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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
51. |
`SO_(2)` can reduce :A. `HCIO_(3)` to `HCl`B. `Cr_(2)O_(7)^(2-)//H^(+)` to `Cr^(3+)`C. `MnO_(4)^(-)//H^(+)` to `Mn^(2+)`D. `IO_(3)^(-)` to `I_(2)` |
Answer» Correct Answer - A::B::C::D | |
52. |
When `H_(2)S` is passed through acidified `K_(2)Cr_(2)O_(7)` solution, the solution turns :A. yellowB. blueC. greenD. white |
Answer» Correct Answer - C | |
53. |
Which of the following hydrogen halide is most volatile?A. HClB. (B) HFC. (C) HID. (D) HBr |
Answer» Correct Answer - A | |
54. |
Which of the following hydrogen halide is most volatile.A. HClB. HFC. HID. HBr |
Answer» Correct Answer - A |
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55. |
Which halogen acid is most volatile?A. HFB. HClC. HID. HBr |
Answer» Correct Answer - B HCl has lowest B.P. |
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56. |
`H_(2)S` is far more volatile than water because :A. sulphur atom is more electronegative than oxygen atom.B. oxygen being more electronegative than sulphur forms hydrogen bond.C. `H_(2)O` has bond angle of nearly `105^(@)`D. hydrogen atom is loosely bonded with sulphur. |
Answer» Correct Answer - B As water has `H`-bonding due to the presence of highly electronegative oxygen but `H_(2)S` does not (electronegativity of sulphur is low) |
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57. |
Water is much less volatile than `H_(2)S` becauseA. `H_(2)O` has a bond angle of nearly `150^(@)`B. hydrogen is ioosely bonded with the sulphurC. sulphur atom is less electronegative than oxygen atomD. sulphur atom is more electronegative than oxygen atom |
Answer» Correct Answer - C Water is much less volatile than `H_(2)` S because sulphure atom is less electronegative than oxygen atom. |
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58. |
Angular shape of ozone molecule consists ofA. `"1 "sigma " and " "1 " pi" bond"`B. `"2 "sigma " and " "2 " pi" bond"`C. `"1 "sigma " and " "2 " pi" bond"`D. `"2 "sigma " and " "1 " pi" bond"` |
Answer» Correct Answer - D Angular shape of ozone molecular consition of two `sigma` and one `pi`- bond. |
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59. |
Statement-1 : Electrovalency of oxygen is two `(O^(2-))` Statement-2 : Dinegative anion of oxygen `(O^(2-))` is quite common but dinegative anion of sulphur `(S^(2-))` is less common.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-10B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-11C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
Answer» Correct Answer - B | |
60. |
Which of the following statement is/are true for `XeF_6` ?A. Its partial hydrolysis gives `XeOF_4`B. Its reaction with silica gives `XeOF_4`C. It is prepared by the reaction of `XeF_4` and `O_2F_2`D. Its reaction with `XeO_3` gives `XeOF_4` |
Answer» Correct Answer - a,b,c,d |
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61. |
Uses of ozone `(O_(3))` includes I. as an oxidising agent in the manufacturing of `KMnO_(4)`. II. As a germicide, disinfectant and for sterilisation. III. For bleaching oils, flour, ivory, starch, etc. The correct set of uses of ozone isA. I and IIB. II and IIIC. I and IIID. All of these |
Answer» Correct Answer - D Uses of ozone As a germicide, disinfecatant and for sterilising water . Also used for bleahing oils, ivory, flour, starch , etc. It is acts as an oxiding agent in the manufacting of `KMnO_(4)`. |
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62. |
The final acid obtained during the manufacturing of `H_(2)SO_(4)` by contact process isA. `H_(2)SO_(4)(conc.)`B. `H_(2)SO_(4)(dil.)`C. `H_(2)SO_(4)`D. `H_(2)S_(2)O_(7)` |
Answer» Correct Answer - D `H_(2)SO_(4) + SO_(4) + SO_(3) rarr underset(("oleum"))(H_(2)S_(2)O_(7)` |
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63. |
Sulphuric acid acts asA. hygroscopic agentB. sulphonating agentC. reducing agentD. oxidising agent |
Answer» Correct Answer - ABD | |
64. |
Asseration: `NH_(3)` can be dried by `CaCl_(2)`. Reason: `CaCl_(2)` is a good dehydrating agent.A. If both asseration and reson are true and the reason is the correct explanation of the asseration.B. If both asseration and reason are true ans the reason is the correct explanation of the asseration.C. If asseration is true but reason is false.D. If asseration is false but reason is true. |
Answer» Correct Answer - D No doubt `CaCl_(2)` is a dehydrating agent but it with `NH_(3)` and thus it cannot be used for drying `NH_(3),NH_(3)` can be dried by `CaO`. |
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65. |
Statement I `HNO_(3)` is a stronger acid than `HNO_(2)`. Statement II In `HNO_(3)`, there are two nitrogen to oxygen bonds whereas in `HNO_(2)` there is only one.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-9B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-10C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
Answer» Correct Answer - C | |
66. |
Statement I `HNO_(3)` is a stronger acid than `HNO_(2)`. Statement II In `HNO_(3)`, there are two nitrogen to oxygen bonds whereas in `HNO_(2)` there is only one. |
Answer» Correct Answer - A |
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67. |
Phosphine is obtained by the reaction whenA. white phosphorus is heated with NaOHB. `Ca_3P_2` reacts with waterC. red phosphorus is heated with NaOHD. phosphorus is heated in a current of hydrogen |
Answer» Correct Answer - a,b |
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68. |
Sodium thiosulphate is prepared byA. reducing `Na_(2)SO_(4)` solution with `H_(2)S`B. boiling `Na_(2)SO_(3)` solution with `S` in alkaline mediumC. neutralising `H_(2)S_(2)O_(3)` solution with `NaOH`D. boiling `Na_(2)SO_(3)` solution with `S` in acidic medium |
Answer» Correct Answer - B |
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69. |
Statement -1 : Sodium thiosulphate is not prepared by boiling `Na_(2)SO_(3)` with S in acidic medium. Statement -2 : `Na_(2)S_(2)O_(3)+H^(+) to 2Na++H_(2)SO_(3)+Sdarr`A. Statement -1 is true , Statement-2 is true, Statement-2 is a correct explantion for Statement -1.B. Statement -1 and Statement- 2 both are False.C. Statement -1 is true, Statement- 2 is false.D. Statement -1 is true, Statement- 2 is false. |
Answer» Correct Answer - A | |
70. |
Which of these statement is true for sodium thiosulphate ?A. it acts as an antichlorB. it is used as an reducing agent in iodometric titration.C. it reacts with hydrochloric acid to form `SO_(2)` and sulphurD. it is used in photography as hypo to dissolves exess of AgBr as soluble complex. |
Answer» Correct Answer - ABCD (A) It removes the chorine from the surface of fibres (while deying) according to following reaction. `Na_(2)S_(2)O+4Cl_(2)+5H_(2)O to 2NaHSO_(4)+8HCl` Therefore, it is known as antichlor. (B)`I_(3)^(-)+S_(2)O_(3)^(2-) to 3I^(-)+S_(4)O_(6)^(2-)` (C ) `S_(2)O_(3)^(2-)+H^(+) to S darr ("white") +SO_(2)+SO_(2)+H_(2)O` ("disproportionation reaction"). `(D)2S_(2)O_(3)^(2-)+Ag^(+) to [Ag(S_(2)O_(3))_(2)]^(3-)` ("soluble complex") or `[Ag(S_(2)O_(3))_(3)]^(5-)` This reaction is utlized in photography where hypo is used as fixer. |
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71. |
In mdern process, manufacturing of phosphorus is occurred byA. heating a mixlure of phosphorite mineral with sand and coke in electric furnaceB. heating calcium phosphate with cokeC. heating bone-ash with cokeD. heating the phosphate mineral with sand |
Answer» Correct Answer - A `Ca_(3)(PO_(4))_(2)+ 3SiO_(2) to 3CaSiO_(3)+P_(2)O_(5)` ` 2P_(2)O_(5) + 10 C to P_(4) + 10CO` |
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72. |
Which of the following statement is /are true for sodium thiosulphate ?A. It acts as an antichlorB. It is used as an reducing agent in iodometric titrationC. It reacts with hydrochloric acid to form `SO_2` and sulphurD. It is used in photography as hypo to dissolve excess of AgBr as soluble complex |
Answer» Correct Answer - a,b,c,d |
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73. |
Ammonia is produced on large scale by Haber-Bosch process which involve the following reaction `N_2(g)+3H_2 hArr 2NH_3 + "Heat"`…(i) The condition used are 200 atmosphere pressure, `450^@ C` and a catalst "Pormoted Iron". Originally H2 required for the reaction was produced by electrolysis of water.This was expensive a cheaper method using coke and steam was then used.Now a days, the `H_2(g)` is produced from hydrocarbons `CH_4+2H_2O hArr CO_2 + 4H_2`...(ii) `CH_4+H_2O hArr CO+ 3H_2`...(iii) Some air is added the `O_2` burns with some `H_2` leaving behind `N_2(g)` to give the required ratio of `N_2:H_2=1:3` Answer the following questions based on the above information. CO produced in the reaction (iii) must be removed continuously during the reaction because.A. it reacts with product ammoniaB. it poison the catalystC. it removes with `H_(2)`D. it removes with `N_(2)` |
Answer» Correct Answer - b |
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74. |
Ammonia is produced on large scale by Haber-Bosch process which involve the following reaction `N_2(g)+3H_2 hArr 2NH_3 + "Heat"`…(i) The condition used are 200 atmosphere pressure, `450^@ C` and a catalst "Pormoted Iron". Originally H2 required for the reaction was produced by electrolysis of water.This was expensive a cheaper method using coke and steam was then used.Now a days, the `H_2(g)` is produced from hydrocarbons `CH_4+2H_2O hArr CO_2 + 4H_2`...(ii) `CH_4+H_2O hArr CO+ 3H_2`...(iii) Some air is added the `O_2` burns with some `H_2` leaving behind `N_2(g)` to give the required ratio of `N_2:H_2=1:3` Answer the following questions based on the above information. Although the reaction is exothermic, it is being carried out at higher temperature beacauseA. it remove the volatile impurities.B. activate the catalystC. maintain a desirable rate of reaction.D. to have the less proportion of CO. |
Answer» Correct Answer - c |
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75. |
Asseration:Although:Although `PF_(5),PCl_(5)` and `PBr_(5)` are known, the pentahalides of nitrogen have not been observed. Reason: Phosphorus has lower electronegative than nitrogen.A. If both asseration and reson are true and the reason is the correct explanation of the asseration.B. If both asseration and reason are true ans the reason is the correct explanation of the asseration.C. If asseration is true but reason is false.D. If asseration is false but reason is true. |
Answer» Correct Answer - B If both asseration and reason are true but reason is not the correct explanation of the asseration. |
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76. |
Which of the following is isoelectronic as well as has the same structure as that of `N_2 O` ?A. `N_3H`B. `H_2O`C. `NO_2`D. `CO_2` |
Answer» Correct Answer - D `overset(* * )underset(* * ) O=C=underset(* *)overset(* * )O,underset(* * )overset(* * )N=N=underset(* *)overset(* * )O` |
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77. |
The hybrid states of phosphorous atoms in each `PCl_(5)` and `PBr_(5)` in gasesous phase are `sp^(3)d`. But, in solid `PCl_(5)`,phosphorous shows `sp^(3)d^(2)` and `sp^(3)` hybrid states. While,P in `PBr_(5)` is in`sp^(3)` hybrid state. This is because:A. `PCl_(5)` in solid form exists as `[PCl_(4)]^(+)[PCl_(6)]^(-)`B. `PBr_(5)` in solid form exists as `[PCl_(4)]^(+)[PBr_(6)]^(-)`C. `PCl_(5)` in solid form exists as `[PCl_(4)]^(+)Cl^(-)`D. `PBr_(5)` in solid form exists as `[PBr_(4)]^(+)Br^(-)` |
Answer» Correct Answer - A::D | |
78. |
In solid state, `PCl_(5)` is a……..A. covalent solidB. octahedral structureC. ionic solid with `[PCl_(6)]^(+)` octahedral and `[PCl_(4)]^(-)` tetrahedralD. ionic solid with `[Pcl_(4)]^(+)` tetrahedral and `[PCl_(6)]^(-)` octahedral |
Answer» Correct Answer - D | |
79. |
`PCl_(5)` is ionic in nature in the solid state. Give reasons. Or Solid phosphorus pentachloride behaves as an inoic compound. Explain. |
Answer» `PCl_(5)` conducts electricity in the molten state. This means that in the solid state, it exists as `[PCl_(6)]^(+)[PCl_(6)]^(-)` in which the cation is tetrahedral and the anion is octahedral `2PCl_(5)to[PCl_(4)]^(+)[PCl_(6)]^(-)` On melting these ions become free to move and hence `PCl_(5)` conducts electricity in the molten state. |
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80. |
On heating `Pb(NO_3)_2` the products formed ate :A. `PbO,N_(2),O_3`B. `Pb(NO_(3))_(2),O_(2)`C. `PbO ,NO_(2),O_(2)`D. `Pb,N_(2),O_(2)` |
Answer» Correct Answer - C `2Pb(NO_(3))_(2) to 2PbO +4NO_(2) +O_(2)` |
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81. |
Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ?A. `NO_(2)`B. `O_(2)`C. `N)_(2)`D. `N_(2)O` |
Answer» Correct Answer - B `PbO_(2)+4HNO_(3) to Pb(NO_(3))_(2)+2NO_(2)+2H_(2)O+O_(2)`. |
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82. |
Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ?A. `NO_(2)`B. `O_(2)`C. `N_(2)`D. `N_(2)O` |
Answer» Correct Answer - B |
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83. |
Which gas is evolved when `PbO_(2)` is treated with conc. `HNO_(3)` ?A. `NO_(2)`B. `O_(2)`C. `N_(2)`D. `N_(2)O` |
Answer» `2PbO_(2) + 4HNO_(3) rarr 2Pb(NO_(3))_(2) + 2H_(2)O + O_(2)` | |
84. |
Bond length is maximum inA. HFB. HClC. HID. HBr |
Answer» Correct Answer - C Oxidising power of species is directly proportional to reduction potentials. Therefore , order of oxidising power to give ions is a follows : `{:("Ion", BrO_(4)^(-), gt, IO_4^(-), gt , ClO_(4)^(-)),(E_(c)(V),1.74,,1.65,,1.19):}` |
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85. |
When `PbO_(2)` reacts with conc. `HNO_(3)` the gas evolved isA. `NO_(2)`B. `O_(2)`C. `N_(2)`D. `N_(2)O` |
Answer» Correct Answer - B `PbO_(2)` being a powerful oxidising agent , liberates `O_2 `, when treated with conc. `HNO_3 ` . |
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86. |
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. Ion `" " CiO_(4)^(-) " " IO_(4)^(-) " " BrO_(4)^(-)` Reduction `" " E^(Theta)=1.19 V " " E^(Theta)=1.65 V " " E^(Theta)=1.74` potential `E^(Theta)//V`A. `ClO_(4)^(-) gt IO_(4)^(-) gt BrO_(4)^(-)`B. `IO_(4)^(-) gt BrO_(4)^(-) gt ClO_(4)^(-) `C. `BrO_(4)^(-) gt IO_(4)^(-) gt ClO_(4)^(-)`D. `BrO_(4)^(-) gt ClO_(4)^(-) gt IO_(4)^(-)` |
Answer» Correct Answer - D When the mixture of noble gas is cooled in a coconut bulb at 173K then Ar, Kr and Xe and adsorbed on charcoal while He and Ne are not adsorbed . |
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87. |
Consider the following perhalate ions in acidic medium `ClO_(4)^(-)(I),BrO_(4)^(-)(II),IO_(4)^(-)(III)` Arrange these in the decreasing order of oxidizing powerA. `IgtIIgtIII`B. `IgtIIIgtII`C. `IIgtIgtIII`D. `IIgtIIIgtI` |
Answer» Correct Answer - D Standared reduction potential (in volts) of the perhalantions are given as below. `{:(CiO_(4)^(-)+2H^(+)+2e^(-)toClO_(3)^(-)+H_(2)O,E^(@)=+1.19 V),(BrO_(4)^(-)+2H^(+)+2e^(-)toBrO_(3)^(-)+H_(2)O,E^(@)=+1.74 V),(IO_(4)^(-)+2H^(+)+2e^(-)toIO_(3)^(-)+H_(2)O,E^(@)=+1.65 V):}` |
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88. |
Statement-1 : Among nitrogen halides `NX_(3)`, the dipole moment is higher for `NI_(3)` and lowest for `NF_(3)`. Statement-2 : Nitrogen halides `NX_(3)`, have trigonal pyramidal structure.A. If both assertion and reason are true and reason is the true explanation of the asseraton.B. If both assertion and reason are true and reason is not the correct explanation of the assertion.C. If assertion is true bit reason is false.D. If assertion is false but reason is true. |
Answer» Correct Answer - B Both assertion and reason are true but reason is not the correct explanaton of assertion. In case of `NI_(3)`, the lone pair moment on partly cancels the resultantn moments. |
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89. |
Asseration: `SCl_(4)`, does not havea tetrahedral structure. Reason: `Se` in `SeCl_(4)` has two lone pairs.A. If both assertion and reason are true and reason is the true explanation of the asseraton.B. If both assertion and reason are true and reason is not the correct explanation of the assertion.C. If assertion is true bit reason is false.D. If assertion is false but reason is true. |
Answer» Correct Answer - C `SeCl_(4)` possess see saw geometry, which can be regarded as a distored trigonal bipyramidal structure laving one lone pair `(lp)` of electrons in the basal position of the trigonal bipyramidal. See-saw geometry of `SeCl_(4)` molecules arises due to the `sp^(3)d` hydridisation of the central atom. the distortion in shape is due to the presence of one lone pair of electrons. |
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90. |
Asseration: `SeCl_(4)`, does not havea tetrahedral structure. Reason: `Se` in `SeCl_(4)` has two lone pairs.A. If both the asseration and reason are ture and reason is the true explation of the assertion.B. If both the asseration and reason are ture but the reason is not the correct explanation of assertion.C. If the asseration is true but reason is false.D. If asseration is false bit reason is true. |
Answer» Correct Answer - C `Se` in `SeCl_(4)` has one lone pair of electron. |
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91. |
Under hydrolytic condition, the compounds used for preparation of linear polymer and for chaing termination respectively areA. `CH_(3)SiCl_(3)` and `Si(CH_(3))_(4)`B. `(CH_(3))_(2)SiCl_(2)` and `(CH_(3))_(3)SiCl`C. `(CH_(3))_(2)SiCl_(2)` and `CH_(3)SiCl_(3)`D. `SiCl_(4)` and `(CH_(3))_(3)SiCl` |
Answer» Correct Answer - B `(CH_(3))_(2)SiCl_(2)` for linear polymerization and `(CH_(3))_(3)SiCl` for chain termination. |
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92. |
Which of the following is not a monomer for a high molecular mass silicone polymer ?A. `Me_(3)SiCl`B. `PhSiCl_(3)`C. `MeSiCl_(3)`D. `Me_(2)SiCl_(2)` |
Answer» Correct Answer - A `Me_(3)SiCl` on hydrolysis gives `Me_(3)SiOH` which has only one OH group and hence cannot act as a monomer in condensation polymerization to give high molecular mass silicone polymer. |
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93. |
Give the oxidation states of halogens in the following : `NaClO_(4)` |
Answer» `NaClO_(4)` : `1+x+4(-2)=0` `x=+7` In `NaClO_(4)` the oxidation state of Cl is + 7 |
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94. |
Complete the following reactions equations : (i)`Ca(O CI)_(2)+HCl to` (ii)`NaClO_(3)(aq)+SO_(2)(g) to` |
Answer» Correct Answer - (i)`Ca(OCI)_(2)+4HCltoCaCl_(2)+2H_(2)O + 2Cl_(2)` (ii)`2NaCIO_(3)(aq)+SO_(2)(g)to2ClO_(2)underset("Chlorine dioxide")((g) +Na_(2)SO_(4))` |
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95. |
Why conc `"H"_(2)"SO"_(4),"P"_(4)"O"_(10)` and anhydrous `CaCl_(2)` cannot be used to dry ammonia ? (Hint : ammonia reacts with them forming `(NH_(4))_(2)SO_(4),(NH_(4))_(3)PO_(4)" and "CaCl_(2),8NH_(3)`) |
Answer» For drying ammonia quick line (CaO) is used. `to` For drying ammonia conc. `H_(2)SO_(4),P_(4)O_(10)` and anhydrous `CaCl_(2)` cannot be used because they react with ammonia and forms `(NH_(4))_(2)SO_(4),(NH_(4))_(3)PO_(4)` and `CaCl_(2).8NH_(3)` `H_(2)SO_(4)+2NH_(3)to(NH_(4))_(2)SO_(4)` `P_(4)O_(10)underset(H_(2)O)overset(NH_(3))to(NH_(4))_(3)PO_(4)`. `CaCl_(2)+8NH_(3)toCaCl_(3)8NH_(3)`. |
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96. |
Identify `(X)` and `(Y)` in the following reactions : Colemanite `+ (X) rarr Na_(2) B_(4) O_(7)` `NaB_(4) O_(7) + (Y) rarr H_(3) BO_(3)`. |
Answer» `Ca_(2)B_(6)O_(11)+2Na_(2)CO_(3)rarrNa_(2)B_(4)O_(7)+2NaBO_(2)+2CaCO_(3)` Colemanite (A) `Na_(2)B_(4)O_(7)+2HCl+5H_(2)Orarr4H_(3)BO_(3)+2NaCl` |
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97. |
Which pair of substances can be combined to produce ammonia gas? (P)` (NH_(4))_(2)SO_(4)(s)" and " NaOH(aq)` (Q) `NH_(3)(aq) and HCl(aq)`A. P onlyB. Q onlyC. Both P and QD. Neither P nor Q |
Answer» Correct Answer - B `NH_(3)+HCl rarr NH_(4)Cl` |
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98. |
Product obtained on heating `KClO_3` with conc. `H_2SO_4` is/areA. Chloride dioxideB. `HClO_4`C. `KHSO_4`D. All |
Answer» Correct Answer - D `2KClO_3 + 3H_2SO_4 to 3KHSO_4 + HClO_4 + 2ClO_2 + H_2O` |
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99. |
Fill in the blanks. Conc. `H_2SO_4` chars paper, wood and sugar by removing _____A____ from them. It is also known as _____B____. It is manufactured by ___C___ process. It is a strong _D_ and _E_ acid.A. A-`H_2O`, B-Oil of vitriol, C-contact , D-oxidising , E-dibasicB. A-`O_2` , B-Oil of vitriol , C-Oleum , D-dehydrating , E-monobasicC. A-`H_2O`, B - Oil of olay, C - Solvay, D - dehydrating, E - dibasicD. A - `SO_2`, B - Oil of winter green, C - Contact, D - oxidising, E - monobasic |
Answer» Correct Answer - A Concentrated `H_2SO_4` acts as strong dehydrating agent. It is also called oil of vitriol, obtained by contact process and is dibasic |
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100. |
The formation of brown ring in the reaction between nitrates, conc. `H_2SO_4` and `FeSO_4` involvesA. oxidation of nitric oxide to nitrogen dioxideB. reduction of ferrous sulphate to ironC. reduction of nitrate to nitric oxideD. oxidising property of sulphuric acid |
Answer» Correct Answer - C `Fe^(2+)` ion has a tendency to reduce `NO_3^- ` to nitric oxide NO `(N^(2+))` in presence of conc. `H_2SO_4`. `NO_3^(-) + 3Fe^(2+) + 4H^(+) to NO+ 3Fe^(3+) + 3H_2O` |
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