InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2901. |
PRESSUREA force of 15N acts on an area of 50 cm2. What is the pressure in pascal.1)3000 Pa2)3500 Pa3)2000 Pa4)2500 Pa |
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| 2902. |
sampleased onDependence of Range10 In broad jumping does it matter how high youjump ? What factors determine the span of thejump?(1) Yes, u &(3) No, h & e(2) No, u & e(4) of these |
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Answer» It does not matter how high an athlete jumps in a long jump. The span of long jump depends upon the initial velocity and the angle at which an athlete jumps. The span of jump is maximum for an angle of 45°. Answer is wrong |
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| 2903. |
A train starting from stationary position and moving with uniform acceleration attains a speed of 30 km/hin 10 minutes. Find its acceleration? |
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| 2904. |
10. A train of 150 m length is going gowards north direction at a speed of 10 m s-1. A parrot flying at the speed of S, m s 1towards south direction parallel to the railway track. The time taken by the parrot to cross the train is equal toA) 15 sB) 12 s10 sD) 8 s |
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Answer» Since the parrot and the train are moving in the opposite direction therefore parrot's relative velocity will be 5m/s + 10 m/s =15m/s distance=speed*time so 150=15*t t=150/15 =10 sec |
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| 2905. |
5. An artificial satellite orbits in a circular path. Theheight of the satellite from the surface of earth is36,000 km. Such a satellite is called geo-stationarysatellite. When the satelite is exactly verticallyupwards the ground station, it sends a signal. Howmuch time will the signal take to reach the groundstation. The speed of signal is 3 x 10 ms-A bodytravels a distance of 10 km with a constantspeed of 30 kn h and then the next 40 kn at ant speed of 50 km h . Find the average speecd6.for the whole journey.arket at an average sneed, af |
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| 2906. |
1. Velu stood on the platform but he felt "as if he was still on a moving |
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| 2907. |
)Wharistheorderofratiooftheelectricandmagnetieforcesbetween two moving charges? |
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Answer» If the charge is undeflected, then the magnetic force equals the electric force: q*v*B =q*E B is the magnitude of the magnetic field E is the magnitude of the electric field v is the magnitude of the velocity of the particle. If the forces are equal then: v =E/B |
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| 2908. |
Illustration 22:A circular track of radius 20 m is banked for thevehicle of mass 200 kg going at a speed of 10 m/s.Find the direction and magnitude of frictionalforce acting on a vehicle if it moves with a speed(a) 5 m/s (b) 15 m/s. Assume that friction is sufficientto prevent slipping. (g - 10 m/s2). |
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Answer» m = 200 kg, R = 20 m, Angle of banking =ФSpeed = v =10 m/s. Let f be the friction force and N be the normal force from the ground. When the banking of road is done for speed v, it means that the normal force supplies the centripetal force. Friction plays no part. If the speed is either less or more than v, then it comes into play. Centripetal force =N sinФ = m v²/RAlso, N Cos Ф = mg=> TanФ = v²/gR = 10²/(10*20) = 1/2 cosФ = 2/√5 SinФ = 1/√5 N = mg SecФ = 200*10*√5/2 = 1000√5 Newtons When the vehicle is moving at 5 m/s less than the optimum speed,the centripetal force required is less. But the normal reaction force N is same.Hence, a friction force f acts upwards (towards outside of the curved road) the incline. So N CosФ + f sinФ = m g => N (CosΦ + μ sinΦ) = m g N sinФ - f cosФ = m u²/R => N (sinΦ -μ CosΦ) = m u²/R=> (CosФ +μ SinΦ) * u²/gR = (sinФ -μ CosΦ)=> μ [sinΦ *u²/gR + cosФ] = [ sinФ - CosФ * u²/gR ]=> μ = [sinΦ - cosΦ * u²/gR] / [sinФ * u²/gR + cosФ] => μ = [1/√5 - 2/√5 * 5²/(10*20)] / [1/√5 * 5²/(10*20) + 2/√5] = [ 3/(4√5) ] / [ 17/(8√5) ] = 6/17 Normal force N = mg/[CosΦ +μ SinΦ] = 200*10/ [2/√5 + 6/17 * 1/√5] = 850√5 NFriction force = f = μ N = 300√5 N upwards the slope. |
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| 2909. |
alla cay of mass 200 kg mating at 36 km Lhuis vuughtto rest atwy it couvred a distance os lo m findthe acceleration |
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Answer» answer will be exactly 64.8m/ s apna phone no de do btate h |
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| 2910. |
24.A 120 m long train is moving in a directionwith speed 20 m/s. A train B moving with30 m/s in the opposite direction and 130 mlong crosses the first train in a time. |
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Answer» The total length of two trains = 120 m + 130 m = 250 m The two trains will cover a distance of 250 m to totally cross each other. The speed of the two trains in this problem must be added together. VAB = VA + VB VAB = 20 m/s + 30 m/s = 50 m/s The total time = total distance / total speed The total time = 250 m / 50 m/s = 5.0 seconds The two trains will totally cross each other after 5.0 seconds. Like my answer if you find it useful! |
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| 2911. |
How long will a boy sitting near the windowof a train travelling at 36 km h 1 see a trainpassing by in the opposite direction withaspeed of 18 km h1. The length of the slow-moving train is 90 m. |
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| 2912. |
il ubjeel at infinity be?ight incident normally on a plane mirror attached to a galvanooil retraces backwards as shown in Fig. 9.36. A current in throduces a deflection of 3.5° of the mirror. What is the displacthe reflected spot of light on a screen placed 1.5 m away?1.5 m |
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Answer» Thank you |
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| 2913. |
An experimental socket sledge can be acceleratedto 1500 Kecht inat a constant date from restOne hind net force ef sledge has a mass of 200kg. |
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Answer» Given that of a rocket sledge,mass (m) = 300 kgInitial velocity (u) = 0Final velocity (v) = 1500 km/hTime taken (t) = 2.4 sForce (F) = ? Value of v in SI system is 1500 X5/18= 416.67 m/s F = ma = m(v-u)/t = 300(416.67-0)/2.4 = 52983.75 newton = 5.21 X 10^4 N (Ans) |
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| 2914. |
Q: An experimental socket sledge can bevaccelerated at a constant scate fromrest to 1500 km lhin 2.408 Eindnet force if sledge has a mass of300kgory |
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| 2915. |
1A string of mass 2.50 kg is under a tension of 200 N. The length of the stretchedstring is 20.0 m. If the transverse jerk is struck at one end of the string, how longdoes the disturbance take to reach the other end?ht 300 m high splashes into the |
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| 2916. |
2) Electric Tuse is baseu UIT3) The shorter line in the symbol of electric cell representsthn firit nersnn who noticed the magnetic effect |
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Answer» The shorter line in the symbol of electric cell represents negative terminal. |
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| 2917. |
Find the area of the seciul24. The radius of a circle is 17.5 cm. Find the area of the sectpr enclosed bytwo radii and an arc 44 cm in length. |
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Answer» Here arc length; Cs =44 cmRadius of a circle; r = 17.5 cmSo, area of sector = Cs/2πr×πr2 =44/2π×17.5×π×(17.5)(17.5)=22×17.5=385 cm sq. hit like if you find it useful C = 2 π x 17•5 cm = 109•9 cm109•9 cm ____360⁰44 cm_____[44/109•9 ] x 360⁰ = 144•1⁰Angle at centre of arc = 144•1⁰ Area of circle = π x 17•5² cm² = 962•1 cm² Area of sector = [ 144•1⁰ / 360⁰] x 962•1 cm²Area of sector = 385•1 cm² |
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| 2918. |
An experimental socket sledge can be acceleratedto 1500 Kecht inat a constant date from reston hind net force ef sledge has a mass of 200kg. |
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Answer» your question is not clearly.Please submit whole question.I can solve it,it us very easy. |
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| 2919. |
2. what is ohm's law ?write experimental and graphical verification of ohm's law ? |
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| 2920. |
2 Write Newton's Second Law. Derive an expression for force. |
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Answer» Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system.Force applied is directly proportional to the product of mass and acceleration . Newton's second lawof motion is F = ma, orforceis equal to mass times acceleration. Learn how to use theformulato calculate acceleration. Created by Sal Khan. newtons 2nd law states that.. the rate of change inomentum is directly proportional to the force applied on the system and the force applied is directly proportional to the product of acceleration and mass the second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system f=m×a is the law of Newton |
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| 2921. |
WriteNewton's law of gravitation (2 marks) |
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Answer» The Newton's law of gravitation states that every point mass attracts every other point mass by a force acting along the line intersecting the two points. The force is proportional to the product of the two masses, and inversely proportional to the square of the distance between them. The equation for universal gravitation thus takes the form: F = G m1m2/r^2 where F is the gravitational force acting between two objects, m1 and m2 are the masses of the objects, r is the distance between the centers of their masses, and G is the gravitational constant. thanks |
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| 2922. |
2. Write the law of conservation of energy and clarify it. |
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Answer» In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another. |
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| 2923. |
2.Write three laws of Kepler? State Newton's universal law of gravitation? |
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Answer» Kepler’s three laws of planetary motion can be stated as follows: (1) All planets move about the Sun in elliptical orbits, having the Sun as one of the foci. (2) A radius vector joining any planet to the Sun sweeps out equal areas in equal lengths of time. (3) The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the SunNewton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. |
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| 2924. |
11 т.2A train of 150 m length is going towards North ata speed of 10 m/s. A bird is flying at 5 m/s paralleto the track towards South. The time taken by thebird to cross the train is(1) 10 s(3) 30 S(2) 15 s(4) 12 s |
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Answer» Since the parrot and the train are moving in the opposite direction therefore parrot's relative velocity will be 5m/s + 10 m/s =15m/s distance=speed*time so 150=15*t t=150/15 =10 sec |
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| 2925. |
The Sun rises from the west and sets in the east on Venus. Do you agree with thisstatement? Why or why not? |
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Answer» Ans :- Sunrise fromWest setsinEastin case ofVenus.Venusspins in the opposite direction from most other planets, including Earth, so that onVenus the sun risesin thewest. Strong Atmospheric tides fromthe sunmade it Flip 180 degrees. Tidal effects of other planets also made it to spin opposite wrt to earth. |
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| 2926. |
A car is going towards north with a velocity 20 m/s.After some time it starts to go towards south withvelocity 20 m/s. Determine change in the velocity ofthe car.Ans. 40 m/s towards south. |
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| 2927. |
2. A car is going towards north with a velocity 20 m/s.After some time it starts to go towards south withvelocity 20 m/s. Determine change in the velocity ofthe carAns. 40 m/s towards south |
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Answer» let the initial velocity towards north be 20j so, the final velocity towards south be -20j then change in Velocity will be -20j-20j = -40j -ve sign is due to the fact that, direction is reversed to south from North.. and north is assumed to be +ve here. thanx i was ensuring this app that how it works |
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| 2928. |
can two balls of similar charge attract each other |
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Answer» 2)Yes,two ballshavingsamekind ofcharge can attract each other, if oneballpossesseschargequite large as compared to that onthe other ball.Thereason is that whentwo charged ballsare placed neareach other, they induce opposite kinds ofchargesonthefaces ofeach other. |
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| 2929. |
gravityattract? |
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Answer» Gravity is the force that attracts two bodies toward each other, the force that causes apples to fall toward the ground and the planets to orbit the sun. The more massive an object is, the stronger its gravitational pull. it is its naturalaty |
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| 2930. |
C. SHORT-ANSWER QUESTIONS (TYPE I): I. Why does a comb rubbed on hair attract pieces of paper? |
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Answer» Plastic comb gets electrically charged due to rubbing & therefore it attracts tiny pieces of paper. A charged body can attract anuncharged body. |
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| 2931. |
(C) an ellipseA ball is suspended by a thread of length L at the point O on a wall which is inclined to the vertical by α. Thethread with the ball is displaced by a small angle β away from the vertical and also away form the wall ftheball is released, the period ofoscil lation ofthe pendulum when β > α will beAIIMS 2009)(A) 11-1 π + 2 sin-1 αC)2sin--1 α |
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| 2932. |
different types for emploment |
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Answer» Types of employment Full-time and part-time employees. Casual employees. Fixed term and contract. Apprentices and trainees. Commission and piece rate employees. Like my answer if you find it useful! |
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| 2933. |
State different types of frictions |
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Answer» Different types of motion of the object gives rise to different types of friction.Generally there are 4 types of friction they are Static friction, Sliding friction, Rolling friction, Fluid friction. STATIC FRICTION Static friction exists between a stationary object and the surface on which it is resting.It prevents an object from moving against the surface. Examples: static friction prevents an object like a book falling from the desk even if the desk is slightly tilted, it helps us pick up an object without slipping through our fingers. When we want to move an object first we must overcome the static friction acting between the object and the surface on which the object is rest. SLIDING FRICTION Sliding friction occurs between objects as they slide against each other. When sliding friction is acting there must be another force existing to keep the body moving. ROLLING FRICTION Rolling friction is the resistive force that slows down the motion of a rolling ball or wheel. It is also called rolling resistance. When a force or torque is applied to a stationary wheel, there is a small static rolling friction force holding back the rolling motion. However, resistance from static sliding friction is what really causes the wheel to start rolling. Rolling friction hinders the motion of an object rolling on a surface, that means it slows down the motion of an object rolling on a surface. There are fourtypes of friction: static, sliding, rolling, and fluidfriction. |
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| 2934. |
explain the different types of frames |
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Answer» full framesrimmed frames and semi rimmed frames FrameStructures -Types of FrameStructures.Framestructures are the structures having the combination of beam, column and slab to resist the lateral and gravity loads. |
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| 2935. |
A piece of lead falls from a height of 100m ona fixed non-conducting slab which brings it torest. If the specific heat of lead is 30.6 Cal/kg °C, the increase in temperature of the leadimmediately after collision is |
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| 2936. |
2. The distance travelled by a particle starting from rest and moving with an acceleration ms2, inthethirdsecond is10(A)3 m(B)12m () 6 m(D) 4 mntl 8 The |
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| 2937. |
5.25 An operational amplifier is connected in voltagefollower configuration. Input given to this is3 sin 10 nt. Compute the slew rate of operationalamplifier(a) 60 x 103 V/usec (b) 31 x 10-3 V/usec(C) 1.51 x 10-3 V/usec (d) it x 10-3 V/usec |
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| 2938. |
Define hook's law of elasticity. Explain different types of modulus of elasticity. |
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Answer» Hooke's law,law of elasticitydiscovered by the English scientist RobertHookein 1660, which statesthat, for relatively small deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load. Depending upon the nature of force applied on the body, themodulus of the elasticity is classified in the following three types: 1. Young’s Modulus of Elasticity (Y) When a wire is acted upon by two equal and opposite forces in the direction of itslength, the length of the body is changed. The change in length per unit length (Δl/l) is called the longitudinal strain and the restoring force (which is equal to the applied force in equilibrium) per unit area of cross-section of wire is called the longitudinal stress. |
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| 2939. |
UName the different types of neutrinosthat exist in nature. |
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Answer» Three types of neutrinos are known.The table below lists the known types of neutrinos (and their electrically charged partners). Neutrino : ne nm ntCharged Partner : electron (e) Neutrino : nm Charged Partner : muon(m) Neutrino : ntCharged Partner : tau (t) |
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| 2940. |
14. An object of size 7.0 cm is placed at 27 cm in front of a concave minor of focallength 18 cm. At what distance from the mirror should a screen be placed, so thata sharp focused image can be obtained? Find the size and the nature of the Imagellha, tune of lane is this? |
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| 2941. |
. A convex mirror has a focal length of18 cm. The image of an object keptin front of the mirror is half the heightof the object. What is the distance ofthe object from the mirror?(Answer: 18 cm) |
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Answer» M = H2= -V/U = 1/2 = -V = U/2 V = -4/2 1/V + 1/U = 1/F 1/-U/2 + 1/U = 1/18-2/U + 1/U = 1/18-U/U = 1/18U = -18U = 18cm |
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| 2942. |
-2. A block hangs from a string wrapped on a disc of radius 20 cm free to rotate about its axis which iaISfixed in a horizontal position. If the angular speed of the disc is 10 rad/s at some instant, with whaspeed is the block going down at that instant ?(A) 4 m/s(B) 3 m/s(C) 2 m/s(D) 5 m/s |
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| 2943. |
a. A particle ia acted upon by a foree of conatant magnitudewhich is alwaya perpendieular to the veloeity of theparticle, The motion of the partiele takes place in aplane. It followa that(a) ita velocity is constant(b) ita acceleration ia conatant(o) ita kinetio energy ia conatanti it movea in a eireular path |
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| 2944. |
23, If the angle between two vectors A and B is 120o, itsresultant C will be(a) C IA-B(c) CHA-BI(b) C <IA-Bl(d) C=[A+BI |
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| 2945. |
9. If the universe of size = 10 m were to shrink!to the size of earth - 10 m, how large would |
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| 2946. |
Two stones A and B are dropped from the top of two different towers such that theytravel 44.1 m and 63.7 m in the last second of their motion respectively. Find the ratio ofthe heights of the two towers from where the stones were dropped |
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Answer» Distance covered in nth second = u + 1/2a(2t - 1 ) this will give the time in which the two stones reached the ground putting that value of 't' in distance = ut + 1/2 at^2 we will get the height of both the towers dividing both heights we will get the ratio which is your answer 25:49 |
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| 2947. |
what is adiabatic cooling |
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Answer» Adiabatic coolingis the process of reducing heat through a change in air pressure caused by volume expansion. In data centers and other facilities,adiabaticprocesses have enabled freecoolingmethods, which use freely available natural phenomena to regulate temperature. |
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| 2948. |
62. A man is at a height of 100 m. He sees a car which makes an angle ofrad with manposition. If the car moves to a point where angle israd, what is the distance moved by it100200150(B) 200、/3m(C)石·m(D)mm(A) |
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| 2949. |
() What is universe ? Name six different kinds of heavenly bodies found in the universe? |
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Answer» Theuniverseis the vast unimaginable space composing manyheavenly bodiessuch as, planets, stars, sun, constellations, comets, meteors etc. |
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| 2950. |
A car increase its speed from 20 km/hr to 50 km/min 10 seconds. Find itsacceleration. [Hint: convertkm/hr to m/s. v = u + at]. |
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