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7101.

METER BRIDGE

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A Meter Bridge is also called as slide wire bridge and is an instrument that works on the principle of a Wheatstone bridge. A meter bridge is used in finding the unknown resistance of a conductor as that of in a Wheatstone bridge.

7102.

With a resistance x ohm, in the left gap and a resistance 3 ohm inthe right gap a balance is found at 40cm for null deflection in a meter bridge. Then x is:

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X/l= R/100-lX/40= 3/60X= 2cm

7103.

questionon the benbevisAnswer the followingof given ut graph1ИВ002030Times

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7104.

t sieel sylindei ut diamete. :exactly, I ini at so"Cs to be nitted into a hole in a steel plate, Thediameter of the hole is 0.99970 em at 30°C. To whatemperature should the plate be heated ? Given7

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(P1) Thermal expansion of an area is like a photographic enlargement. Every linear dimension increases by the same percentage with a change in temperature, including holes.

Let α be the linear expansion coefficient for a material. Then:

(E1) ΔL / L0 = α * ΔT

Since we are given a linear dimension (the diameter), we can use it, together with (P1) and (E1), to calculate the temperature T. First,

(E2) ΔT = T - T0 = T - 30and(E3) ΔL = L - L0 = 1.00000 - 0.99970 = 0.00030cm

Substituting into (E1):

(E4) ΔL / L0 = α * (T - 30)

= α * T - α * 30

Solving for T:

(E5) T = (ΔL / L0 + α * 30) / α

= (ΔL / L0 ) / α + 30

and substituting from (E3):

= (0.00030 / 0.99970 ) / α + 30

= 0.00030 / α + 30

Now all we need to know is what material the plate is made of, plus an experimentally determined value for α at 30C for that material.

For example, using the table at Source 3, if the material is steel and we assume that

(E6) α30 ≈ α20,

then

(E7) T = 0.00030 / α + 30

= 0.00030 / 13e-6 + 30

= 53.C

7105.

(13) An a.c. e.m.f. is given by;ε= 220 sin! 100m-πvoltage and frequency.. Calculate its r.ms

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Erms = 220/√2 = 155.56

frequency = 2π/w = 2π/100π = 1/50

7106.

if a body weight is1.0gm is travelling along with x=100m in one second what is the theoritical uncertainityin position?

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7107.

Time taken by the projectile to reach from A toThen the distance AB is equal to303utut(a) 3(b) 2(d) 2ut(c) /3u t

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7108.

३: 1 उस दर्पण का नाम बताइए जो बिंब का सीधा तथा आवर्धित प्रतिबिंब बनासके?Name the mirror that can give an erect and enlarged image of anme object.rer

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I am a five digit number my once digit is three my hundred digit is 2 times my once digit my 10 digits is the sums of 16 digits and hundred digits my thousand and 10000 digits is one less than 100 digits for what number and I II write my success II III and IV greater than or less than the Number 55 1936

Concavemirror gives an erect and enlarged image of an object, when theobjectis between pole (P) and principal focus ofmirror(C).

concave mirror is correct answer

concave mirror is the correct answer of the given question

7109.

7. Write the functions of the following in communication systems. () Transducer /if Repeater(it)Modulator

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A transducer is a device that converts energy from one form to another. Usually a transducer converts a signal in one form of energy to a signal in another

In telecommunications, arepeateris an electronic device that receives a signal and retransmits it.Repeatersare used to extend transmissions so that the signal can cover longer distances or be received on the other side of an obstruction.

In electronics and telecommunications, modulation is the process of varying one or more properties of a periodic waveform, called the carrier signal, with a modulating signal that typically contains information to be transmitted.

7110.

59. Ifa convex lens of refractive index 1.44 is 5dipped in a liquid of refractive index 1.49,then it behaves as:(A) Concave lens(B) Convex lens(C) Mirror(D) of these

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It will behave as concave lens as refractive index of lens is less than refractive index of surrounding

7111.

Give differences between:(ix) Concave lens and convex lens(x) Lens and mirrors

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I want the difference between lens and mirror

Ok Thanks

7112.

Which one of the following materials cannot be used to make a lens?(b)(c)(d)GlassPlasticClayormed by a concave mirror is observed to be virtual, erect and lala)Waterbie

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I think it is option (d) clay becoz light doesn't pass through it as it is opaque

plz like my answer.....

clay because it does not let light to pass through it

7113.

6 5००८- 6 पा5६ 0 पष्य/ है 89907+ g UG P 7 = O Ve

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7114.

whal ugal

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Rate of change of acceleration it is just irregular change in velocity. We all know that rate of change of velocity is acceleration, but acceleration is constant only when there is proportional change in velocity with time,if it doesn't it results in change in velocity, in the term rate of change of acceleration there is everything about velocity nothing significantly about acceleration, that is why we don't use it generally.

We can also say that varying force is the cause for it. Or it is the work done to displace an object of unit mass by a unit displacement.

If I just say that it is called ‘jerk'.

Rate of change of acceleration is calledJerk

We know

v = dx/dt

a = dv/dt

therefore, mathematically ,

it is second derivative of velocity with respect to time or

it is third order derivative of displacement with respect to time.

7115.

(d) How do we click photographs?

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Photographyis the art, application and practice of creating durableimagesby recording light or otherelectromagnetic radiation, either electronically by means of animage sensor, or chemically by means of a light-sensitive material such asphotographic film. It is employed in many fields of science, manufacturing (e.g.,photolithography), and business, as well as its more direct uses for art, film and video production, recreational

7116.

It is 320km from Patna to Ranchi by road. A bus taken 8 hours. find the average velocity of the bus.

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velocity = distance / time320km/ 8 hours40kmph

7117.

s A and B start moving with velocities1. Two particle30/2 m/s along x-axis and at an angle20 m/s and46° with x-axis respectively in xy-plane from oriThe relative velocity of B w.r.t. A

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7118.

what type of wave is represented by density distance graph

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longitudinal wave

7119.

4.Five homogeneous bricks, each of length L, are arranged as shown infigure. Each brick is displaced with respect to the one in contact by L/. Findthe x-coordinate of the centre of mass relative to the onigin O shown.

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7120.

. Five homogeneous bricks, each of length L, are arranged as shown inigure. Each brick is displaced with respect to the one in contact by L/5. Findthe x coordinate of the centre of mass relative to the ongin O shown

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7121.

Five homogeneous bricks, each of length L, are arranged as shown infigure. Each brick is displaced with respect to the one in contact by L/5. Findthe x-coordinate of the centre of mass relative to the origin O shown.4.

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please post clear image

7122.

3. Seven homogeneous bricks, each of length L, arearranged as shown in figure (9-E2). Each brick isdisplaced with respect to the one in contact by L/10.Find the x-coordinate of the centre of mass relative tothe origin shown.Figure 9-E2

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thanks

7123.

State the type of motion represented by the given graphdistancetimem/s1/8) -

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c is correct answer I think

a.uniform velocity b.rest motion d.retardation

7124.

3.a Find the position of centre of mass of the unifom planner sheet shown in figure with respect to the onigin2a0Five homogeneous bricks, each of length L, are arranged as shown infigure. Each brick is displaced with respect to the one in contact by U5. Findthe x-coordinate of the centre of mass relative to the onigin O shown.4.

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7125.

e equation 2x +y=6 Shade the region bounded by the graphand the coordinate axes. Also find the area of the sided Tegion

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sorry i can't understand your question

7126.

24. A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s. Calculate the speed ofthe motorcycle after 10 seconds, and the distance travelled in this time.

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7127.

24. A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speedthe motorcycle after 10 seconds, and the distance travelled in this time.

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7128.

24. A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed ofthe motorcycle after 10 seconds, and the distance travelled in this time.

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7129.

नींद का अध्ययन क्या कहलाता है ?(83 हिनोलॉजी () g(0) पोमोलॉड्-....... (0) आर्नीथोलॉजी

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the correct answer is (A) hypnology.

7130.

1. The point from where a ball is projected is taken as the oringin of the coordinate axes. The z and y components of itsdisplacement are given by 6t and y t-512. What is the velocity of projection?A) 6 ns-1B) 8 ms-19)10 ns-1D) 14 ms-1

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7131.

20. A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s?. Calculate the speed of themotor cycle after 10 second, and the distance travelled in this time.[And. 7 m/s; 60 m]I

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7132.

10. Ram has met with an accident and after that he lost the capacity to(a) walk in a straight line (b) smell anything (c) feel full after eatingVhich part of brain is damaged in each case?

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The brain has many different areas which are responsible for different tasks, which help humans perform different abilities. The damage would be to the parts that are responsible for these attributes:

(a) Cerebellum is situated at the back side of the skull

(b) Temporal lobe in cerebrum is under the lateral fissure

(c) Hypothalamus is located over the pituitary gland.

Like my answer if you find it useful!

7133.

Compare the power at which each of the following is moving upwards against the force of gravity? (giveng9.z 10 ms2)a. a butterfly of mass 1.0 g that flies upward at a rate of 0.5 m s-1.b. a 250 g squirrel climbing up on a tree at a rate of 0.5 m s-1.

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Butterfly force= mg=1/100power=f×s÷t. {s÷t=velocity}power=1÷100×.5power=1÷200Wsquirrel force=mg=25power=25×.5power=12.5W

POWER OF SQUIRREL IS MORE THANPOWER OF BUTTERFLY.

7134.

028. A motor cycle moving with a speed of 5m/s is subjected to an acceleration of 0.2m/s. Calculate the speed of(Ans: -1.87m/s, 60.2m)the motor cycle after 10 seconds, and the distance travelled in this time.(Ans: 7m/s, 60m

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7135.

22. The equation of trajectory of an oblique projectileThe angle of projection isA) 30°B) 450C) 60°D) 15°

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option c

7136.

4. The trajectory of a projectile as seen from another projectile is aa. Straight line b. ellipse c. hyperbola di parabola

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Acceleration of a projectile is constant (equal to the acceleration due to gravity, g) towards the earth. Hence, acceleration of both projectiles is same and relative acceleration is zero. Since relative acceleration is zero, relative velocity is constant and hence, the path of a projectile seen from another projectile is a straight line.

the trajectory of the projetile is parabola

7137.

21.At the topmost point of a trajectory, its velocity and acceleration are at an angle of(2) 45°(4) 18093) 90°

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option 3

7138.

The equation of trajectory of an oblique projectile y=\sqrt{3} x-\frac{g x^{2}}{2} The angle of projection isA) 30°B) 45°C) 60°D) 15°

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7139.

22. The equstion of trajectory of an oblique projectil y The uple of projectin isA)30B)45C) 60D) 15

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7140.

A projectile is fired from the surface of the earth witha velocity of 5 m/s and angle e' with the horizontal.Another projectile fired from another planet with avelocity of 3 m/s at the same angle follotrajectory which is identical with the trajectory of theprojectile fired from the earth. The value of theacceleration due to gravity on the planet is (in m/s')is (Given g 9.8 m/s3)16.ws aAIPMT 2014](2) 5.9(4) 110.8(3) 16.3

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7141.

The force experience by moving vectorcharged particle is given by:(b)(iii) q ธิ์(iv) 18%d

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The forceisgiven by thechargetimes thevectorproduct of velocity and magnetic field.

option (i) is right

7142.

A particle is projected up an inclined plane with initialspeed v-20 m/s at an angle θ 30° with plane. Thecomponent of its velocity perpendicular to plane when itstrike the plane is(a) 10/3 m/s(b) 10 m/s(c) 5v3 m/s(d) data is insufficient

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Componet of velocity perpendicular to plane at the time of projection is sameas the component of velocity perpendicular to plane when it strikes the ground (inoppositedirection)

usin30=20sin30

usin30=20sin30

=10m/s

=10m/s

*Additional information*

A body which is in flight through the atmosphere under the effect of gravity alone and is not being propelled by any fuel is called projectile.

Assumptions of Projectile Motion

i. There is no resistance due to air.

ii. The effect due to curvature of earth is negligible.

iii. The effect due to rotation of earth is negligible.

iv. For all points of the trajectory, the acceleration due to gravity ‘g’ is constant in magnitude and direction.

Principle of Physical Independence of Motions

(i) The motion of a projectile is a two dimensional motion. So, it can be discussed in two parts. Horizontal motion and vertical motion. These two motions take place independent of each other. This is called the principle of physical independence of motions.

(ii) The velocity of the particle can be resolved into two mutually perpendicular components. Horizontal component and vertical component.

(iii) The horizontal component remains unchanged throughout the flight. The force of gravity continuously affects the vertical component.

(iv) The horizontal motion is a uniform motion and the vertical motion is a uniformly accelerated or retarded motion.

And There are Three types of Projectile Motion

a. Oblique projectile motion

b. Horizontal projectile motion

c. Projectile motion on an inclined plane

7143.

Now c15.Find the acceleration of the block of mass M in the situation shown in figure. All thesurfaces are frictionless and the pulleys and the string are light.(A) g /2 up the plane(C) g/3 down the planeHowrelathe(B) g /2 down the plane(D) g/3 up the planeLD30°

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7144.

b) Crystallization is a better technique than simple evaporation. Why?

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A solution is a mixture of a solid component called the solute and a liquid component called the solvent. Crystallization is the process by which the solute is formed into solid crystals and separated from the solution. Evaporation is the process by which the solvent is converted into vapor, leaving the solute component behind. Evaporation is a heat absorbing process requiring energy to take place. Crystallization occurs by letting a heated solution cool and letting formed crystals drop off.

The better method would depend on the solution. Generally, crystallization would be better when a solution is saturated but would be less effective if the solution is dilute. Also, solutions containing solvents such as acetone or ether, which evaporate at lower temperatures, would be better separated by evaporation than solutions containing water as solvent which evaporates at a higher temperature.

Because crystallized particles would be in solid or semi solid compounds and if evaporation is done for the case it is to be distilled too get the substance.... instead of doing evaporation process and distillation process .... if u obtain crystal particles of that substance ... it would be easier for u to separate.. than that of evaporation

7145.

HisOROLL.NODATEtwo bulbs of 1002 each are come adin Sensacorolla 230V Supoy. Sintthe peace & card taken by the condi

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7146.

4.V2 SNEA particle moves in x-y plane with a velocityv = 2y i +4j. Equation of the path followed bythe particle is(1) * = Vy(2) = x(3) 4x = y2(4) 4y = x?

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4) is the correct answer

2) is the correct answer

3) is correct answer

7147.

It is required to throw an image, magnifiedtwo times, on a screen placed at a distance of6 cm from the object. Find the focal lengthand nature of the lens required.

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m=2m=v/u=2v=2ualsov=u+62u=u+6u=6v=2uv=12the object distance is always negativesou=-6also the image is on the same side of the object .sov=-12using lens formula1/f=1/v-1/u1/f=1/-12-1/-61/f=1/12f=12

Focal length is positive.So,it is a convex lens.

7148.

पड echi® (ot be headSenag ity

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To hear an echo, our distance from the reflecting surface should be atleast 17.2 m which is not possible in a small room. Therefore, echo is not heard in a small room.

7149.

Monika has to determine the focal9length of a concave mirror and aconvex lens offocal length of about 15 cm each. Sheuses a distant tree as the object andobtains asharp image of the tree, one byone, on a screen. If 11 and 12 are thedistancesbetween the mirror/lens and thescreen in the two cases, thencalculate 11 and 12.Also, state the nature of theirrespective images obtained on thescreen526:46 PM

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When an object is placed very close to a concave mirror and convex lens, than only an erect virtual image is formed .

But, a virtual image cannot be obtained on screen .

So , image has to be real and inverted .

Applying mirror formula-

1/v + 1/u = 1/f

where, v = image distance

u = object distance

f = focal length

Here, for concave mirror , f = - 15 cm

if u = - 30 cm

1/v - 1/30 = -1/15

=> image distance , v = - 30 cm

=> the distance l1 between mirror and screen = 30 cm

This is possible when object is placed at centre of curvature of mirror , a real and inverted image is formed at centre of curvature .

Applying lens formula-

1/v - 1/u = 1/f

where, v = image distance

u = object distance

f = focal length

Here, for convex lens , f = 15 cm

if u = - 30 cm

1/v + 1/30 = 1/15

=> image distance , v = 30 cm

=> the distance l2 between lens and screen = 30 cm

This is possible when object is placed at 2f of convex lens , a real and inverted image is formed at 2f of lens on other side .

So, correct option is : (30 cm, 30 cm) and (inverted, inverted)

7150.

modulus ot av// Then Value, 아 PisThe

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