InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7051. |
The equation area Ă velocity-constant is called(a)(c)The energy stored in thn2.Benoulli's theoremEquation of continuity(b) Stoke's equation(d) Reynold's number3. |
|
Answer» The equation is called as Bernoulli's equation. so option a is correct answer. |
|
| 7052. |
9) A wire of length 1, and area of cross section A was drawn into awire of double its length by melting it. If its original resistivity and |
| Answer» | |
| 7053. |
sicBASIC to t add tuso |
| Answer» | |
| 7054. |
n1. Ifg is the acceleration due to gravity on thesurface of the earth, the gain in potentialenergy of an object of mass in raised fromthe earth's surface to a height equal to theradius Ro the earth is |
|
Answer» Let R→Radius of the earth M→Mass of the earth m→Mass of the body g→Acceleration due to gravity on earthWhen the body is on earth surface, considering the force of attraction of earth on it we can write mg = GMm/R^2 where G = Gravitational constant ⇒GM = gR^2.....(1) Now the PE of the system when the body is on the surface Es = −GmMR....(2) Again the PE of the system when the body is at height h from the the earth surface is given by Eh = −GmM/R+h If h = R then ER = −GmM/R+R = −GmM/2R....(3) Soincrease in PEdue to shift of the body of massmfrom surface to the height equal to the radius (R) of the earth is given by: ΔEp = ER−Es = −GmM/2R + GmM/R = GmM/2R = mgR^2/2R = 1/2mgR Inserting GM = gR^2 from (1) |
|
| 7055. |
c. The mass and weight of an object onearth are 5 kg and 49 N respectivelyWhat will be their values on themoon? Assume that the accelerationdue to gravity on the moon is 1/6thof that on the earth |
|
Answer» Acceleration due to gravity on the earth's surface : Weight = mg 49N = 5 × g 5g = 49 g = 9.8 m/s² Acceleration on the moon : 1/6 × 9.8 = 1.6333 m/s² The weight on the moon: 5 × 1.6333 = 8.1665N Answer : 8.1665 N Data=m=5 kg, w=49n,, |
|
| 7056. |
61. An ice cube of density 900 kg Im is floating in water of density 1000 kg /m'. The percentageof volume of ice-cube outside the water is:(A) 20%(B) 35%(C) 10%(D) 25%/o |
|
Answer» Density of ice outside = 1000 - 900 = 100kg/m3 % of ice outside = 100/1000 × 100 = 10%. Ans |
|
| 7057. |
A current of 0.4A flows through a conductor for 5 minutes. How muchcharge would have passed through the conductor? |
|
Answer» 2 amphere ........................... |
|
| 7058. |
factors on which, at a given temperature, the resistance of a cylindrical conductorndiue is 10 ohm. If the resistivity of the material ofteprocess of asexual reproduction in hydra with diagram.A) State thedepends. |
|
Answer» Factors on which the resistance of a cylindrical conductor depends are :(i)Length of the conductor (ii) Area of cross-section of the conductor (iii) Nature of the material SI unit of resistivity is ohm-m. |
|
| 7059. |
8. Who was the inventor of lightning rod? |
|
Answer» The pointed lightning rod conductor, also called a lightning attractor or Franklin rod, was invented by Benjamin Franklin in 1749 as part of his groundbreaking exploration of electricity. |
|
| 7060. |
PAGEDATEJenineMathematicallyag. |
|
Answer» Aij basically representation of rows and Columnsin any matrixby putting the value of i n j we can make any matrix of any order thank you |
|
| 7061. |
Express Joule's law of heating mathematically. |
|
Answer» Joule’s law of heating states that when a current ‘i ' passes through a conductor of resistance ‘r’ for time ‘t’ then the heat developed in the conductor is equal to the product of the square of the current, the resistance and time. H = i^2rt The reason behind the heat produced is the collision of the free electrons with the lattice ions or atoms while accelerating in presence of the external electric field. |
|
| 7062. |
derive the Newton's second law of motion mathematically. |
|
Answer» Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system.Force applied is directly proportional to the product of mass and acceleration .Let be the initial and final momentums respectively.According to newton's second law :-pf - pi / t ∝ FWe know that,Momentum ( P) = mv .Let v be the final and u be the initial velocity .Now,mv - mu / t ∝ FF ∝ m ( v-u) /tF ∝ ma.F = kma.Here, K is the proportionality constant. It's value is 1 .Units of Force are given by the units of mass and acceleration. Units of force is Kgm/s² .In accordance to honour the contributions of Newton, 1 kgm/s² is termed as 1 Newton. |
|
| 7063. |
State the law which governs the amount of heatproduced in a metallic conductor when current ispassed through it for a given time. Express this lawmathematically2CBSE 2007 |
|
Answer» Heat produced is directly proportional to the square of the current, time t through which the current flown and resistance of the conductor. The heat produced is independent of the direction of current. H ∝ I^2 x R x t |
|
| 7064. |
FOODElectrocardiogram (ECG) machines used in hospitals. Its reason is |
|
Answer» Electrocardiogram (ECG) and high blood pressure. An electrocardiogram (ECG) is a test whichmeasuresthe electrical activity of your heart to show whether or not it is working normally. An ECGrecordsthe heart's rhythm and activity on a moving strip of paper or a line on a screen. |
|
| 7065. |
If the radius of a cylindricalconductor doubles, by what factormust the current density change inorder to maintain the same currentalong the axis of the cylinder ? |
|
Answer» current density must be 1/4 times to maintain the same current along the axis of the cylinder.. to maintain the same current , current density decreases 1/4 times Current density= Current/Perpendicular area For a cylinder, area= πr^2If radius is doubled, area becomes four times. So current density must become one fourth of its value to maintain same current. Hope it helps.Mark as best if you like it. current density must be 1/4 times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current Along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 times########*********, *,, current density must be 1/4 times to maintain the same current along the axis of the cyclinder current density must be made 1/4 time to maintain the same current along the axis... current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 is correct answer 1/4 is the correct answer of the following question Current Density becomes 1/4 times to maintain the same current current density decreases 1/4 times,to maintain the same current. I don't know please like me I also like you 1/4 is the right ans (1/4)th time is the correct answer current density must be 1/4 times to maintain the same current along the axis of cylinder The refraction index of a glass prism is situated a minimum deviation position show that the angle of minimum deviation dm=180-2A where A is the angle of prism? to maintain the same current , current disitu decreases 1/4 times. is the correct answer. current density must be 1/4 times to maintain the same current along the axis of the cylinder current density should be one fourth times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cyclinder current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 times *, *****7,***,,,****, current density should be 1/4 to maintain the same current current density must be 1/4 times current density must be 1/4 times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 times answer...... current density must be 1 upon 4 to maintain the same current along the axis of the cylinder .it is the correct answer 1/4 is a current correct answer density became 1/4 please mark best current density must be 1/4 times to maintain the same current along the axis of the cylinder.. it will be 1/4 times 1/4 is the correct answer to maintain the same current , current density decreases 1/4 times 1/4 is the right answer of the following current density must be 1/4 times to maintain the same current along the axis of the cylinder. current density must be 1/4 times to maintain the same current along the axis I think 1/4 is the current density along the axis of the cylinder. 1/4 is the right answer of the following to maintain the same current, current density decreases 1/4 times this is right answer 1/4 the current density must have to Current Density should be one-fourth times ( 1/4 times) to maintain the same current. current density j=i/A and A=pi r^2so i=j. A i=j. pi r^2if radius doubled i=j. pi (2r)^2i=j. 4pi r^2hence in order to maintain same current the current density j has to become one-fourth of its original value Current density is double 1/4is a right answer after calculate the sum answer is 1/4 current density must (1/4) times. current density must be 1/4times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 is the right answer of the following To maintain the same current, current density decreases 1/4 times decrease current density by factor of 4 1/4 should be the current density current density must be one by fourth X to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder curre turn density must be burned by 4 times to maintain the same current and Andy excessively cylinder current density must be one by four times to maintain the same current along the axis of the cylinder the correct answer is to maintain the same current , current density decreass 1/4 times current density must be 1/4 times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of cylinder current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 is the right answer of the following The current density must be 1/4 times to maintain the same current along the axis of the cylinder current density most be 1/ 4 times to maintain the same current along the axis of the cylinder To maintain the same current,current density decrease 1/4 times If you want to maintain same current then you have to decreased current by 4x. current density must be 1/4 times to mantain the same current to maintain the same current, current density decreases 1/4 times ???????????????????????????? please like my answer then I will also like your answer current density become 1/4 times 1/4 time in orderto maintaining the same current 1/4 is the correct answer 1/4 is the right answer 1/4 is the right answer of the following current density must be 1/4 times to maintain the same current along the axis of the cylinder 1/4 is the right answer of the following current density be 1/4 1/4 is the right answer current density decreases 1/4 times to maintain the same current ,current density decreases 1/4. times 1/4 is the right answer of the following current density must be 1/4timed current dencity must be 1/4 times to maintain the same current along the axis of the cylinder current density must be 1/4 times current density must be1/4. times to maintain the same current along the axis of the cylinder current density must be 1/4 times to maintain the same current along the axis of the cylender Your correct answer is 1/4 to maintain the same current, current density 1/4 times 1/4 is the right answer of the following to maintain the same current, current density decreases 1/4 times current density must be 1/4 times to maintain the same current along axis of cylinder to maintain the same current the density should be 1/4 along the axis of the cylinder current density must be 1/4 time to maintain the same current along the axis of the cylender same current along the axis of the current density must be 1/4times maintain the same current along the axis of the cylinder 1/4times current density changes Current density=current÷perpendicular area for a cylinder, area=πr²if radius is doubled,area becomes four times. So current density must become one fourth of its value to maintaion same current mark as best if u like it current density must be 1/4 times to maintain the same current along the axis of the cylinder J=I/A so j= 1/4 time to maintain same current 1/4 times current density changes current density must be 1/4 times to maintain the same current along the axis of cylinder density decreses 1/4 times if r doubles the j must be 1/4 times changed in order to maintain the same current to maintain the same current density decrease 1/4 times 1÷2 or half is the answer current density becomes 4 times is the correct answer for this question current density must be 1/4 times to maintain the same current along the axis of the cylender current density must be 1/4 times to maintain the same current along the axis of the cy cylender current denusity must be 1/4 times to maintain the same current along the axis of the cylinder it is the correct answer of the following question The current density acrossa cylindrical conductor of radius R varies ... dA= 2pi*rdr considering it is a cylinder, so consider a ring ... On integrating we get I=J0*pi*R2/3. Above answers are absolutely correct... .. Please like my answer.. |
|
| 7066. |
According to Newton's third law, every force is accompanied by equal and opposite force. How cananything move then? |
|
Answer» https://www.quora.com/According-to-Newtons-third-law-of-motion-every-action-has-an-equal-and-opposite-reaction-But-when-we-move-an-object-why-does-it-move open this link to know the concept behind this question. |
|
| 7067. |
Construct a tangent to a circle of radius 4cm from a point on the concentric circle of radius6em and measure its length. Also verify the measurement by actual calculation.Draw a circle with the help of a bangle, Take a point outside the circle. Construct the pairof tangents from this point to the circle measure them. Write conclusion |
| Answer» | |
| 7068. |
2 Prove that the current density of a metallic conductor is directlyProportional to the drift speed of electron. |
| Answer» | |
| 7069. |
35. A wire of a given length having current density J is stretched to doubleits length. What will be the value of current density in it (a) if samecurrent is passed (b) if same P.D. is maintained.Ans. (a) 2 J (b) 0-5 J. |
| Answer» | |
| 7070. |
11-if A+Bǐs a unit vector along xaxis and A-i-j-k, then what is B ?(a) j+k(b) j-K(d)i-i-k |
|
Answer» A + B = unit vectors so, we can just check from the alternative given as in option B A+B = (i-j+k) +(j-k) = i ... a unit vector so, option B mera vi aaya tha lekin option diya hai d |
|
| 7071. |
J JIS3.A car travelling with a speed 126 KMPH alonga straight line comes to rest after travelling adistance 245 m. The time taken by the car tocome to rest, in second it (AP EAMCET-2016)1) 11 2 12 3 16 4) 14alongstraight road |
|
Answer» I don't know the answer because it's of class 11 but I am of class 9th so please try again with some another Hii can you help me in grammer speed = 126x5/18 = 35 m/stime =distance/speed time = 245/35 = 7 second speed=126x5/18=35m/stime=distance/speedtime=245/35=7 second Given is the data of the speed and the distance travelled by car, and we need to find out the time taken to travel the given distance with the given speed. Therefore, we will apply the equation of motion. Given is the u= 126/frac {km} {h}, convert it into m/s which will be 35/frac {m} {s}. Given that d = 245m. d=(u+/frac{v} {2} ) /times t.t = 14 second it question answer 7second |
|
| 7072. |
A motorcyclist driver from A to B with a uniform speed of 30 km b' and return backa speed of 20 kmh. Find its average speed |
| Answer» | |
| 7073. |
state Newton's law of gravitation. what is the relation between ‘g' and ‘cr'.find the time taken by the body protected vertically up with a speed of ‘u' to return back to the ground |
|
Answer» G stands for Newton's universal gravitational constant, whereas g stands for the acceleration due to gravity at a certain point.G = 6.67300 × 10-11 G is a constant throughout space and time and it is a scalar quantity.g = 9.8 m.s -2 , g is acceleration due to gravity which is a variable quantity and a vector qualtity.According to Newton's law of universal gravitation the force of attraction between two bodies is given byF = GMm/r2---------- (i) From Newton's second law of motion the weight of a body of mass m is F = mg -----------------(ii) From (i) and (ii)mg = GMm/r2org = GM/r2 |
|
| 7074. |
A super-ball is to bounce elastically back and forth between two rigid walls at a distance d from eachother. Neglecting gravity and assuming the velocity of super-ball to be vo horizontally, the average force(in large time interval) being exerted by the super-ball on one wall is16.1 mva(A)d2mv6(D) Amvamvo(C)O |
|
Answer» As the ball do back and forth motion,the distance covered by the ball is 2d So time taken=2d/v∆p=2mvAs F∆t=∆pF=2mv/2d/v As v go upper side and become v^2and 2 from both upper and lower side get cancelled out and we get-F=mv^2/d /jhggjfffhhhjjjjhhjikkooojhjjijjjjjjj |
|
| 7075. |
The conductivity of a super conductois |
|
Answer» zero is the conductivity of superconductor. |
|
| 7076. |
What are the ways by which we can enhance our eyesight? |
|
Answer» Proper diet of vitamin A and proper exercise can help in reducing the power of lenses |
|
| 7077. |
(q*((9*10^9)*q))/0.9^2=0.0250000000000000 |
|
Answer» q*q = (0.90)^2*0.25/9*10^10,q = 0.90*0.5/3*10^5,q = 15*10^-7. |
|
| 7078. |
29. The unit of refractive index is- a) meter, b) degree, c) m/s, d) unit less. |
|
Answer» option D is the answer.refractive index is unitless as it is the ratio of two quantities. There is no unit of refractive index bcz refractive index= c/vSo correct answer is =d) unit less |
|
| 7079. |
7. unit of stress is equal to the- (a) force, (b) work, (c) strain (d) pressure. |
|
Answer» The unit of stress is the same as that ofpressure.pascal |
|
| 7080. |
14. The S.I. unit of strain i . (a) N-m, (b) N'm,(c)N'm(d)unitless |
|
Answer» strain is adimensionlessunit |
|
| 7081. |
VIlviRydberg constant R stands for |
|
Answer» Rydberg constant. ... TheRydberg constant represents the limiting value of the highest wavenumber (the inverse wavelength) of any photon that can be emitted from the hydrogen atom, or, alternatively, the wavenumber of the lowest-energy photon capable of ionizing the hydrogen atom from its ground state. hit like if you find it useful 1.0973731568508 × 107 |
|
| 7082. |
14. Draw the architecture of 8051. |
| Answer» | |
| 7083. |
A boy runs on a circular track of radius 20 m and stopsafter covering one sixth of the track. The magnitude of hisdisplacement will be- |
| Answer» | |
| 7084. |
An athletcover in 1 minute?e covers one round of a circular track of 7 m, radius is 44 sec. How much distance will i(Answer 60 m.) |
| Answer» | |
| 7085. |
के... तक et |
|
Answer» Unit of power is Joule/sec that is Watt |
|
| 7086. |
Tiwo mirrors are kept perpendicular to each other. A ray strikes one mirror at an angle of45° to the normal. Find the direction of the ray after reflection by the second mirror, bydrawing a ray diagram. |
|
Answer» thanks so much 😀👍🐾🐾🙏🙏 |
|
| 7087. |
Distinguish between speed andvelocity.10 ) |
|
Answer» Velocity is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity - it is the magnitude of the velocity. Speed is measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.) speed:(1)speed gives how fasts the body moves. (2)formula: - distance/time(3)units: - meter/sec.velocity:- (1) velocity gives the how fasts the body moves and specific direction. (2) formula:- displacement/time.(3) units:- meter/sec. |
|
| 7088. |
1. Distinguish between speed and velocity. |
|
Answer» The short answer is thatvelocityis thespeedwith a direction, whilespeeddoes not have a direction.Speedis a scalar quantity—it is the magnitude of thevelocity.Speedis measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc. The short answer is thatvelocityis thespeedwith a direction, whilespeeddoes not have a direction.Speedis a scalar quantity—it is the magnitude of thevelocity.Speedis measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc. Distance is an amount of space (e.g., that has been traversed by an object, between two bodies, or the like). Speed is the rate of change of distance; mathematically, speed is the time derivative of distance. Todistinguishmeans to tell apart. If you win the lottery, you're going to need to learn todistinguish betweenpeople who really like you and people who like your money. Todistinguishis to discern, which means to perceive or recognize the way something differs from what's Todistinguishmeans to tell apart. If you win the lottery, you're going to need to learn todistinguish betweenpeople who really like you and people who like your money. Todistinguishis to discern, which means to perceive or recognize the way something differs from what's The short answer is thatvelocityis thespeedwith a direction, whilespeeddoes not have a direction.Speedis a scalar quantity—it is the magnitude of thevelocity.Speedis measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.). The short answer is thatvelocityis thespeedwith a direction, whilespeeddoes not have a direction.Speedis a scalar quantity—it is the magnitude of thevelocity.Speedis measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.). |
|
| 7089. |
1. Distinguish between speed andvelocity |
|
Answer» Ans :- velocityis thespeedwith a direction, whilespeed does not have a direction.Speedis a scalar quantity—it is the magnitude of thevelocity.Speedis measured in units of distance divided by time (e.g., miles per hour, feet per second, meters per second, etc.). |
|
| 7090. |
1. Distinguish between speed andvelocity. |
| Answer» | |
| 7091. |
41. Aray of light incident on the first mirror and parallel tothe second of reflected from the second mirror parallelto first mirror. The angle between the mirror is(b) 75(d) 120(a) 60(c) 90 |
|
Answer» b is the best answer |
|
| 7092. |
Calorific value of wood is 18000 kJ/kg. How much of wood isrequired to produce 240,000 kJ of heat energy? |
| Answer» | |
| 7093. |
What does it mean, heat produceis directly proportional tothe squake of luccent? |
|
Answer» It means heat is directly proportional to square of currentHeat(H) directly proportional to Current (I)^2 fine,does that mean if current is doubled It means that if more current is given,more heat is proved Sorry it is produced |
|
| 7094. |
Distinguish between speed andVelocity. |
| Answer» | |
| 7095. |
A former tokes round of a sopare hieldd side 45m in 6 minutes. Find o distanceand displacement cover after 90 second 180second, 220 second and 360 second |
|
Answer» 180.220 360 540 is the answer of the quation |
|
| 7096. |
Q18. Calorific value of wood is 1800 ku/kg. How much wood is required toproduce heat energy of 144,000KJ?Q19. A force of 150N is applied to an object of area 5m2 Calculate thepressure |
|
Answer» 19)pressure = force /area150N/530N/m thanks and second Required wood = 144000/1800=80kg |
|
| 7097. |
State the condition in. which a force does nowork. |
|
Answer» 1. When the force is conservative2. When the displacement is zero (S=0)W = F.S = 03. When the displacement is perpendicular to the direction of force (theta = 90)W = FS cos 90 = 0 |
|
| 7098. |
wheatstone bridge |
|
Answer» A Wheatstone bridge is an electrical circuit used to measure an unknown electrical resistance by balancing two legs of a bridge circuit, one leg of which includes the unknown component. The primary benefit of the circuit is its ability to provide extremely accurate measurements. |
|
| 7099. |
Q1)The dimensions of(μοεο)-D2 are(e)[LT1(d) LT |
| Answer» | |
| 7100. |
The resistance in the two arms oare 5Ω and RΩR if the meter bridgerespectively. When the resistances shunted with an equal resistance, the newbalance point is at 1.6 1. The resistance R is100-1110Ω(B)(B)15 Ω(A)(C)20 Ω25 Ω |
| Answer» | |