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Option B

1 A= 10^-10 mso1.6* 10^-4 m= 1.6*10^-4+101.6*10^6

Thedimension of powerisenergydivided by time. The SI unit ofpoweris the watt (W), which is equal to one joule per second.

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Let the train must travel with a speed of x km

Average speed = Total distance travelled\Total time taken

40 = 60/ x + 1

x + 1 = 1.5

c = 0.5 hr

Speed for the next 30 km = 30 /0.5 = 60 km/h

Given that

vp= 30km/h

vq= 40km/h

Assume acceleration of the car is a.

PQ = s

Using,

v^2= u^2+ 2as

=> 402= 30^2+2as

=> 2as = 700

=> as = 350 ....................(1)

Now, assume velocity of car at a midpoint of PQ is v'.

Then v^'2= vp^2+ 2a(s/2)

=> v'^2= 900 + 350 = 1250

=> v' = 35.35 m/s.

answer is 3980 these is the correct answer comment me if you want full solution

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(1) Total time of journey = Distance /speed = 30/60 + 30/40 = 30(2 + 3)/120 = 30*5/120 = 1.25 hours

(2) Average speed of car = (60 + 40)/2 = 100/2 = 50 km/hr

Given:Distance d1=30kmspeed s1= 60km/hrtime= 30/60 = 1/2hr

distance d2=30kmspeed s2=40km/hrtime t2=30/40= 3/4hr

total time =t1+t2 =1/2+3/4=5/4hr

Initial velocity = 90km/h = 90×5/18 m/s = 25m/s final velocity = 18 km/h = 18× 5/18 m/s = 5 m/sacceleration = (final velocity -initial velocity )/ time taken =( 25 - 5)/4 = 5 m/s²now, change in momentum = m( final velocity - initial velocity ) =1200×( 25 - 5) = 24000 Kgm/s

force = change in momentum / time = 24000/4 = 6000 N

u=0 m / sv=15 m / st=5 sec. acceleration = Change in velocity / Time taken during change in velocity a = v - u / ta = 15 - 0 / 5a = 15 / 5a = 3 m / s 2

18km/hr in m/s =18*1000/3600=5m/s36km/h--36*1000/3600=10m/sacceleration=v-u/ta=10-5/5a=5/5=1m/s^2

Thanks my dear friend

Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (5*5)+(1/2*1*5*5) s=25+12.5 i.e., s=37.5 m

Given:

d = 110 m

t = 5.21 s

vi = 0 m/s

Find:

a = ??d = vi*t + 0.5*a*t2110 m = (0 m/s)*(5.21 s)+ 0.5*(a)*(5.21 s)2

110 m = (13.57 s2)*a

a = (110 m)/(13.57 s2)

a = 8.10 m/ s2

where are you comes from 3600

a)Newton's Second law:-The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

∴Acceleration=(v-u)/t=(36-18)km/h/5 secs=(10-5)/5=1 ms⁻²

b)So when thebusor train stopped suddenly, apassengersitting inside tends tofall forward. Because the lower part of the body comes to rest with thebuswhile the upper part tends to continue its motion due to inertia.

Given,Two bodies m1 and m2Let the velocity of 1st body be = v1Then its Kinetic energy = p²/2m1=(m1v1)²/2m2Let the velocity of 2nd body be = v2Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2Now, (m1v1)²/2m1 = (m2v2)²/2m2∴(m1v1)/(m2v2) =Then Ratio =√(2m2) :√(2m1)

this is maths.................

Present Population = Previous population* [(1+r/100)^n]=> 302500 = P*(11/10 * 11/10)=> P = (302500*100)/121=> Previous Population = 250000

but in the options its not there

1)Relative permittivityis the factor by which the electric field between the charges is decreasedrelativeto vacuum. Likewise,relative permittivityis the ratio of the capacitance of a capacitor using that material as adielectric, compared with a similar capacitor that has vacuum as itsdielectric.

2)In physics, the termdielectric strengthhas the followingmeanings: Of an insulating material, the maximum electric field that a pure material canwithstandunder ideal conditions without breaking down (i.e., without experiencing failure of its insulating properties)

thank you madam

Molecular mass of Sulphur (S8) = 32 x 8 = 256 g

Given mass = 50 g

No: of moles = Given mass / Molar mass= 50/256

No: of molecules = No: of moles x Avogadro no:= 50/256 x 6.022 x 10²³ molecules= 0.195 × 6.022 × 10^23= 1.17 × 10^23

Dielectric constant isrelative permittivity ,( K=er =e/eo).

Here, e and eo are permittivities of the medium and vacuum.

Also, K=C/Co, where C is capacitance in the presence of dielectric and Co is capacitance when there is vacuum( practically air) between two ' plates' of capacitor.

Thus, dielectric constant is ratio of same quantities it is dimensionless number.

Both b and c are ratios of the same physical quantity. Hence they are also dimensio less.

hence, option (A) is correct

Relative permittivityis the factor by which the electric field between the charges is decreasedrelativeto vacuum. Likewise,relative permittivityis the ratio of the capacitance of a capacitor using that material as a dielectric, compared with a similar capacitor that has vacuum as its dielectric.

Relative permittivityis the factor by which the electric field between the charges is decreasedrelativeto vacuum. Likewise,relative permittivityis the ratio of the capacitance of a capacitor using that material as a dielectric, compared with a similar capacitor that has vacuum as its dielectric.

0.5 m is focal lengths of lens