

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
201. |
le balanceThe difference in compound interest and simple interest on a certain amount at 10% per annum at the end ofthe third year is 620. What is the principal amount? |
Answer» Sum =X×(100)^3 /r^2(300+r) =620(100)^3/10^2(300+10) =20000 |
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202. |
For an oscillating pendulum of fixed length, which ofthe following is true ?A. Frequency depends on amplitude of oscillation.B. Frequency and time period are not related.C. Time period depends on amplitude of oscillationD. Frequency and time period are related and do not19.depend on amplitude of oscillation. |
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203. |
EXERCISESA. Choose the most appropriate answer.1. For an oscillating pendulum of fixed length, which of the following is true?a. Frequency depends on amplitude of oscillation.b. Frequency and time period are not related.c. Time period depends on amplitude of oscillation.e period do not depend on amplitude of oscillation. |
Answer» a. Frequency depends on amplitude of oscillation. |
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204. |
The time period of simple pendulem is 2 second. Ifmass of pendulem is double then what timeperiod-(A) One less than(C) Two more than(B) 1 s(D) 2 s |
Answer» Even if it’s mass is doubled the time period will remain the same. As the increase in mass, the distance covered by the pendulum decreases.But the speed of the oscilating pendulum decreases resulting in no change in the time period.The answer is Option D. |
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205. |
If a proton enters perpendicularly a magnetic fieldwith velocity v, then time period of revolution is T.If proton enters with velocity 2v, then time periodwill be(2) 2 T(4) 4 T(3) 3 T |
Answer» In a circular motion under magnetic field, the centripetal force is provided by the magnetic force. (mv2)/r = qvB r = (mv)/(Bq) T = (2Πr)/v Putting r = (mv)/(Bq) T = (2Πm)/(Bq) Time period is independent of the velocity of charged particle. |
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206. |
Define time period of a satellite.*Obtain an expression for the period of asatellite in a circular orbit round the earth. |
Answer» Theperiodof a satellite is the time it takes it to make one full orbit around an object. The period of the Earth as it travels around the sun is one year. If you know the satellite’s speed and the radius at which it orbits, you can figure out its period. |
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207. |
A simple pendulum has time period T. The pointof suspension is now moved upward accordingthe relation y - kt. (K-1 mys) where y is thevertical displacement. The time period nowbecomes T. The ratio of1s: (g = 10 m/39 |
Answer» 1 answer is correct or not tell me 6/5 is correct answer 1 is the correct answer 1 is correct answer. |
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208. |
5) Find 'a if A-3i-2+ 4k and B- ai+2k areperpendicular to one another. (Ans : a 8/3) |
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209. |
31. The potential energy of water at a height isconverted into electricity in a(a) Thermal power plant(b) Nuclear power plant(c) Hydro power plant(d) Solar power plant |
Answer» Hydropower plants capture the energy of falling water to generate electricity. (c) is correct option hydro power plant |
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210. |
(4) MomentumA 5 kg mass is accelerated from rest to 60 m1 s. What force acts on it:(1) 5 × 60 N(2) (5/60) × 981 N(3) 602 x 52 N(4) (5/2) x 602x9811N |
Answer» acceleration will be 60-0/1=60m/sec^2and f=ma=5*60N |
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211. |
3 1:2af 25 N acts on a body at rest for 12s and a force of 7U N acts for the nest 01s in opposie3 08 kg2-14 2:1e final velocity of the body is 5ms', tse mass of the body is22kg04kgie |
Answer» let the mass be M. and initial velocity be 0 ,now acceleration for first 0.2sec is F1/M = 25/M so velocity after 0.2 is V = at = (25/M)*0.2 = 5/M now the acceleration changes to -70/Mand, Vfinal = -5m/s = 5/M -70/M(0.1) => -5 = 1/M*(5-7) => M = 2/5 kg = 0.4kg |
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212. |
The momentum of a body of mass 5 kg is 10 kA force of 2 N acts on the body in the directionmotion for 5 sec. The increase in the kinetic energy is(1) 15J(3) 20J(2) 30J(4) 40J |
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213. |
OR NINTH CLASS : PHYSICS45. A force of 20 N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is iacceleration ? (g = 9.8 m s-2).46. A stono |
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214. |
A fore F = (20 +3t2 j) N acts on an object moving in xy plane. Find magnitude of change inmomentum of the object in time interval t 0 to t 2 s.8 : |
Answer» Integrate the equation of force with respect to 't'.Here upper limit will be 2 and lower will be 0. Final answer will be 4i+8j |
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215. |
What would be the final temperature of a mixture of 50g of water at 20°Ctemperature and 50g of water at 40°C temperature. |
Answer» 50 gms water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.=====================final temperature of the mixture = = [ m1 * T1 + m2 * T2 ] / (m1 + m2) = [ 50 gms * 20⁰ C + 50 gms * 40⁰C ] / (50+50) = 3,000 / 100 = 30⁰C ====================another way using specific heats : let the final temperature be = T ⁰C Amount of heat given out by the hot water = m * s * (40⁰C - T) = 50 gms * s* (40 -T) Amount of heat taken in by the cold water = m * s * (T - 20⁰C) = 50 gms * s * (T - 20 ) As the amounts are equal, because the heat is transferred from hotwater to the cold water without any loss of heat to any surroundings, 50 * s * (40 -T) = 50 gm * s * (T-20) 40 - T = T - 20 2 T = 60 => T = 30⁰C============================= |
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216. |
What would be the final temperature of a mixture of 50g of water at 20 Ctemperature and 50gof water at 40°C temperature? (AS1)1.douc using the concept of evaporation? (AS1) |
Answer» 50 gms water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.=====================final temperature of the mixture = = [ m1 * T1 + m2 * T2 ] / (m1 + m2) = [ 50 gms * 20⁰ C + 50 gms * 40⁰C ] / (50+50) = 3,000 / 100 = 30⁰C ====================another way using specific heats : let the final temperature be = T ⁰C Amount of heat given out by the hot water = m * s * (40⁰C - T) = 50 gms * s* (40 -T) Amount of heat taken in by the cold water = m * s * (T - 20⁰C) = 50 gms * s * (T - 20 ) As the amounts are equal, because the heat is transferred from hotwater to the cold water without any loss of heat to any surroundings, 50 * s * (40 -T) = 50 gm * s * (T-20) 40 - T = T - 20 2 T = 60 => T = 30⁰C |
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217. |
46.At 27° C temperature, the kinetic energy of an ideal gasis E,. If the temperature is increased to 3270 C, thenkinetic energy would be(2) 5E2(4)E2 |
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218. |
27 28 29 30An objectes at temperatur 693 R. WednesdayAt what temperature would it radiateenergy twice Asfas. |
Answer» answer 643k-273=370 thek h.. answer 643 - 273=370 |
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219. |
1) h/42) h/23) h4) independent of hHalf life radio active element is 5 min. 10 sec. Time taken for 90% of it to disintegrateis nearly1) 100 min2) 1000 sec 3)104 4) 10 min4) 104 min |
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220. |
A car is being driven by a force of 2.5 x 1010reach a certain place. Calculate the work done.esaoyoigt a distance of I m in its own direction?N. Travelling at a constant speed of 5 m/s, it takes 2 minutes to43. |
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221. |
A metallic wire has a radius of 0.2 mm How much force is required to increase its length by 0.2%?CY 9.0x 1010 N/m213.(UPB 2014) Ans. 22.608 N2 |
Answer» To find :The force required to increase the length of the wire by 0.2%Given: r=0.2mm : Y=9.0*10^10 N/m^2Formula used:Young's modulus = tensile stress/ tensile strainY= Force per unit area / strainSolution:Y=(F/A)/(∆L/L) F=Y A (∆L/L) F=Y (πr^2)(∆ L/L) F=(9×10^10) ×3.14×(0.2×10^-3)^2 × ( 0.2/100)L/L F=22.608NAnswer:22.608 N |
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222. |
11. At any instant, the velocity and acceleration of aparticle moving along a straight line are v and aThe speed of the particle is increasing if> 0, a > 0(2) v < 0, a> 0(4) v>0, a = 0(3) v> 0, a< 0 |
Answer» Answer is a.acceleration must be positive for increase in speed. if acceleration is negative, it means the object is slowing down |
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223. |
A conductor of capacity 20 mF is charged to 1000V. The potential energy of the conductor wi(a) 20 x 104 J(c) 20 Ă 103 Jbe(b) 104 j(d) 10 |
Answer» Energy stored in a capacitor = cV²/2 Given Capacitance = 20 mF = 20 x 10^3 Voltage V = 1000 v Hence energy = cV²/2 = 20 x 10^-3 x 1000^2 / 2 = 10^4 J = 10 KJ Hence the energy stored in the conductor will be 10 kilojoules. (b) is correct option |
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224. |
5. A 50kg man with 20 kg load on his head climbs up 20 steps of 0.25 m height each. The work done by theman on the block during climbing is(A) 5 J(B) 350 J(C) 1000 J(D) 3540 J |
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225. |
A body constrained to move in Y direction, is subjected to a force given by, F (-2 i +15 j+6 k)N. The work done by this force in moving the body through a distance of 10 m along Y axis is(1) 190J(2) 160.J(3) 150 J(4) 20 J |
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226. |
5. A 50kg man with 20 kg load on his head climbs up 20 steps of 0.25 m height eache work done by theman on the block during climbing is(1)5J(2) 350 J(3) 1000 J(4) 3540 J |
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227. |
Describe the refrigeration and air conditioningsystem? Explaisin |
Answer» Refrigeration may be defined as the process of achieving and maintaining a temperature below that of the surroundings, the aim being to cool some product or space to the required temperature. Air conditioning is the process of altering the properties of air to more comfortable conditions, typically with the aim of distributing the conditioned air to an occupied space, such as a building or a vehicle, to improve the thermal comfort and indoor air quality |
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228. |
A person travelling on a scooter at 43.2 km/happlies the brakes, giving a deceleration of 6.0ms2 to his scooter. How far will it travel beforestopping?A body moving with uniform acceleration covers |
Answer» Solution : Initial velocity=u=43.2km/hr =43.2 x 5/18 =12 m/sfinal velocity =V=0m/s [ As brakes are applied]Acceleration=a= -6.0m/s2Distance =s=? Formula to be used : v²-u²=2as s= v²-u²/2as=0²-12²/2x-6S=12m Hence distance travelled before stopping is 12m |
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229. |
14. A train is running at a constant speed of 90 km/hon a sfraight track. A person standing at the top ofa boggey moves in the direction of motion of thetrain such that he covers 1 meters on the train eachsecond. The speed of the person with respect toground is(1) 25 m/s(3) 26 km/h(2) 91 km/th(4) 26 m/s |
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230. |
7-5km/h,sleptfor56min.andIn the hare-tortoise race, the hare ran for 2 min. at a speed ofagain ran for 2 min. at a-speed of 7-5 km/h. Find the average speed of the hare |
Answer» Avg speed = 7.5 + 7.5 / 2 it means = 7.5 km /h D1 = 7.5×2/60= 0.25km D2= 7.5×2/60= 0.25km Total Distance= 0.25+0.25=0.50km Total time taken = 2+2+56=60min= 1 HR Average speed =total distance/ total timeAverage speed= 0.50/1= 0.50 km/hr |
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231. |
What is the role of decomposers in the eco system? Draw adiagram showing flow of energy in an eco system. 1+29ĺš! |
Answer» Decomposersand scavengers break down dead plants and animals. They also break down the waste (poop) of other organisms. Decomposersare very important for anyecosystem. If they weren't in theecosystem, the plants would not get essential nutrients, and dead matter and waste would pile up. |
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232. |
Draw a labelled block diagram of communication system showing its various components |
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233. |
A ball of mass m moving with speed u collides witha smooth horizontal surface at angle θ with it asshown in figure. The magnitude of impulse impartedto surface by ball is [Coefficient of restitution ofcollision is el37.(1) mu(1+e)cosθ(3) mu(1-e)cosθ(2) mu(1 - e)sine(4)mu(1 + e)sinθ |
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234. |
Acopper wire 4m long has diameter of 1 mm, if a load of 10 kg.wt. is attached atother end. What extension is produced, if poisson's ratio is 0.26?How muchlateral compression is produced in it?(y 12.5x 100 N/m2) |
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235. |
(v) Briefly explain the classification of de machine. |
Answer» Each DC machine can act as a generator or a motor. Hence, thisclassification is valid for both:DC generatorsandDC motors. DC machines are usuallyclassified on the basis of their field excitation method 1)Separately excited DC machines:In separately excited dc machines, the field winding is supplied from a separate power source. That means the field winding is electrically separated from the armature circuit.Separately excited DC generatorsare not commonly used because they are relatively expensive due to the requirement of an additional power source or circuitry. They are used in laboratories for research work, for accuratespeed control of DC motorswith Ward-Leonard system and in few other applications where self-excited DC generators are unsatisfactory. In this type, the stator field flux may also be provided with the help of permanent magnets (such as inpermanent magnet DC motors). PMDC (permanant magnet DC) motors are popularly used in small toys, e.g. a toy car. 2)Self-excited DC machines:In this type, field winding andarmature windingare interconnected in various ways to achieve a wide range of performance characteristics (for example, field winding in series or parallel with the armature winding).In aself-excited type of DC generator, the field winding is energized by the current produced by themselves. A small amount of flux is always present in the poles due to the residual magnetism. So, initially, current induces in the armature conductors of a dc generator only due to the residual magnetism. The field flux gradually increases as the induced current starts flowing through the field winding. |
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236. |
Explain Vein's displacement Law and De-broglie waveleng |
Answer» Wien’s law, also called Wien’s displacement law, relationship between the temperature of a blackbody (an ideal substance that emits and absorbs all frequencies of light) and the wavelength at which it emits the most light. It is named after German physicist Wilhelm Wien, who received the Nobel Prize for Physics in 1911 for discovering the law. Wien studied the wavelength or frequency distribution of blackbody radiation in the 1890s. It was his idea to use as a good approximation for the ideal blackbody an oven with a small hole. Any radiation that enters the small hole is scattered and reflected from the inner walls of the oven so often that nearly all incoming radiation is absorbed and the chance of some of it finding its way out of the hole again can be made exceedingly small. The radiation coming out of this hole is then very close to the equilibrium blackbody electromagnetic radiation corresponding to the oven temperature. Wien found that the radiative energy dW per wavelength interval dλ has a maximum at a certain wavelength λm and that the maximum shifts to shorter wavelengths as the temperature T is increased. He found that the product λmT is an absolute constant: λmT = 0.2898 centimetre-degree Kelvin. De Broglie wavelength is a wavelength, which is manifested in all the particles in quantum mechanics, according to wave-particle duality, and it determines the probability density of finding the object at a given point of the configuration space. |
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237. |
Write De Broglie equation of matter wave and explain the terms. |
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238. |
26.a) Explain briefly with tforward bias & ii) reverse bias.es.elpara? eita aFW ă-lehrve"ăsofapnjunciondie de areobtained in. O |
Answer» APN Junction Diodeis one of the simplest semiconductor devices around, and which has the characteristic of passing current in only one direction only. However, unlike a resistor, a diode does not behave linearly with respect to the applied voltage as the diode has an exponential current-voltage (I-V) relationship and therefore we can not described its operation by simply using an equation such as Ohm’s law. If a suitable positive voltage (forward bias) is applied between the two ends of the PN junction, it can supply free electrons and holes with the extra energy they require to cross the junction as the width of the depletion layer around thePN junction is decreased. By applying a negative voltage (reverse bias) results in the free charges being pulled away from the junction resulting in the depletion layer width being increased. This has the effect of increasing or decreasing the effective resistance of the junction itself allowing or blocking current flow through the diode. |
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239. |
Q.A photon and electron have got same de-Broglie wavelength,has greater total energy? Explain. |
Answer» L= h/p= h / mv , de-Broglei wave length for the electron. L = h/ p = h/E/c= h/hf/c=c/f or E= hc/L for the photon So h/p =hc/E 1/p= c/E P=(2mKE)^1/2 for the electron. So pE= C or E= c/ (2mKE)^1/2 Like my answer if you find it useful! kya hua bolo kya hai ye |
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240. |
7410R-x100 = 10, ΔR = R × 100 = 50 ×100=,'" R = (50+5) 3101000Tar :ax100 =x100-1%,37:R=1000 3冊±1%[Hint:S-6L2, V=L3][FAT: 0.4%) |
Answer» Sorry, we are currently answering only for the questions posted in english! |
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241. |
kg 07. A rod of length L and mass M is acted on by twoalunequal forces F and F2 (< F1) as shown in fig. Thetension in the rod at a distance x from end B will be(b) 지 เ:/+F,(c) (月-5)(d) of these |
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242. |
. The pressure exerted by 50 kg (g 10 m/s2) onan area of cross section of 2 m2 is:(a) 50 Pa(c) 250 Pa(b) 200 Pa(d) 1000 Pa |
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243. |
The current in the given circuit is4.8V6Ω3Ω6Ω |
Answer» wrong answer |
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244. |
2.17 In the given circuit, the effective resistancebetween points A and C will beR.2RR. |
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245. |
q=\sqrt{2 r-t^{2}} \text { find } \frac{d q}{d r} |
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246. |
Why does my room get dark whenturn the lights off even if mywindow is shut? |
Answer» Light does not go away by leaking out through doors and windows. Light goes away by being quickly absorbed by materials and converted to heat and other forms of energy. In contrast to wind or smoke, light has no mass and is not composed of atoms. Because of this, light travels quickly in straight lines until it hits an object. It does not float around, billow with the wind, or leak out like a gas. All of the light from a light bulb is converted to heat and other forms of energy within microseconds. Public Domain Image, source: Christopher S. Baird.When light hits an object, part of the light gets absorbed, part of it is transmitted trough the object, and part of it is reflected/scattered. Exactly how much gets absorbed, transmitted, or reflected depends on the material, shape, and thickness of the object. Thick metal objects like cooking pots reflect most of the light that hits them, absorb a little of the light, and transmit almost none of the light. In contrast, clear glass transmits most of the light, reflects a little of the light, and absorbs almost none. Coal absorbs most the light that hits it, and reflects and transmits almost none. Understanding and predicting exactly how much light of a certain color that a certain object absorbs, transmits, and scatters involves a complex field of study that involves many different effects not worth examining here. However, we can summarize the basic principles behind absorption. |
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247. |
Explain total internal reflection |
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248. |
The optical fibre used in signal communication works onwhich principle?(A) Total Internal Reflection(B) ReflectionRefractionD) Dispersion |
Answer» A.Total Internal Reflection signal communication works which principle " Refraction" it works on refraction in optical fibre refracton is answer of question ok |
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249. |
what is total internal reflection |
Answer» the complete reflection of a light ray reaching an interface with a less dense medium when the angle of incidence exceeds the critical angle. it means the rays will come in the same medium???? |
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250. |
a particle is dropped from a height of the 20.40 metre. calculate the final velocity of particle and also, find total time taken |
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