1.

7. A stone is dropped into water from a bridge 44.1m above the water.Another stone is thrown vertically downward 1 second later. Bothstrike the water simultaneously the initial velocity of the secondstone is

Answer»

Let ‘t’ be the time taken by both the stones to reach the water.

For the stone that is dropped, using,

S = ut + ½ at2

=> 441 = 0 + ½ (9.8)t2

=> t = 9.5 s

Let the other stone be thrown at initial speed ‘u’. It reaches the water in (9.5 – 1 =) 8.5 s.

Using,

S = ut + ½ at2

=> 441 = 8.5u + ½ (9.8)(8.52)

=> u = 10.2 m/s

So, the second stone is thrown at 10.2m/s



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