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1.

An equilateral triangle and d square has equal perimeter. If side of the triangle is 9.6 cm ; what is the length of the side of the square ?

Answer»

Perimeter of equilateral triangle = Perimeter of square Side of triangle = 9.6 cm

∴ Perimeter of triangle = 3 x side

= 3 x 9.6 cm = 28.8 cm

=> Perimeter of the square = 28.8 cm

4 x the side of square = 28.8 cm

⇒ The side of the square = 28.8/4 cm

= 7.2 cm Ans.

2.

Find the perimeter of a square whose each side is 1.6 m.

Answer»

∵ Side of the square = 1.6 m

∴ its perimeter = 4 x side

= 4 x 1.6 m

= 6.4 m

3.

The perimeter of a square is 60 m, find :(i) its each side its area(ii) its new area obtained on increasing(iii) each of its sides by 2 m.

Answer»

Perimeter of a square = 60 m

(i) Perimeter of a square = 4 x side

60 m = 4 x side

60/4 = side 4

∴side = 15 m

(ii) Area of square = (side)² = (15 m)²

= 15 m x 15 m

= 225 m²

(iii) Increased each side = 2 m

Side of square = 15 m

New length of side = (2m + 15m)

= 17m

∴ New Area of square = (17m)² = 17m x 17m = 289 m²

4.

What will happen to the area of a rectangle, if its length and breadth both are trebled?

Answer»

Let the original length of the rectangle = l and its original breadth = b

∴ its original area = length x breadth i.e A = l – b 

Since,

Increased length = 3l

and, increased breadth = 3b

∴ New area = 3l x 3b = 9 x l x b [∵A = l x b]

⇒ Area of the new rectangle = 9 times than area of original rectangle

5.

The perimeter of a square plot = 360 m. Find :(i) its area.(ii) cost of fencing its boundary at the rate of Rs 40 per meter.(iii) cost of leveling the plot at Rs 60 per square meter.

Answer»

Given, perimeter of square plot = 360 m

∵ Perimeter of the square = 4 x its side

∴ 4 x side of square = 360 m

⇒ side of the square = (360/4) m = 90 m

(i) The area of the square field = (side)²

= (90 m)²

= 90 m x 90 m

= 8100 m²

(ii) Cost of fencing at Rs 40 per metre

= 8100 m2 x Rs 40 per metre

= Rs 324000

(iii) Cost of levelling at Rs 60 per m²

= 8100 m² x Rs 60 per m²

= Rs 486000

6.

The interior of a figure is called region of the figure. Is this statement true ?

Answer»

Yes. The interior of the figure along with its boundary is called the region of the figure.

7.

Each side of a square field is 70 cm. How much distance will a boy walk in order to make ?(i) one complete round of this field ?(ii) 8 complete rounds of this field ?

Answer»

(i) Distance covered by the boy to make one complete round of the field.

Perimeter of the field : 4 x its side = 4 x 70 = 280 m

(ii) Distance covered by the boy to make 8 complete rounds of this field.

= 280 m x 8 m = 2240 m

8.

The length of a rectangle is twice of its breadth. If its perimeter is 60 cm, find its length.

Answer»

Let the breadth of the field = x cm

∴ its length = 2x

and, its perimeter = 2 x (length + breadth)

= 2 x (2x + x)

= 2(3x)

= 6x cm

Perimeter = 60 cm

⇒ 60 cm = 6x cm

⇒ x = 60/6 = 10 cm

∴Breadth = x = 10 cm

Length = 2x = 2 x 10 = 20 cm

9.

A square field has each side 70 m whereas a rectangular field has length = 50 m and breadth = 40 m. Which of the two fields has greater perimeter and by how much?

Answer»

Perimeter of the square field = 4 x side = 4 x 70m = 280m

Perimeter of rectangular field = 2 (length + breadth)

= 2 (50 m + 40 m)

= 2 x 90 m

= 180 m

∴ Square field has greater perimeter by 280 m – 180 m = 100 m

10.

The perimeter of a rectangular field is 500 m and its length = 150 m. Find:(i) its breadth,(ii) its area.(iii) cost of ploughing the field at the rate of Rs 1.20 per square meter.

Answer»

(i) Perimeter of a rectangle = 2 x (length + breadth)

⇒ 500 m = 2x(150 m + breadth)

⇒ 250 m – 150 m = breadth

∴ breadth = 100 m

(ii) Area of rectangular field = length x breadth

= 150 m x 100 m = 15000 m²

(iii) Cost of ploughing the field at the rate of

= Rs 1.20 per square m² = area of the field x rate of ploughing = 15000 m² x Rs 1.20 per square metre = Rs 15000 x 1.20 = Rs 18000