In the circuit diagram given in figure suppose the resistors R_1, R_2 and R_3have the values 5Omega, 10 Omega, 30 Omega respectively, which have been connected to a battery of 12V. Calculate (a) the current through each resistor, (b) the total current in the circuit, and (c) the total circuit resistance.

In the circuit diagram given in figure suppose the resistors R_1, R_2

1.	In the circuit diagram given in figure suppose the resistors R_1, R_2 and R_3have the values 5Omega, 10 Omega, 30 Omega respectively, which have been connected to a battery of 12V. Calculate (a) the current through each resistor, (b) the total current in the circuit, and (c) the total circuit resistance.
Answer» Solution :( a )`R_1 = 5Omega, R_2 = 10 Omega and R_3 = 30 Omega`. Potential defferenceacross the bettery, V = 12 V. This is also the potential difference across each of the individual resistor, therefore, to calculate the CURRENT in the RESISTORS, we use Ohm.s law. The current `I_1`, through `R_1 = V/R_1` `I_1=(12 V)/(5 Omega) =2.4 A` The current `I_2` , through `R_2 = V/R_2` `I_2 = (12V)/(30Omega) = 0.4 A` ( b )The TOTAL current in the circuit, `I = I_1 + I_2 +I_3` = (2.4 + 1.2 + 0.4) A =4 A ( c ) The total resistance `R_p`,is given by `1/R_p = 1/5 + 1/10 + 1/30 = 1/3` Thus, `R_P = 3 Omega`