InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 9451. |
lind he eauivaleot capacity belusyin tbe Collowingme2teuf |
|
Answer» this is another representation of wheat-stone-brige. type circuit... in which we can remove the middle 6μF capacitor. and the remaining 4 will make pair between them in parallel.. so, the parallel equivalent C = 6+6 = 12μF for both pairs now theses are connected in series..therfor Ceq = 12*12/(12+12) = 144/24 = 6μF |
|
| 9452. |
abtained? FI10 f a convex lens of focal length 20 cm.mcipal axa of the object from the lens is 30 cm. ByI object is placed perpendicular to theis of a c450 cm tallconalculation determine) the position anda the size of the image formed |
|
Answer» Given :height of object=h0=5cmfocal length of lens=10cmobject distance=-30cm after sign conventions.image distance=?By lens formula :1/f=1/v-1/u1/v=1/f+1/u=1/10-1/30=3-1/302/30v=30/2= 15cmmagnification=m=v/um=15/-30 =-1/2= -0.5cmm=hi/hohi=mxho=-0.5x 5= -2.5cmsThus object is placed beyond C and image formed is in between F and c.Inverted, real and diminished. |
|
| 9453. |
lone Which octor will have bigger(d) Calculate the effective resistance of the two resistors(c) Calculate the current that flows from the battery31.An and a 20 collare connected in parallel What is their combined resistance total current3 A passes through the colle What current passes through the 28 coll?Long Answer Type Questions32. With the help of etdir dil ettance of two resistances connected in(0) Two resistances are connected in series as shown in the diagram:What is the current throuch the schme ce?(1) What is the current through ?What is the value of R7(e) What is the value of VWith the help of a dia deve the formula for the resultanttande of three resistors connecte |
|
Answer» area of square=49 sq.cma=7 cmperimeter of square=4a =28 cm.perimeter of semi circle=perimeter of square =28 π *r = 28r=28*7/22r=8.91 your questions look is bad ok area of square=sq.cma=7cmperimeter of square |
|
| 9454. |
ay 170 32 resistors (in parallel) are tequn2+35after being switched on. Using the same mains supply.length of the heating element be increased or decreased if the water is to boiled in 10 minutes ? Why ?(b) Does Ohm's law bold good |
|
Answer» Let total heat supply to the water by kettle for boiling is HNow,Voltage in heater = V=220V ( In household circuit, each aplliance is linked in parallel combination and so, each appliance would have same voltage and it will be equal to the voltage of supply line = 220V)Let the respective resistance of 2 coils of heater be r' and r" respectively.Now, heat supply by both coil will be the same (because it has to boil the same water) = HNow, heat supplied = electric power × time = (V^2/R) × t = (V^2 × t)/RHeat by first coil = HVoltage = 220 VResistance = r'time = 15 min. = 15×60 = 900 sso, H = (220^2 × 900)/r' = (4.356 × 10^7)/r' ...(1)Again,Heat by 2nd coil = HVoltage = 220VResistance = r"time = 10 min. = 600 sso, H = (220^2 × 600)/r" = (2.904×10^7)/r" ...(2)From (1) and (2),(4.356 × 10^7)/r' = (2.904×10^7)/r"=》r'/r" = (4.356×10^7)/(2.904×10^7) = 3/2=》r'/r" = 3/2Now, if these coils must have same resistivity and thicknessso, r' = p × l'/AAnd, r" = p × l"/Aso, r'/r" = (p × l'/A )/(p × l"/A ) = l'/l"Now, r'/r" = l'/l" = 3/2so, l'/l" = 3/2=》l" = (2l')/3so, length of second coil is two-third of the length of first coil |
|
| 9455. |
the advantages and disadvantages of the reflection of sound in everyday life. |
|
Answer» Advantage:1.SONAR system is based on reflection of sound.2.Sonography is also based on reflection of sound.3.A musical instrument called as Jaltarang is also based on reflection of sound.Disadvantage:1. When sound get reflected for multiple times a phenomenon of reverberation is taken place.2.Because of this,reflected sound get mixed up and a continuous sound of large loudness and less clearness is produced. |
|
| 9456. |
2.Explain Some examples from our everyday life based on Newton's laws of motion. |
|
Answer» Take Tennis as example,Now, 1st Law : Every body continues its state of motion until and unless an external force acts on it, Example : Tennis ball continues its motion until another player strikes it ! 2nd Law : The acceleration is produced when there is a net Force change on the body, Actually the 2nd law is used to derive Force Formula, Example : The harder you hit, The more faster the ball travels, 3rd Law : For every action there is equal and opposite reaction, Example : If you hit a ball with racket, The ball also applies same momentum on the racket so we feel a small backwards push in our body, |
|
| 9457. |
Can the temperature of a system be increased without heating it? |
| Answer» | |
| 9458. |
1 Newton is equivalent to |
|
Answer» 1kg body accelrating at 1m/sec^2 |
|
| 9459. |
the voltage of 'AC'is increased without change in power which is the appropriate term for this process |
|
Answer» step up transformation options are (power transformer, power transmission, star connection, amplifier) |
|
| 9460. |
(3) 15 kWh(4) 20 kWh79.The energy consumed (in kWh) by four devices of 500 W each in 10 hours is(1) 4 kWh(2) 5 kWh(3) 10 kWh(4) 20 kWh |
|
Answer» please answer my more question tonight solve my questions |
|
| 9461. |
71.Find the work done by a force of F-7i+6kânewton displacing a body throughs=meter |
| Answer» | |
| 9462. |
If the unit of length is doubled, unit of timiehalved and unit of force is gtadrupteunit of power would change by the factor1) 1/4 2) 16 3) 1/16 4) 8 |
|
Answer» Option (2) is correct as:- |
|
| 9463. |
newton meter is the si unit of! |
|
Answer» Newton Meter is the SI unit of Torque. |
|
| 9464. |
The energy consumed (in kwh) by four devices of 500 W each in 10 hours is(a) 4 kwh(b) 5 kwh(c) 10 kwh(d) 20 kwh |
|
Answer» total energy = 500 × 4 × 10 = 20000wh = 20kwh thank you but also give my left questions answer |
|
| 9465. |
ol Convert an energy of one joule into ergs. |
| Answer» | |
| 9466. |
a) 3 unitsWhat is the energy in KWH consumed in 10 hours by four devices of power 05 KW each ?a) 20 KWHb) 5 KWHc) 40 KWHd) 10 KWH |
| Answer» | |
| 9467. |
Numericals1. Express 4 kWh in joule. |
|
Answer» another easy method |
|
| 9468. |
33. Ifa bulb of 60 W is lited for 4 hours everyday for30 days, then the energy consumed is:(a) 7.2 kwh (b) 7200 kwh (c) 720 kwh (d) 72 kwh |
|
Answer» Power (P1) = 60W time (t) = 4 hr Energy consumed in one day = P * t = 60*4 = 240 wh Therefore, energy consumed in 30 days = 30*240= 7200 wh= 7.2 kwh (a) is correct option |
|
| 9469. |
what is the meaning of symbol kwh? |
|
Answer» It means killo watt hourthanks kilo watt hour it is unit of energy for electricity paying (heat) |
|
| 9470. |
what does 1 Newton meant for? |
|
Answer» One newtonis equal to1kilogram meter per second squared. 1 newtonof force is the force required to accelerate an object with a mass of1kilogram,1meter per second per second. |
|
| 9471. |
46. Four cars A, B, C and D are moving on a levelled, straight road. Their distance-timegraphs are shown in the given figure. Which of the following is the correct statementregarding the motion of these cars ?(a) car A is faster than car D.(b) car B is the slowest(c) car D is faster than the car C(d) car C is the slowestDistance (m) |
| Answer» | |
| 9472. |
How many joule is 1 newton meter? |
|
Answer» TheNewton metersunit number 1.00N-mconverts to1J,one joule. It is the EQUAL energy value of1 joulebut in theNewton metersenergy unit alternative. |
|
| 9473. |
How many ergs are there in one joule ? |
|
Answer» Unit of energy is joule = kg*m²/s²Joule is a MKS unit and erg is a CGS unitMKS = CGS1 m = 100 cm1 s = 1 s1 kg = 1000 gmFrom above :1 joule = 1 kg*m²/s² = 1000 * 10000 / 1 cm*m²/s²= 10^7 gm*cm²/s² = 10^7 ergSo,Answer : 1 joule = 10^7 erg thanks bro u r so sexy 😍😍😍😍😙😙😘😘😚😚 |
|
| 9474. |
Define 1 kilowatt hour. |
| Answer» | |
| 9475. |
9. Define 1 Kilowatt hour. |
| Answer» | |
| 9476. |
(i) i kilowatt-hour (kWh) is equal to- |
|
Answer» 3.6 ×10^6 joule or 3600000 joule |
|
| 9477. |
1 newton into 1 dyne |
|
Answer» Dyne is that force which produces an acceleration of 1 cm/s² in a body of mass 1 g. ... So, 1 Newton= (1 kg) × (1 m/s²)= (1000 g)×(100 cm/s²)= 100000 ×(1 g)× (1 cm/s²)= 100000 dyne. 1N=10^5 dyne......... try it from guide by according your question 1N = 10^5 DynePlease like my answer 1N=10^5 dyne...,......... |
|
| 9478. |
1 N = 10 ^ { 5 } dyne |
|
Answer» 1 N force is the force which when applied on a 1 kg mass results to an acceleration of 1 m/s^2 in the body. 1 dyne force is the force which when applied on a 1 gram mass leads to an acceleration of 1 cm/s^2 in it. 1 kg = 1000 gram and 1 m = 100 cm => 1 N = 1(kg)(m/s^2) = (1000 gram)(100cm/s^2) = 10^5 dyne |
|
| 9479. |
NIJL Calculatedccelelalui UE wuuuy.12. A body covered 8 km along north direction, and then took a turn towards southdirection and covered again 8 km. Find distance and displacement of the body. |
|
Answer» distance - 16 kmdisplacement - 0 8 KM NORTH AND 8 KM SOUTH THEN DISPLACEMENT IS EQUAL TO 0 KM |
|
| 9480. |
The potential energy of a certain spring whenstretched through a distance s is 10 joule. Theamount of work (in joule) that must be done onthis spring to stetch it through additionaldistance s, will be:(1) 30J 240J (3) 10J (4)20 Jdlep a orizontal |
| Answer» | |
| 9481. |
relation between kilowatt hour and joule |
|
Answer» Realtion between kWh and Jouleis1 kilowatt hour= 3600000 joules From which book have you taken this question? Please tell us so that we can provide you faster answer. question answer |
|
| 9482. |
How many joule are csuivalent tollil |
| Answer» | |
| 9483. |
. Convert one dyne into newton. |
|
Answer» 1 dyne= 1 × 10^(-5) newtonthat is1 dyne is eqaul to 10 to the power -5 newton convert it by step by step so 1 dyne = 10^-5 newton |
|
| 9484. |
Convert 1 dyne into Newton. |
| Answer» | |
| 9485. |
PA man moves 4 m along east direction, then 3m along north direction, after that he climbs up a polea height 12m. Find the distance covered by him and his displacement. |
| Answer» | |
| 9486. |
how much force is applied on the body when 150 joule of work is done in displacing the body through adistance of 10 m in the direction of force. |
|
Answer» thanks bhya |
|
| 9487. |
The gravitational potential differencebetween the surface of a planet and point 20m above the surface is 2 J/kg. If thegravitational field is uniĂrm then the workdone in carrying a 5kg body to a height of4m above the surface is1) 2 Joule2) 20 Joule3) 40 Joule4) 10 Joule |
|
Answer» the answer is 2 joule |
|
| 9488. |
13. Work done in moving a 50 kg block through a horizontal distance of 10 m by applying a force of 100N whichmakes an angle of 60° with the horizontal is(A) 200 joule500 joule(B) 425 joule(D) 575 joulde |
|
Answer» option c |
|
| 9489. |
Tuberculosis is caused by it. |
|
Answer» bacteria |
|
| 9490. |
Tuberculosis is caused by it |
|
Answer» Bacteria |
|
| 9491. |
How much joule is 1 calorie? |
|
Answer» 1 kilocalorie= 4184 joules |
|
| 9492. |
Section AIf the diameter of the earth becomes twice its present values but its mass remains unchanged. then howwould be the weight of an object on the surface of the carth affected? |
|
Answer» we know that weight of an object = mg (Mass of the object x Acceleration due to gravity) now we know that accleration due to gravity (g) is given by: g= GM/(R^2) (Let this be the first equation) Where G is the gravitational constant M is the mass of the Planet R is the radius of the planet Now changing the first equation we get g= 4GM/(D^2) where D is the diameter of the planet (R=D/2) Now applying the conditions given in the question Df (final diameter) = 2D So g would be given as g(f)= 4GM/(4D^2) (here gf is the final accleration due to gravity) g(f)= GM/D^2 so comparing g(f) and g, we can clearly see that… g= 4 g(f) so g(f)= g/4 That is we can say that the wight of the object would be1/4 (one-fourth of its initial value). |
|
| 9493. |
Section AIf the diameter of the carth becomes twice its present values but its mass remains unchanged. then howwould be the weight of an object on the surface of the earth affected? |
|
Answer» g= GM/(R^2) (Let this be the first equation) Where G is the gravitational constant M is the mass of the Planet R is the radius of the planet Now changing the first equation we get g= 4GM/(D^2) where D is the diameter of the planet (R=D/2) Now applying the conditions given in the question Df (final diameter) = 2D So g would be given as g(f)= 4GM/(4D^2) (here gf is the final accleration due to gravity) g(f)= GM/D^2 so comparing g(f) and g, we can clearly see that… g= 4 g(f) so g(f)= g/4 That is we can say that the wight of the object would be1/4 (one-fourth of its initial value). |
|
| 9494. |
What is unification? |
|
Answer» Unification: it is the process of unifying the different physics laws valid for different phenomena in to a single theory and one theory that explains all the different.For example example—Maxwell unified electric, magnetic and optical phenomenon on when he explained that light is an electromagnetic wave. |
|
| 9495. |
Three rods A,B and C have the same dimensions. Their thermal conductivities are kA, ks and kerespectively. A and B are placed end to end, with their free ends kept at a certain temperaturedifference C isplaced separately, with its ends kept at the same temperature difference. The twoarrangement conduct heat at the same rate. kc must be equal to(A) k +kek+kc)a+(D)2K2 |
| Answer» | |
| 9496. |
59 (a) Identify the various elements of the circuit shown below:27(b) What does the bigger line of element 7 represent? |
|
Answer» 1) Voltmeter2) resistor 3) switch4) switch closed5) ammeter6) wire7) battery the bigger line represents positive terminal of the cell |
|
| 9497. |
The displacement of a particle after time t is given by x-(k/b2) (1 - eb), where b is a constant. What is theacceleration of the particle?(a) ke-bt(b) -kebtbt-bt(d) ,2 e2 |
| Answer» | |
| 9498. |
force is 15 kilo newton distance is 4kmwork done = ? |
|
Answer» work = force × distance= 15 × 4= 60J w=fx=15×4000=60000=60kj 6×10^7 J or 6×10^4 kj w=f×s= 15×4= 60J |
|
| 9499. |
2. Two masses m, and m, are connected by a masslessstring as shown in Fig. 5.55. Find the value oftension in the string if a force of 200 N is applied on[Ans. (i) 125 N (ii) 75 N]the(i) m and (ii) m2 |
|
Answer» thank you |
|
| 9500. |
Suggest any four ways to take care of the eyes. |
|
Answer» .washing eyes with cold water frequently.eating food rich in vitamins A such as carrots.not watching TV and electronic gadgets for too long.doing circular eye moments and exercise. |
|