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A person travelling on a scooter at 43.2 km/happlies the brakes, giving a deceleration of 6.0ms2 to his scooter. How far will it travel beforestopping?A body moving with uniform acceleration covers

Answer»

Solution :

Initial velocity=u=43.2km/hr =43.2 x 5/18 =12 m/sfinal velocity =V=0m/s [ As brakes are applied]Acceleration=a= -6.0m/s2Distance =s=?

Formula to be used : v²-u²=2as

s= v²-u²/2as=0²-12²/2x-6S=12m

Hence distance travelled before stopping is 12m



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