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option B is the answer.zero work done by stone.

parabolic path as it will have horizontal velocity when dropped

it will be V2/v1 is the answer to that question

65o so the reflected sound should be clearly listen

Let MN and MP are two plane mirrors be inclined at an∠PMN=θ. A light ray AB parallel to MN is incident on MP and the ray after third reflection on MP at B retraces its path as shown in the diagram. Hence CD is perpendicular to MP.

This means∠BCN=∠DCM=90∘−θ.AB||MNand BC is the intercept.

So∠PBA=corresponding ∠PMN=θ

And∠ABC=180∘−2θ

SinceAB||MNand BC is the intercept ,

then

∠ABC+∠BCN=180∘

⇒180∘−2θ+90∘−θ=180∘

⇒3θ=90∘

⇒θ=90∘3=30∘

Let MN and MP are two plane mirrors be inclined at an∠PMN=θ. A light ray AB parallel to MN is incident on MP and the ray after third reflection on MP at B retraces its path as shown in the diagram. Hence CD is perpendicular to MP.

This means∠BCN=∠DCM=90∘−θ.AB||MNand BC is the intercept.

So∠PBA=corresponding ∠PMN=θ

And∠ABC=180∘−2θ

SinceAB||MNand BC is the intercept ,

then

∠ABC+∠BCN=180∘

⇒180∘−2θ+90∘−θ=180∘

⇒3θ=90∘

⇒θ=90∘3=30∘

he discovered cell is the correct answer of the given question

SolutionsActionshello Krish. Equivalent resistance will be =R1+R2 considering ideal voltmeter thus no current flow into it. The current will be l=V/R

hello Krish.

In the case of a hollow metal sphere (spherical shell), the electric field inside the shell is zero.

This means that the potential inside the shell is constant.

Therefore the potential at the centre of the sphere is the same as that on its surface, i.e. 80 V as no work is done in moving a charge inside the shell.

According to Kepler

4/3 ohm is the correct answer of the given question

Voltage=200 VResistance=50 ohm∴Current=200/50=4 Amp

Option- B

option D - none of this

Mars is the fourth planet from the Sun and the seventh largest. Mars is a terrestrial planet with a thin atmosphere composed primarily of carbon dioxide.The bright rust color Mars is known for is due toiron-rich mineralsin its regolith — the loose dust and rock covering its surface. The soil of Earth is a kind of regolith, albeit one loaded with organic content

40 is answer because it in series contions is there

resistance EA and AF are in series sum of EA and AF = R1 = 10+10 = 20 OHMNow R1 and EF are in parallel. sum of R1 and EF = 1/R2 = 1/20 + 1/10 = 3/20 OHMR2 = 20/3 ohmagain, resistance BE, R2 and FC are in series. sum of resistance BE, R2 and FC = 10 + 20/3 + 10 = 80/3 OHM..

HENCE, equivalent resistance = 80/3 ohm. ANS..

40 is the answer of this particular question

P / Q = R / S' S' = QR / P = 2*3/2 = 3 1/S + 1/r = 1/S' 1/4 + 1/r = 1/3 r = 12 ohms.connect a resistance of 12 ohms, in parallel with the resistance S (4 ohms) to balance the wheat-stone bridge.

option (2) is the right answer?

option (3) is the right answer

option 3. is the correct answer of the given question

3) is the correct answer

Thank you so so much sir....

thanku mam for this question

Heat produced in the circuit is inversely proportional to the resistanceR.

LetRSbe the equivalent resistances of the wires if connected in series andRPbe the equivalent resistances of the wires if connected in parallel

ThenRS=R+R=2RAnd 1/RP= 1/R +1/R

1/RP= 2/R

OrRP=R/2

Now the ratio of heat produced is given by

Hs/Hp=V^2/Rs*t/V^2/Rp*t=1/4

Energy loss by hot water = Energy gain by cold water

Let final temperature of mixture be tThen20x(50-t) = 60x(10+t)1000-20t = 600 + 60t40t = 400t = 10

a ball is released from the top of a tower of height h metre it takes T second. what is the position of the ball above the ground in T/5 second?

specific heat of water is 4.186 J/gCheat of fusion of ice is 334 J/g

To melt 100g of ice takes 334 J/g x 100g = 33400 J

Heat stored in water at 100 is4.186 J/gC x 100g x 100C = 41860 J

so there is more than enough heat to melt all the ice and raise it in temperature. The question is what temperature.

the 33400J lost melting the ice lowered the hot water by:33400J = 4.186 J/gC x 100g x ΔTΔT = 33400 / 418.6 = 80C, so the hot water is at 20 deg.

So we now have 100g of water at 20, and 100g of water at 0 mixed, which gives us 200g of water at 10C

🙂 tnku

hand writing aachi nikal bhai samaj nahi raha jai

option 3 is the answer

It is a device used to accelerate charged particles like protons, deutrons,αα-particles, etc, to very high energies.

PRINCIPLE :A charged particle can be accelerated to very high energies by making it pass through a moderate electric field a number of times. This can be done with the help of aperpendicularmagnetic field which throws the charged particle into a circular motion, the frequency of which does not depend on the speed of the particle and the radius of the circular orbit.

CONSTRUCTION :As shown in figure, a cyclotron consists of the following main parts:

1. It consists of two small, hollow, metallic half-cylindersD1D1andD2D2calleddeesdeesas they are in the shape ofDD.2. They are mounted inside avacuum chamberbetween the poles of a powerful electromagnet.3. The dees are connected to the source of high frequency alternating voltage of few hundred kilovolts.4. The beam of charged particles to be accelerated is injected into the dees near their centre, in a plane perpendicular to the magnetic field.5. The charged particles are pulled out of the dees by a deflecting plate (which is negatively charged) through a windowWW.6. The whole device is in high vacuum (pressure∼10−6∼10−6mm of Hg) so that the air molecules may not collide with the charged particles.

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ions and OH-ions to generate water.

It should hower above a fixed point of earth, thus it should have same period of rotation ~24 hrs to be precise 23hrs and 56min

For it to be practically possible the geostationary satellite must satisfy 3 basic requirenments

it should rotateaboutthe axis of rotation of earth with absolutelyzeroinclinationand in thesamesenceas rotation of earth ( west ot east).

The period of revolution of satellite must be identical with theperiodof rotation of earth about it’s axis (23hrs 56mins).

The satallight must revolve inearth’s equitorial planeabout the axis of rotation of earth the trejectory of satallight must becircular. ( by zero inclination as mentioned above i ment the circle made by satallight must have its central axis exactly along the axis of rotation of earth.).