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the SQUARE ROOT of 2 is 1.41421356237

our QUESTION CORRECTLY... I can't UNDERSTAND.. sorry.. Step-by-step explanation:plzz FOLLOW me...

The SUM of the number = 95 If one = other+ 15 Find the numbers Step-by-step explanation:Let the 1ST number be n Then the 2nd = n+15 As given, n + (n+15) = 95 n + n + 15 = 95 2n = 95-15 2n = 80 n = 80/2 n = 40 1st number = n = 40 2nd number =(n+15) = (40+15) = 55 Thus the numbers are 40 and 55 which when added is 95........

so , RATIONAL no when NUM is 5 -5/3*-1/-1 I Ans 5/-3ii)35so ,for NUM 35 rational no be -5/3*-7/-7 35/-21ISI TARAH Kar lo AGE ke

1/2Step-by-step explanation: Hope it HELPS you Please like and FOLLOW Please mark as BRAINLIEST

Step-by-step explanation:LET the NUMERATOR be xdenominator = 2x-23 is added :-Numerator= x+3Denominator= 2x-2+3=2x+1x+3/2x+1=2/33(x+3)=2(2x+1)3x+9=4x+23x-4x=2-9-x=-7x=7Original Numerator = x = 7Original DENOMINATOR = 2x-2= 2×7-2= 14-2= 12Original Fraction = 7/12HOPE IT HELPS YOU

I HOPE this will HELP you in your HOMEWORK

It can 45,35 etc.PLEASE MARK IT AS A BRAINLEST ANSWER.I HOPE YOU WILL LIKE IT.THANKS GUYS

4+4-8+4-4 = 12-12 = 0hope it HELPS.....

x²*y²x=2,y=-12²*-1²4*1=4 is your ANSWER MARK as BRAINLIST answer PLZ plz

The EQUATION of x-axis is y = 0Step-by-step explanation:since, x-axis is a PARALLEL to itself at a distance 0 from it.

45Step-by-step EXPLANATION:

/4X=1/4*8/7X=2/7Check7/8*2/7=7/28or 1/4

this is how HISTOGRAM is MADE and data। is REPRESENTED

Radius of smaller CIRCLE = 7.5 Radius of bigger circle = 11.25Step-by-step explanation:CIRCUMFERENCE of bigger circle = 22.5π unitsSo,      2πr = 22.5π (circumference of a circle = 2πr)SOLVING above equation we get,      r = 11.25 unitsnow the RADII are in the ration 2:3So, smaller radius = 2/3 X 11.25solving this we get smaller radius = 7.5 UNITS

please please please mark me as BRAINLIEST and thanks if it helped you good day Step-by-step explanation:3.1 Class 8 Maths Question 1. Q1.1Classify each of the above figure on the basis of the following:(a) Simple curve(b) Simple closed curve(c) Polygon(d) Convex polygon(E) Concave polygonSolution:(a) Simple curve: (1), (2), (5), (6) and (7)(b) Simple closed curve: (1), (2), (5), (6) and (7)(c) Polygon: (1) and (2)(d) Convex polygon: (2)(e) Concave polygon: (1)Ex 3.1 Class 8 Maths Question 2.How many diagonals does each of the following have?(a) A convex quadrilateral(b) A regular hexagon(c) A triangleSolution:(a) In Fig. (i) ABCD is a convex quadrilateral which has two diagonals AC and BD.NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Q2(b) In Fig. (ii) ABCDEF is a regular hexagon which has nine diagonals AE, AD, AC, BF, BE, BD, CF, CE and DF.Q2.1(c) In Fig. (iii) ABC is a triangle which has no diagonal. Q2.2Ex 3.1 Class 8 Maths Question 3.What is the sum of the measures of the angles of a convex quadrilateral? Will this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and verify)Solution:In the given figure, we have a quadrilateral ABCD. Join AC diagonal which divides the quadrilateral into two triangles ABC and ADC.Q3In ∆ABC, ∠3 + ∠4 + ∠6 = 180°…(i) (ANGLE sum property)In ∆ADC, ∠1 + ∠2 + ∠5 = 180° …(ii) (angle sum property)Adding, (i) and (ii)∠1 + ∠3 + ∠2 + ∠4 + ∠5 + ∠6 = 180° + 180°⇒ ∠A + ∠C + ∠D + ∠B = 360°Hence, the sum of all the angles of a convex quadrilateral = 360°.Let us draw a non-convex quadrilateral.Yes, this property also holds true for a non-convex quadrilateral. Q3.1Ex 3.1 Class 8 Maths Question 4.Examine the table. (Each figure is divided into triangles and the sum of the angles reduced from that).Q4What can you say about the angle sum of a convex polygon with number of sides?(a) 7(b) 8(c) 10(d) nSolution:From the above table, we conclude that the sum of all the angles of a polygon of side ‘n’= (n – 2) × 180°(a) Number of sides = 7Angles sum = (7 – 2) × 180° = 5 × 180° = 900°(b) Number of sides = 8Angle sum = (8 – 2) × 180° = 6 × 180° = 1080°(c) Number of sides = 10 Angle sum = (10 – 2) × 180° = 8 × 180° = 1440°(d) Number of sides = nAngle sum = (n – 2) × 180°Ex 3.1 Class 8 Maths Question 5.What is a regular polygon? State the name of a regular polygon of(i) 3 sides(ii) 4 sides(iii) 6 sidesSolution:A polygon with equal sides and equal angles is called a regular polygon.(i) Equilateral triangle Q5.1(iii) Regular HexagonNCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Q5.2Ex 3.1 Class 8 Maths Question 6.Find the angle measure x in the following figures:Q6Solution:(a) Angle sum of a quadrilateral = 360°⇒ 50° + 130° + 120° + x = 360°⇒ 300° + x = 360°⇒ x = 360° – 300° = 60°(b) Angle sum of a quadrilateral = 360°⇒ x + 70° + 60° + 90° = 360° [∵ 180° – 90° = 90°]⇒ x + 220° = 360°⇒ x = 360° – 220° = 140°(c) Angle sum of a pentagon = 540°⇒ 30° + x + 110° + 120° + x = 540° [∵ 180° – 70° = 110°; 180° – 60° = 120°]⇒ 2x + 260° = 540°⇒ 2x = 540° – 260°⇒ 2x = 280°⇒ x = 140°(d) Angle sum of a regular pentagon = 540°⇒ x + x + x + x + x = 540° [All angles of a regular pentagon are equal]⇒ 5x = 540°⇒ x = 108°Ex 3.1 Question 7.(a) Find x + y + zQ7(b) Find x + y + z + wQ7.1Solution:(a) ∠a + 30° + 90° = 180° [Angle sum property]⇒ ∠a + 120° = 180°Q7.2⇒ ∠a = 180° – 120° = 60°Now, y = 180° – a (Linear pair)⇒ y = 180° – 60°⇒ y = 120°and, z + 30° = 180° [Linear pair]⇒ z = 180° – 30° = 150°also, x + 90° = 180° [Linear pair]⇒ x = 180° – 90° = 90°Thus x + y + z = 90° + 120° + 150° = 360°(b) ∠r + 120° + 80° + 60° = 360° [Angle sum property of a quadrilateral ]Q7.3∠r + 260° = 360°∠r = 360° – 260° = 100°Now x + 120° = 180° (Linear pair)x = 180° – 120° = 60°y + 80° = 180° (Linear pair)⇒ y = 180° – 80° = 100°z + 60° = 180° (Linear pair)⇒ z = 180° – 60° = 120°w = 180° – ∠r = 180° – 100° = 80° (Linear pair)x + y + z + w = 60° + 100° + 120° + 80° = 360°.

99999 DOUBTS the ANSWER is YES

bStep-by-step EXPLANATION:

{130-46})63-25+84147-25122 not EQUAL 531

2.22222....Step-by-step EXPLANATION:

Step-by-step explanation:i)  (i) Two equilateral triangles with sides 1 cm and 2 cm Two squares with sides 1 cm and 2 cm (ii) Trapezium and square Triangle and PARALLELOGRAM Video Solution Question 3: State whether the following quadrilaterals are similar or not: Answer: Quadrilateral PQRS and ABCD are not similar as their corresponding sides are proportional, i.e. 1:2, but their corresponding angles are not EQUAL. Video Solution Page No 128: Question 1: In figure.6.17. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii). (i) (ii) Answer: (i) Let EC = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain (ii) Let AD = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain Video Solution Question 2: E and F are POINTS on the sides PQ and PR respectively of a ΔPQR. For each of the following CASES, state whether EF || QR. (i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm (iii)PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm Answer: (i) Given that, PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm, FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm, RF = 9 cm (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm Video Solution Question 3: In the following figure, if LM || CB and LN || CD, prove that Answer: In the given figure, LM || CB By using basic proportionality theorem, we obtain Video Solution (i) Two equilateral triangles with sides 1 cm and 2 cm Two squares with sides 1 cm and 2 cm (ii) Trapezium and square Triangle and parallelogram Video Solution Question 3: State whether the following quadrilaterals are similar or not: Answer: Quadrilateral PQRS and ABCD are not similar as their corresponding sides are proportional, i.e. 1:2, but their corresponding angles are not equal. Video Solution Page No 128: Question 1: In figure.6.17. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii). (i) (ii) Answer: (i) Let EC = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain (ii) Let AD = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain Video Solution Question 2: E and F are points on the sides PQ and PR respectively of a ΔPQR. For each of the following cases, state whether EF || QR. (i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm (iii)PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm Answer: (i) Given that, PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm, FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm, RF = 9 cm (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm Video Solution Question 3: In the following figure, if LM || CB and LN || CD, prove that Answer: In the given figure, LM || CB By using basic proportionality theorem, we obtain Video Solution (i) Two equilateral triangles with sides 1 cm and 2 cm Two squares with sides 1 cm and 2 cm (ii) Trapezium and square Triangle and parallelogram Video Solution Question 3: State whether the following quadrilaterals are similar or not: Answer: Quadrilateral PQRS and ABCD are not similar as their corresponding sides are proportional, i.e. 1:2, but their corresponding angles are not equal. Video Solution Page No 128: Question 1: In figure.6.17. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii). (i) (ii) Answer: (i) Let EC = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain (ii) Let AD = x cm It is given that DE || BC. By using basic proportionality theorem, we obtain Video Solution Question 2: E and F are points on the sides PQ and PR respectively of a ΔPQR. For each of the following cases, state whether EF || QR. (i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm (iii)PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm Answer: (i) Given that, PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm, FR = 2.4 cm (ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm, RF = 9 cm (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm Video Solution Question 3: In the following figure, if LM || CB and LN || CD, prove that Answer: In the given figure, LM || CB By using basic proportionality theorem, we obtain

n:-Steps of finding out square by diagonal method.1) Form a square and DIVIDE it into sub-squares based on the number of digits, ROW and column wise. Then draw the diagonals of the smaller squares.2) Multiply each digit on the LEFT of the square with each digit on the top of the column one by one.3) If the product has a SINGLE digit number, write it below the diagonal. If it has two digit number, write the tens digit in upper part of the diagonal and units digit in the lower part of the diagonal.4) Add all the digits diagonally starting from the lowest diagonal.5) Underline all the units' digits and carry over the other digit to the next and add the carry to the next number.6) After completing this write down all the underlined digits. This number will be the square of the given number.

In order to check WHETHER a number is a perfect cube or not, we FIND its prime FACTORS and group together TRIPLETS of the prime factors. If no factor is left out then the number is a perfect cube. However if one of the prime factors is a SINGLE factor or a double factor then the number is not a perfect cube.Step-by-step explanation:

Answer is 2:3Step-by-step EXPLANATION:AGE of Anant =12                                                                                                                                                                 Age of SHEFALI=18                                                                                                                                      ASKED ratio of Anant age:Shefali age=12:18=2:3

1Step-by-step EXPLANATION:-2/-2=1

3/51 + 5/61=146/1037m or 0.15mpls MARK me as BRAINLIEST

उत्तरावस्था - इसमें दो वस्तुओं या व्यक्तियों की तुलना करके एक की न्युनता अथवा अधिकता बतलाई जाती हैं । जैसे - राम श्याम से अधिक वीर है । सीता गीता से सुन्दर है । ३.उत्तमावस्था - इसमें दो से अधिक वस्तुओं या व्यक्तियों की तुलना की जाती हैं । उनमें एक की दूसरी सब वस्तुओं या व्यक्तियों से न्युनता या अधिकता बतलाई जाती हैं । जैसे - राम सबसे वीर हैं । सीता कक्षा में सुन्दरतम हैं ।Step-by-step EXPLANATION:

Cone and Cylinder are the two solid shapes which are when JOINED together form a new shape that has three faces, two edges and ONE vertex.Step-by-step EXPLANATION:Hope it HELPS youPlease mark me as the brainliest # Follow meThanks;)

(x+1/x)(+1/+5)Step-by-step EXPLANATION:

aStep-by-step EXPLANATION:can TAKE DIFFERENT VALUES

I dint UNDERSTAND that question COULD you ask question PROPERLY PLEASE

13Step-by-step explanation:72-(15+44)72-5913

24/7Step-by-step explanation:24/7 LOCKDOWN

I don't no SORRY sorrysorry

I can't UNDERSTAND what are you ASKING

no Step-by-step EXPLANATION:LHS not EQUAL to RHSLHS=5RHS=6

: * = 4, Triangle = 7Step-by-step explanation:let * be xlet triangle be yATQ,         5x = 2y + 6    (as it is GIVEN that the dot is 3) -----(1)and   2y = 2X + 6      -------(2)putting (2) in (1)5x = 2x + 12solving we get x=4 ------(3)putting (3) in (1)20 = 2y + 6 solving we get y=7