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1.	The value of sin2 (45° + A) – sin2 (45° – A) is equal to1). ½ cos 2A2). ½ sin 2A3). ½ tan 2A4). sin 2A
Answer» SIN²A – sin²B = sin (A + B).sin (A – B) sin² (45°+ A) – sin² (45°– A) ⇒ sin(45° + A + 45° – A)sin(45° + A – 45° + A) ⇒sin 90° × sin 2A = sin 2A

The value of sin2 (45° + A) – sin2 (45° – A) is equal to1). ½ cos 2A2). ½ sin 2A3). ½ tan 2A4). sin 2A

Answer»

SIN²A – sin²B = sin (A + B).sin (A – B)

sin² (45°+ A) – sin² (45°– A)

⇒ sin(45° + A + 45° – A)sin(45° + A – 45° + A)

⇒sin 90° × sin 2A = sin 2A

Discussion