Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

5051.

resultant of two vector of anunequal magnitude can neverbe zeroexplain with an example

Answer»
5052.

A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled upby a string with an acceleration of 2.2 m/sec?. The tension T, will be12kgT,8kgfa(2) 240 N(3) 220 N(4) 200 N(1) 260 N

Answer»
5053.

Roll -apter 5 Laws Of MotionHow much work is done in taking an object of mass 8 kg to height of 2.5 m?

Answer»

Work done =potential energy=mgh=8*10*2.5=200J

5054.

Two equal forces have the square of their resultant equal to three times their product. Find the angle between them.

Answer»

Given two forcesPandQ, such that |P | =P,| Q | =Q, and P = Q, acting at a point, such that square of magnitude R of resultantRofPandQis 3 P² = 3 Q². We are required to find the angle betweenPandQ.

Let the angle betweenPandQ is ∅.Then by parallelogram law of vectors we have for the resultant,that,

R² = P² + Q² + 2 P Q Cos ∅ = P² + P² + 2 P P Cos ∅= 2 P² + 2 P² Cos ∅. ……..(1)

We are given that R² = 3 P². Substituting for R²in equation 1, we get,

3 P² = 2 P² + 2 P² Cos ∅, or Cos ∅ = ½ or ∅ = 60° .

The angle between the two forces is 60° .

5055.

1. Two equal forces have their resultant equal to either.What is the inclination between them? INCT, 2002]2.

Answer»
5056.

The M.I. of a uniform thin rectangular plate of mass M , length L andbreadth B about an axis passing through its diagonal is given by

Answer»
5057.

14. The length of a rectangular plate is measured bya meter scale and is found to be 10.0 cm. Itswidth is measured by Vernier calipers as1.00 cm. The least count of the meter scale andVernier callipers are 0.1 cm and 0.01 cmrespectively. Maximum permissible error in areameasured is(1) + 0.2 cm2 (2) + 0.1 cm(3) + 0.3 cm(4) Zero

Answer»

B is correct answer of this question

5058.

A block of mass 10 kg is suspended by three strings asshown in the figure. The tension T2 is:60°30°T.2T.T1100(a) 100 N(c) v3 x100 N(d) 50 3 N

Answer»
5059.

(c) 1 Erga)ass ókg is under a force which causes2displacement in it given by S=-metres where t is timeThe work done by the force in 2 seconds is(a) 12J42(b) 9J(d) 3J(c) 6J

Answer»

After 2sS = t^2/4S = 1m

v = dS/dtv = 2t/4v = t/2

a = dv/dta = 1/2 m/s^2

F = maF = 6*1/2F = 3N

W = F * SW = 3 * 1W = 3J

5060.

Did you mean: definition electrical engineerThis law appies to the besicprinciples of the electricgenerator, the electric motorand the transformer,www.youtube.com

Answer»

Electrical engineering is a technical discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism

electrical engineer do? "Electrical engineers design, develop, test and supervise the manufacturing of electrical equipment, such as electric motors, radar and navigation systems, communications systems and power generation equipment, states the U.S. Bureau of Labor Statistics.

Electronic engineering(also calledelectronicsand communicationsengineering) is anelectrical engineeringdiscipline which utilizes nonlinear and activeelectricalcomponents (such as semiconductor devices, especially transistors, diodes and integrated circuits) to designelectroniccircuits, devices, VLSI devices ...

5061.

A triangular block of mass 'M' with angles30°, 60°and 90° rests with its 30° -90° side on ahorizontal table. A cubical block of mass 'm' rests onthe 60°- 30° side. Assuming contact is frictionless,the acceleration of mass 'M' relative to the table tokeep 'm' stationary relative to the triangular block is1. g2. g/v23. g/v34. g/v5

Answer»
5062.

3. A 40 kg slab rests on a frictionless floor. A 10 kgblock rests on top of the slab. The coefficient offriction between the block and the slab is 0.40. The10 kg block is acted upon by a horizontal force of100 N. If g 10 m/s2, the resulting acceleration ofthe slab will be100 N10 kg40 kgTIITTITIITTTTITITIITTITIUT77(1) 1.0 m/s2(3) 1.52 m/s2(2) 1.47 m/s2(4) 6.1 m/s2

Answer»
5063.

OROne half of a cenvex lens of focal length 10 cm is covered with a black paper. Can suproduce an image of a complete object placed at a distance of 30 em from thelens.Dray:

Answer»

1.A convex lens can produce the complete image of the object even though half of the lens is covered .Because light rays coming from the object can be refracted from the other part of the lens.

2.Given:height of object= 4cm=h0focal length=f=20cm.u=-15cm after sign conventions.by lens formula,1/f=1/v-1/u1/v=1/f+1/u=1/20-1/15=3-4/60=-1/60v=-60cmsm=v/um=hi/ho=v/uhi=hoxv/u=4x(-60)/(-15)=8cmhi=8cm∴ Position of image is 60cm in front of lens size of image is 8cmnature of image is virtual and erect.

5064.

c) Convert a SpeeU UUTI8. (a) What is meant by the term 'acceleration'? State the SI unit of acceleration(b) Define the term 'uniform acceleration'. Give one example of a uniformly accelerated aThe distance between Delhi and Agra is 200 km. A train travels the first 100 km at a speed.n70 km/h for the whole journe,

Answer»

rate of change of velocity on every moving body is called acceleration

rate of change of velocity on every moving body is called acceleration

5065.

why light make us able to see

Answer»

The Role ofLightto Sight. The bottom line is: withoutlight, there would be no sight. The visualabilityof humans and other animals is the result of the complex interaction oflight, eyes and brain. We areable to seebecauselightfrom an object can move through space and reach our eyes

5066.

A circular plate of uniform thickness has a diameter of 56 cm. A circular portion of diameter 42cone edge of the plate. Find CM of the remaining portion.(9cm]

Answer»
5067.

1. A circular plate of uniform thickness has a diameter56 cm. A circularportion of diameter 42cm is removed from oneedge as shown in thefigure. The centre of omass of the remainingportion from the centreof plate will be28 cm

Answer»

Thickness of plate = t Totalmass of circularplate = MDensity of plate = M /(πr₁² t) , r₁ = 28 cm r₂= radius of cut out part= 21 cm

Mass of small circular portion cut out = volume* density =πr₂² t *(M/π r₁² t) m₂ = M r₂² / r₁²

Mass of the remaining part = m3 = M - Mr₂² / r₁² = M (r₁² - r₂²) / r₁²

Let the center of mass of remaining portion be at a distance d from the center of original full plate. From symmetry the center of mass of remaining portion lies along the line joining the center of original plate and the center of removed part.

Let Center of mass of total full plate = 0 0 = 1/M ( d * mass of remaining part + C₁C₂ * mass of removed part) 0 = d *M (r₁² - r₂²) / r₁² + 7 * M r₂² / r₁² 0 = d * (r₁² - r₂²) + 7 *r₂² d = - 7 * r₂² / (r₁² - r₂²) = - 7 * 21² / (28² - 21²) = - 7 *21 * 21/ 49*7 = - 9 cm

Center gravity of the remaining portion is 9 cm to the left of the original center of full plate on the line of symmetry. Or, it is 19 cm from the edge of remaining plate along the line of symmetry.

5068.

Fig. 3.25 shows the x-tgraphs of car A and B. Thevelocity of car A with respectto car B will be...x(m) ↑252015T-10(A) +5m s-12.5m s5-(C)-5m s-1t(s+2.5m s-1Figure 3.25

Answer»

From the graph , the velocity of A = 15/(6-0)= 5/2 m/s

and velocity of B = 15/(6-3) = 5m/s

now velocity of A w.r.t B = Va -Vb = 2.5-5 = -2.5m/s

option B.

5069.

as 34. The thickness of a glass plate is measured to be217 mm, 2-17 mm and 218 mm at three differentplaces. Find the average thickness of the plate from thisdata.he

Answer»
5070.

Example 81. A ray of light strikes a glass plate at an angleof60° lf the reflected and refracted rays are perpendicular toeach other, find the refractive index of glass.

Answer»
5071.

2.Cantheradiusofcurvatureofwrist-watchglassmeasuredbyusingaSpherometer?glass plate3 Write the effect of changing the nitch from 1mm to 2mm on accuracy of

Answer»

No, because the wrist-watch glass is small and all the legs of the spherometer cannot rest on it.

5072.

DATEPAGEthen ah

Answer»

As it's a wheatstone bridgeso if R1/R2= R3/R4no current will flow through Galvanometer

5073.

14. A battery of 9 V is connected in series with resistors of 0.2 S2, 0.3 2,0.422, 0.5 22 and 12 92.current would flow through the 122 resistor ?How much

Answer»
5074.

23. in the circuit diagnosen given below five resistances of 100, 400, 300, 30 9 and 60In the circuit diagram given below five resistances of 10 92, 40 92,30shown to a 12 V battery., 20 22 and 60 22 are connected as102302W2002WA402w602WWWHP12VCalculate :(a) total resistance in the circuit.

Answer»
5075.

of ehromosomes in the progeny remains the same as l ut the13. For which position of the object does a convex lens form a virtual and evect inmasgeysthe help of a ray diagram.

Answer»
5076.

0A piece of wood of uniform cross-section and 15 cmheight sinks 10 cm in water and 12 cm in spirit. Find therelative densities of wood and spirit. Ans. 0.67, 0.8

Answer»

thanks bro

5077.

te directions with equal speeds along theWhat is the impulse impated to each8. Two billiard balls cach of mass 0.05 kg, moving in opposisame line of 16 m's collide and rebound with same speed.

Answer»
5078.

4. If resistarices Ltui5. How should the two resistances of 2 ohms each be connencted so as to produce an equivalent resistance ot1 ohm ?re snected turn by turn : (i) in parallel, and (ii) in series. In which case the

Answer»

It should be connected in parallel as Please like the solution 👍 ✔️

5079.

A coin placed on a rotating turn table just slips ifit is placed at a distace of 4 cm from the centre. Ifthe angular velocity of the turn table is doubled, itwill just slip at a distance of-(A) 1 cm(C) 4 cm(B) 2 cm(D) 8 cm

Answer»
5080.

Calculate the combined resistance in each case :5001220

Answer»

Answer of b part is 1 and c part is 5

5081.

\left. \begin{array} { l } { \text { Their combined resistance is: } } \\ { ( a ) 1 \frac { 5 } { 7 } \Omega } & { ( b ) 14 \Omega } & { ( c ) ^ { 6 \frac { 2 } { 3 } } \Omega } & { ( d ) 7 \frac { 1 } { 2 } \Omega } \end{array} \right.

Answer»

we can see that 6 and 2 ohm resistors are in parallel so and another 6 ohm is in series with both of themso Req. =((6×2)/(6+2))+6Req. = (12/8)+6=3/2 +6=1.5+6=7.5=15/2=7 1/2 ohm

d is the right answer

5082.

5.3 TYPES OF DEMAND FORECASTS

Answer»
5083.

highwayngdistance d from the highshown in the figurethe field is half to thatWhat should be the distancethe time taken to reach P is

Answer»
5084.

TheshortesttimeitA particle is executing harmotakes to reach a pointm from its mean position in seconds isng simple hamonic motion with a period of T seconds and amplitude A metre.2(D) T/16(A) T(B) TI4(C) T/8They nass one another

Answer»
5085.

(29A object placed 20cm in front of minoris found to form an mage of 18umin front of it.1 Behind the mirror and what kindof image in each case

Answer»
5086.

6. The image formed by a convex mirror of focal length 20cm is at adistance of 50cm. What is the distance of the object from the13]mirror?

Answer»
5087.

1. A lens has a refractive index 1.5 and itsfocal length is 20 cm while in air. The samelens is put in a liquid having 1.25 refrac-tive index. So find the focal length of thelens while in liquid.

Answer»

20.20 is the correct answer

sorry it is wrong

ok

we can use the lens makers formula to solve this problem. Lens makers formula is

For lens in air

1/20 = (1.5–1)(1/R1–1R2) (1/R1 - 1/R2) = 2/20 = 1/10

When lens immersed in water1/f'= (1.5/1.25 –1)(1/R1–1/R2)

1/f' = (6/5 - 1) * 1/10

1/f' = (1/5) * 1/10

f' = 50 cm

5088.

20cm and -20cm focus length of two lenses forms a equivalent lens what is its power?

Answer»

Two key facts:1.The power of a lens is the reciprocal of the focal length in meters.2. Powers are additive.

The lens with a focal length of +20 cm has a power of 1/0.2 = +5

The lens with a focal length of -20 cm has a power of 1/(-0.2) = - 5

The two lenses together have a power of 5 - 5 = 0

5089.

Equivalent focal length of two lenses in contact having power- 15 D and + 5 D will be-

Answer»

Please hit the like button if this helped you

5090.

two lenses of focal length +10cm and+25 cm are kept in contact . Find the power of the.combination

Answer»

First convert f in metres so lens 1 has f=0.1m and lens2 has f=0.25m.

Power of lens1 = 1/0.1 = 10D

Power of lens2 = 1/0.25 = 4D

Effective power = P1+P2 = 10D + 4D = 14D.

5091.

Two lenses of focal length 20cm and -40cm are co-axillary in contact find power of the combination

Answer»

F1=20F2=-40we know P=P1+P2NOWP1=1/20P2=-1/40P=1/20-1/401/40ANSWER

5092.

Two lenses of focal length 20cm and -40cm are co -axially in contact find power of the combination

Answer»

Power will be P=1/F1+1/f2F1=20/100=0.2mand F2=-40/100=-0.4mhenceP=1/0.2-1/0.4=0.2/0.08=2.5D

5093.

Find equivalent focal length of two convex lenses in contact with each other.

Answer»
5094.

combination!21.Explain the principle and working of a Nuclear reactor with the help of a labelled diagagran

Answer»

The energy source of a nuclear power plant is fission reaction. In fission reaction we start with an unstable atom (uranium-235) which splits apart into two small more stable atoms. When we go from something that is really very unstable (uranium-235) to thing that is more stable (barium and krypton), energy is released.

Now to split the uranium atom we need to aggravate it, what we do is we strike a neutron into this big uranium atom, which converts it into uranium-236 from uranium -235.

Uranium-236 is super unstable atom and splits up into krypton-92 and barium-141, which are way more stable. Other than release of energy, 3 free neutrons are also released in the process.

These neutrons further strikes another 3 uranium atoms and starts up a chain reaction, helping in getting a great amount of thermal energy.

Working

It all starts with a thermal neutron striking the uranium pellet and starting the chain reaction, with release of 3 new high energy neutrons as by-products of this exothermic reaction. These neutrons strike another 3 uranium atoms, and this chain reaction keeps on increasing. Heavy water is feed into the high pressure vessel which absorbs the heat generated by the chain reaction. This water doesn’t really boil as its being heated under high pressure. This is not the ordinary water that is feed into high pressure vessel; it’s 10 times heavier than the ordinary water. The main function of this water is to slow down the high energy neutrons to the level of thermal neutron or to modify the speed of neutron, that’s why it is called moderator. When neutrons travels in heavy water (deuterium oxide) it strikes with each and every molecule of heavy water thus transferring its energy to moderator, and slows down to an optimum speed.

In nuclear power plant, the chain reaction so started is controlled by the controls rods mainly boron or cadmium rods. These rods absorb the extra neutrons thus stopping the chain reaction. Generally these rods are put in and out of pressure vessel every 10 seconds, to control the power output according to the requirement or load at the turbine.

Heated water or moderator in the pressurized vessel is then pumped to the heat exchanger. Keeping in mind moderator cannot leave the circuit as it is radioactive so the water for the heat exchange is pumped from a water source (river) and this water absorbs the heat of moderator and converts into highly pressurized steam.

This pressurized steam is first feed in a high pressure turbine which converts its pressure energy into mechanical energy, but this steam still have enough pressure energy left in it to turn a low pressure turbine, so this combined mechanical energy from both the turbines is used to turn the armature of a generator thus producing electricity.

This electricity is then stepped-up to high voltage by step-up transformer, and transmitted to the nearest power grid through transmission lines.

The steam that leaves the turbines is then condensed in a condenser. The condenser is connected to the cooling tower. The cold water from the cooling tower takes the heat from the condensed water of the condenser. The hot water in cooling tower is sprayed in air thus cooling it down, to be again pumped back to the condenser.

5095.

oceall lWhat is geothermal energy ?

Answer»

thanks bro

best

5096.

What do you understand by term electric energy?

Answer»

Electrical energy is a form of energy resulting from the flow of electric charge. Electrical energy is the most convenient form of energy for most human uses.

5097.

14. Explain the term geothermal energy. How can it be exploitedThough it is economical yet it is notharnessed in most of the countries. Why ?

Answer»

Like my answer if you find it useful!

5098.

Give the location of the centre of mass of a (l) sphere, (u) cylinder, (i) ring, and (iv)cube, each of uniform mass density. Does the centre of mass of a body riecessarilylie inside the body?

Answer»

center is mass of Sphere

(I)Centre of mass of a sphere lies at its geometrical centre.

(ii) Centre of mass of a cylinder lies at its geometrical centre i.e. at the mid-point of its axis of symmetry.

(iii)Centre of mass of a ring lies at its geometrical centre.

(iv)Centre of mass of a cube lies at its geometrical centre i.e. at the point of intersection of its diagonals.

No, it does not necessary that centre of mass of a body lie inside it, because in some cases such as a ring, a hollow cylinder, a hollow sphere and a hollow cube centre of mass lies outside.

5099.

If we started at (5,-2), where would we end up after a displacementof (3, 2)?

Answer»
5100.

Cirucuit diragram for comparison of emf of twoprimary cells using a potentialmeter.ns.

Answer»