InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An equilateral triangle and d square has equal perimeter. If side of the triangle is 9.6 cm ; what is the length of the side of the square ? |
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Answer» Perimeter of equilateral triangle = Perimeter of square Side of triangle = 9.6 cm ∴ Perimeter of triangle = 3 x side = 3 x 9.6 cm = 28.8 cm => Perimeter of the square = 28.8 cm 4 x the side of square = 28.8 cm ⇒ The side of the square = 28.8/4 cm = 7.2 cm Ans. |
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| 2. |
Find the perimeter of a square whose each side is 1.6 m. |
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Answer» ∵ Side of the square = 1.6 m ∴ its perimeter = 4 x side = 4 x 1.6 m = 6.4 m |
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| 3. |
The perimeter of a square is 60 m, find :(i) its each side its area(ii) its new area obtained on increasing(iii) each of its sides by 2 m. |
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Answer» Perimeter of a square = 60 m (i) Perimeter of a square = 4 x side 60 m = 4 x side 60/4 = side 4 ∴side = 15 m (ii) Area of square = (side)² = (15 m)² = 15 m x 15 m = 225 m² (iii) Increased each side = 2 m Side of square = 15 m New length of side = (2m + 15m) = 17m ∴ New Area of square = (17m)² = 17m x 17m = 289 m² |
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| 4. |
What will happen to the area of a rectangle, if its length and breadth both are trebled? |
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Answer» Let the original length of the rectangle = l and its original breadth = b ∴ its original area = length x breadth i.e A = l – b Since, Increased length = 3l and, increased breadth = 3b ∴ New area = 3l x 3b = 9 x l x b [∵A = l x b] ⇒ Area of the new rectangle = 9 times than area of original rectangle |
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| 5. |
The perimeter of a square plot = 360 m. Find :(i) its area.(ii) cost of fencing its boundary at the rate of Rs 40 per meter.(iii) cost of leveling the plot at Rs 60 per square meter. |
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Answer» Given, perimeter of square plot = 360 m ∵ Perimeter of the square = 4 x its side ∴ 4 x side of square = 360 m ⇒ side of the square = (360/4) m = 90 m (i) The area of the square field = (side)² = (90 m)² = 90 m x 90 m = 8100 m² (ii) Cost of fencing at Rs 40 per metre = 8100 m2 x Rs 40 per metre = Rs 324000 (iii) Cost of levelling at Rs 60 per m² = 8100 m² x Rs 60 per m² = Rs 486000 |
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| 6. |
The interior of a figure is called region of the figure. Is this statement true ? |
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Answer» Yes. The interior of the figure along with its boundary is called the region of the figure. |
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| 7. |
Each side of a square field is 70 cm. How much distance will a boy walk in order to make ?(i) one complete round of this field ?(ii) 8 complete rounds of this field ? |
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Answer» (i) Distance covered by the boy to make one complete round of the field. Perimeter of the field : 4 x its side = 4 x 70 = 280 m (ii) Distance covered by the boy to make 8 complete rounds of this field. = 280 m x 8 m = 2240 m |
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| 8. |
The length of a rectangle is twice of its breadth. If its perimeter is 60 cm, find its length. |
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Answer» Let the breadth of the field = x cm ∴ its length = 2x and, its perimeter = 2 x (length + breadth) = 2 x (2x + x) = 2(3x) = 6x cm Perimeter = 60 cm ⇒ 60 cm = 6x cm ⇒ x = 60/6 = 10 cm ∴Breadth = x = 10 cm Length = 2x = 2 x 10 = 20 cm |
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| 9. |
A square field has each side 70 m whereas a rectangular field has length = 50 m and breadth = 40 m. Which of the two fields has greater perimeter and by how much? |
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Answer» Perimeter of the square field = 4 x side = 4 x 70m = 280m Perimeter of rectangular field = 2 (length + breadth) = 2 (50 m + 40 m) = 2 x 90 m = 180 m ∴ Square field has greater perimeter by 280 m – 180 m = 100 m |
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| 10. |
The perimeter of a rectangular field is 500 m and its length = 150 m. Find:(i) its breadth,(ii) its area.(iii) cost of ploughing the field at the rate of Rs 1.20 per square meter. |
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Answer» (i) Perimeter of a rectangle = 2 x (length + breadth) ⇒ 500 m = 2x(150 m + breadth) ⇒ 250 m – 150 m = breadth ∴ breadth = 100 m (ii) Area of rectangular field = length x breadth = 150 m x 100 m = 15000 m² (iii) Cost of ploughing the field at the rate of = Rs 1.20 per square m² = area of the field x rate of ploughing = 15000 m² x Rs 1.20 per square metre = Rs 15000 x 1.20 = Rs 18000 |
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