1.

Section AIf the diameter of the earth becomes twice its present values but its mass remains unchanged. then howwould be the weight of an object on the surface of the carth affected?

Answer»

we know that weight of an object = mg (Mass of the object x Acceleration due to gravity)

now we know that accleration due to gravity (g) is given by:

g= GM/(R^2) (Let this be the first equation)

Where G is the gravitational constant

M is the mass of the Planet

R is the radius of the planet

Now changing the first equation we get

g= 4GM/(D^2)

where D is the diameter of the planet (R=D/2)

Now applying the conditions given in the question

Df (final diameter) = 2D

So g would be given as

g(f)= 4GM/(4D^2) (here gf is the final accleration due to gravity)

g(f)= GM/D^2

so comparing g(f) and g, we can clearly see that… g= 4 g(f)

so g(f)= g/4

That is we can say that the wight of the object would be1/4 (one-fourth of its initial value).


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