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two body's of masses of m1 m2 have equal kinetic energy which. body posses grater linear momentum m2 is grater then m1 |
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Answer» Given,Two bodies m1 and m2Let the velocity of 1st body be = v1Then its Kinetic energy = p²/2m1=(m1v1)²/2m2Let the velocity of 2nd body be = v2Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2Now, (m1v1)²/2m1 = (m2v2)²/2m2∴(m1v1)/(m2v2) =Then Ratio =√(2m2) :√(2m1) |
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