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Q.A photon and electron have got same de-Broglie wavelength,has greater total energy? Explain.

Answer»

L= h/p= h / mv , de-Broglei wave length for the electron.

L = h/ p = h/E/c= h/hf/c=c/f or E= hc/L for the photon

So h/p =hc/E

1/p= c/E

P=(2mKE)^1/2 for the electron.

So pE= C or E= c/ (2mKE)^1/2

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