InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1751. |
227. The speed regulation of a dc motor is given as |
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| 1752. |
How much work is done by an electric motor to pump 150 kg of water to a height of 30 meters? Also to calculate the power of the motor if it completes this work in 0.5 minutes. (Given g- 10 m) |
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Answer» sorry mam/Sir. your answer is unfortunately wrong .my teacher had completed this question and his answer was different from your. it's correct answer according to my teacher is 1:1. |
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| 1753. |
. The speed of a dc shunt motor supplying a load at its rated speedcan be reduced by |
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Answer» The speed of a DC shunt motor supplying a load can be reduced byarmature circuit |
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| 1754. |
(a)(b)(c)State Fleming's left hand rule.Write the principle of working of an electric motor.Explain the function of the following parts of an electric moto(i) Armature (ii) Brushes (iii) Split ring |
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Answer» Fleming's left-hand rule is used for electric motors, while Fleming's right-hand rule is used for electric generators. ... In an electric motor, the electric current and magnetic field exist (which are the causes), and they lead to the force that creates the motion (which is the effect), and so the left hand rule is used. |
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| 1755. |
km/h, crossing the21. A police jeep is chasing a culprit going on a motoThe motorbike crosses a turning at a speed of 79The jeep follows it at a speed of 90 km/h, crossingturning ten seconds later than the bike. Assumingthey travel at constant speeds, how far from the turniwill the jeep catch up with the bike? |
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| 1756. |
( )Oth momentum and kinetic energy are conserved in al comA 1.0 H.P. motoheight of 10 m from the ground. The running time of the motor to fill the empty water(1)5 minutes6.r pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a(2) 10 minutes(3) 15 minutes(4) 20 minutesf 5 ko As a result of the |
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Answer» thank u |
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| 1757. |
100. Select from the following a group100.of electrical appliances in whichmagnets are used(1) Electric bell, electric iron,electric bulb(2) Electric generator, electricmotor, electric bel(3) Electric motor, electricgenerator, electric furnace(4) Electric generator, electric bell,electric heater |
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Answer» Option two (2) is correct as electric generator, electric motor and electric bell do use the magnets in the function. |
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| 1758. |
Electric fuse is based on theeffect of the electric current.n he sumhol of electric cell represents |
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Answer» electrical fuse is based on the joule effect of the electrical current |
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| 1759. |
80. The velocity of a projectile at the initial point A(2 i+3 j) m/s. Its velocity (in m/s) at point B is(a) 2i-3j(b) 2i+3j(c) 2i-3)(d) -2i+3 j(NEE |
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| 1760. |
Find the cross product of A&B if A 2i+3j+4kand B--2i +6j -5k |
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| 1761. |
what type of graph is represented by displacement distance graph? |
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Answer» transverse waves |
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| 1762. |
7. A stone is dropped into water from a bridge 44.1m above the water.Another stone is thrown vertically downward 1 second later. Bothstrike the water simultaneously the initial velocity of the secondstone is |
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Answer» Let ‘t’ be the time taken by both the stones to reach the water. For the stone that is dropped, using, S = ut + ½ at2 => 441 = 0 + ½ (9.8)t2 => t = 9.5 s Let the other stone be thrown at initial speed ‘u’. It reaches the water in (9.5 – 1 =) 8.5 s. Using, S = ut + ½ at2 => 441 = 8.5u + ½ (9.8)(8.52) => u = 10.2 m/s So, the second stone is thrown at 10.2m/s |
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| 1763. |
In the circuit shown in Fig, 22.3, the reading ofammeter A is604Ω3Ω2Ω2 V |
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Answer» The resistance 2,3, and 6 are in parallel to each other so, 1/Req = 1/6+1/3+1/2 1/Req = (1+2+3)/6 = 6/6 = 1Ω now this is in series with 4Ω , so they add up to give Req as 4+1 = 5Ω now current will V/R = 2/5 = 0.4A reading in the ammeter is = 0.4A |
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| 1764. |
a) Write principle of electric generator.b) Explain construction and working of generator.c) Draw labelled diagram of electric generator. |
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Answer» a)Electric generator works on the principle of electromagnetic induction. Electricity is generated by rotating a coil inside magnetic field. b)Construction Of A DC Machine: Note:A DC generator can be used as a DC motor without any constructional changes and vice versa is also possible. Thus, a DC generator or aDC motorcan be broadly termed as aDC machine. These basic constructional details are also valid for theconstruction of a DC motor. Hence, let's call this point asconstruction of a DC machineinstead of just 'construction of a dc generator'. . Basic constructional parts of a DC machine are described below. Yoke:The outer frame of a dc machine is called as yoke. It is made up of cast iron or steel. It not only provides mechanical strength to the whole assembly but also carries the magnetic flux produced by the field winding. Poles and pole shoes:Poles are joined to the yoke with the help of bolts or welding. They carry field winding and pole shoes are fastened to them. Pole shoes serve two purposes; (i) they support field coils and (ii) spread out the flux in air gap uniformly. Field winding:They are usually made of copper. Field coils are former wound and placed on each pole and are connected in series. They are wound in such a way that, when energized, they form alternate North and South poles Armature core:Armature core is the rotor of a dc machine. It is cylindrical in shape with slots to carry armature winding. The armature is built up of thin laminated circular steel disks for reducing eddy current losses. It may be provided with air ducts for the axial air flow for cooling purposes. Armature is keyed to the shaft. Armature winding:It is usually a former wound copper coil which rests in armature slots. The armature conductors are insulated from each other and also from the armature core. Armature winding can be wound by one of the two methods; lap winding or wave winding. Double layer lap or wave windings are generally used. A double layer winding means that each armature slot will carry two different coils. Commutator and brushes:Physical connection to the armature winding is made through a commutator-brush arrangement. The function of a commutator, in a dc generator, is to collect the current generated in armature conductors. Whereas, in case of a dc motor, commutator helps in providing current to the armature conductors. A commutator consists of a set of copper segments which are insulated from each other. The number of segments is equal to the number of armature coils. Each segment is connected to an armature coil and the commutator is keyed to the shaft. Brushes are usually made from carbon or graphite. They rest on commutator segments and slide on the segments when the commutator rotates keeping the physical contact to collect or supply the current. c) |
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| 1765. |
4. ELO UVO.U LILULILUI........... is used to measure electric resistance in a circuit.. Voltmeterb. Galvanometer c. Ammeterd. Ohm meter |
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Answer» ohm meter is used to measure resistance in a circuit. ohmmeter is used to calculate the resistance in a circuit ohm meter is correct answer voltmeter is used to measure electric resistance in a circuits option ( d ) is the right answer Ohm meter is used to measure electric resistance in a circuit. Ohm meter is used to measure electric resistance in a circuit ohm meter is correct option d is the correct answer of the given question ohm meter is the correct answer. d- ohm meter is used to measure electric resistance in a circuit ohm meter is used to measuring the electric resistance in a circuit. ohm meter is best answer |
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| 1766. |
. A moving coil galvanometer is converted into an ammeterreading upto 0.03 A by connecting a shunt of resistance4r across it and into an ammeter reading upto 0.06 A whena shunt of resistance r is connected across it. What is themaximum current which can be sent through thisgalvanometer if no shunt is used?(a) 0.03 A(c) 0.02 A(b) 0.04 A(d) 0.01 A |
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| 1767. |
An object of mass m and velocity u has kinetic energy 200 J. Find the new kinetic energithe mass of the object becomes double and velocity still remáins the same? |
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Answer» Let the k.e. in first case be xx = 1/2*m*v^2=200jin second caselet the kinetic energy be x'v'=vm'=2mx'= 1/2*2m*v^2x'= 2(1/2*m*v^2)x'=2(x)x'=2*200jx'=400j |
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| 1768. |
4) 0.5 FAn elastic wire is cut to half its original length. Themaximum load that the wire can support(1) is same(3) becomes four times (4) becomes half(2) becomes double |
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Answer» a elastic wire is not depending to its original length ,so 1is correct Option 1 is correct.Explanation:The maximum load supported by an elastic wire is independent of its length. Both the pieces will have same tension and the area of cross section remains same. Hence, the maximum stress which the pieces of wire will support remains the same. |
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| 1769. |
7. The gravitational force betweentwo objects is 49 N. How muchdistance between these objectsbe decreased so that the forcebetween them becomes double.123) 42r |
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Answer» F=GmM/R^2 F = 1/R^2 More the force less the distance. More the distance less theme forceThe radius must be decreased to root2 |
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| 1770. |
3. The gravitational force between two objects is 2 N. What will be the gravitational force between theseAns. 0-5 N]objects if the distance between them becomes double ?een these |
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Answer» Gravitational force between two objects is inversely proportional to square of the distance between the two objects. So,force becomes one fourth of original force.Hence, answer is 2/4=0.5N |
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| 1771. |
An object of mass m and velocity v has kinetic energy 200 J. Find the new kinetic energy ifthe mass of the object becomes double and velocity still remains the same. |
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Answer» Health is a state of complete physical, mental and social well-being and not merely the absence of disease or infirmity. |
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| 1772. |
Displacement, velocity and Acceleration1. A car accelerated from initial position and then returned at initial point, thentA) Velocity is zero but speed increases(C) Both speed and velocity increase(B) Speed is zero but velocity increases(D) Both speed and velocity decrease |
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Answer» option (A) is correct.As starting and ending point is same, the displacement is zero, therefore, velocity is zero. |
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| 1773. |
The period of moon around the earth is 27.3 daysand radius of the orbit is 3.9 × 10^5 km.\mathrm{G}=6.67 \times 10^{-11} \mathrm{Nm}^{-2} \mathrm{kg}^{-2} , find the mass of the earth. |
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Answer» T = 2π √r^3/GM 27.3 = 2 * 3.14 √(3.84 * 10^5)^3/6.67 * 10^-11 * M or 2.73 * 2.73 = 2 * 3.14 * (3.84 * 10^5)^3/6.67 * 10^-11 * M or M = 2 * (3.14)^2 * (3.84)^3 * 10^15/3.335 * 10^-11 (27.3)^2 = 6.02 * 10^24 kg ∴ mass of earth si found to be 6.02 * 10^24 kg. |
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| 1774. |
A solid sphere falls with a terminal velocity of 10 m/s in air. If it is allowed to fall in vacuum,(A) terminal velocity will be more than 10 m/s (B) terminal velocity will be less than 10 m/s(C) terminal velocity will be 10 m/s(D) there will be no terminal velocity |
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| 1775. |
The circumference of the Earth's orbit around the Sun is 940 million km. Approximately howkilometres does the Earth move in one day? |
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Answer» Earth orbitstheSunatanaverage distanceof149.60million km(92.96millionmi), andonecompleteorbittakes 365.256 days (1sidereal year), during which timeEarthhas traveled940 million km(584millionmi). |
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| 1776. |
Calculate the period of revolution of Neptunearound the sun if the diameter of its orbit is 30times that of the earth orbit around the sun. |
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| 1777. |
SECTION-B22. The current flowing through a resistor and the potential difference developed acrossends are shown in the given diagrams.mA100MA |
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Answer» Resistance = Voltage/current= 0.9/180ohmas pointer is showing theae values in voltmeter and in ammeter |
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| 1778. |
08. Torque developed in the rotor isdirectly proportional to slipinversely proportional to slipeither of thesenot dependent on the slip |
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Answer» option-Binverse to slipthanks In this mode of operation, supply is given to the stator sides and the motor always rotates below the synchronous speed. The induction motortorquevaries from zero to full loadtorqueas theslipvaries. Theslipvaries from zero to one. ... From the curve it is seen that thetorqueis Invertly proportional to theslip. option b inversely proportional to slip B. inversely proportional to slip |
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| 1779. |
3. A physical balance has its arms of length 60 cm and40 cm. What weight kept on the pan of longer armwill balance an object of weight 100 gf kept on theAns. 66-67 gfother pan? |
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Answer» For the pan to come in equilibrium... The anticlockwise moment of one force must be equal to clockwise moment of other force. Anticlockwise moment= F*length= x*60 Clockwise moment=F*len= 100*40=4000 At equilibrium, Anticlockwise moment=Clockwise moment60x = 4000x= 66.667 gf |
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| 1780. |
ol)Elertroreining ot metalsElee trodesthree uses of the phenomenon of electrolysiaefollowing questionsfor the followingid sodium chloride does not conduct electrigity wation conductsinot safe to carryout electrical repairs outdoors durinpoureasonsowg s heser, a few drops of sulphuric acdrryout electrolysis of wat |
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Answer» In thesolidstate, ionic compounds such assodium chloridehave their ions fixed in position and therefore these ions cannot move sosolidionic compounds cannotconduct electricity. However in the molten state, ions in ionic compounds are free to flow and therefore moltensodium chloridecanconduct electricity.. No. It is not safe to repair electrical appliances outdoors during heavy downpour. This is because rain water contains dissolved salts. Therefore, rain water can conduct electricity. The electrician may get electrical shocks while working outdoors during rain. |
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| 1781. |
what is the use of slip rings in ac generator |
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Answer» Aslip ringis an electromechanical device that allows the transmission of power and electrical signals from a stationary to a rotating structure. Aslip ringcan be used in any electromechanical system that requires rotation while transmitting power or signals. |
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| 1782. |
What is the function of slip rings and the armature in an electric generator |
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Answer» The Slip Rings function is to make one or more continuous electrical connections from points in a stationary unit to points in a rotating section. The armature has two functions. The first is to carry current crossing the field, thus creating shaft torque in a rotating machine or force in a linear machine. The second role is to generate an electromotive force (EMF). In the armature, an electromotive force is created by the relative motion of the armature and the field. |
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| 1783. |
a A curved section of a road is banked for a speed v. If there is no fniction between road and tyres of thecar, then(A) car is more ikely to slip at speeds higher than v than speeds lower than v(Bytar cannot remain in static equilibrium on the curved sectionC)car ill not slip when moving with speed v(D) none of the above |
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Answer» The answer is car will not slip when moving with speed v if you want to explain it then explain with reason and theoretical not optionally because I tick the right options |
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| 1784. |
y=\frac{\cos x}{1+\sin x} \text { find } \frac{d y}{d x}l+ sin xdx-11+sin x(D) 1-sin x(C)1+sin x1-sin x |
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Answer» so Option a is correct |
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| 1785. |
Motion of earth around sun is an example of .................. motion |
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Answer» motion of earth around sun is an example of circular motion circular motion is correct answer circular motion is the correct answer of the given question Motion of earth around sun is an example of circular motion motion of earth around sun is an example of circular motion uniform circular motion |
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| 1786. |
D. Short Answer Type-ll QuestionWhat is the role of fallopian tubes and testes? |
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Answer» Fallopian tubes are thefemalestructures that transport the ova from the ovary to the uterus each month In the presence of sperm n fertilization theuterine tubestransport the fertilized egg to the uterus for implantation & thetestesare contained in the scrotum and are composed of dense connective tissue containing around three hundred internal compartments called lobules |
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| 1787. |
20. Aflywheelisauniformdiscofmass/72kgandradius50 cm. When it is rotating at the rate of 70 rpm itskinetic energy is(a) 142J(c) 342 J(b) 242 J(d) 300 J |
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| 1788. |
300 J work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against friction is (Take g 10 m/s)(1) 1000 J(2) 200 J(3) 100J(4) zero |
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| 1789. |
23. Why does a satellite need no fuel to move round a planet in a fixed orbit? |
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Answer» You require the satellite to have fuel only for putting into the orbit of the planet around which it needs to revolve. Once the satellite is sent into the atmosphere at a sufficient height above the planet (which can be calculated using classical mechanics considering the gravitational field theory of newton) it is imparted a horizontal velocity because of which it is set into a circular motion. See, this component of velocity is very much required for the satellite to undergo a circular motion as then only the gravitational force acting on the satellite acts as a centripetal force which is essential for everybody to undergo a circular motion, and once it starts revolving in a circular motion , it doesnot require any fuel as then the required fuel(centripetal force) is provided to the satellite by the gravitational force. |
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| 1790. |
(Kepler's Laws)1. The ratio of kinetic energy of a planet at perigeeand apogee during its motion around the sun inelliptical orbit of eccentricity e is |
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Answer» We can consider eccentricity to be a general term represented by e. Apogee is the point in the elliptical orbit where the planet is farthest from the sun and perigee is the point where the planet is nearest to sun.In order to calculate the ratio of kinetic energy, we can use conservation of angular momentum. Now, we know that angular momentum is conserved for the planet throughout the orbit. Hence,Angular momentum at apogee = angular momentum at perigee Let rabe the distance at apogee and rpbe the distance at perigee. The value of r1andr2can be represented in terms of the semi major axis and eccentricity (e) as mentioned below. If a is the length of semi major axis, thenra= a(1+e)and,rp= a(1-e)Now, by conservation of angular momentum, if the mass of the planet is m and the velocity at apogee and perigee be vaand vprespectively.m vara= m vprp, orva/vp=rp/ra= (1-e)/(1+e) The ratio of kinetic energy is given by = (1/2mvp2)/(1/2mva2) = (vp/va)2=[(1+e)/(1-e)]2 |
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| 1791. |
A planet of mass m moves around the sun of massM in an elliptical orbit. The maximum and minimumdistances of the planet from the sun are r, and r2respectively. The time period of the planet isproportional to(1) r,32(2) r232(4) ( 2)32r- r(3) (,12)3/2 |
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Answer» Given the perihelion = r2 = shortest distance of a planet from Sun aphelion = r1 = longest distance of planet from Sun mass of planet = m. mass of Sun = M So the length of the major axis of the Elliptical orbit of the planet = r1 + r2. Semimajor axis = R = (r1 + r2)/2. According to Kepler's laws: The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet. T² ∞ R³ T∞R³/² T ∞ [r1 + r2] ³/² Answer. Actual value of the time period is given by: |
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| 1792. |
166. The earth revolves around the sun in an elliptical orbitwith mean radius 9.3 x 107 m in a period of 1 yearAssuming that there are no outside influences, then(a) The earth's potential energy remains constant(b) The earth's kinetic energy remains constants(c) The earth's angular momentum remains constant(d) The earth's linear momentum remain constant |
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Answer» option C the angular momentum of the earth is conserved ( taking the sun as the origin) because gravitational force is a central force ,hence it has the functional form f(r)r^ .by definition of torque, torque on earth = rr^ * f(r)r^=0.Thus angular momentum of Earth is conserved .hope that helps. |
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| 1793. |
Q62. A heavenly body (such as a comet) revolves in a highly elliptical orbit. Is it's angular momentumconstant over the entire orbit? |
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Answer» Yes, the angular momentum is constant over the entire elliptical orbit. When the radius becomes small, the velocity compensates and vice versa so the total angular momentum is conserved. L=mvr |
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| 1794. |
Il of water is whirled in a vertical circle at arms length. Find the minimumspeed at top to ensure that no water spills out. Also find corresponding angular speed.(Assume r- 0.75 m, g 9.8 m/s?) |
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Answer» A bucket containing water is whirled in a vertical circle at arms length.then, radius of vertical circle = arms length it is given that radius of vertical circle , r = 0.75 so, minimum speed v at the top to ensure that no water spills out is given by v=√grwhere g is acceleration due to gravity. so, v = √(9.8 × 0.75) = 2.711 m/s we know, w=v/r where is angular speed so, = 2.711/(0.75) =3.615 rad/s |
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| 1795. |
What is the work done by a field of nucleus in a complete circular orbit of the electron ? What ifthe orbit is elliptical ?NCERT |
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| 1796. |
In an AC generator, a coil with N turns,all of the same area A and total resistahceR, rotates with frequency Ď in a magneticfield B. The maximum value of emfgenerated in the coil i:s5. |
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Answer» In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates withfrequency ω in a magnetic field B. The maximum value of emf generated in the coil is NBAω |
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| 1797. |
(4) A bucket containing water is whirled in avertical circle at arms length. Find the minimumspeed at top to ensure that no water spills out.Also find corresponding angular speed.Assume r 0.75 m)Ans : 2.711 m/s, 3.615 rad/s) |
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Answer» given : r=0.75m , g=9.8m/s2 To find : vH, wH(angular speed) Formula : vH2=rg wH=vH/r Calculation: vH2=o.75 * 9.8 =2.711m/s wH=2.711/0.75 =3.615r ad/s Like my answer if you find it useful! |
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| 1798. |
30. The colour of light which travels with the minimum speed in glass is- a) yellow, b) red, c) violet, d) blue |
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Answer» For visible range,Violetcolour has maximum refractive index in glass so its speed will be minimum. |
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| 1799. |
A passenger is standing d meters away from a bus Thebus begins to move with constant acceleration a. Tocatch the bus, the passenger runs at a constant speedtowards the bus. What must be the minimum speed cfthe passenger so that he may catch the bus? |
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| 1800. |
A bucket tied at the end of a 1.6 m long stringis whirled in a verticle circle with constant speed.What should be the minimum speed so that thewater from the bucket does not spill when thebucket is at the highest position?Take g 10 ms2) |
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