1.

two body's of masses of m1 m2 have equal kinetic energy which. body posses grater linear momentum m2 is grater then m1

Answer»

Given,Two bodies m1 and m2Let the velocity of 1st body be = v1Then its Kinetic energy = p²/2m1=(m1v1)²/2m2Let the velocity of 2nd body be = v2Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2Now, (m1v1)²/2m1 = (m2v2)²/2m2∴(m1v1)/(m2v2) =Then Ratio =√(2m2) :√(2m1)



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