1.

\left. \begin{array} { l } { \text { Their combined resistance is: } } \\ { ( a ) 1 \frac { 5 } { 7 } \Omega } & { ( b ) 14 \Omega } & { ( c ) ^ { 6 \frac { 2 } { 3 } } \Omega } & { ( d ) 7 \frac { 1 } { 2 } \Omega } \end{array} \right.

Answer»

we can see that 6 and 2 ohm resistors are in parallel so and another 6 ohm is in series with both of themso Req. =((6×2)/(6+2))+6Req. = (12/8)+6=3/2 +6=1.5+6=7.5=15/2=7 1/2 ohm

d is the right answer



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