Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The sum of greatest 7-digit number and the smallest7-digit number dash |
| Answer» GREATEST 7 DIGIT NUMBER = 9999999Smallest 7 digit number = 10000009999999+1000000 = 10999999 | |
| 2. |
1. Write various property related to national number like1) commutative 2)associative |
|
Answer» /////////???????????????Step-by-step EXPLANATION: |
|
| 3. |
(-22) -[(-23)-(-17-(-61) ] |
|
Answer» Wrong Step-by-step EXPLANATION:DONT type anything RANDOMLY..Question is wrong...By VERIFYING theorem... |
|
| 4. |
P(x)=x3-6x2+11x-6,x=1,2,3 |
|
Answer» this Will HELP you |
|
| 5. |
Please send the answers fast |
|
Answer» -step EXPLANATION: let, the two no. be x and y a to q, x+y=11 .... (i). x-y=5. ...... (ii).from eqn 1&2we get 2x= 16 x= 8 and X+y= 11 = y = 3 I hope it will help you... PLEASE mark me as brainliest.... _ |
|
| 6. |
Who come after 10 cror |
|
Answer» after 10 crores 1 ARAB comes and EVEN it is usually said as 1 BILLION 1,00,00,00,000Step-by-step EXPLANATION:HOPE THIS HELPS YOU |
|
| 7. |
Find the value of a and b given that P is parallel to q and R is parallel to S |
| Answer» | |
| 8. |
If a/b=-2/3and c/d=+5/18then show that (a/b+c/d) =(c/d+a/b) |
|
Answer» -step explanation:The VALUE of a/b + c/d = -2/3 + 5/18[-2(6)+5]/18= (-12+5)/18= -7/18The value of c/d + a/b = 5/18 + (-2)/3= [5+(-2)(6)]/18= (5-12)/18= -7/18LHS=RHSHence proved.HOPE IT HELPSPLEASE MARK AS BRAINLIEST |
|
| 9. |
A school there are 40% girls if number of girls 200 find the total number of the students |
|
Answer» 500Step-by-step EXPLANATION:TOTAL number:200/40*100= 500 |
|
| 11. |
Subtract the difference of 43.8 75 and 53.9 from the sum of 29.3 58 and 2.3023 hey guys my answer is coming 21. 4953 but the correct answer is 21.6 353please help me guys in solving this step by step |
|
Answer» 21.6353Step-by-step explanation:53.9 - 43.875 = 10.02529.358 + 2.3023 = 31.6603now subtract 31.6603 - 10.025 = 21.6353do it LIKE this you will DEFINITELY GET the answer.HOPE IT HELPS AND IF IT HELPS THEN PLEASE MARK AS BRAINLIEST ANSWERSTAY HOME STAY SAFE |
|
| 12. |
How many possible outcomes are there for the following experiments? 1) tossing a coin ______2) throwing a die ______3) choosing a letter from the word EIGHT ______4) two 1 rupee coins are tossed _____5) Choosing a number from the first ten whole numbers _________6) choosing a colour from the colour of the rainbow ______ |
|
Answer» p sino - qcos ep sino + q coseis :If SEC 0 =then the VALUE of theqр+q?p² - 9²рp(D)2(A)(B)2terp²+q²р-92qq bsbsb |
|
| 13. |
a fruit seller bought 300 fruits. out of these 2/5 of the fruits were mangoes and the rest were apples. 2/15 of the apples were rotten. he sold the good apples at Rs 4 1/13 each. how much money did he receive on selling the good apples |
|
Answer» 492 rupeesStep-by-step explanation:2/5 of 300= 120300- 120= 180so there are 180 APPLES.2/15 of 180=24so there are 24 rotten apples.180-24 =GOOD apples=156price of good apples= 41/13 each41/13 * 156=492so ,he earned 492. |
|
| 14. |
I am two single - digitno. who am I my total is 8, my difference is 2 |
| Answer» ANSWER is 53Step-by-step EXPLANATION:MARK as BRAINLIEST PLSS | |
| 15. |
Under root 5 + under root 11 + under root 18 + under root 49 |
|
Answer» √18+√49√5+√11+3√2+72.23+3.31+3(1.41)+75.54+4.23+79.77+716.77 |
|
| 16. |
The length of the longer ladder is 37 ft and climbing on it, one can climb upto a height of 35 ft. The shorter ladder is 25 ft long and it reaches to a height of 24 ft. Find the distance between the foot of the two ladders? |
|
Answer» -step EXPLANATION:Answer:5ftStep-by-step explanation:The TWO ladder will form Right ANGLED triangle.Length of ladder will be the hypotenuse.Third side of Right angled triangle having sides 37ft and 35ft= √37² - 35²= √(37+35)(37-35) = √72*2=√144=12ftThird side of Right angled triangle having sides 25ft and 24ft=√25²-24²= √(25+24)(25-24) =√49*1 = √49 = 7ftDistance between foot of ladder = 12-7 =5FT |
|
| 17. |
Convert the following decimal into fraction 0.65, 0.7, 0.325 |
|
Answer» 0.65=65/1000.7=7/100.325=325/100030thx+FOLLOW=inbox ✌ follow me ❤ |
|
| 18. |
What should be added to -8/9 to get 2/5 |
|
Answer» 58/45Step-by-step EXPLANATION:PLS FOLLOW me and MARK me BRAINLIEST |
|
| 19. |
Write the additive inverse andshow that their sum is zero. give answer carefully |
| Answer» LET , the required no. be X then, it's additive INVERSE will be.. -x now, Their . SUM is.... x+(-x) = x-x=0 | |
| 20. |
152700375 fix in ones tens ect |
| Answer» HEY Jungkook07 here!!!Sorry I can't FOLLOW u..Please post clearly.Thank u for ur concern.Don't FORGET to follow me and I will follow you back. | |
| 21. |
I am two single - digit no. whoam I my total is 8 my difference is 2 |
|
Answer» -STEP explanation:let the NUMBER be 10x + y x + y = 8 + x - y = 2 2x = 10=) x = 5=) y = 3 there fore the number is 53 |
|
| 22. |
4. If A:B = 7: 9 and B: C= 6: 7. then A: Cis(a) 2:3(b) 3:2(c) 1:3(d) 2:7 |
| Answer» ANSWER is 1 but it is not in OPTION | |
| 23. |
9th class math plot two points A(-1,5) and B(-3,2) on the graph sheet. Plot reflections of A and B in y-axis and denote them D and C respectively. identify the figure ABCD. |
| Answer» ABCDIS a PARALLELOGRAM for that QUESTION | |
| 24. |
Represent the following rational numbers on a number line1/4 |
|
Answer» -STEP EXPLANATION:on TH NUMBER LINE of 1/4 =0.25 |
|
| 25. |
Using divisibility test check whether the following are divisible by 2,3,4,5,6,8,9,10 and 11Plz... answer fast... |
| Answer» GIVE the NUMBERS after that can ANSWER it... | |
| 26. |
Please tell ans fast rational number |
|
Answer» -STEP EXPLANATION:IF YOU LIKE IT, FOLLOW ME. |
|
| 27. |
G(x)=3x2-2,x=2/√3,-2√3 |
|
Answer» -STEP EXPLANATION:SORRY buttell the COMPLETE QUESTION |
|
| 28. |
AD is a median of triangle ABC Show that AB +BC+AC>2AD |
| Answer» PROVED that from triangle ABC where AD is MEDIAN, AB + BC + CA > 2AD. We will be using the property of triangle which says SUM OF TWO SIDES OF TRAINGLE IS ALWAYS GRATER THAN THIRD SIDE | |
| 29. |
Find the value of b |
| Answer» UE of b is 3PLEASE please MARK me as BRAINLIEST. | |
| 30. |
If a+b=5 and ab=16 find a square + b square |
|
Answer» -step EXPLANATION:HOPE this helps you...if so please MARK me as the BRAINIEST |
|
| 31. |
3. Find the missing values :-ZG-503|(x+50)ofduhan please send me answers. |
| Answer» FIND the missing values VERIFIED by 2x-1and verify the division algorithm to USE waste smart WATCH a film | |
| 32. |
In an election 10% of the votes on the voters ist did not cast their votes and 60 votes were rejected. There were only two candidates. The winner was supported by 47% of all voters in theand he got 308 votes more than his mal. Find out the number of votes in the list. Pls answer this qs with proper explaination wrong ones will be reported |
|
Answer» -step explanation:INDIA’s history is enriched by various monuments BUILT over centuries. These famous buildingsand STRUCTURES represent the CULTURE and heritage of a place and time in history. Over the yearsmany rulers of India would build these grand structures as a sign of progress and wealth.Between the 8th and the 18th centuries kings and their officers built many structures likeforts, palaces, tombs, temples, mosques, tanks, WELLS, bazaars etc.A new style of architecture developed during this period.So, taking into account these changes in architecture, prepare a Power Point presentation on,“If given an opportunity, which structure built between the period of 8th – 18th century wouldyou like to recreate and why”?Presentation should include:1. Introduction2. Development of architecture during 8th -18th century in India3. History of the structure you would like to recreate4. Your style of recreation5. Reasons for the same |
|
| 33. |
If X-10°and 190°-X an supplementary angles then find X |
|
Answer» -step EXPLANATION:TOTAL ans of the value XIS 100 |
|
| 34. |
Werite the additive inverse of 2/33 andshow that their sum is zero. |
| Answer» | |
| 35. |
nancy dii hmna uper term transfer ki hai to niche bi krni hoti hai term transfer ???? hmm na 2nd last equation kui change kiya 2nd last term bi nhi rah skti kya???? |
| Answer» KNOW the RIGHT ANSWER | |
| 36. |
Approximate answer for each of the following calculations also, find the actual sum 279+395 |
|
Answer» Full SiteNavigationEstimating a SumCustom SearchWe will learn the BASIC knowledge for estimating a sum. Here we will learn an easy way to estimate a sum of two numbers by rounding.In CASE of two digit numbers we can only round the NUMBER to the nearest tens place i.e. only one place estimate.For example, let us estimate the following sums:(i) 47 + 32We NEED to round the number to the nearest 10.47 → 5032 → 3050 + 30 = 80(ii) 25 + 34 We need to round the number to the nearest 10.25 → 3034 → 3030 + 30 = 60(iii) 75 + 13We need to round the number to the nearest 10.75 → 8013 → 1080 + 10 = 901. Estimate the sums of 72 and 48Solution:We round the number to the nearest 10.72 → 7048 → 50So, 72 is nearest to 70 and 48 is nearest to 5070 + 50 = 120Thus the estimated sum = 120 |
|
| 37. |
Give fast answer please please please please please |
|
Answer» vpgoflflflg lclvlfceh B lfnff s |
|
| 38. |
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming pool in 4 hours. How many hours will it take 4 large and 4 small pumps to fill the swimming pool.(We assume that all large pumps are similar and all small pumps are also similar.) |
|
Answer» Step-by-step explanation:Call the portion of the job that the large pump can do in 1 hour = 1/R where R is the total number of hours that it takes 1 large pump to complete the task Call the portion of the job that the small pump can do in 1 hour = 1 / r where r is the total number of hours that it takes 1 small pump to complete the task And Rate x TIME = Amt of the job done So...we have the following system 2*(1/R)*4 + 1*(1/r)*4 = 1 → 8/R + 4/r = 1 1*(1/R)*4 + 3*(1/r)*4 = 1 → 4/R + 12/r = 1 Multiply the SECOND equation by -2 and add it to the first -20/r = -1 → r/20 = 1 so r = 20 hours for one small pump to fill the pool And using 8/R + 4/r = 1 to solve for R, we have 8/R + 4/20 = 1 8/R + 1/5 = 1 8/R = 4/5 R/8 = 5/4 R = 40/4 = 10 hrs for one large pump to fill the pool So... for 4 large pumps and 4 small pumps working in UNISON, we have..... The 4 large pumps will fill 4/10 = 2/5 of the pool in one hour [each fills 1/10 of the pool in one hour] The 4 small pumps will fill 4/20 = 1/5 of the pool in one hour [each fills 1/20 of the pool in one hour] So...in one hour 2/5 + 1/5 = 3/5 of the pool is filled And...inverting this fraction gives us the total time = 5/3 hrs = 1 + 2/3 hrs = 1 hr 40 minPlease give me the Brainlest |
|
| 39. |
Verify commutative property of multiplication for following pairs of rational number -7/20 and 5/-14answer me fast |
|
Answer» -STEP EXPLANATION:IF YOU LIKE IT, FOLLOW ME. |
|
| 40. |
Pls answer this question correctly friends. I will mark u as braniliest |
|
Answer» this is algebraStep-by-step EXPLANATION: |
|
| 41. |
Convert 19/20 into decimal form |
|
Answer» 1.05263158pls FOLLOW and GIVE BRAINLIEST MARK |
|
| 42. |
SIMPLIFY 1. 2 2/3 OF 2 1/4+1/9*4 1/2-2 2/3÷ 8/9 ANEWER WITH SOLUTION IN DETAIL |
|
Answer» -STEP EXPLANATION:SORRY, this not my SUBJECT |
|
| 43. |
The fraction 17/34 in simplest form is _____. 9+2/10+6/100 is equal to the decimal number_____.3 hundredths + 3 tenths=______.4.55+9.73=______.12 added to 8 times p ______. |
| Answer» FRACTION Apple 1 hour 25 dusre ka 14 4th ka hai 16.5 AUR 5 ka 104 | |
| 44. |
Calculate the difference between the largest and the smallest perfect square having 6 digits. |
| Answer» HEY dude here is your answer999^2=998001(LARGEST six digit SQUARE)317^2=100489(smallest six digit square)Their difference=998001-100489 =897518 | |
| 45. |
Tan 35 tan 40tan 45 tan 5o tan 55. saw that this is for 15 points |
|
Answer» -step EXPLANATION:HOPE it will HELP you THANKS please mark as brainlist answer |
|
| 46. |
Is sign ko kya bolte hain |
|
Answer» I hope it is CORRECT answer FOLLOW me MARK as BRAINLIST answer |
|
| 47. |
Find the zeroes of the polynomial 2x-2+√3 |
|
Answer» -step explanation:ANSWERX = 2 + √3 and x = 2 - √3 are Zeros of P ( x )( x - 2 - √3 ) ( x - 2 + √3 ) ( using identity ( a - b ) ( a +b ) = a² - b²then,( x - 2 )² - ( √3 )²x² + 4 - 4x - 3x² + 1 - 4x .... ( i )When we DIVIDE p ( x ) by ( i ) we GET the other zeros Other zeros are :- x = 1 and x = -1/2 |
|
| 48. |
Find the value of square root243/squareroot867 |
| Answer» | |
| 49. |
Prove i) cosA/1+sinA + 1+sinA/cosA= secA ii)tan/1-cot + cot/1-tan = 1+ sec,cosec.... |
|
Answer» hєчα mαtєReplace tan A by SIN A/cos A and cot A by cos A/sin A. We getReplace tan A by sin A/cos A and cot A by cos A/sin A. We GET[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]REPLACE tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].Replace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)Replace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we getReplace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]Replace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]= (sin A – cos A)( sin^2 A + cos^2 A + sin A.cos A] / [sin A.cos A (sin A – cos A)]Replace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]= (sin A – cos A)( sin^2 A + cos^2 A + sin A.cos A] / [sin A.cos A (sin A – cos A)]= (sin A – cos A)( 1 + sin A.cos A] / [sin A.cos A (sin A – cos A)]Replace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]= (sin A – cos A)( sin^2 A + cos^2 A + sin A.cos A] / [sin A.cos A (sin A – cos A)]= (sin A – cos A)( 1 + sin A.cos A] / [sin A.cos A (sin A – cos A)]=( 1 + sin A.cos A] / sin A.cos AReplace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]= (sin A – cos A)( sin^2 A + cos^2 A + sin A.cos A] / [sin A.cos A (sin A – cos A)]= (sin A – cos A)( 1 + sin A.cos A] / [sin A.cos A (sin A – cos A)]=( 1 + sin A.cos A] / sin A.cos A= 1 + SEC A.cosec AReplace tan A by sin A/cos A and cot A by cos A/sin A. We get[sin A / cos A]/[1 – cos A/sin A] + [cos A/sin A]/[1 – sin A/cos A]Or sin A.sin A/[cos A(sin A – cosA)] + cos A.cos A/[sin A(cos A-sinA)].LCM of denominator is sin A.cos A (sin A – cos A)On simplifying we get(sin^3 A – cos^3 A)/ [sin A.cos A (sin A – cos A)]= (sin A – cos A)( sin^2 A + cos^2 A + sin A.cos A] / [sin A.cos A (sin A – cos A)]= (sin A – cos A)( 1 + sin A.cos A] / [sin A.cos A (sin A – cos A)]=( 1 + sin A.cos A] / sin A.cos A= 1 + sec A.cosec AProvedplz mαrk αѕ вrαnlíѕt |
|
| 50. |
a for the Republic Day celebration in a school student are going to perform Israel in the presence of chief guest they are standing 8 in a row how many student will stand in r row |
|
Answer» I am not UNDERSTANDING what is the QUESTION I am not understanding what is the question I am not understanding what is the question I am not understanding what is the question |
|