InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3051. |
Artificial satellite needs a specific velocity for revolving around earth. Why ? |
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Answer» Solution :1.All artificial SATELLITES do not revolve in similar orbits around the earth. 2.When satellite is launched in its orbit by launcher then satellite is given a SPECIFIC velocity in a tangential direction to the orbit so it can START REVOLVING around the earth. 3.Each satellite NEEDS a different velocity as per its orbit. |
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| 3053. |
Give the SI unit of radioactivity . |
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Answer» roentgen |
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| 3054. |
One half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens?Draw a ray diagram to justify your answer. A 4 can tall objectis placed perpendicular to the perpendicular to the principal axis of a convex lens of focal length 20 cm. The distince of the object from the less is 15 cm. Find nature, position and size of the image. |
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Answer» Solution :(i) Yes . If a convex lens of focal length 10 cm is convered one half with a BLACK paper , it can produce an image of the complete object between `F_(2) and 2 F_(2)`. The rays of light coming from the object get refrected by the upper half of the lens. The image formed will be real, inverted and diminished . ![]() (ii) Object height,` h_(1) = 4 cm `Focal length, f + 20 cmObject DISTANCE, u = - 15 Imagedistance, V = ? Image height , `h_(2) = ?` By lens formula, `(1)/(f) = (1)/(v) - (1)/(u)rArr(1)/(v) = (1)/(f) + (1)/(u) = (1)/(+20) + (1)/(-15)= (1)/(20) - (1)/(15) rArr(1)/(v) = (3-4)/(60) = (-1)/(60)` Positive sing of `h_(2)` SHOWS that the image is erect. Therefore, a virtual, erect, magnified (16 cm) image will be formed at a distance of 60 cm on the same side as of the object by the convex lens. |
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| 3055. |
What is transpiration pull ? |
| Answer» Solution :In plants, as water is LOST from the LEAVES, pressure is created at the top to more water from XYLEM to the MESOPHYLL CELLS, this process is called transpiration. | |
| 3056. |
Suppose the orbit of a satellite is exactly 35780 km above the earth's surface. Determine the tangential velocity of the satellite. |
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Answer» Solution :GIVEN : `G=6.67xx10^(-11) Nm^2//kg^2, M=6xx10^24` kg (for earth) R=6400 KM (for earth) = `6.4xx10^6` m, h=height of the SATELLITE above the earth's surface 35780 km. To find: TANGENTIAL velocity (v) Solution: R+h =6400 + 35780 = 42180x `10^3` m `v=SQRT((G4M)/(R+h))` `=sqrt(((6.67xx10^(-11))xx(4xx6xx10^24))/(42180xx10^3 m))` `=sqrt((40.02xx10^13)/(42e180xx10^3 m))=sqrt((40.02xx10^10)/(42180))` `=sqrt(0.0009487909xx10^10)=sqrt(9487909)` =3080.245 m/s = 3.08 km/s The tangential velocity of the satellite is 3.08 km/s. |
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| 3057. |
Explain the three R's to serve the enviroment. What do they refer to ? |
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Answer» Solution :The three R.s to save the environment : Reduce, Recycle and Reuse. Reduce. This means that use LESS. Save electricity by switching off unnecessary lights and fans. Save water by repairing LEAKY taps. Do not watste food. Recycle. This means that collection of plastic, paper, glass and metal ITEMS and recycle this material to MAKE required things instead of synthesising or EXTRACTING fresh plastic, paper, glass or metal. In order of recycle , first need to segregate waste so that the material than can be recycled is not dumped along with other waste. Reuse. This is actually even better than recycling becuase the process of recycling uses some energy. In the .reuse. strategy, simply use things again and again. Instead of throwoing away used envelopes, you can reverse it and use it again. The plastic bottles in which you buy varous food-items like jam or picklecan be used for storing things in the kitchen. |
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| 3058. |
For students performed experiments on series and parallel combination of two given resistors R_(1)and R_(2) which obey Ohm's law and plotted the following V-I graphs : Which of the graphs is correctly labelled in terms of 'series' and 'parallel' ? |
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Answer» GRAPH A |
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| 3059. |
AB and CD two spherical mirrors, forms parts of a hollow sherical ball with its centre at O as shown in the diagram. If arc AB=1/2 arc CD, what is the ratio of their focal lengths? State which of the two mirrors will always from virtual image of an object placed in front of it and why? |
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Answer» Solution :Focal length of both the mirrors will be the same 1:1. Mirror AB will always FORM virtual IMAGE as it is a DIVERGING /convex mirror. |
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| 3060. |
(a) State the reasons which lead to hypermetropia. With the help of suitable diagram explain this defect of vision and its correction. (b) Draw diagram of an experimental arrangement for observing scattering of light in colloidal solution. Name the two chemicals used in this activity. |
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Answer» SOLUTION :(a) This defect arises either because : (i) the focal length of the eye lens is too long, or (ii) the EYEBALL has become too small. Such a person has to keep a reading MATERIAL much beyond 25 cm from the eye for comfortable reading. This is because the light rays from a nearby object are focused at a point behind the retina. Correction of Hypermetropia : (i) This defect can be corrected by using a convex lens of appropriate power. (ii) Eye-glasses with converging lenses PROVIDE the additional focusing power required for forming the image on the retina.
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| 3061. |
Suppose you have three concave mirrors A, B, C of focal lengths 10 cm, 15 cm and 20 cm. For each of these concave mirrors, you perform the experiment of image formation for three values of object distance of 10 cm, 20 cm and 30 cm. Answer the following reasons. (a) Identify the mirror/mirrors with linear magnification - 1.(b) Out of the three mirrors, identify the mirror which would be preferred to be used for shaving purposes/makeup.(c ) For the mirror B, draw ray diagram for image formation for object distance 10 cm and 20 cm. |
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Answer» Solution :(a) `{:("Concave MIRROR","f cm","u cm","u cm","u cm","2f cm"),("A",10,10,20,30,20),("B",15,10,20,30,30),("C",20,10,20,30,40):}` • Magnification |m| = 1 means IMAGE size is equal to object size •For a concave mirror, image size is equal to object size when the object is at C, the centre of curvature. [r = 2f] • Concave mirror A FORMS image which has the same size as the object when u = 20 cm [ie u = 2f] • Concave mirror B forms image which has the same size as the object when u = 30 cm •Concave mirrors A [at u = 20 cm] and B [at u = 15 cm] has linear magnification - 1. (b) For a concave mirror to be used as a make up mirror or shaving mirror, the object should be within the pole and the PRINCIPAL focus. Concave mirror B [u = 10 cm and u = 20 cm] Concave mirror C [u = 10 cm, u = 20 cm, u = 30 cm] (c ) Ray diagram for concave mirror B for object positions u = 10 cm and u = 20 cm ![]() When u = 10 cm, Object is between P and F ![]() When u = 20 cm, object is between F and C
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| 3062. |
State at least three points of differencebetween the followingterms/ quantities : Permanent magnet and Electromagnet. |
Answer» SOLUTION :
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| 3063. |
The phenomenon of electromagnetic induction is |
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Answer» The processof inducingcharges in a body |
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| 3064. |
In the circuit diagram given in figure suppose the resistors R_1, R_2 and R_3have the values 5Omega, 10 Omega, 30 Omega respectively, which have been connected to a battery of 12V. Calculate (a) the current through each resistor, (b) the total current in the circuit, and (c) the total circuit resistance. |
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Answer» Solution :( a )`R_1 = 5Omega, R_2 = 10 Omega and R_3 = 30 Omega`. Potential defferenceacross the bettery, V = 12 V. This is also the potential difference across each of the individual resistor, therefore, to calculate the CURRENT in the RESISTORS, we use Ohm.s law. The current `I_1`, through `R_1 = V/R_1` `I_1=(12 V)/(5 Omega) =2.4 A` The current `I_2` , through `R_2 = V/R_2` `I_2 = (12V)/(30Omega) = 0.4 A` ( b )The TOTAL current in the circuit, `I = I_1 + I_2 +I_3` = (2.4 + 1.2 + 0.4) A =4 A ( c ) The total resistance `R_p`,is given by `1/R_p = 1/5 + 1/10 + 1/30 = 1/3` Thus, `R_P = 3 Omega` |
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| 3065. |
What is electromagnetic induction? |
| Answer» Solution :Whenever the magnetic FLUX linked with a circuit CHANGES, an induced e.m.f. (ELECTROMOTIVE force) and hence induced current is PRODUCED in the circuit. This phenomenon is known as electromagnetic INDUCTION and is used to generate electric current in a generator or a dynamo. | |
| 3066. |
Explain the series combination of resistors and derive the formula of equivalent resistance. |
Answer» Solution :Two or more than two resistors are said to be connected in SERIES, if they are joined end to end and the same (i.e., total) current flows through each one of them when a potential difference is APPLIED across the combination. In figure (a), three resistors with resistance `R_1, R_2 and R_3`are connected in series across the points A and B. Here, current (1) flowing through each of the resistors `R_1 R_2 and R_3` is the same, but the total potential difference (p.d.) of the battery V is divided according to the resistances between the two ends of the respective resistors. If the potential difference (p.d.) across `R_1, R_2 and R_3" are " V_1, V_2 and V_3` respectively, then `V = V_1 + V_2 + V_3` Now, if one resistor with resistance `R_s`, INSTEAD of these three resistors with resistances `R_1, R_2 and R_3`is connected in the CIRCUIT in such a way that the current flowing through the circuit remains the same as I, then `R_s` is the resistance of the series combination. It is also called equivalent resistance of the combination (figure (b)). Now, applying Ohm.s law, `V = IR_s ... ...(12.9)` From equation (12.8) and (12.9). `IR_S =V_1 + V_2 + V_3 ... ...(12.10)` On applying Ohm.s law to the three resistors separately, we have `V_1 = IR_1` `V_2= IR_2` `V_3 = IR_3` `:. IR_s = IR_1 + IR_2 + IR_3` `:. R_s = R_1 + R_2+ R_3` ... ...(12.11) Thus, the equivalent resistance `R_s` of the series combination is EQUAL to the sum of the individual resistances and is thus greater than any of the individual resistances. [Note: If n resistors with resistances `R_1, R_2 ...R_n` are connected in series, `R_s = R_1+ R_2 +...+ R_n]` |
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| 3067. |
The voltage-current (V-I) graph of a metallic conductor at two different temperatures T_(1) and T_(2) is shown below. At which temperature is the resistance higher ? |
| Answer» SOLUTION :At TEMPERATURE `T_(1)` because its SLOPEIS GREATER . | |
| 3068. |
What do you mean by central dogma? |
| Answer» SOLUTION : INFORMATION about protein synthesis is present in DNA. As PER th is information, proteins are produced by DNA through RNA molecules. This is called central DOGMA. | |
| 3069. |
When does a rigid body said to be in equilibrium ? State the necessary condition for a body to be in equilibrium |
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Answer» Solution :For translation equilibrium `sum vecF_(ext)=0` `ALPHA` in CYLINDER `alpha_(C) = TAU/(I)` `alpha` in sphere `alpha_(S) = tau/I` `alpha_(C)/alpha_(S) =I_(S)/I_(C) = (2/5 MR^(2))/(MR^(2)) -2/5` |
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| 3070. |
Gear box bearing gas turbine blades |
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Answer» GEAR box BEARING and blades are parts of a wind mill while gas turbine is part of power PLANT based on natural gas. |
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| 3071. |
During a short circuit, small amount of current flows through it. |
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Answer» SOLUTION :FALSE. During a short circuit, huge AMOUNT of current FLOWS through it. |
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| 3072. |
Whenthe north poles of two different magnets are placednear each other , then the force and when the north poleand the south pole are placed near each otherthe force of …….results. |
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Answer» ATTRACTION ANDATTRACTION |
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| 3073. |
Four students recorded the readings of the potential differece by observing the position of the pointer of an ideal voltmeter as shown below : The correct reading is : |
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Answer» 2.5 V |
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| 3074. |
Which of the following is not an example of a bio - mass energy source ? |
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Answer» Wood |
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| 3075. |
A student performs an experiment to study the magnetic effect of current around a current carrying straight conductor with the help of a magnetic compass. He reports that (i) the degree of deflection of the magneticcompass increases when the compass is moved away from the conductor. (ii) the degree of deflection of the magnetic compass increases when the current through the conductor is increased. Which of the above observations of the student appears to be wrong and why? |
| Answer» Solution :The first observationis WRONG. Because as the DISTANCE from the conductor increases, the STRENGTH of the magnetic FIELD will decrease. So the degree of deflection of the compass should decrease instead of INCREASING. | |
| 3076. |
(a) What causes the existence of very large number of carbon compounds ?(b) Draw structuralformulae of compounds from their molecular formula given below : (1) C_(3)H_(8) (2) C_(3) H_(4) |
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Answer» Solution :(a) (1) Carbon has a unique ability to FORM strong covalent bonds with other carbon atoms , this results in formation of big molecules . This property of carbon is called catenation power . The carbon COMPOUNDS contain open chains or closed chains of carbon atoms . An open chain can be straight chain or a branched chain . A closed chain is a ring structure . The covalent bond between two carbon atoms is strong and therefore stable . Carbon is bestowed with catenation power due to the strong and stable covalent bonds. (2) One , two or three covalent bonds can bond together two carbon atoms . These bonds are called single covalent bond , double covalent bond and triple covalent bond respectively . Due to ability of carbon atoms to form multiple bonds as WELL as single bonds, the number of carbon compounds increases . For example , there are three compounds , namely , ethane `(CH_(3) - CH_(3))` , ethene `(CH_(2) = CH_(2))` and ethyne `(CH-=CH)` which contain tow carbon atoms . (3) Carbon being tetravalent , one carbon atom can form bonds with four other atoms (carbon or any other ) . This results in formation of many compounds . These compounds POSSESSES different properties as per the atoms to which carbon is bonded . For example , five different compounds are formed using one carbon atom and two MONOVALENT elements hydrogen and chlorine : `CH_(4) , CH_(3)Cl , CH_(2) Cl_(2) , CHCl_(3) , C Cl_(4)` . Similarly carbon atoms form covalent bonds with atoms of elements like O , N, S , halogen and P to form different types of carbon compounds in large number . (4) Isomerism is one more characteristic of carbon compound which is responsible for large number of carbon compounds . (b) Structural formulae : (1) `C_(3) H_(8)` Propane : `H- underset(H)underset(|)overset(H)overset(|)(C)-overset(H)overset(|)underset(H)underset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H` (2) `C_(3) H_(4)` Propyne : `H - C-= C - overset(H)overset(|)underset(H)underset(|)(C)-H` |
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| 3077. |
Establish a relationship to determine the equivalent resistance R of a combination of three resistors having resistances R_1, R_2 and R_3 connected in series. (b) Calculate the equivalent resistance R of a combination of three resistors of 2 Omega, 3 Omega and 6 Omega joined in parallel. |
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Answer» Solution :(B) Here `R_1=2 OMEGA, R_2=3 Omega and R_3=6 Omega` The equivalent RESISTANCE R for parallel COMBINATION of RESISTORS will be `1/R=1/R_1+1/R_2=1/2+1/3+1/6=1/1 implies R=1 Omega` |
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| 3078. |
Anemophilousflowershave _____. |
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Answer» SESSILE STIGMA |
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| 3079. |
How can we find the maximum and minimum focal lengths of the eye lens ? |
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Answer» Solution :a) When the OBJECT is at infinity. `u=- oo, v=2.5` cm (image DISTANCE which is equal to distance between eye lens and retina ) ltbRgtUsing the formula `1/f =1/v -1/u =1/(f_("MAX")) =1/(2.5)-1/oo implies1/(f_("max")) =1/(2.5)+0` `therefore f_("max")=2.5 cm` b) Ojbect at a distance of 25 cm from eye. In this case eye has minimum focal LENGTH. Here u=-25 cm, v=2.5 cm Using the formula `1/f =1/v -1/u` `implies f_("max")=1/(2.5) +1/(25) implies1/(f_("max")) =(10)/(25) +(1)/(25) implies1/(f_("min")) =(10+1)/(25)implies 1/(f_("min"))=(11)/(25)` `therefore f_("min")=(25)/(11)=2.27` cm |
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| 3080. |
Give reasons for using lead in making fuses. |
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Answer» Solution :1. LEAD is used in making fuses because it has low melting point. 2. If the current in the lead wire exceeds certain value the wire will HEAT up and melt, so the circuit in the HOUSEHOLDS. Opened and all the electric devices are SAVED. |
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| 3082. |
Ideal Gas laws state the relationship between . .......... properties of gas. |
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Answer» pressure |
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| 3083. |
State Newton's II law of motion. |
| Answer» Solution :Every body CONTINUES to be in its state of rest or the state of uniform motion ALONG a straight line UNLESS it is acted upon by some external force. | |
| 3084. |
Particles generated due to incomplete burning of fossil fuels which cause air pollution |
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Answer» |
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| 3085. |
A concave mirror gives a virtual, erect and magnified image of an object if the object is placed : |
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Answer» <P>at infinity |
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| 3086. |
What precautions must you take while going to school or in public places? |
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Answer» Solution :Some precautions to be taken while going to school ro in public PLACES are as follows: i. Look on both the sides of the road whilecrosing Make sure that no vehicle is passing by. ii. Do not touch any UNCLAIMED OBJECT. iii. Do not spread rumours. iv. Do not create chaos or push others at crowded public places or while using staircases in the school. v. REMEMBER important help lines and use them when in trouble. some important help line numbers are as follows: Police -100 Fire fighting force-101 Disaster control unit -108 Ambulance -102 |
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| 3088. |
Methods of preventing corrosion |
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Answer» SOLUTION :Alloying: The metals can be alloyed to prevent the process of corrosion. E.g: Stainless Steel. (in) Surface Coating: It involves application of a protective coating over the METAL. It is the following types: (a) Galvanization: It is the process of coating ZINC on iron sheets by using electric current () Electroplating: It is the method of coating one metal over another metal by passing electric current. (c) ANODIZING: It is an electrochemical process that converts the metal surface into an decorative, durable and corrosion resistant. ALUMINIUM is widely used for anodizin process. (d) Cathodic Protection: It is the method of controlling corrosion of a metal surfac protected is coated with the metal which is easily corrodible. The easily corrodible metal is called Sacrificial metal to act as anode ensuring cathodic protection. |
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| 3089. |
A balloon partialy filled with the gas volume 30m at on surface of earth where pressure is 76 cm of Hg and temperature is 27°C. What will be the increase in volume of gas balloon when it rises to a height where temperature become (-54^(@)C) and pressure become 7.6 cm of Hg. |
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Answer» SOLUTION :Given `P_(1)=36 cm Hg` `V_(1)=30 m^(3)` `T_(1)=27+273=300 K` `P_(2)=7.6 cm of Hg` `V_(2)= ?` `T_(2)=-54+273=219 K` By gas equation `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=(76xx30xx219)/(300xx7.6)` `=219 m^(3)` So INCREASE in volume of gas `=219-30 m^(3)` `=189m^(3)` |
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| 3090. |
When a student added zinc granules to dilute HCI, a colourless and odourless gas was evolved, which was then tested with a burning match stick, what would be observed? |
| Answer» SOLUTION : When the colourless gas was TESTED with a burning matchstick, the matchstick extinguished and the gas burnt with a POP sound. This is because when zinc granules are added to silute HCI, HYDROGEN gas is EVOLVED. | |
| 3091. |
Tell me who am I ? What is my class/phylum ? My body is covered by tunic . As a larva I swim but as an adult I settle down . |
| Answer» SOLUTION :Doliolum or SALPA , Phylum : CHORDATA subphylum : UROCHORDATA. | |
| 3092. |
A, B in the figure are identical lamps. What changes occur in the brightness of the lamps when its switch S in closed? |
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Answer» BRIGHTNESS of A increases but that of B decreases |
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| 3093. |
Name the process of large energy production in the sun. |
| Answer» SOLUTION :NUCLEAR FUSION REACTION in the interior of the sun. | |
| 3094. |
Electric energy is produced in various ways like hydroelectric, wind power, solar energy, bio-fuel, etc. These energy sources are inexhaustible, sustainable. Bisides, it does not cause any environmental problem. Wheather the fossil fuel is an example of this energy? |
| Answer» SOLUTION :FOSSIL FUEL are not GREEN ENERGY. | |
| 3095. |
Describethe activity to show that a current-carrying conductor experiences a force perpendicularto its lengthin an external magnetic field. |
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Answer» Solution :i] To show that a current-carrying conductorplaced in a magneticfield experiencesa force perpendicular to its length : Figure : Experiment to study force on a current carrying conductorin a magneticfield 1] Takean aluminium rodAB (of length about 5 cm) and SUSPEND it horizontally froma stand using two connecting wires as shown in the figure. 2] Connect the two ends OFTHE wire in serieswith a battery and a plug key. 3] Place a strong horse- shoe magnet in such away that its north pole lies below and SOUTH pole abovethe aluminium rodas shown. Then, the magnetic field will be directed upwards. 4] Insetthe plug key so that currentflows through thealuminium rodfrom A to B. Notice the movementof the rod . 5] Holdthe magnet at differentangles to the rod and observe the change. Inference : When current flows,the aluminium rod gets displaced because of the force acting on it due to magnetic field of the horse shoe magnet. It is observedthat the displacementof the rod is largest or the force onit is maximum when thedirection of current is perpendicular to the direction of the magnetic field . A current-carryingconductorexperiencesa force perpendicular to its length in a external magnetic field . ii] Fleming.s left-hand rule: Fleming.s left hand rule gives the direction of the force experienced by a straight currentcarrying conductorplaced in a magnetic field . According to this rule, if the thumb,fore-finger and middle finger of the left hand are stretched TOBE perpendicular to each other asshownin the figure , ANDIF theforce fingerrepresents thedirection of magnetic field , the middle finger represents thedirection of current, thenthe thumb represents the direction of force.
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| 3096. |
Cryolite (Na_(3)AlF_(6)) and fluorspar (CaF_(2)) are added to the electrolytic mixture containing pure alumina. |
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Answer» Solution :(1) Alumina has very high melting point `(lt 2000^(@)C)`. Cryolite `(Na_(3)AIF_(6))` and fluorspar `(CaF_(2))` LOWER the FUSION temperature of the mixture containing alumina from `2000^(@)C" to "1000^(@)C`, thereby saving electrical energy. (2) They increase the conductivity and the mobility of the fused mixture. Hence, cryolite and fluorspar are added to the electrolytic mixture containing PURE alumina. |
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| 3097. |
Fill the blanks to complete the following sentence: Q: When light travels from a denser to a rarer medium, its speed ______ |
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Answer» |
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| 3098. |
Environment includes biotic, abiotic and natural factors only. |
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Answer» Solution :FALSE. Environment includes BIOTIC, abiotic and NATURAL FACTORS as WELL as arificial factors. |
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| 3099. |
The apaarent frequency in Doppler's effect does not depend upon : |
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Answer» SPEED of the LISTENER. |
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| 3100. |
Depending on which factor, wind turbines are installed? |
| Answer» SOLUTION :Wind turbines are INSTALLED based on the wind velocity availabe at the site of INSTALLATION. | |