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Q.A photon and electron have got same de-Broglie wavelength,has greater total energy? Explain. |
Answer» L= h/p= h / mv , de-Broglei wave length for the electron. L = h/ p = h/E/c= h/hf/c=c/f or E= hc/L for the photon So h/p =hc/E 1/p= c/E P=(2mKE)^1/2 for the electron. So pE= C or E= c/ (2mKE)^1/2 Like my answer if you find it useful! kya hua bolo kya hai ye |
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