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InterviewSolution
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A conductor of capacity 20 mF is charged to 1000V. The potential energy of the conductor wi(a) 20 x 104 J(c) 20 Ă 103 Jbe(b) 104 j(d) 10 |
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Answer» Energy stored in a capacitor = cV²/2 Given Capacitance = 20 mF = 20 x 10^3 Voltage V = 1000 v Hence energy = cV²/2 = 20 x 10^-3 x 1000^2 / 2 = 10^4 J = 10 KJ Hence the energy stored in the conductor will be 10 kilojoules. (b) is correct option |
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