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7. A stone is dropped into water from a bridge 44.1m above the water.Another stone is thrown vertically downward 1 second later. Bothstrike the water simultaneously the initial velocity of the secondstone is |
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Answer» Let ‘t’ be the time taken by both the stones to reach the water. For the stone that is dropped, using, S = ut + ½ at2 => 441 = 0 + ½ (9.8)t2 => t = 9.5 s Let the other stone be thrown at initial speed ‘u’. It reaches the water in (9.5 – 1 =) 8.5 s. Using, S = ut + ½ at2 => 441 = 8.5u + ½ (9.8)(8.52) => u = 10.2 m/s So, the second stone is thrown at 10.2m/s |
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