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301.

9.A particle is dropped from the top of a tower: Durting its motion coers a5 purt of heisht of tower inthe last 1 second Then find the height of tower

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302.

A ball is released from the top of a tower of height h metres. It takes T seconds to reach.the ground. What is the position of the ball in T/3 seconds?

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The acceleration of the ball will be g. Initial velocity will be 0.in T sec. body travels h mts. by applying equations of motion we gets= ut +1/2gT2

h = 1/2gT2 ------[1]

in T/3 sec h1 = 1/2gT2/9 -------[2]

from [1] and [2] we get h1 = h/9 distance from point of release.

therefore distance from ground is h-h/9 = 8h/9

303.

14. Two point-charges +9e and te are placed at a 2distance of 16 cm from each other. At what pointbetween these charges should a third charge q beplaced so that it remains in equilibrium?Ans. At a distance of 12 cm from the charge +9e.

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1st case

Given charges: +e and +9e

Let the third chare q be placed at a distance x from e and hence its distance from 9e is 16-x cm

For the system to remain in equilibrium,

F1 = F2

Therefore,

F1 = K(e q)/x2

F2 = K(9e)/(16-x)2

Equating F1 and F2 , we get,

9/x2= 1/(16-x)2

Taking square root on both sides:

3/x = 1/(16-x)

Solving for x, we get,

x = 12cm

hence the charge q should be placed at 12 cm from e.

2ndcase

See the figure below,

Now net force at q3 is 0 as given in the question. Hence,

Applying coloumb’s law on q3 we get,

q3q1K/(2x)2+ Kq2q3/x2= 0

q1/4 +q2 = 0

q1 = - q2/4

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304.

uohy we do Jct fearsdo 9e

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These are the tears produced in response to that strong emotion you may experience from stress, pleasure, anger, sadness and suffering to indeed, physical pain. Psychic tears even contain a natural painkiller, called leucine enkephalin – perhaps, part of the reason why you might feel better after a good cry

305.

०| 1.०दो बिन्द आवेश +9 तथा + एक दूसरे सेकी दूरी पर रखे हैं। दोनों आवेशों को मिलाने वालीरेखा पर एक अन्य विन्द आवेश "q" कहाँ पर रखें।कि वह संतुलित रहे?०।(A) +e आवेश से 6m की दूरी पर ।(B) +e आवेश से 2 m की दूरी पर ।(C) +9e आवेश से 2 m की दूरी पर(D) +e आवेश से 12 m की दूरी पर। *2.*धारिता C के चार समान संधारित्र चित्र के अनुसार।रखा गया है। A व B के बीच परिणामी संधारित्रहोगा :*|||ज

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Answer for question number 2 is c)5C/3

306.

a solid cube with 10cm edge of made of a material of density 7000 kg/m^3 answer the following question based on this information I) calculate the volume of cube in m^3

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Area of cube is l3 means l×l×l10×10×10=1000cm3=10m3volume=density/area=7000Kgm-3/10m3=7000kg/10=70

307.

A gas bubble from an explosion under water oscillates witha time period T, depends upon static pressure p, density ofwater p and the total energy of explosion E. Find theepression for the time period T. (where, k is a dimensionlessconstant)(a) T kp pl2E1/3(c) T kp2E2(d)T - kp"plEIA

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308.

7. The Kinetic energy of a body dependsupon

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Kinetic Energy of a Body is Directly Proportional to its Mass and Square of its Velocity

309.

Specific resistance of a wire depends upon(a) length(b) cross-sectional area(c) mass(d) of these.

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Answer: a) length, b) cross sectional areaExplanation: The resistance of a given piece of wire depends of three factors: the length of the wire, the cross-sectional area of the wire, and the resistivity of the material composing the wire.

310.

Specific resistance of a wire depends upon(a) length(b) cross-sectional area(c) mass(d) of these.I.

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Specific resistance depends on type of material.

d) of these

311.

In Young's double-slit interference experimentthe slit separation is made 3-fold. The fringe widthbecomes(a) 1/3 times(c) 3 times(b) 1/9 times(d) 9 times

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312.

A trolley is pushed along a road with a force of 400N through a distance of 60 m in 1 min. Calculate the power developed.

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Power = work /timeforce*displacement /time400*60/60second400joule/second

313.

A force f' accelerates a block of mass 'm' along astraight line to velocity 'v' from rest and displaceit through a distance 's'. What is the averagepower developed?

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314.

C CLEAR 14 MIN FINISHCorrect: +4/Incorrect:-1Q3.A force 'f' accelerates a block of mass 'm' along astraight line to velocity 'v' from rest and displaceit through a distance 's'. What is the averagepower developed ?

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315.

230. If the applied voltage to a de machine is 230V, then the back emf,for maximum power developed is

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We know that at maximum power Eₐ₌v/2= 230/2115 Volt

316.

waterfall on the Blades of turbine from a height of 50 M 100 kg of water force on a blade in one second asuam hole energy to be transferred what is the power developed to the turbine

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Work done = Force × Distance.

From the question :

Force = 100 × 10 = 1000N

Distance = 50m

Work done = 50 × 1000 = 50000Joules

Power = Work done /Time

The time = 1 second.

Power = 50000/1 = 50000 Watts

= 50kW

317.

It takeses 20 s for a person A of mass 50 kg to climup the stairs, while another person B of same massdoes the same in 15 s. Compare the (i) work done,and (ii) power developed by the persons A and B.

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318.

The length of second's hand in a watch is1 cm. The change in velocity of its tip in15 seconds is(A) Zero(B) 302cm / sec(C) 2 cm/ sec(D)π32cm / sec30

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319.

28.The seconds hand of a clock is 14 cm long. The average speed of the tip of theseconds hand in 15s iscm/s

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320.

0. Angular speed of seconds hand of a clock is in radian

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The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater. The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds, so ω = π/30 rad.s-1 =0.03 rad.s-1.

321.

The value of universal gravitational constant Gdepends upon.(1) nature of material of two bodies(2) medium between the two bodies(3) acceleration of two bodies

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none of the above A constant does not depend on anything, its a value. Its not a characteristic of a particular phenomena or define any process.

Its simply a value which is fixed anywhere and anypart of the universe. Just as mass of a body is fixed, be it on the earth or be it in the moon or be it in some other galaxy. Its fixed. But what changes is its weight in different situations, such as a body have different weight on earth and different on moon.

tnx

322.

0.0.UUUUUix)xiv)An object is falling freely under thegravitational force. Its velocity aftertravelling a distance his v. If v dependsupon gravitational acceleration g anddistance, prove with dimensionalanalysis that v=kgh where k is aconstant.

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◆ Answer -

v = k √(gh)

◆ Explaination -

For a object falling freely under gravity, let velocity be expressed as -

v = k.g^x.h^y

Substituting known dimensions of given quantities -

[v] = [g]^x [h]^y

[L1T-1] = [L1T-2]^x [L]^y

[L1T-1] = [L^(x+y) T^(-2x)]

Comparing indexes -

x + y = 1

-2x = -1

Solving these eqns,

x = 1/2

y = 1/2

Therefore, velocity of freely falling body would be -

v = k.g^½.h^½

v = k √(gh)

323.

2 Three forces given by vectors 21+2), 2-2) and-4i are acting together on aport dm¡w. T.object moves along the direction(1) x-axis(2) y-axis(3) z-axis(4) Object does not move

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324.

An object moves along a straight line with anexlaration of linss?. In the intial Speed 10 ms.What will be its Speed 5 second laten?

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V=u+atHere u=10m/sa=2m/s^2t=2sec

v=10+2×2=10+4=14m/s

325.

Three forces given by vectors 2i 2),2i -2) andai ars acding together on a int iech aobject moves along the dirsction(1) x axis(3) z-axit(2) y avis(4) Object does not move

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Adding the forces: (2i+2j) + (2i-2j)+ (-4i) = 4i-4i= 0hence ans should be d.

Dei loose it's wrng

326.

An object of mass 40 kg moving along a straightline with a horizontal velocity of 15 ms1collides and sticks to a stationary wooden blockof mass 10 kg. If the surface is smooth, theombined object (object and the wooden block)after collision moves along the same straightline with a velocity of:

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thank you Dear... Actually this question came in the KVS examination for PRT and answered wrongly

327.

2. When an object moves on a circular path withdecreasing angular velocity, its angularacceleration is directed ----(a) along the axis of rotation in downward direction.(b) along the axis of rotation in upward direction(c) along the radius towards the centre(d) none of thesehorizonta

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c is the correct option

c is the right answer

along the radius towards the centre

c is the right answer

Option (c) is right answer

328.

An object moves along a straight line path from P toQ under the action of a force (4i 3jIf the coordinates of P and Q, in metres, are(3, 3, - 1) and (2,- 1, 4) respectively, then the workdone by the force is17.3k) N(1) +23J(2) -23 J(3) 1015 J(4) 35 J

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Here the displacement vector is i(2-3)+j(-1-3)+(4+1)k = -i-4j+5k

F = 4i-3j+3k

and W= f.ds = (4i-3j+3k)•(-i-4j+5k) = -4+12+15= 23J.

329.

Two protons are brought together,how will thepotential energy of the system change?

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A repulsive force acts between protons, if they are brought nearer, work must be done by external force.

Hence the potential energy of system increases

330.

रेखा 5x + 4y = 10 का ढलान क्या है?1. 5/42. -4/53. -5/44. 4/5

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4/5. .

4/5 this is right answer

es ko y= MX+c k rup m liknh pr slope -5/4 hogi

the correct answer is-5/4

5/4 is the answer of the question

3. point is correct answer(-5/4)

slope of equation 5x+4y=10 will be -5/4

The correct answers is a - 5/4

correct answer is -5/4

5/4 is the answer may be

4/5 is the correct answer

the right answer is - 5/4

the right answer is -5/4

5×+4y=104y=10-5×y=10/4-5/4×y=mx+c m=-5/4

4y=10-5× ,y=10/4-5/4y=mx+cm=-5/4

-5/4 is the right answer

3) -5/4 is the correct answer

5/4 is the right ans

right answer is 3.-5/4

the answer is -5/4

-5/4 will be the final answer

-5/4 is the answer of this question

4/5 is the correct answer to the question

5/4 is the correct answer

331.

5. A constant force of 2:50 N accelerates a stationaryparticle of mass 15 g through a displacement of 2 50 m.Find the work done and the average power delivered.

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332.

10. Find the potential energy of an object of mass 15 kg situateat a height of 10m above the ground. Given g-10 m/s (

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333.

rikes a thick targetA bullet of mass 15 g has a speed of 400 m/s. What is its kinetic energy ? If the bulletand is brought to rest in 2 cm, calculate the average net force acting on the bullet. What happens to thekinetic energy originally in the bullet ?80

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334.

A clock hung on a wall has marks instead ofnumerals in its dial. On the adjoining wall,there is a plane mirror and the image of theclock in the mirror indicates the time 4.20.Then the time on the clock is

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the time in the click is 6.20.

trick 12 o'clock minus whatever time in real watch (11:60)-(4:20)=07:40

(12=11:60=11:59:60)

so 7:40 is answer

7.40 is the correct answer of the given question

7.40 is the correct solution of this question

335.

94. The pendulum of a certain clock has time period 2-04 s.How fast or slow does the clock run during 24 hours ?

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336.

5. The odometer of a car reads 57321.0 km when the clock shows the time08:30 AM. What is the distance moved by the car, if at 08:50 AM, theodometer reading has changed to 57336.0 km? Calculate the speed ofthe car in km/min during this time. Express the speed in km/h also.

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Distance traveled at 8:30 a.m -- 57321 kmFinal distance traveled at 8:50 a.m -- 57336 kmDistance traveled between 8:30 and 8:50 am -- 57336-57321=15 kmTime taken -- 20 mins( since 8:30 to 8:50 is 20 minutes)

So,speed of car in km per minute = 15/20 km per min.= 0.75 km per min.in km per hour= 15/20 X 60 = 45 kmph.

So the speed of car is 45kmph or 0.75 km per min if it covers 15km in 20 minutes.

337.

4. Two identical metallic spheres of exactly equal masses are taken. One is given a positivecharge g coulombs and other an equal negative charge. Are their masses equal after charging,?

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When two bodies are rubbed together, electrons get removed from one body and these electrons so removed get transferred to the other body. The body from which the electrons get removed becomes positively charged and the body to which the electrons get transferred becomes negatively charged. Since an electron is a material particle, the mass of the positively charged body decreases and that of the negatively charged body increases. Hence, when one of the two identical metallic spheres is charged positive and the other negative, their masses after charging will not be equal.The metallic sphere which gets negatively charged gains electrons and hence its mass increases. The metallic sphere which gets positively charged loses electrons and hence its mass decreases.

338.

) Two objects have masses 8 kg and 25 kg. Which one has more inertia? Why(AS

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25kg will have greater inertia Heavy objets have more inertia

25 kg has greater inertia.Inertia is directly proportional to mass.

339.

s of different masses (one lighter and other heavier) are thrown vertically upwat- with same initial speed. Which one will rise to greater height?

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They will rise to same height as according to equation of motion v²-u²=2as. The height (s)will depend upon v ,u & g(which is acceleration due to gravity)but it doesn't depends upon mass.

340.

os Two bodies of unequal masses have same linear momentum. Which one hasgreater kinetic energy

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Kinetic energy is related to linear momentum by

KE=momentum squared divided by twice the mass.

KE for a given momentum is inversely proportional to the mass.

So, the lighter mass has greater kinetic energy.

341.

Q11. Three point masses each of mass m is placed atcorners of equilateral triangle of side r, find force ofattraction on any one of them?

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342.

Two bodies of masses 5kg and 3kg are moving in same direction along same straight5m/s and 3m/s suffer one-dimensional elastic collision. Find their final velocities.

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343.

d) thè odjeel Iioapplication of the force remains fixed7. A particle of mass m is attached to a light string oflength l, the other end of which is fixed. Initially thestring is kept horizontal and the particle is given anupward velocity v. The particle is just able to completea circle(a) The string becomes slack when the particle reaches

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344.

FC5 N and FBH 45 NAheavy cart is pulled by a constant force F along a frictionless horizontal track with the help of a rope that passes over afixed pulley, as shown in the figure. Consider motion of the cart until it reaches vertically below the pulley.ldd cth, 29As the cart moves to the right, its acceleration(1) decreases.(2) increases.3) remains constant.(4) is zero30. A block is being pulled by a force Fon a lonafrictionlesrln

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345.

. If mass of a body is doubled, its acceleration will (ifthe applied force remains the same)a. become double.c. become half.b. not change.d. become four times

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346.

A block of mass 15 kg hangs from three chords as shownin figure (a). What are the tensions in the chords ?2847°Knot

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347.

EXAMPLESblock of mass 15 kg, is moving with a constant velocity of 4m/secthen calculate the force on the block.

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348.

matakes15minutesfromherhoušetoreächHerStlo01Uycle. If the bicycle has a speed of 2 m/s, calculate the distatweenher house and the school.

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349.

is school at an average speed of 12 km/hr. It takes him 20 minutes to reach the school.If he wants to reach his school in 15 minutes, what should be his average speedrtional to the sneed. A person

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350.

one out. Give scientific reason for your answerthe odd1. Potential energy, mass of object, height attained, speed of body, acceleration due to gravityV. Pick2. Kinetic energy, mass of the object, speed of the object, gravitational force

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1)speed of bodyas the other three are related by pe=mgh2)gravitational forceas the other three are realted by ke=1/2mv^2

thank you