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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 751. |
Which existing element would the chemistry of element 119 most resemble?A. `Rn(Z = 86)`B. `Fr (Z = 87)`C. `Ra (Z = 88)`D. `Ac (Z = 89)` |
| Answer» Correct Answer - B | |
| 752. |
The atomicity of noble gases isA. 2B. 1C. 4D. 6 |
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Answer» Correct Answer - B |
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| 753. |
Ionization energy is high forA. Sulphide ionB. Phosphide ionC. Calcium ionD. Magnesium ion |
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Answer» Correct Answer - D |
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| 754. |
The first ionisation energy of magnesium is greater than that of sodium, whereas the recerse is true for second ionisation energy. Explain. |
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Answer» (i) electronic configuration of sodium and magnesium (ii) comparison of atomic size of sodium and magnesium (iii) effect of atomic size on first ionization energy (iv) electronic configuration of stable ions of sodium and magnesium (v) relation between the stability of ion and the respective ionization energy |
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| 755. |
Why the first ionisation energy of carbon atom is greater than that of boron atom whereas, the reverse is true for the second ionisation energy. |
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Answer» Correct Answer - [Zeff & half filled config.] `[C = 1s^(2) 2s^(2) 2p^(2)` `B = 1s^(2) 2s^(2) 2p^(1)` Left to right atomic size decreases, `IE_(1) uarr` After the removal of `1e^(-), B` acquire fully filled stable s-orbital configuration, therefore `IE_(2)` of `B gt C` |
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| 756. |
Assertion (A): First ionisation energy of beryllium is greater than that of boron. Reanos (R): Boron has larger size than beryllium.A. (a) Both A and R are true and R is the correct explanation of AB. (b) both A and R are true and R is not the correct explanation of AC. (c) A is true, R is falseD. (d) Ais false, R is true |
| Answer» Correct Answer - b | |
| 757. |
The first ionisation energy of beryllium is more than that of boron becauseA. B has `1s^(2) 2s^(2) 2p^(1)` configurationB. B has small atomic sizeC. B has higher nuclear chargeD. B has more number of shells |
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Answer» Correct Answer - A |
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| 758. |
An element "X" has `IP=1681` kJ/mole and `EA=-333` kJ/mole then its electronegativity isA. `1681+333//544`B. `1681-333//544`C. `1681+333//2`D. `(0.208sqrt(1681+333))/(544)` |
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Answer» Correct Answer - A |
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| 759. |
Statement-1: Boron has a smaller first ionisation enthalpy than beryllium. Statement-2: The penetration of a 2s electron to the nucleus is more than the 2p electron hence 2p electron is more shielded by the inner core of electrons than the 2s electrons.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-2B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-2C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - C | |
| 760. |
Beryillum resembles Aluminium in properties. This is mainly due toA. Equal electronegativity values of elementsB. Equal atomic volumes of the elementsC. Equal electron affinityD. Equal nuclear charges in the their atoms |
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Answer» Correct Answer - A |
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| 761. |
The incorrect statement in the following isA. The third ionisation potential of Mg is greater than the third ionisation potential of `Al`B. The first ionisation potential of Na is less than first I.P. of MgC. The first I.P. of Al is less than the first I.P. of MgD. The second I.P. of Mg is greater than the second I.P. of Na |
| Answer» Correct Answer - D | |
| 762. |
EN of the element (A) is `E_(1)` and EA is `E_(2)` hence IP will be :A. `2e_(1)-E_(2)`B. `E_(1)-E_(2)`C. `E_(1)-2E_(2)`D. `(E_(1)+E_(2))//2` |
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Answer» Correct Answer - A |
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| 763. |
The chemical similarly between boron and silicon is mainly due to equal value of theirA. electronegativityB. nuclear chargeC. charge to `("ionic radius"^(2))` ratioD. atomic volume |
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Answer» Correct Answer - C |
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| 764. |
One mole of magnesium in the vapor state absored `1200 kJ mol^(-1)` of enegry. If the first and second ionization energies of `Mg` are `750` and `1450 kJ mol^(-1)`, respectively, the final composition of the mixture isA. `69% Mg^(+), 31% Mg^(2+)`B. `59% Mg^(+), 41% Mg^(2+)`C. `49%Mg^(+), 51% Mg^(2+)`D. `29% Mg^(+), 71% Mg^(2+)` |
| Answer» Correct Answer - A | |
| 765. |
Which family of elements has solid, liquid and gaseous members at `25^(@)C` and 1 atm pressure?A. Alkali metals `(Li-Cs)`B. Phinctogens `(N-Bi)`C. Chalcogens `(O-Te)`D. Halogens `(F-I)` |
| Answer» Correct Answer - D | |
| 766. |
Which of the following does not represents the correct order of the property indicated ?A. `Sc^(3+) gt Cr^(3+) gt Fe^(3+) gt Mn^(3+)` ionic radiiB. `Sc lt Ti lt Cr lt Mn`densityC. `Mn^(2+) gt Ni^(2+) lt CO^(2+) lt Fe^(2+)` ionic radiiD. `FeO lt CaO gt MnO gt CuO` basic nature |
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Answer» Correct Answer - A |
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| 767. |
Which of the following properties are the properties of metal?A. They are sonorousB. They are in general poor conductor of heat and electricityC. They are malleable and ductileD. They are hard |
| Answer» Correct Answer - A::C::D | |
| 768. |
Consider the following ionization energies for a metal M `M_((g)) rarr M_((g))^(+) + e^(-) , " " DeltaH = + 580` kJ / mole `M_((g))^(+) rarr M_((g))^(+2) + e^(-) , " " DeltaH = + 1815` kJ / mole `M_((g))^(+2) rarr M_((g))^(+3) + e^(-) , " " DeltaH = + 2740` kJ / mole `M_((g))^(+3) rarr M_((g))^(+4) + e^(-) , " " DeltaH = + 11600` kJ / mole Select correct orderA. `M_((g))^(+2) lt M_((g))^(+4)` (size )B. `M_((g))^(+4) lt M_((g))^(+3)` (ionization energy )C. `M_((g))^(+3) lt M_((g))^(+4)` (electron affinity)D. All given orders are correct |
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Answer» Correct Answer - C |
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| 769. |
Which atom has the highest electronegativity?A. `Na`B. `P`C. `CI`D. `Br` |
| Answer» Correct Answer - C | |
| 770. |
Which of the following represents the correct order of the properties indicated ?A. `{:(F gt O gt N gt C, ("Electronegativity")):}`B. `{:(Sc^(3+) gt Ti^(4+) gt K^(+),("Size")):}`C. `{:(Ni^(2+) lt Co^(2+) lt Fe^(2+) lt Mn^(2+),("Unpaired electron")):}`D. `{:(HNO_(3) gt HNO_(2),("Acidic strength order")):}` |
| Answer» Correct Answer - A::C::D | |
| 771. |
`M_((g)) rarr M_((g))^(+) +e^(-), DeltaH = 100eV` `M_((g)) rarr M_((g))^(2+) +2e^(-), DeltaH = 250 eV` which is incorrect statement?A. `I_(1)` of `M_((g))` is `100eV`B. `I_(1)` of `M_((g))^(+)` is `150eV`C. `I_(2)` of `M_((g))` is `250eV`D. `I_(2)` of `M_((g))` is `150eV` |
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Answer» Correct Answer - C |
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| 772. |
Which of the following does not represent the correct order of the properties indicated?A. `F gt CI gt Br gt I (EN)`B. `Sc^(3+) gt Ti^(2+) gt Cr^(1+) gt Mn` (size)C. `O lt S gt Se gt Te (EA)`D. `Fe^(2+) gt Co^(2+) gt Ni^(2+) gt Cu^(2+)` (unpaired electron) |
| Answer» Correct Answer - B | |
| 773. |
the correct order of electron gain enthalpy with negative sign of `F,Cl,Br and I` , having atomic number `9,17,35 and 53` respectively isA. `I gt Br gt Cl gt F`B. `F gt Cl gt Br gt I`C. `Cl gt F gt Br gt I`D. `Br gt Cl gt I gt F` |
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Answer» Correct Answer - C |
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| 774. |
The correct relation given by Pauling to calculate electronegativity of an element X is (with respect to hydrogen). Given `EN` of `X gt EN` of HA. `EN(X) -EN(H) = 0.208 sqrt(BE_(H-X) -sqrt(BE_(X_X)xx BE_(H-H)))`B. `EN(X)-EN(H) = 0.102 sqrt(BE_(H-X)-sqrt(BE_(X-X)xx BE_(H-H)))`C. `EN(X) - EN(H) = 0.102 sqrt(BE_(H-X)-sqrt(BE_(X-X)xx BE_(H-H)))` where bond energies (BE) are in kJ/mole.D. Both (a) and (c) are correct |
| Answer» Correct Answer - C | |
| 775. |
Consider the following ionization steps : `M(g) rarr M^(+)(g) +e^(-), DeltaH=100eV` `M(g) rarr M^(2+)(g)+2e^(-),DeltaH=250eV` Select correct statement(s)a)`I.E._(1) " of "M(g) ` is 100eVb)`M^(+)(g) rarr M^(2+)(g)+e^(-),DeltaH=150eV`c)`I.E._(2)` of `M(g)` is 250eVd)`I.E._(2)` of M(g) is 14=150eVA. `IE_(1) of Mg is 100 eV`B. `IE_(1) of M^(+) (g) is 150 eV`.C. `IE_(2) of M(g) is 250 eV`D. `IE_(2) of M(g) is 150 eV` |
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Answer» `M(g) rarr M^(+)(g) +e^(-) IE_(1) of M` `{:(M^(+) rarr M^(2+)+e^(-1),,IE_(2) of M but IE_(1) of M^(+)),(M rarrM^(2+) -: 2e^(-) ,,(IE_(1)+IE_(2))):} (A,B,D)` |
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| 776. |
First, second & third ionization energies are 737, 1045 & 7733 `KJ//mol` respectively. The element can be `:`A. `Na`B. BC. AlD. Mg |
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Answer» Correct Answer - 4 Mg has two electrons in tis `s-` subshell after removing these electrons it will obtain inert gas configuration . So a big jump in `I.E.` will be there. |
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| 777. |
A large difference between the third and fourth ionization energies indicates the presence of:A. 4 valence electrons in an atomB. 5 valence electrons in an atomC. 3 valence electrons in an atomD. 2 valence electrons in an atom |
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Answer» Correct Answer - C For possible `n^(2)np^(1)` configuration, the removal of fourth electron will be possibly from an inert gas electron configuration. So there will be high jump in the fourth ionisation enthalpy than the third ionisation enthalpy which will take place from `ns^(1)` electron configuration. |
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| 778. |
The first four successive ionization energies for an element are 6 , 113 , 11.871, 50.908,67.01 (in eV) respectively . The number of velence shell electrons is ____ . |
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Answer» Correct Answer - 3 |
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| 779. |
The first four successive ionization energies for an element are 6 , 11.3 , 11.871, 50.908,67.01 (in eV) respectively . The number of velence shell electrons is ____ . |
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Answer» Correct Answer - 2 |
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| 780. |
The transition elements (d-blocks elements) show variable oxidation states becauseA. Of the presence of ns ,np and nd electronsB. The energy difference between (n-1)d and ns electrons is very less , thus (n-1)d electrons also behave like valence electronsC. Of the presence of ns and nd orbitalsD. Of the presence of electrons in np and nd orbitals |
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Answer» Correct Answer - B |
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| 781. |
Elements with atomic numbers 9, 17, 35, 53 are collectively known asA. chalcogensB. halogensC. lanthanidesD. rare gases |
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Answer» Correct Answer - B |
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| 782. |
Element with lowest electronegativity isA. NitrogenB. ChlorineC. FluorineD. Hydrogen |
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Answer» Correct Answer - D |
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| 783. |
Following graph shows variation of ionization energies with atomis number in second period `(Li -Ne)`. Value of ionization energies of `Na(11)` will be- A. above `Ne`B. below `Ne` but above `O`C. below `Li`D. between `N` and `O`. |
| Answer» `Na` is `3rd` period element and is bigger than `Li`. The distance between the nucleus and outer most electron is more as compared to `Li`. Thus the outer most electron is loosely bound with nucleus and removal of electron is easier. So option `(C )` is correct. | |
| 784. |
Which element exhibits the successive ionization energies given in the table? `{:("Ionization Energy" kJxx mol^(-)),(1st" "738),(2nd" "1451),(3rd " "7733),(4th " "10540),(5th " "13628):}`A. `Na`B. `Mg`C. `AI`D. `Si` |
| Answer» Correct Answer - B | |
| 785. |
When the elements carbon, nitrogen and oxygen are arranged in order of increasing ionization energies, what is the correct order?A. `C,N,O`B. `O,N,C`C. `N,C,O`D. `C,O,N` |
| Answer» Correct Answer - D | |
| 786. |
How does th reducing ability of the elements vary across the period from N to At? It:A. decreases steadilyB. increases steadilyC. decreases then increasesD. increases then decreases |
| Answer» Correct Answer - A | |
| 787. |
The period that includes all blocks of elements isA. 1B. 2C. 6D. 7 |
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Answer» Correct Answer - C |
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| 788. |
The correct order of the non`-` metallic character is `:`A. `B gt C gt N gt F`B. `C gt B gt N gt F`C. `F gt N gt C gt B`D. `F gt N gt B gt C` |
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Answer» Correct Answer - 3 The non`-` metallic character of the elements is highest at the extremely right( high ionisation energies and high negative values of electron gain enthalpies ) and then decreases from right to left across the period ( ionisation energies decreases and also negative values of electron gain enthalpies decrease from right to left ). |
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| 789. |
The correct of the metallic character is `:`A. `Na gt Mg gt Al gt Si`B. `Mg gt Na gt Al gt Si`C. `Al gt Mg gt Na gt Si`D. `Si gt Al gt Na gt Mg` |
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Answer» Correct Answer - 1 The metallic character of the elements is highest at the extremely left ( low ionisation energies ) and then decreases across the period from left to right (ionisation energies across the period). |
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| 790. |
The lowest electronegativity of the element from the following atomic number isA. 37B. 55C. 9D. 35 |
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Answer» Correct Answer - B [Electronegativity `prop (1)/("atomic size")]` |
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| 791. |
The correct order regarding the electronegativity of hybrid orbitals of carbon is ?A. `sp lt sp^(2) lt sp^(3)`B. `sp gt sp^(2) lt sp^(3)`C. `sp gt sp^(2) gt sp^(3)`D. `sp lt sp^(2) gt sp^(3)` |
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Answer» Correct Answer - C [Electronegativity `uarr` Atomic size `darr %s` character `uarr` order of `%s` character `= C_(sp) gt C_(sp^(2)) gt C_(sp^(3))`] |
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| 792. |
Ionization energies vary from left to right across the periodic table. Factors that contribute to this variation include which of the following? (P) Changes in the nuclear charge (Q) Differences in shielding by valence electrons (R) Differences in shielding by core electronsA. P onlyB. R onlyC. P and Q onlyD. P,Q and R |
| Answer» Correct Answer - C | |
| 793. |
Process `Na_((g))^(2+) overset(I)rarr Na_((g))^(+) overset(II)rarr Na_((g))`A. In (I) energy is released, (II) energy is absorbedB. In both (I) and (II) energy is absorbedC. In both (I) and (II) energy is releasedD. In (I) energy is absorbed, (II) energy is released |
| Answer» Correct Answer - C | |
| 794. |
Which list includes elements in order of increasing metallic character?A. `Si,P,S`B. `As,P,N`C. `AI,Ge,Sb`D. `Br,Se,As` |
| Answer» Correct Answer - D | |
| 795. |
In the periodic table, with the increase in atomic number the metallic nature of elementsA. Decreases in a period and increase in groupB. Increases in a period and decreases in groupC. Increases both in a period and the groupD. Decreases both in a period and the group |
| Answer» Correct Answer - A | |
| 796. |
Which group best illustrates the transition from non-metallic to metallic behavior with increasing atomic numbers?A. `Be,Mg,Ca,Sr`B. `N,P,As,Sb`C. `F,CI,Br,I`D. `Fe,Ru,Os,Hs` |
| Answer» Correct Answer - B | |
| 797. |
The atomic numbers of the metallic and non-metallic elements which are liquid at room temperature respectively are:A. 55,87B. 33,87C. 35,80D. 80,35 |
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Answer» Correct Answer - D `Hg,Br` |
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| 798. |
Which of the following is the correct order of increasing radius of species (atom/ion) ?A. `Mg lt Na^(+) lt F^(-) lt Al`B. `Na^(+) lt Al lt Mg lt F^(-)`C. `Na^(+) lt F^(-) lt Al lt Mg`D. `Na^(+) lt F^(-) lt Mg lt Al` |
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Answer» Correct Answer - B |
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| 799. |
The order of magnitude of ionic radii of ions `Na^(+),Mh^(2+),Al^(3+)` and `Si^(4+)` isA. `Na^(+) lt Mg^(2+) lt Ai^(3+) lt Si^(4+)`B. `Mg^(2+) gt Na^(+) gt AI^(3+) gt Si^(4+)`C. `Ai^(3+) gt Na^(+) gt Si^(4+) gt Mg^(2+)`D. `Na^(+) gt Mg^(2+) gt AI^(3+) gt Si^(4+)` |
| Answer» Correct Answer - D | |
| 800. |
Most of the ratio active elements are inA. LanthanidesB. ActinidesC. Representative elementsD. Second transitional series |
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Answer» Correct Answer - B |
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