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101.

0n1 → 1P1 + 1e0 + θ-1. Which process is represented by the equation?2. What happens to the parent nucleus after the process?3. After this process the nucleus will be in a higher energy state. How will it come to ground state?4. If a proton splits in a nucleus what are the changes. Represent it with an equation.

Answer»

1. β – emission.

2. Atomic increases to one unit. But mass number remains constant

3. The parent atom comes to ground state by emitting gamma ray.

4. P → n + e+ + ν

Atomic number decreases by one unit. But mass number remains constant.

102.

a. Two protons and two neutrons may bound to form a single particle it is called1. α particle 2. β particle3. deuteron4. triton b. If such a particle is emitted what changes will occur in the nucleusc. The penetrating power of the particle is very small in air. Why?d. If the particle is projected upward in a uniform magnetic field with direction perpendicular to plane in ward, towards which plate (A or B) it is deflected? To find this which law is applied?

Answer»

a. 1. α particle.

b. Mass number decreases to 4 and atomic number decreases to 2

c. penetrating power of the particle is very small in air:

(i) Mass of α particle is

4. Hence penetrating power of the particle is small.

d. Towards A (left) Flemings left hand rule is used.

103.

Match the following.α-particleElectro magnetic wavesSpeed is greater than Cβ-particleNuclei of helium atomSpeed is equal to Cγ-raysFast moving electronsSpeed is equal to 0.66 CSpeed is about 1/10th velocity to light

Answer»
α-particleNuclei of helium atomSpeed is about 1/10th velocity to light
β-particleFast moving electronsSpeed is equal to 0.66 C
γ-raysElectro magnetic wavesSpeed is equal to C
104.

β – Particles does not exist inside a nucleus. But it is emitted from the nucleus!1. What is β Particle2. What happens to nucleus of a atom, when a particle is emitted? Explain3. Why β particle is emitted from the nucleus?

Answer»

1. It is electron

2. When α is emitted, mass number decreases to 4 and atomic decreases by 2.

3. To get stability, β is emitted from the nucleus.

105.

The fission of one nucleus of 92U239 release 200 Mev of energy.1. What is meant by fission2. Express 200 Mev energy in joule3. How many fission of 92U239 should occur per send for producing a power of 1 Mev

Answer»

1. The splitting of heavy nucleus into two nucleus is called fission.

2. E = 200 Mev

= 200 × 10-6 ev

E = 200 × 106 x 1.6 x 10-19J

= 3.2 x 10-11J.

3. Number of fission

\(n=\frac{Total\,energy}{energy\,per\,fission}\) = \(\frac{1\times10^6}{3.2\times10^{-11}}\)

= 3.3 x 1010

106.

Nuclear radius depends on the mass number of the element.1. Write down the expression for nuclear radius.2. Prove that the density of the nucleus is independent of mass number A.

Answer»

1. R = R0 A1/3 .

2. Density of nucleus = (mass of the nucleus)/ (volume of the nucleus)

\(\frac{mA}{\frac{4}{3}\pi R^3}=\frac{mA}{\frac{4}{3}\pi R^3_0A}\) = \(\frac{m}{\frac{4}{3}\pi R_0^3}\)

This shows that nuclear density is independent of mass number.

107.

Match the following.      A   B1. Nuclear fissionβ – decay2. Nuclear fusionHydrogen spectrum3. Transition between atomic energy levelNuclei with low atomic numbers4. Electron emission from nucleusGenerally possible for nuclei with high atomic numberPhotoelectric emission

Answer»
      A   B
1. Nuclear fissionGenerally possible for nuclei with high atomic number
2. Nuclear fusionNuclei with low atomic numbers
3. Transition between atomic energy levelHydrogen spectrum
4. Electron emission from nucleusβ – decay
108.

Write down the expression for nuclear radius.

Answer»

\(R=R_0A_\frac{1}{3}\)

109.

Classify the following statement in to nuclear fission and nuclear fusion 1. Products are radio active 2. Can be controlled 3. Reaction is spontaneous 4. Can’t proceed as a chain reaction

Answer»

1. fission 

2. fission 

3. fission 

4. fusion

110.

The half-life of `._(38)^(90)Sr` is 28 years. What is the disintegration rate of 15 mg of this isotope ?

Answer» Here T = 28 years `= 28xx3.154xx10^(7)s`
As number of atoms in 90 g of `._(38)Sr^(90)`
`= 6.023xx10^(23)`
`therefore` Number of atoms in 15 mg of `._(38)Sr^(90)`
`= (6.023xx10^(23))/(90)xx(15)/(1000)`
i.e., `N=1.0038xx10^(20)`
Rate of disintegration `(dN)/(dt)=lambda N`
`= (0.693)/(T)N`
`= (0.693xx1.0038xx10^(20))/(28xx3.154xx10^(7))`
`= 7.87xx10^(10)Bq`
111.

Assertion Two different radioactive substances have initially same number of nuclei. Their decay constants are `lamda_(1)and lamda_(2)(ltlamda_(1)).` Then, initially first radioactiv substance decays at faster rate. Reason Half-life of first radioactive substance is less.A. If both Assertion and Reason are true and Reason is the correct explanation of Assertion.B. If both Assertion and Reason are true but Reason are true but Reason is not correct explanation of Assertion.C. If Assertion is true but Reason is false.D. If Assertion is false but Reason is true.

Answer» Correct Answer - A
(a) `t_(1//2) =(0.693)/(lamda ) implies _(1//2) prop 1//lamda implies lamda prop(1)/(T_(1//2))`
112.

If `T` is the half-life of a radioactive material, then the fraction that would remain after a time `(T)/(2)` isA. `1/sqrt2`B. `(sqrt2-1)/sqrt2`C. `1/2`D. `3/4`

Answer» Correct Answer - A
113.

if an electron and a positron annihilitate , them the energy relasesed isA. `3.2xx10^(-13)J`B. `1.6xx10^(-13)J`C. `4.8xx10^(-13)J`D. `6.4x10^(-13)J`

Answer» Correct Answer - b
Mass of electron = Mass of position `=9.1xx10^(-31)kg`
According to positron annihilation,
`""_(+)beta^(0)+""_(-)beta^(0)tohv+hv`
Energy released, `E=(2m).c^(2)`
`=2xx9.1xx10^(-31)xx(3xx10^(8))=1.6xx10^(-13)J`
114.

The percentage of quantity of a radioactive material that remains after 5 half-lives will be .A. `1%`B. `0.3%`C. `3.125%`D. `0.2%`

Answer» Correct Answer - C
115.

A Zener of power rating 1 W is to be used as a voltage regulator. If Zener has a breakdown of 5V and it has to regulate voltage which fluctuated between 3 V and 7 V, what should be the value of `R_(s)` for safe operation (see figure) ?

Answer» Given, power `= 1W`
Zener breakdown `V_(z) = 5V`
Minimum voltage `V_("min") = 3V`
Maximum voltage `V_("max") = 7V`
Current `I_(Z_("max")) = (P)/(V_(z)) = (1)/(5) = 0.2 A`
The value of `R_(s)` for safe operation `R_(s) = (V_("max") - V_(Z))/(I_(Z_("max"))) = (7 - 5)/(0.2) = (2)/(0.2) = 10 Omega`
116.

Which of the following process will result into fission reaction ?A. `""_(92)U^(235)` is bombarded with fast moving neutronsB. `""_(92)U^(235)` is bombared with thermal neutronsC. `U^(238)` is bombarded with slow moving neutronsD. `U^(235)` being unstable breaks into smaller fragments

Answer» Correct Answer - B
117.

1 atomic mass unit is equal toA. `1/16` (mass of `O_2` molecules)B. `1/25` (mass of `F_2` molecules )C. `1/12` (mass of one C-atom)D. `1/14` (mass of `N_2` molecules )

Answer» Correct Answer - C
118.

Neutrino is a particle, which isA. Charge less and has spinB. Charged and has spinC. Charged and has no spinD. Charge less and has no spin

Answer» Correct Answer - A
119.

Heavy water isA. Compound of helium and oxygenB. Water at `4^@C`C. Compound of heavy oxygen and heavy hydrogenD. Water in which soup does not lather

Answer» Correct Answer - A
120.

The binding energy of nucleus is a measure of its.A. MassB. StabilityC. ChargeD. Momentum

Answer» Correct Answer - B
121.

In one average-life,A. half the active nuclei decayB. less than half the active nuclei decayC. more than half the active nuclei decayD. All the nuclei decay

Answer» Correct Answer - C
The average life of a randiactive element is `1.44` times, the half life of the element.
122.

Which of the following is a wrong description of binding energy of a nucleus?A. It is the energy required to break a nucleus into its constituent nucleonsB. It is the energy made available when free nucleons combine to form a nucleusC. It is the sum of the rest mass energies of its nucleons minus the rest mass energy of the nucleusD. None of the above

Answer» Correct Answer - D
`BE=Deltamc^(2)`
123.

The `._1^3H` isotope of hydrogen, which is called tritium (because it contains three nucleons), has a half-life of 12.33 yr.It can be used to measure the age of objects up to about 100 yr. It is produced in the upper atmosphere by cosmic rays and brought to Earth by rain. As an application , determine approximately the age of a bottle of wine whose `._1^3H` radiation is about `1/10` that present in new wine .

Answer» Correct Answer - 41 yr
124.

Some elementary particle theories suggest that the proton may be unstable , with a half life `ge10^32` yr. How long woud you expect to wait for one proton in your body to decay (consider that your body is all water) ?

Answer» Correct Answer - `6xx10^3` yr
125.

Which of the following is most unstableA. `alpha`-particleB. NeutronsC. `beta`-particleD. `beta^+`-particle

Answer» Correct Answer - B
126.

In an atom bomb, the energy is released because of the.A. chain reaction of neutrons and `""_(92)U^(235)`B. chain reaction of neutrons and `""_(92)U^(238)`C. chain reaction of neutrons and `""_(92)U^(240)`D. chain reaction of neutrons and `""_(92)U^(236)`

Answer» Correct Answer - A
To sustain a chain reaction in atom bomb one of the neutrons emitted in the fission of `""^(235)U` must be captured by another `""^(235)U` nucleus and cause it to fission.
127.

What is the Q-value of the reaction? `""^(1)H+""^(7)Lito ""^(4)He+""^(4)He` The atomic masses of `""^(1)H,""^(4)Heand ""^(7)Li` 1.007825u, 4.0026034u and 7.01600u, respectively.A. `17.35` Me VB. `18.06` Me VC. `177.35` Me VD. `170.35` Me V

Answer» Correct Answer - A
The total mass of the initial particles,
`m_(i)=1.007825+7.016004=8.023829u`
and the total mass of final particles,
`m_(f)=2xx4.002603=8.005206u`
Difference between initial and final mass of particles, `Deltam=m_(i)-m_(f)=8.023829=8.005206=0.018623u`
The Q-value is given by
`Q=(Deltam)c^(2)=0.018623xx931.5=17.35MeV`
128.

A nuclear reaction along with the masses of the particle taking part in it is as follows `underset("amu")underset(1.002)A+underset("amu")underset(1.004)Btounderset("amu")underset(1.001)C+underset("amu")underset(1.003)D+QMeV` The energy Q liberated in the reaction isA. `1.234MeV`B. `0.931MeV`C. `0.465MeV`D. `1.862 MeV`

Answer» Correct Answer - D
`Q(1.002+1.004-1.001-1.003)(931.5)MeV=1.863 MeV`
129.

The atoms of same element having same chemical properties but different masses are calledA. isotonesB. IsomersC. IsotopesD. Isobars

Answer» Correct Answer - C
130.

The curve of blinding energy per nucleon as a function of atomic mass number has a sharp peak for helium nucleus. This implies that helium.A. can easily be broken upB. is very stableC. can be used as fissionable materialD. is radioactive

Answer» Correct Answer - B
The elements high on the BE versus mass number plot are very tightly bound and hence are stable. And the elements those are lower on this plot, are less tightly bound and hence are unstable.
Since, helium nucleus shown a peak on this plot, so it is very stable.
131.

The curve of blinding energy per nucleon as a function of atomic mass number has a sharp peak for helium nucleus. This implies that helium.A. Is very stableB. Is radioactiveC. Can easily be broken upD. Can be used as fissionable material

Answer» Correct Answer - A
132.

The half-life of a radioactive substance is 100 years. Calculate in how many years the activity will decay to `1//10^(th)` of its initial value.

Answer» T = 100 years
`(N)/(N_(0))=(1)/(10), t = ?`
`lambda = (0.693)/(T)=(0.693)/(100)=0.693xx10^(-2)` years
`N=N_(0)e^(-lambda t)rArr e^(-lambda t)=(N)/(N_(0))=(1)/(10)`
`e^(lambda t)=10 rArr lambda t = log_(e )^(10)=2.303xxlog_(10)^(10)`
`t=(2.303xx1)/(0.693xx10^(-2))=3.323xx10^(2)`
`= 332.2` years
133.

Describe the Activity (decay rate) and its units.

Answer»

The decay rate R at a certain time t and the number of undecayed nuclei N at the same time are related by R = λN 

The decay rate of a sample is experimentally measurable quantity and is given a specific name: activity. The SI unit for activity is becquerel, named after the discoverer of radioactivity, Henry Becquerel. 

1 becquerel is simply equal to 1 disintegration or decay per second. 

There is also another unit named “curie” that is widely used and is related to the SI unit as: 

1 curie = 1 Ci = 3.7 × 1010 decays per second 

= 3.7 × 1010 Bq.  

134.

the three stable isotopes of 9.051% , 0.27% and 9.22% the atomic masses of the three isotopes are 19.99 u , 20 .99 u and 21.99u respectively the average atomic mass of neon will beA. 20.71uB. 30.17uC. 20.98uD. 30.98u

Answer» Correct Answer - a
The mass of the isotopes are `19.99` u `20.99` u and `21.99` u.
Their relative abundances are `90.51%,0.27 and 9.22%`
`therefore` Average atomic mass of neon
`m=(90.51xx19.99xx0.27xx20.99+9.22xx21.99)/((90.51+0.27+9.22))`
`=(2017.7)/(100)=20.17u`
135.

What are isotopes and isomers ?

Answer» Isotones : The nuclei having same neutron number (N) but different atomic numbers (Z) are called isotones.
E.g. : `._(80)^(198)Hg, ._(79)^(197)Au`.
Isomers : Nuclei having the same atomic number (Z) and mass number (A) but with different nuclear properties such radioactive decay and magnetic moments are called isomers.
E.g. : `._(35)^(80)Br^(m), ._(35)^(80)Br^(g)`.
136.

The Q value of a nuclear reaction `A+b to C+d` is defined by `Q=[m_(A)+m_(b)-m_(C )-m_(d)]c^(2)` where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic. `._(6)^(12)C+ ._(6)^(12)C to ._(10)^(20)Ne+ ._(2)^(4)He` Atomic masses are given to be `m(._(1)^(2)H)=2.014102 u` `m(._(1)^(3)H)=3.016049 u` `m(._(6)^(12)C)=12.000000 u` `m(._(10)^(20)Ne)=19.992439 u`

Answer» `._(6)C^(12)+._(6)C^(12)rarr ._(10)Ne^(20)+ ._(2)He^(4)`
`Q = Delta m xx 931 MeX = [2m(._(6)C^(12))-m(._(10)Ne^(20))-m(._(2)He^(4))]xx931 MeV`
`= [24.000000-19.992439-4.002603]xx931 MeV`
`= pm 4.61 MeV`
`therefore` The reation is exothermic.
137.

The Q value of a nuclear reaction `A+b to C+d` is defined by `Q=[m_(A)+m_(b)-m_(C )-m_(d)]c^(2)` where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic. `._(1)^(1)H+ ._(1)^(3)H to ._(1)^(2)H+._(1)^(2)` Atomic masses are given to be `m(._(1)^(2)H)=2.014102 u` `m(._(1)^(3)H)=3.016049 u` `m(._(6)^(12)C)=12.000000 u` `m(._(10)^(20)Ne)=19.992439 u`

Answer» `._(1)H^(1)+ ._(1)H^(3)rarr ._(1)H^(2)+ ._(1)H^(2)`
`Q= Delta m xx 931 MeV = [m(._(1)H^(1)). +m(._(1)H^(3))-2m (._(1)H^(2))]xx931 MeV`
`= [1.007825+3.01604-2xx2.014102]xx931 MeV = - 4.03 MeV`
`therefore` This reaction is endothermic.
138.

The Q value of a nuclear reaction A+b=C+d is defined by `Q=[m_A+m_b-m_C-m_d]c^2` where the masses refer to the respective nuclei. Determine form the given data the Q value of the following reactions and state whether the reactions are exothermic of endothermic. (i) `._1H^(1)+._1H^3to ._1H^2+._1H^2` (ii) `._6C^(12)+._6C^(12) to ._10Ne^(20)+._2He^4` Atomic masses are given to be `m(._1H^2)=2.014102u , m(._1H^3)=3.016049 u, m(._6C^(12))=12.000000u , m(._10Ne^(20))=19.992439u`

Answer» Correct Answer - (i)-4.031 MeV, Endothermic
(ii)+4.616 MeV, Exothermic
(i)Mass of LHS = 4.023874 u
Mass of RHS =4.028204 u
Q=[(Mass of LHS-Mass of RHS) u] x 931 MeV
Q=-4.031 MeV `rArr` reaction is endothermic
(ii)[12.000000+12.000000-(19.992439+4.002603)] x 931
Q=4.616 MeV
Q is positive `rArr` reaction is exothermic
139.

Calculate the packing fraction of `alpha`-particle from the following data : Mass of helium nucleus =4.0028 amu Mass of free proton =1.00758 amu Mass of free neutron =1.00897 amu

Answer» Correct Answer - `75.75xx10^(-4)` amu
Packing fraction =`("mass defect" Deltam)/"Total number of nucleons, A"`
140.

Define the term AMU.

Answer»

On the atomic scale, mass is measured in atomic mass units (u). By definition, 1 atomic mass unit (1u) is 1/12th mass of one atom of 12C; 1u = 1.660563 × 10–27 kg. 

141.

What are isotopes and isobars ?

Answer» Isotopes : The nuclei having the same atomic number (Z) but different mass numbers (A) are called isotopes.
E.g. : `._(8)^(16)O, ._(8)^(17)O, ._(8)^(18)O`.
Isobars : The nuclei having the same neutron number (N) but different atomic number (Z) are called isobars.
R.g. : `._(6)^(14)C, ._(7)^(14)N`.
142.

Compare isotopes, isobars and isotones with examples.

Answer»

Nuclides with the same atomic number Z, but different neutron number N are called isotopes. 

Ex : Nuclides with the same A are isobars and those with the same N are isotones. 

Ex : (i) Isobars  (ii) Isotones

Most elements are mixtures of two or more isotopes. The atomic mass of an element is a weighted average of the masses of its isotopes. The masses are the relative abundances of the isotopes. 

143.

Tritium is an isotope of hydrogen whose nucleus triton decays , it would transform into `He^3` nucleus . This does not happen .This is becauseA. Triton energy is less than that of a `He^3` nucleusB. The electron created in the beta decay process cannot remain in the nucleusC. both the neutrons in triton have a decay simultaneously resulting in a nucleus with 3 protons which is not a `He^3` nucleus .D. because free neutrons decay due to external perturbations which is absent in a triton nucleus .

Answer» Correct Answer - a
144.

Write a note on Nucleus.

Answer»

An atom has a nucleus. The nucleus is positively charged. The radius of the nucleus is smaller than the radius of an atom by a factor of 104. More than 99.9% mass of the atom is concentrated in the nucleus. 

A nucleus contains a neutral particle called neutron. Its mass is almost the same as that of proton. 

The atomic number Z is the number of protons in the atomic nucleus of an element. The mass number A is the total number of protons and neutrons in the atomic nucleus; A = Z+N; Here N denotes the number of neutrons in the nucleus. 

A nuclear species or a nuclide is represented as AZX, where X is the chemical symbol of the species. A nucleus can be considered to be spherical in shape and assigned a radius. Electron scattering experiments allow determination of the nuclear radius; it is found that radii of nuclei fit the formula R = R0 A1/3

where R0 = a constant = 1.2 fm. This implies that the nuclear density is independent of A. It is of the order of 1017 kg/m3

Neutrons and protons are bound in a nucleus by the short-range strong nuclear force. The nuclear force does not distinguish between neutron and proton. 

145.

Which of the following is correct for a nuclear reaction ?A. A fission represented by `._92U^235 + ._0n^1 to ._56Ba^143 + ._36Kr^93`+energyB. heavy water is used as moderator in preference to ordinary water because H-atom may capture neutrons, while D-atom would notC. Cadmium rods increase the reactor power when they go in, decrease when they go outwardD. Slower neutrons are more effective in causing fission than faster neutrons in case of `U^235`

Answer» Correct Answer - A::B::D
146.

The probability disintegration per second of a nucleus in a given radio-active sampleA. Increases in proportion to life time lived by the nucleusB. Decreases with the life time livedC. Is independent of life time livedD. Depends on the total number of identical nuclei present in the sample

Answer» Correct Answer - C
147.

Which of these is a fusion reaction ?A. `""^(3)H_(1)+""^(2)H_(1)to ""^(3)He_(1)+""^(1)""N_(0)`B. `""^(238)U_(92)+""^(206)Pb_(82)+8(""^(4)He_(2))+6(""^(0)B_(1))`C. `""^(12)C_(7)to ""^(12)C_(6)+beta+gamma`D. none of the above

Answer» Correct Answer - a
In fusion reaction, two lighter nucleis combine tgo from a heavy nuclei.
148.

The principle of controlled chain reaction is used in.A. atomic energy reactorB. atom bombC. the core of sumD. artificial readioactivieity

Answer» Correct Answer - a
In nuclear reactor, nuclear fission can be carried out through sustained and controlled chain reaction.
149.

A chain reaction is continuous due toA. large mass defectB. large energyC. producation of more neutrons in fissionD. none of the above

Answer» Correct Answer - c
Chain reaction occurs due to the production of more neutrons.
150.

The principle of controlled chain reaction is used in.A. atomic energy reactorB. atom bombC. the core of sunD. artificial radioactivity

Answer» Correct Answer - A