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Il of water is whirled in a vertical circle at arms length. Find the minimumspeed at top to ensure that no water spills out. Also find corresponding angular speed.(Assume r- 0.75 m, g 9.8 m/s?) |
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Answer» A bucket containing water is whirled in a vertical circle at arms length.then, radius of vertical circle = arms length it is given that radius of vertical circle , r = 0.75 so, minimum speed v at the top to ensure that no water spills out is given by v=√grwhere g is acceleration due to gravity. so, v = √(9.8 × 0.75) = 2.711 m/s we know, w=v/r where is angular speed so, = 2.711/(0.75) =3.615 rad/s |
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