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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
701. |
Elements which generally exhibit multiple oxidation states and whose ions are usually coloured areA. MetalloidsB. Transition elements 0C. Non-metalsD. Gases |
Answer» Correct Answer - B |
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702. |
The total numbers of elements in the Group 11 isA. 3B. 5C. 7D. 9 |
Answer» Correct Answer - A |
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703. |
Which of the following ion of an element E (E belongs to 2nd period) having `1s^(2)2s^(0),2p^(0)` electronic configuration in ground state? For the element E following data is given: `IE_(1)` of `E = 800 kJ//"mole" IE_(2)` of `E = 1428 kJ//"mole"` `IE_(3)` of `E = 2394 kJ//"mole" IE_(4)` of `E = 25020 kJ//"mole"`A. `E^(+)`B. `E^(++)`C. `E^(+++)`D. `E^(++++)` |
Answer» Correct Answer - C | |
704. |
Which of the following electronic configuration in the outermost shell is characterstic of alkali metals?A)`(n-1) s^(2) p^(6), ns^(2) p^(1)`B)`(n-1) s^(2)p^(6), d^(10), ns^(1)`C)`(n-1) s^(2)p^(6), ns^(1)`D)`(n-1) s^(2)p^(6), ns^(1)`A. `(n-1) s^(2) p^(6), ns^(2) p^(1)`B. `(n-1) s^(2)p^(6), d^(10), ns^(1)`C. `(n-1) s^(2)p^(6), ns^(1)`D. `ns^(2) p^(6) d^(1)` |
Answer» Correct Answer - C |
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705. |
The atomic numbers of elements of second transition series lie in the range ofA. 38 to 47B. 39 to 48C. 40 to 49D. 41 to 50 |
Answer» Correct Answer - B |
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706. |
The element with atomic number 12 belongs to.........Group and........periodA. IA, thirdB. IIA, thirdC. IIA, thirdD. IIA, second |
Answer» Correct Answer - C |
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707. |
Which of the following electronic configuration corresponds to an inert gas?A)`1s^(1) 2s^(2) 2p^(5)`B)`1 s^(2) 2s^(2) 2p^(6)`C)`1 s^(2) 2s^(1)`D)`1 s^(2) 2s^(2) 2p^(6) 3s^(1)`A. `1s^(1) 2s^(2) 2p^(5)`B. `1 s^(2) 2s^(2) 2p^(6)`C. `1 s^(2) 2s^(1)`D. `1 s^(2) 2s^(2) 2p^(6) 3s^(1)` |
Answer» Correct Answer - B |
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708. |
Atomic number of next inert gas to be discovered will beA. 87B. 104C. 118D. 132 |
Answer» Correct Answer - C |
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709. |
The inert gas present in the second long period is |
Answer» Correct Answer - 1 | |
710. |
What should be the atomic number of the next inert gas if discovered in future ?A. 115B. 119C. 118D. 121 |
Answer» Correct Answer - C The next halogen will have `7s^(2)7p^(5)` outer configuration. Since, the filling of 7-orbitals will begin after `5f` and `6d-`orbitals, thus the atomic number of the new halogen will be 112 (up to the filling of 6d-orbitals) plus 5, i.e., 117. |
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711. |
S-1:- `IE_(1)` of `Sr gt Rb` but `IE_(2)` for `Rb gt Sr` S-2:- The ionic radii of `Li^(+)`, `K^(+)`, `Mg^(2+)` and `Al^(3+)` in `A^(@)` are `0.76, 1.38, 0.720, " and " 0.535` respectively. S-3:- The negative value of electron gain enthalpy of `Cl gt F` because there is weak electron-electron repulsions in the bigger 3p-subshell of Cl as compared to compact 2p-subshell of F. S-4:- The second ionisation energy of copper is less than potassium.A. FFTTB. TTFTC. TTTFD. TTTT |
Answer» Correct Answer - D |
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712. |
Arrange `Ce^(3+),La^(3+), Pm^(3+)` and `Yb^(3+)` in increasing order of their size -A. `Yb^(+3) lt Pm^(+3) lt Ce^(+3) lt La^(+3)`B. `Ce^(+3) lt Yb^(+3) lt Pm^(+3) lt La^(+3)`C. `Yb^(+3) lt Pm^(+3) lt La^(+3) lt Ce^(+3)`D. `Pm^(+3) lt La^(+3) lt Ce^(+3) lt Yb^(+3)` |
Answer» Correct Answer - A Since of lanthanides progressively decreases as atomic number increases |
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713. |
`IE_(1)` and `IE_(2)` of `Mg` are `178` and `348 kcal mol^(-1)`. The energy required for the reaction `Mg rarr Mg^(2+)+2e^(-)` isA. `+170` kcalB. `+526` kcalC. `-170` kcalD. `-526` kcal |
Answer» Correct Answer - B `E = IE_(1)+IE_(2) = 178 +348 =+ 526` kcal |
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714. |
In above graph element F is:A. oxygenB. nitrogenC. fluorineD. neon |
Answer» Correct Answer - A `{:(A rarr Li, Brarr Be),(C rarr B, D rarr C),(E rarr N, F rarrO),(G rarrF, H rarr Ne):}` |
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715. |
As the alkaline earth metals (except Be) tend to lose their valence electrons readily they act asA. Weak oxidising agentB. Weak reducing agentC. Strong oxidising agentD. Strong reducing agent |
Answer» Correct Answer - D |
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716. |
The order in which the following oxides are arranged according to decreasing basic nature isA)`CuO, Na_(2)O, MgO, Al_(2)O_(3)`B)`Al_(2)O_(3), MgO, CuO, Na_(2)O`C)`MgO, Al_(2)O_(3), CuO, Na_(2)O`D)`Na_(2)O, MgO, Al_(2)O_(3), CuO`A. `CuO, Na_(2)O, MgO, Al_(2)O_(3)`B. `Al_(2)O_(3), MgO, CuO, Na_(2)O`C. `MgO, Al_(2)O_(3), CuO, Na_(2)O`D. `Na_(2)O, MgO, Al_(2)O_(3), CuO` |
Answer» Correct Answer - D |
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717. |
Arrange `S,O and Se` in acending order of electron affinity?A. `Se lt S lt O`B. `O lt Se lt S`C. `S le O le Se`D. `S lt Se lt O` |
Answer» Correct Answer - B |
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718. |
Which of the following statement is not correctA. Tc and Pm are not found in natureB. Element having `ns^(2) np^(5)` configuration are placed in the column before the extreme righ in the P.T.C. Most of the man made element occurs in the actinide series.D. In 3rd period no. of electrons=18 |
Answer» Correct Answer - D | |
719. |
Which of the following is/are correct?A. For `A(g) +e^(-) rarr A^(-) (g) DeltaH` may be negativeB. For `A^(-)(g) +e^(-) rarr A^(2-) (g) DeltaH` may be negativeC. For `A^(-)(g)+e^(-) rarr A^(2-)(g) DeltaH` must be positiveD. For `A^(+3) (g) +e^(-) rarr A^(+2)(g)DeltaH` must be negative |
Answer» Correct Answer - A::C::D | |
720. |
The ionic compound `A^(+)B^(-)` is formed when theA. electron gain enthalpy of B is highB. ionization energy of A is lowC. lattice energy of AB is highD. lattice energy of AB is low |
Answer» Correct Answer - A::B::C | |
721. |
Amongst the following statements, which is/are correct?A. Electronegativity of sulphur is greater than that of oxygenB. Electron affinity of oxygen is smaller than that of sulphurC. Electron gain enthalpy of fluorine is most negativeD. Electron gain enthalpy of chlorine is most negative |
Answer» Correct Answer - B::D | |
722. |
Which of the following statement is not correctA. Noble gases have a different number of outermost electrons than their group numberB. In the sixth period the orbitals being filled are 6s, 4f, 5d, 6pC. Zn, Cd, Hg are non transition elementsD. `O^(-2)` has the same no. of `e^(-)s` in its outermost as well as penultimate shell. |
Answer» Correct Answer - D | |
723. |
Which of the following is correct order of EA.A. `N lt C lt O lt F`B. `F gt CI gt Br gt I`C. `CI gt F gt Br gt I`D. `C lt N lt O lt F` |
Answer» Correct Answer - A::C | |
724. |
The elements which are radioactive and have been named after the name of planet areA. HgB. NpC. LuD. Ra |
Answer» Correct Answer - B | |
725. |
Which of the following is/are correct?A. For `A(g)+e^(-)rarr A^(-)(g) DeltaH` mat be negativeB. For `A^(-)(g) +e^(-) rarr A^(2-)(g) DeltaH` may be negativeC. For `A^(-)(g)+ e^(-) rarr A^(2-)(g) DeltaH` must be positiveD. For `A^(+3) (g)+e^(-) rarr A^(+2)(g) DeltaH` must be negative |
Answer» Correct Answer - A::C::D | |
726. |
Which of the following statements is/are incorrect ?A. Ionisation energy of `A^(-)` is greater than A when A is a halogen atom.B. Ionisation energy of `A^(+)` is greater than that of `A^(2+)` when A is the number of alkali metalsC. Successive ionisation energy is always increasing for 1st and 2nd period elementD. Electron affinity value of `A^(+)` is numerically identical with the ionisation potential of `A^(-)` [for any atom] |
Answer» Correct Answer - A::B::D | |
727. |
Which of the following is/are correctly matcged?A. `E gt O` (Electronegativity)B. `Mg gt AI` (1st ionisation energy)C. `HCI gt HI` (Thermal stability)D. Diamond `gt` Graphite (Electrical conductance) |
Answer» Correct Answer - A::B::C | |
728. |
Which of the following is not correctly matchedA. d-block element: `(n-1)d^(1-10)ns^(0-2)`B. p-block element:`ns^(2)np^(1-6)`C. s-block element: `(n-1)f^(@)(n-1)d^(@)ns^(1-2)`D. Representative element : `ns^(1-2)np^(1-5)` |
Answer» Correct Answer - D | |
729. |
Which of the following is not correctly matchedA. `[Xe]4f^(14)5d^(10)6s^(2) to ` Transition elementB. `[Rn]5f^(14)6d^(1)7s^(2) to ` Inner transition elementC. `[Xe]4f^(14)5d^(10)6s^(2)6p^(6)7s^(2) to ` Representative elementD. `[Xe]4f^(14)5d^(2)6s^(2) to ` d- block element |
Answer» Correct Answer - A | |
730. |
An element whose IUPAC name is ununtrium (UUT) belong toA. s-blockB. p-blockC. d-blockD. f-block |
Answer» Correct Answer - B | |
731. |
Which will have the maximum value of electron affinity `O^(x),O^(y),O^(z)` [x,y and z respectively are `0,-1` and `-2]`?A. `O^(x)`B. `O^(y)`C. `O^(z)`D. All have equal |
Answer» Correct Answer - A Being neutral atom oxygen will have highter electron affinity as there is electrostatic repulsion between additional electron and negative ion in case of `O^(-)` and `O^(2-)`. So option (a) is correct. |
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732. |
If we move from centre towards end points through three different paths (P),(Q),(R) in following figure, then which path is correct increasing order of `IE_(1)`? `[N,S,C,O,P,Si` represent various elements of periodic table]A. P onlyB. Q and RC. R onlyD. P and R |
Answer» Correct Answer - A (P) and (Q) both paths are possible. |
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733. |
The atomic numbers of elements A,B,C and D are Z - 1, Z, Z + 1 and Z + 2 respectively. If B is a noble gas, choose the correct statement among the following statements : I. A has higher electron affinity. II. C exists in +2 oxidation state. III. D is an alkaline earth metal.A. a & bB. b & cC. a & cD. a,b & c |
Answer» Correct Answer - C |
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734. |
Decreasing order of electronegativities of `F,CI,Br` and `I` isA. `F lt CI lt Br lt I`B. `I lt Br lt CI lt F`C. `Br lt I gt CI gt F`D. `I lt Br gt CI lt F` |
Answer» Correct Answer - B Electronegativity decreases in a group on going from top to bottom. Therefore `I lt Br lt CI lt F` |
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735. |
Which of the following process refers to ionisation potential ?A. `X_((s)) rarr X_((g))^(+) +e^(-)`B. `X_((g)) +aq rarr X_((aq))^(+) +e^(-)`C. `X_((g)) rarr X_((g))^(+) +e^(-)`D. `X_((g)) +e^(-) rarr X_((g))^(-)` |
Answer» Correct Answer - C |
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736. |
The element with highest ionization potential isA. NitrogenB. OxygenC. HeliumD. Neon |
Answer» Correct Answer - C |
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737. |
Why do some of the periodic properties like atomic size, electronegativty and ionisation potential of transition and inner transition elements not show as much variation as the representative elements? |
Answer» (i) shell into which the differentiating electron enters (ii) general electronic configuration of representative elements (iii) comparison with general electronic configurations of transition and inner transition elements (iv) comparison of effective nuclear charge and its effect on the periodic properties |
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738. |
In the long form of periodic table elements with low ionisation potential are present inA. IA groupB. IV A groupC. VII A groupD. Zero group |
Answer» Correct Answer - A |
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739. |
As atomic number of elements increases I.P. value of the elements of the sameA. DecreasesB. IncreasesC. Remains constantD. First increases and then decreases |
Answer» Correct Answer - B |
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740. |
The ionization potential values of an element are in the following order `I_(1) lt I_(2) lt lt lt lt I_(3) lt I_(4) lt I_(5)`. The element isA. Alkali metalB. ChalcogenC. HalogenD. Alkaline earth metals |
Answer» Correct Answer - D |
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741. |
Which of the following elements has the lowest ionization potential ?A. NB. OC. FD. Ne |
Answer» Correct Answer - B |
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742. |
Which of the following elements has the lowest ionization potential ?A. NitrogenB. OxygenC. FluorineD. Neon |
Answer» Correct Answer - B |
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743. |
Which one of the following order is correct for the first ionisation energies of the elements?A. `B lt Be lt N lt O`B. `Be lt B lt N lt O`C. `B lt Be lt O lt N`D. `B lt O lt Be lt N` |
Answer» Correct Answer - C |
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744. |
The energy released when a neutral gasous atom, takes up an electron and forms a uninegative ion is called itsA. Effective nuclear chargeB. Polarising powerC. Electron affinityD. Ionization potential |
Answer» Correct Answer - C |
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745. |
The group of elements with highest second ionisation energy isA. IIA groupB. Zero groupC. VIIA groupD. IA group |
Answer» Correct Answer - D |
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746. |
Ionisation energy is highest for:A. FB. `CI^(-)`C. `Be^(-)`D. `S^(-)` |
Answer» Correct Answer - A | |
747. |
The ionization potential for hydrogen atom is `13.6 eV`, the ionization potential for `He^(+)` isA. `13.6eV`B. `54.4eV`C. `6.8eV`D. `3.4eV` |
Answer» Correct Answer - B |
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748. |
First and second ionisation energies of `Be_((g)) are 900 kJ mol_(1) and 1750 kJ mol_(1)` approximately. Claculate approximate percentage of `Be^(2+)_((g))` ions, if 1 g of `Be_((g))` absorbs 150 kJ of energy [atomic weight of Be is 9]. |
Answer» (i) amount of energy absorbed by 1 g of Be to form `Be^(+) and Be^(+2)` (ii) energy required for conversion of 1 g `Be_((g)) into `Be^(+)` ions (iii) calculation of additional amount of energy (iv) conversion of `Be^(+)` ions to `Be^(+2)` ions (v) 25%. |
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749. |
Two elements A and B have the following electronic configurations. The formula of the compound formed between them can be `A=1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(1), B=1s^(2) 2s^(2) 2p^(4)`A. ABB. `AB_(2)`C. `A_(2)B_(3)`D. `A_(3)B_(2)` |
Answer» Correct Answer - C |
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750. |
Elements `A, B, C, D` and `E` have the following electronic configurations: A: `1s^(2) 2s^(2) 2p^(1)` B: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(1)` C: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(2)` D: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(5)` E: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2)` Which among these will belong to the same group in the periodic table? |
Answer» Out of these, elements `A` and `B` will belong to the same group of the periodic table because they have same outer electronic configuration, `ns^(2) np^(1)`. | |