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Letn be the number of turns andR be the radius of the coil

ℓ=2πRn

R=ℓ/2πn

M=niA=iℓ^2/4πnHere, n=2;=>M=iℓ^2/8π

Option (2) is correct.

When the bar magnet is pushed intothe coilor withdrawn fromthe coilthere will be a deflection in the galvanometer. This is because of the induced current inthe coilwhich is generated due to the relative motion betweenthe coiland magnet.

(b) When the barmagnet is withdrawn from inside the coil, again an induced current is set­up in thecoil due to change of magnetic field through it. As a result galvanometer givesa deflection in the reverse direction. (say towards right).

(c) If the bar magnet is heldstationary inside the coil, then there is no induced current in the coil,because there is no change in magnetic field through it. Asa result,galvanometer doesnot show any deflection.

66)20V. [VB+5+15+5=VA]

Ya it's just opposite to potential energy I.e. 2M J

no the correct option is 1MJ

Sorry it's - 1/2 times P.E hence 1 M J is the correct answer.

Refer those formulas for reference.

option 2 Rahul will fall backwards. because when the bus starts accelerating in same direction., the body (of Rahul) will try to resist the motion and hence he will fall backwards.

there are three answers

also find the acceleration of the box with respect to ground

and find the contact force between the vertical Wall and box bill view

W (weight of the body) =?m (mass of the body) = 10 kgg (acceleration due to gravity) = 9.8 m/s2W= mg = 10 × 9.8 = 98 NAnswer : Weight = 98N

There is a basicdifference, becausemassis the actual amount of material containedin abody and is measured in kg, gm, etc.

Whereasweightis the force exerted by the gravity on that object mg. Note thatmassis independent of everything butweightis different on the earth, moon, etc

The acceleration due to gravity on the surface of the Moon is about 1.625 m/s2. So, an object the mass of 10 kg. will weigh 10 × 1.625 =16.25 N(newton) on the moon.

Theearthis not exactly asphere, it bulges at the equator, nor is its density uniform. In addition, its rotation causes the value of g to decrease slightly as one moves from the poles to the equator. However, all of these effects are less than 1% of the nominal value of 9.81 m/s2at theearth'ssurface.

thank you 😊

Radioactive substances are atoms that decay naturally. They can give off alpha particles, beta particles and gamma radiation.

They can give off alpha particles, beta particles and gamma radiation. Unlike X-ray sources they cannot be turned off, so their control is more difficult. Sources for industrial radiography such as iridium 192 are emitters of gamma radiation and they can be used to radiograph thick sections of steel and other metals. These, too, are used inside shielded enclosures, but since the sources cannot be turned off electrically, they are housed in shielded containers.

Froth flotationis a process for selectively separatinghydrophobicmaterials fromhydrophilic. This is used in mineral processing,paper recyclingand waste-water treatment industries. Historically this was first used in the mining industry, where it was one of the great enabling technologies of the 20th century. It has been described as "the single most important operation used for the recovery and upgrading ofsulfide ores.

option 3

Let the distance from the earth to the moon equals to D.

Convert the 57' min to Arc second

57 × 60 = 3420

Convert the arc second to radians :

1 s = 4.85 × 10⁻⁶ radians

3420 × 4.85 × `10⁻⁶ = 0.016587

Using the formulae :

D = R / Ф

Where R is the radius of the earth and Ф the arc able in radians.

Doing the substitution we have :

(6.4 × 10⁻⁶) / (0.016587) = 3.85 × 10^8

Ohm is unit for resistence

ans is 2.22m/s

Stakeholder is a person with an interest or concern in something, especially a business.

Thnx to both ji

By lens formula,1/f=1/v-1/u1/v=1/f+1/Uv=uf/u+ff=20cm,u=-30cmv=-30*20/-30+20v=-600/-10v=60cmm=v/um=60/-30m=-2v/u=hi/ho60/-30=hi/4hi=-8cm

Height of object, h₀ = 4cm object distance from lens , u = 30cm Focal length of lens , f = 20cm

Now, use formula, 1/v - 1/u = 1/f Here, u = -30cm, f = 20cm ∴ 1/v -1/-30 = 1/20 ⇒ 1/v = 1/-30 + 1/20 = (30 - 20)/20×30 = 1/60⇒1/v = 1/60 ⇒ v = 60cm now, we should use formula of magnification m = v/u = height of image/height of object Here , v = 60cm, u = -30cm, height of object = 4cm , so, 60cm/-30cm = height of image/4cm-2 = height of image/4 height of image = -8cm , here negative sign shows image is formed below of optical axis { horizontal line }

Now, size of image/size of object = 8cm/4cm = 2 { excluding sign }

Hence, height of image or size of image = 8cm image distance form lens = 60cm , right side and ratio of image size or object size is 2 {excluding sign }

ray diagram of image , its position , principal focus are shown in figure.Where h shown height of image e.g., 8cm , v is shown distance of image from lens e.g., 60cm .

For a lens, the lens formula is given as :

1/f = 1/v - 1/u

given, f = focal length = 12 cm

u = object distance = 10 cm

v = image distance = ?

hence,

1/12 = 1/v - 1/10

=> 1/v = 1/12 + 1/10

=> 1/v = 22/120

=> v = 120/22 = 5.45 cm

Hence the image will be formed at a distance of 5.45 cm.

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i) Virtual Image. Avirtual imageis a reproduction of an object via light that is formed where the light rays cross when projected back from their path beyond a lens or mirror. Avirtual imageonly exists within the brain of the observer, but is said to exist at the perceived point of intersection.

ii) The name of mirror is convex mirror.

iii) However, onlyvirtualimage formed by a spherical concave mirror is erect, and only if the object is placed closer to the mirror than its focal point.Basically, this is the same case as with convex lens, except the object must be placed in front of the mirror.

thanks