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There are two Kirchoff's laws concerning electric networks in which steady currents are flowing. The first law states that the algebraic sum of the currents in all the conductors that meet in a point is zero. The second law states that the algebraic sum of the products of current and resistance in each part of any closed path in a network is equal to the algebraic sum of the electromotive forces in the path.

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Ohm's law. [ōmz] A law relating the voltage difference between two points, the electric current flowing between them, and the resistance of the path of the current. Mathematically, the law states that V = IR, where V is the voltage difference, I is the current in amperes, and R is the resistance in ohms

distance travelled in 10 sec s = ut -1/2gt² s = 98*10-(1/2)*9.8*(10)² = 980- 490 = 490m so , option A and B both are wrong. for option c , after 10 sec the body will be at its peak , and not at earth. this is also wrong.

option D is only correct. v = u-gt or, v = 98 -9.8*5sec v = 98-49 = 49m/s

No changes will be thereas applied voltage is not dependent on load current

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Option C

Not understood...... Aap steps jump kiye hai......

Plz cover all the steps...... Then it will be easy for me

Sorry.... Now understood 😊

sorry for late response..phir se krna h??? ya smjh aa gya??

As gya☺Thanks for solution

as given in question the answer will be option (1) 2 is correct.Take two vectors B and -B both have equal magnitude but opposite direction, further they will cancel out each other.

The rate of change of angular velocity is defined as angular acceleration. If particle has angular velocityω1at timt1, and angular velocity ω2at time t2, thenAngular acceleration α = ω2– ω1/ t2– t1

When the disc is rotated with constant angular velocity, angular acceleration of the disc is zero. Because we know that angular accelerationα = ∆ ω/∆ tHere ω is constant, so ∆ ω = 0

the refractive index of medium relative to lens would be 1

please post the clear image

ans is 10.2

The velocity with which the ball reaches the ground is given by root over to 2GH where H is the height from which the ball is dropped. this comes out to be 20 metre per second. Now, after it touches the ground it rebounds with 3/4th of its velocity on reaching the ground. this comes out to be 15 metre per second and by using V is equal to U +AT( take A as acceleration due to gravity 10m/s^2) where V is the final velocity U is the initial velocity and T time. As V is zero and U is 15 we get The as 1.5seconds

this is numerical not a theory

and also thanks

Component of vector A = 2i+3j along the vector = i+j

is = A•B/|B| and A•B= 2+3 = 5

and |B| = √1²+1² = √2

so , the component is = 5/√2

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CH4+ Cl2 = CH3Cl+HCl

C2H6+HNO3=C2H5NO2 + H2O

CH4+O2= CO2+H2O

d. CH2=CH-CH3 + H2

Here total resistance= 1*1/1+1= 1/2 and 2*2/2+2= 2 ohmnow

so voltage = 3.5

1. Thermometer cold Hot2. Watch Hour Minutes3. Weighing balance Kilogram gram4. Scale meter centimeter5. Digital Balance kilograms grams

the question is asking conditions for them

Neutralization is a chemical reaction in which acid and base react to form salt and water. Hydrogen (H+) ions and hydroxide (OH- ions) reacts with each other to form water.Example : HCL+ NaOH---NaCL + H2O and HNO3+KOH---KNO3+ H2O

The some of the uses/applications of UV(Ultraviolet) light include:tanning,fluorescent inspection,disinfection,hygiene control,water sanitization, etc.

ozone layer ..................

which is the hottest planet in the solar system

stratosphere or ozone layer

The value of G in this equation is approximately equal to 6.67 x 10-11newtonmeters squared perkilogramsquared (N x m2x kg-2). This constant is uniform throughout the Solar System, and apparently throughout our galaxy and other galaxies in its vicinity

Formula F = GMn/r²,

Value

G = 6.67 × 10^ (-11) Nm²/kg²

The value of the gravitational constant G is 6.67408x10^-11 m3⋅kg−1⋅s−2 where m3⋅kg−1⋅s−2 is the SI unit.

The formula is derived from the Newton's law of gravitation and the constant G is known as the Newton's gravitational constant. It states that gravitational force between two masses m1 and m2 is directly proportional to the product of the mass and inversely proportional yo the distance between them.

Acceleration due to gravity ,g is related to universal gravitational constant as;

g = GM/rwhere,r is the concerned location of the body under effect.

wt is meant by g

B) 6.46 x 10^5 m s^-1 is the answer

options b is the correct answer

option b is a correct answer

c) is the correct answer

We know,Force = mass * acceleration

Force on m1, F = m1*a1Force on m2, F = m2*a2

Then, m1*a1 = m2*a2

So, a1/a2 = m2/m1

According to Pascal's law, Pressure is transmitted equally and undiminished through out the fluid.P1=P2F1/A1=F2/A2F1= (A1/A2 ) F2=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)=1470N=1.5 x 10³ NThe air pressure that will produce this forceP=F1/A1=1.5x10³N/π(5x10⁻²)² m=1.9 x 10⁵ PaThis is almost the double of atmospheric pressure.

Coulomb's lawstates that: The magnitude of the electrostaticforceof attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. Theforceis along the straight line joining them.

In a tug of war, the team that pushes hardest against the ground wins. It is true that both teams have the same force on them due to the tension in the rope.But according to Newton’s third law ,the winning team pushes harder against the ground and thus the ground pushes harder on the winning team, making a net unbalanced force.

Convex lens is also called as converging lens as it can converge the refracted rays at one point on principal axis called Focus .

It's clear that child used spectacles having convex lens to burn paper as it focussed Sunrays at a point.

Conclusion:Child's father is suffer with hypermetropia where he can see far things clearly and finds difficulty in seeing near things Corrective measures used for eyedefect: Doctor suggest convex lens spectacles.

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