InterviewSolution
Saved Bookmarks
| 1. |
A super-ball is to bounce elastically back and forth between two rigid walls at a distance d from eachother. Neglecting gravity and assuming the velocity of super-ball to be vo horizontally, the average force(in large time interval) being exerted by the super-ball on one wall is16.1 mva(A)d2mv6(D) Amvamvo(C)O |
|
Answer» As the ball do back and forth motion,the distance covered by the ball is 2d So time taken=2d/v∆p=2mvAs F∆t=∆pF=2mv/2d/v As v go upper side and become v^2and 2 from both upper and lower side get cancelled out and we get-F=mv^2/d /jhggjfffhhhjjjjhhjikkooojhjjijjjjjjj |
|