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651.

Explain the process of conduction of heat throughmetal rod. Why are metals good conductors of heatas well as electricity?

Answer»

The mechanism of heat transfer through the bulk of the ceramic mug is described in a similar manner as it before. The ceramic mug consists of a collection of orderly arranged wigglers. These are particles that wiggle about a fixed position. As the ceramic particles at the boundary between the hot coffee and the mug warm up, they attain a kinetic energy that is much higher than their neighbors. As they wiggle more vigorously, theybang intotheir neighbors and increase their vibrational kinetic energy. These particles in turn begin to wiggle more vigorously and their collisions with their neighbors increase their vibrational kinetic energy. The process of energy transfer by means of the littlebangerscontinues from the particles at the inside of the mug (in contact with the coffee particles) to the outside of the mug (in contact with the surrounding air). Soon the entire coffee mug is warm and your hand feels it.This mechanism of conduction by particle-to-particle interaction is very common in ceramic materials such as a coffee mug. Does it work the same in metal objects? For instance, you likely have noticed the high temperatures attained by the metal handle of a skillet when placed upon a stovetop. The burners on the stove transfer heat to the metal skillet. If the handle of the skillet is metallic, it too attains a high temperature, certainly high enough to cause a bad burn. The transfer of heat from the skillet to the skillet handle occurs by conduction. But in metals, the conduction mechanism is slightly more complicated. In a manner similar to electrical conductivity, thermal conductivity in metals occurs by the movement offree electrons. Outer shell electrons of metal atoms are shared among atoms and are free to move throughout the bulk of the metal. These electrons carry the energy from the skillet to the skillet handle. The details of this mechanism of thermal conduction in metals are considerably more complex than the discussion given here. The main point to grasp is that heat transfer through metals occurs without any movement of atoms from the skillet to the skillet handle. This qualifies the heat transfer as being categorized as thermal conduction.

652.

good conductors of electricity ?(6) Calculate the resistance of a copper wire 1.0 km long and 0.50 mm diameter if the resistivity of copper isire of the same material when connected to1.7 x 10-8 2mQu

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653.

22) Electron is looked upon as a cloud ofnegative charge according to what?

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Wave-mechanics theory explains electron clouds.

654.

7.Two point charges q and 10 q repel each other with a force of 3.6 *10' N when they are 0.02 mapart. Find the magnitude of charges.(4x10 & 0.4x10°C)

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655.

A train of 100 meters is moving at a speed of 60 km/h, in how much time it is 1 km.the long bridge will cross.

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thanx

656.

Section-CExplain the term. a) linear charge density b) surface charge densityc) volume charge density

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657.

Electron attributes negative charge, protons attribute positive charge. An atom has both but why there is no charge ?

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In an atom both electrons and protons are present in equal Magnitude They neutralise each other's charge Therefire atom is neutral

658.

2. A current of 1 A is flowing through a conductor. Howmany electrons pass through any cross-section of theconductor (i) per second, (ii) in 1.6 second?Ans. (i) 6.25 x 10^18, (ii) 10^19

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659.

23. If the charge on an electron is 1.6 x 10-19 coulombs, how many electrons should pass through a conductor in1 second to constitute 1 ampere current ?

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6.25×10^18 is the correct answer of the given question

660.

29. The acceleration due to gravity g on earth is 9.8ms?. What would the value of g for a planetwhose size is the same as that of earth but thedensity in twice that of earth?(a) 19.6 ms 2(c) 4.9 ms(b) 9.8 ms(d) 2.45 ms2

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size of planet is same as that of earth, it means volume of planet is same as volume of earth. So, the radius of planet = radius of earth = R {let }

Also we know, density = mass/volume , If volume is constant then density depends upon mass and it is directly proportional to mass.

A/C to question, density of planet is twice that of earth. ∴mass of planet is twice that of earth.Let mass of earth is M Then mass of planet is 2M

Now, g = GM/R² , for earth g' = G(2M)/R² , for planet .Here you observed , 2g = g' Hence, acceleration due to gravity on surface of planet is two times of acceleration due to gravity on Earth's surface.E.g., acceleration due to gravity on planet' surface = 2 × 9.8 = 19.6 m/s²

661.

car travels a certain distance with a speedof 40 ms-1 and returns with a speed uthe average speed for the whole journey is48 ms-1, what is the value of u?

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Average speed =speed 1+speed2/248=40+u/296=40+uu=96-40=50m/s

this answer is wrong and write and is 60m/s

662.

The acceleration due to gravity at a place is9.8 ms 2. Find its value in km h2 and its order ofmagnitude for that value.

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order of magnitude for 127008 = 1.2 x 10^5

663.

Example L1 The acceleration due to gravity is 9.8 ms-2. Giveits value in fts2

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1m=3.32fthence9.8m/sec^2=32.103ft/sec^2

664.

49. The unit of the refractive index is(1) Meter(2) Meter/second(3) Diopter(4) Nothing

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(4) NothingRefractive index has no units because the refractive index is the ratio of the speed of light within the material of interest divided by the speed of light in a vacuum, thus the consistent units of measure.

665.

2. A 100 meter long train moving with constantspeed of 90 kmh crosses a tunnel of 300 meterlong. The time taken by the train to cross thetunnel completely is2) 8 seconds4) 2 seconds1) 16 seconds3) 4 seconds

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666.

25) The image of a candle flame placed at a distance of 40 cm from a spherical lens is formed on a screen placed on the other side odistance of 40 cm from the lens. Identify the type of lens and write its focal length. What will be the nature of the image formeflame is shifted 25 cm towards the lens? Draw a ray diagram to justify your answert ad if the candle

Answer»

Object distance, u = -40cm

Image distance, v = 40 cm

Using lens formula,

1/f=1/v-1/u=1/40-1(-40)

or Focal length,

f=+20cm

The positive sign of focal length shows that it is a convex lens.

Now,

Magnification, m = v/u= 40/(-40)= -1

Thus, the image is real, inverted and same size as object.

If candle flame is shifted 25 cm towards the lens, then

u=-(40-25)=-15cm1/20=1/v-1/(-15)=-60cmm=v/u=-60/-15=4Thus the image will be virtual, erect and enlarged.

what is this nonsense 😠

667.

12The magnification of an image formed by a lens is - I. If the distance of the image from the (3)optical centre of the lens is 25 em, where is the object placed? Find the nature and focallength of the lens. If the object is displaced 15 cm towards the optical centre of the lens,where would the image be formed? Draw fray diagram)to justify your answer..

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668.

20.A man goes 10m towards North, then 20m towards east then displacement is) 22.5 mB) 25 mC) 25.5 mD) 30 m

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669.

QS. When th(True False)e lift moves upward the weight of the person inside it decreasestribution in physics (discoveries).

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Isaac Newton

Co-inventor of calculus, a major contributor to the science of optics and a gifted mathematician, Isaac Newton (1643-1727), who was born in Lincolnshire, outlined the laws of mechanics that now underpin vast swaths of classical physics.

Most important of all, Newton outlined theprinciple of gravity, which explained how the planets revolve round the sun. During his life, he was showered with honours, including the presidency of the Royal Society. He is renowned as a supreme rationalist, though he actually wrote more about alchemy and religion, including a 300,000-word treatise.

Galileo Galilei

Born in Pisa, Galileo (1564-1642) initially trained as a doctor. On hearing of the invention of the telescope in 1609, he built his own and turned it to the heavens, revealing the existence of sunspots and a pitted, mountainous surface on the moon:the heavens were not incorruptible.

His studies also provided support for the idea that the Earth revolves round the sun. This got Galileo into considerable trouble with the Catholicchurch and he was forced to abandon that backing in 1633. His work on falling bodies also laid the groundwork for Newton’s subsequent theories.

Thanks🤗

670.

A car starting from rest accelerates with 5 ms-2 andreaches a maximum velocity 20 ms-1. Then by theapplication of breaks it comes to rest with a decelerationof 8 ms 2. The total time of journey is1) 2.50 2) 4.82 s 3) 6.25 s 4) 6.50 s

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671.

13. In the figure the current i in the circuit will be-30Ω30Ω30Ω(A) 5 ampere(B) is ampere15(c) io ampere(D) ampere10

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all the 3 resistances are in parallelhence1/R=1/30+1/30+1/30R=30/3=10henceI=V/RI=2/10=1/5A

672.

The___ ampere current is required to run appliances with higher rating such as fridge, AC etca. 15Ab. 5Ac. 25Ad. 10A

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We generally gets 220 v ac supply for our homes. Their are two current ratings available in India one is 5 Amps and other is 15 Amps. The amount of current is mainly chosen on the total load you are going to use at your homes.

As our lines are connected in parallels, the voltage remains 220 v ac but the current is different for different loads. So the supply is 5 amps or 15 amps and this current is divided within the loads

673.

A body is moving along a straight line at 20 ms 'undergoes an acceleration of 4 ms-2. After 2 s, its speedwill be-(A) 8 ms-1(B) 12 ms-1(C) 16 ms-(D/28 ms-

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674.

In the figure, the velocity V3 will be :-A, = 0.2 m²V, = 4msV2 = 2msA.=0.2m?Az=0.4m(1) Zero(2) 4 ms-1(3) 1 ms-1(4) 2 ms-1

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2 is the right answer

A1V1= A2V2= A3v3so0.4*2= 0.8= 0.4*2= 0.8option- D

675.

A particle moves along a semicircle of radius 10m in 5 seconds. The velocity of the particle is-1(A) 2π ms4 ms(C) 2 ms

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676.

4.The acceleration of the particle is given by a = 2t+1. The velocity at the particle at t = 2 s if it was atrest at t = 0(1) 6 ms -1(2) 8 ms -1(3) 4 ms-1(4) 10 ms-1

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how to solve

For this integrate the acceleration as dv/dt =afrom 0 to 2hence2t^2/2+t]2-[2t^2/2+t]0t^2+t]2=4+2=6m/s

677.

1. The ratio of kinetic energy of a planet at perigeeand apogee during its motion around the sun inelliptical orbit of eccentricity e is1+ e1- e(2),21-ะต1+ e1-e

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we can consider eccentricity to be a general term represented by e. Apogee is the point in the elliptical orbit where the planet is farthest from the sun and perigee is the point where the planet is nearest to sun.In order to calculate the ratio of kinetic energy, we can use conservation of angular momentum.Now, we know that angular momentum is conserved for the planet throughout the orbit. Hence,Angular momentum at apogee = angular momentum at perigeeLet rabe the distance at apogee and rpbe the distance at perigee. The value of r1andr2can be represented in terms of the semi major axis and eccentricity (e) as mentioned below. If a is the length of semi major axis, thenra= a(1+e)and,rp= a(1-e)Now, by conservation of angular momentum, if the mass of the planet is m and the velocity at apogee and perigee be vaand vprespectively.m vara= m vprp, orva/vp=rp/ra= (1-e)/(1+e)The ratio of kinetic energy is given by = (1/2mvp2)/(1/2mva2) = (vp/va)2=[(1+e)/(1-e)]2

678.

101. Aparticle is moving with a velocity of 10m/s towardseast. After 10 s its velocity changes to 10m/stowards north. Its average accelaration is:-(1) zero2 m/s2 towards N-W(3) a m/s towards N-W(4)m/s2 towards N-W

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The average acceleration is (change in Velocity)/time

=>vf = 10j , vi = 10i , t = 10

so avg. a = (10j-10i)/10 = 1j-1i = √2( j-i) North-west

option 2

679.

Ans. (i) 40 m/s, (ii) 100 eutUgraph isds? What is the5. How far does the runner whose time-velocityshown in the figure travel in 16 seconacceleration of the runner at t =11 second ?ト470 2 4 68 10 12 14 16TIME t (b)

Answer»

Incorrect Answer...

Do not Answer If you don't know...

680.

16. Two bodies of masses m, and m2 are connectedbt string which passes over a frictionless,massless pulley. If the pulley is moving upward withuniform acceleration, then tension in the string willbe2m, + m24m,m2m,m23m.m22m,m2m +m+ m2

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Let m2 > m1.

Consider the masses m₁ and m₂, with forces Tension T in the string upwards and their weights downwards, acting on them. Both of these masses are moving with same acceleration a up (m1) or down (m2 as m2>m1), asthe string is tight and has a uniform tension all along its length. This explanation is valid in the frame of reference of moving pulley with an acceleration g/2 upwards.

In the frame of reference of pulley, with an acceleration g/2 upwards, the two masses are having acceleration a and -a. To balance forces in this non-inertial frame, we need to add a fictitious force of m₁g/2 downwards on m₁ and -m₂ g/2 downwards on m₂. Then we write free body diagrams and apply Newtons' laws.

T - (m₁ g +m₁ g/2) = m₁ a => T - 3 m1*g/2 = m1 a (m₂ g +m₂ g/2) - T = m₂a => 3 m₂*g/2 - T = m₂ a

Add the two equationsto get

a = (3g/2) *(m₂- m₁) / (m₁ + m₂) then, T = 3m₁ g/2 + m₁ a = 3 m₁m₂ g / (m₁ + m₂)

681.

wouobe the acceleration it the force were doubledA man pushes a box of mass 50 kg with a force onwould be the acceferation if the mass were halvedo N. What wil be the doedctatiee aceeleration of the box What3

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682.

The electric potential at the surface of anatomic nucleus (7-50) of radius9.0 x 10-15 m is:(A) 9x105 Volt(B) 8 Volt(C) 8 x 10 Volt(D) 9 VoltC.

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which option buddy ? 🤔

v=k*q/r=k*ze/r9*50*1.6*10^9-19/9*10^-159*80*10^-10/9*10^-1580*10^-10+158*10^6

683.

The electric potential at the surface of an 4atomic nucleus (z= 50) of radius9.0 x 10^-15 mis(A) 9x10^5 Volt(B) 8 Volt(C) 8 x 10^6 Volt(D) 9 Volt

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684.

15.A conductor of 3 m in length is moving perpendicularlyto magnetic field of 10- tesla with the speed of102 m/s, then the e.m.f. produced across the ends ofconductor will be[MP PET 1990)(a) 0.03 volt(b) 0.3 volt(c) 3 x 10-3 volt(d) 3 volt

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option C ) is the correct answer

685.

Baok MenuAIST181103J19PShowing qn 7 of 45Qn 7. In L.C.R. circuit potential difference between terminals ofinductance is 60 V, between terminals of condenser is 30 V andbetween terminalsof resistance is 40 volts. Then find the supplied voltage.(a) 130 volt(b) 10 volt(c) 70 volt(d) 50 volt

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supplied voltage = voltage across inductance + voltage across capacitance + voltage across resistance=60+30+40=130 volt

686.

A old man goes for evening for exercise on a park he covers of a distance 20m in 30s if he keep walking at this rate find the distance covers by him 5m and 10 second

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687.

2 A river is flowing from west to east at a speed o5 metres per minute. A man on the south bank of thriver, capable of swimming at 10 metres per minute istill water, wants to swim across the river in the shortestime. He should swim in a direction(a) due north(c) 30° west of north(b) 30° east of north(d) 60° east of north

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688.

A man A moves with speed 10 m/s in north and another man B moves in east-30-north with 10 m/s .Find velocity of B With respect to A

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A similar example.

ram moves in east direction at a speed of 6m/s and shyam moves 30 degree east of north at a speed of 6m/s. the magnitude of their relative velocity is?

689.

straight road from his home to market 2.5 km away with a speed ofCample 4. A man walks on a road5 kmis the magnitude of average velocity, and average speed of the man over the interval of timerample 4. A man waaiet close, he instantly turns and walks back with a speed of 7.5 km h.Whatwalks on aFinding the market closed, he instantly tu(i) 0 to 30 min,(l0 to 50 min, (ii) 0 to 40 min ?

Answer»

Time taken by the man to reach the market from home,t1= 2.5/5 = 1/2 h = 30 minTime taken by the man to reach home from the market,t2= 2.5/7.5 = 1/3 h = 20 minTotal time taken in the whole journey = 30 + 20 = 50 min

(i) 0 to 30 minAverage velocity = Displacement/Time = 2.5/(1/2) = 5 km/hAverage speed = Distance/Time = 2.5/(1/2) = 5 km/h

(ii) 0 to50 minTime = 50 min=50/60 = 5/6 hNet displacement = 0Total distance = 2.5 + 2.5 = 5 kmAverage velocity = Displacement / Time = 0Average speed = Distance / Time = 5/(5/6) = 6 km/h(iii) 0 to 40 minSpeed of the man = 7.5 km/hDistance travelled in first 30 min = 2.5 kmDistance travelled by the man (from market to home) in the next 10 min= 7.5×10/60 = 1.25 kmNet displacement = 2.5 – 1.25 = 1.25 kmTotal distance travelled = 2.5 + 1.25 = 3.75 kmAverage velocity = Displacement/Time = 1.25/(40/60)= 1.875 km/hAverage speed = Distance/Time = 3.75/(40/60) = 5.625 km/h

690.

A man moves in north direction with speed 10 m/s and another man B moves in E-30-N with 10 m/s.Find the relative velocity of B w.r.t. A.Ans. 5 31-5. E-30 S

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1

2

691.

6.A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km/h. Finding themarket closed, he instantly turns and walks back home with a speed of 7.5 km/h. The average speed of theman over the interval of time 0 to 40 min. is equal to(A) 5 km/h(B) 25 km/h30445(Dy 1km/h8(C) km/h

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692.

A 50 Ω resistance galvanometer has 25 divisions onits scale. On sending a current of 4.0 x 10 A in it,the pointer gives a deflection of 1 division. How muchresistance should be connected in series with thegalvanometer to convert it into a voltmeter of 2.5 Vrange?4Ans. 200 2.

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693.

21.Two resistances are conected in parallel whoseresultant is = ohm. One of the resistance wires isbroken and the effective resistance becomes 2 ohmThen the resistance of the wire that got brokenwas(a) 202(b) 302(c) 0.622(d) 1.202

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694.

2. What length of wire (sp. resistance 48 x 10^-8 ohm m)is needed to make a resistance of 4.2 ohm ?(Diameter 0.4 mm).[109 cm]

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695.

A resistor of 9 ohm is connected in series with a cell of electro motive force 2 volt. and interval resistance 1 ohm. fine the current through resistance

Answer»

I=V/R+rI=2/9+1=2/10=1/5=0.2A

696.

A resistor of 9 ohm is connected in series with a cell of e. m. f. 2 volt. and interval resistance 1 ohm. fine the current through resistance

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V= IR2 = I*(9+1)2/10= I0.2 AMPERE

697.

3. A galvanometer of resistance of 9 ohmshows a deflection of 30 divisions. If thegalvanometer is shunted with 6 ohmresistance, the deflection in the galvanometerwill be:1) 12 div3) 60 div2) 18 div4) 20 div

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14 division will be thereresistance is being shunted means a resistance is being connected in parallel with the existing resistanceso new resistance will be 4.2 ohm

698.

18. The e.m.f. of a Daniel cell is 1.09 V and its internalresistance is 2 ohm. If the terminals of the cell arejoined by a wire of resistance 18 ohm, find P.Drecorded by a high resistance voltmeter connected tothe terminals of the cell.

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699.

33. Two electric lamps of 40 watt each are connected inparallel. The power consumed by the combination willbe :oa zowat(a) 20 watt(c) 80 wattO(6) 60 watt(d) 100 wattowo

Answer»

Given, P1 = 40 W

And P2 = 40 W

If you've given power along each of the branches, the total power P equals the sum of all branch power values (P1+ P2 + P3 + ...).

Therefore here in this case

Total Power (P) = P1 + P2

P = 40 + 40

P = 80 Watt.

(c) is correct option

answer is 80watt because each are connected in parller

700.

18. The e.m.f. of a Daniel cell is 1.09 V and its internalresistance is 2 ohm. If the terminals of the cell arejoined by a wire of resistance 18 ohm, find P.D.recorded by a high resistance voltmeter connected tothe terminals of the cell.

Answer»