(3) (s)`B. `2NH_(4)NO_(3) (s) rarr 2N_(2) (g) + 4H_(2) O (g) + O_(2) (g)`C. `Ba(N_(3))_(2) (s) rarr Ba (s) + 3N_(2) (g)`D. `2NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)` |
| Answer» Correct Answer - D | |
| 44. |
Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`A. KOHB. `O_(2)`C. `I_(2)`D. KOD |
| Answer» Correct Answer - A | |
| 45. |
The correct statements(s) regarding hydrides `(H_(2)E)` of group -16 is/areA. The acidic character increases from `H_(2)O " to " H_(2)Te`B. The bond `(H -E)` dissociation enthalpy decreases down the groupC. The thermal stability of hydrides decreases down the groupD. The reducing character of hydrides increases down the group |
| Answer» Correct Answer - A::B::C::D | |
| 46. |
The correct order of thermal stability of hydrides of group `15` isA. `NH_(3) lt PH_(3) lt AsH_(3) lt SbH_(3) lt BiH_(3)`B. `NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3) gt BiH_(3)`C. `PH_(3) gt NH_(3) gt AsH_(3) gt SbH_(3) lt BiH_(3)`D. `AsH_(3) lt PH_(3) gt SbH_(3) gt BiH_(3) gt NH_(3)` |
| Answer» Correct Answer - B | |
| 47. |
How many of the following is correct order of sphecified property |
| Answer» Correct Answer - 2 | |
| 48. |
The hydribes of group 15 elements act as :A. lewis acidB. lewis baseC. bothD. none |
| Answer» Correct Answer - B | |
| 49. |
The correct statements regarding ozone is/areA. Ozone is thermodynamically less stable with respect to oxygenB. It acts as powerful oxidising agentC. It rapidly react with `NO_((g))` and form `NO_(2(g)) and O_(2(g))`D. It is toxic substance |
| Answer» Correct Answer - A::B::C::D | |
| 50. |
Which of the following may ignite sphontaneously in air ?A. White phosphorousB. Red phosphorusC. Black PhosphorusD. Nitrogen |
|
Answer» Correct Answer - A Factual |
|