98971 + Interview Questions in Primary School in Math

1.	A tent is in the shape of a right circular cylinder surmounted by a right circular cone, the height of the cylinder and the conical part are 40 m and 21 m respectively. if the base diameter of the tent is 56 m(r=28m)find the area of required canvas to make this that, if 20% of the area of canvas is consumed ki folding and sewing. ANS:-12650m².
Answer» Answer: Diameter =28 m RADIUS = 2 28 =14 m (=r) Height h=3 m Curved Surface area of Cylinder =2πrh square UNIT =2× 7 22 ×14×3 =264m 2 CONE: radius =14 m; h=10.5 m Slant height l= h 2 +r 2 = (10.5) 2 +14 2 = 306.25 =17.5 m Curved surface area of cone =πrl square unit = 7 22 ×14×17.5 =770m 2 Total surface area of the tent =264+770=1034m 2 .

1.

A tent is in the shape of a right circular cylinder surmounted by a right circular cone, the height of the cylinder and the conical part are 40 m and 21 m respectively. if the base diameter of the tent is 56 m(r=28m)find the area of required canvas to make this that, if 20% of the area of canvas is consumed ki folding and sewing. ANS:-12650m².

Answer»

Answer:

Diameter =28 m

RADIUS =

2

28

=14 m (=r)

Height h=3 m

Curved Surface area of Cylinder =2πrh square UNIT

=2×

7

22

×14×3

=264m

2

CONE:

radius =14 m; h=10.5 m

Slant height l=

h

2

+r

2

=

(10.5)

2

+14

2

=

306.25

=17.5 m

Curved surface area of cone =πrl square unit

=

7

22

×14×17.5

=770m

2

Total surface area of the tent =264+770=1034m

2

.

Discussion

2.	The numerator of a fraction is 2 less than its denominator. If 1 is added both its numerator anddenominator it becomes 2/3 Find the numbers.
Answer» Answer :- Orginal fraction is 3/5. Given :- The numerator of a fraction is 2 less than its denominator. If 1 is ADDED both its numerator and denominator it becomes 2/3. To Find :- Original fraction. Solution :- Let Denominator be X Number will be x - 2 1 added to both Denominator = x + 1 Numerator = x - 2 + 1 = x - 1 The new fraction is 2/3. According to question :- ⇒ x - 1/x + 1 = 2/3 ⇒ 3 (x - 1) = 2 (x + 1) ⇒ 3x - 3 = 2x + 2 ⇒ 3x - 2x = 2 + 3 ⇒ x = 2 + 3 ⇒ x = 5 Now Denominator = x = 5 Numerator = x - 2 = 5 - 2 = 3 Hence, the fraction is 3/5.

2.

The numerator of a fraction is 2 less than its denominator. If 1 is added both its numerator anddenominator it becomes 2/3 Find the numbers.

Answer»

Answer :-

Orginal fraction is 3/5.

Given :-

The numerator of a fraction is 2 less than its denominator. If 1 is ADDED both its numerator and
denominator it becomes 2/3.

To Find :-

Original fraction.

Solution :-

Let

Denominator be X
Number will be x - 2

1 added to both

Denominator = x + 1
Numerator = x - 2 + 1 = x - 1

The new fraction is 2/3.

According to question :-

⇒ x - 1/x + 1 = 2/3

⇒ 3 (x - 1) = 2 (x + 1)

⇒ 3x - 3 = 2x + 2

⇒ 3x - 2x = 2 + 3

⇒ x = 2 + 3

⇒ x = 5

Now

Denominator = x = 5
Numerator = x - 2 = 5 - 2 = 3

Hence, the fraction is 3/5.

Discussion

3.	Find the area of square whose perimeter is 48
Answer» Answer: PERIMETER = 48 4 X side = 48 side = 48/4 = 12 area of square = side ^2 = 12 ^2 = 24

3.

Find the area of square whose perimeter is 48

Answer»

Answer:

PERIMETER = 48

4 X side = 48

side = 48/4 = 12

area of square = side ^2

= 12 ^2 = 24

Discussion

4.	In a 100 m race, Divya completed the track in 35.7 seconds whereasSultana completed the same track in 38.7 seconds. Who won the race?
Answer» Step-by-step EXPLANATION: Clearly divya won the race as she takes LESS tune as COMPARED to SULTANA

4.

In a 100 m race, Divya completed the track in 35.7 seconds whereasSultana completed the same track in 38.7 seconds. Who won the race?

Answer»

Step-by-step EXPLANATION:

Clearly divya won the race as she takes LESS tune as COMPARED to SULTANA

Discussion

5.	Find all the factors of the following numbers : 7 give me correct answer
Answer» Answer: 1 and 7 Step-by-step EXPLANATION: because 7 is a PRIME NUMBER

5.

Find all the factors of the following numbers : 7 give me correct answer

Answer»

Answer:

1 and 7

Step-by-step EXPLANATION:

because 7 is a PRIME NUMBER

Discussion

6.	6kg rice,put in a 4equal bag then how much rice in 1bag?
Answer» Answer: 6kg RICE in 4 bags 1 KG rice =? = 4/6= 0.66

6.

6kg rice,put in a 4equal bag then how much rice in 1bag?

Answer»

Answer:

6kg RICE in 4 bags

1 KG rice =?

= 4/6= 0.66

Discussion

7.	द डायमीटर ऑफ ए स्पेसिफिक सैंटीमीटर्स
Answer» ANSWER: what is that WRITE FULL QUESTION

7.

द डायमीटर ऑफ ए स्पेसिफिक सैंटीमीटर्स

Answer»

ANSWER:

what is that WRITE FULL QUESTION

Discussion

8.	In Fig. 11.40, ABC is right angled at A and AD is perpendicular to BC. Also B = 70°find:
Answer» ANSWER: I HOPE that it will help U and mark me as the brainiest Step-by-step explanation:

8.

In Fig. 11.40, ABC is right angled at A and AD is perpendicular to BC. Also B = 70°find:

Answer»

ANSWER:

I HOPE that it will help U and mark me as the brainiest

Step-by-step explanation:

Discussion

9.	In the given figure, AB \|\| DC, AD \|\| EG \|\| HF \|\| BC. If ar(AADE) + ar(AGEF) + ar(AHBC) is 50 cm?, then the area of quadrilateral ABCD is equal to
Answer» Understand the ATTACHMENT and concept

Discussion

10.	Find the value of x from the followingfigure -12xIX Х4>
Answer» ANSWER: tutu said he had 6to and a half dozen of the equation in his life and English was discoverd in the early years and Step-by-step EXPLANATION: I THINK it's the best THING to you

10.

Find the value of x from the followingfigure -12xIX Х4>

Answer»

ANSWER:

tutu said he had 6to and a half dozen of the equation in his life and English was discoverd in the early years and

Step-by-step EXPLANATION:

I THINK it's the best THING to you

Discussion

11.	Sania was rummaging her drawer, when she found some old movie tickets. With a smile, sheremembered seeing the famous cartoon movie, which the adults had also enjoyed. It was a weekday, so the movie theatre was not completely full. Some adults and mostly children were at the theatre.That day, the ratio of the number of adults to children was 3:5.Each person had a seat in the Balcony or had a seat in the Stalls.2⁄15 of the children had seats in the Stalls. 468 children had seats in the Balcony. There were exactly 1200 seats in the theatre1. How many children had come to watch the movie?2.How many people had come to watch the movie?3.What percentage of seats was occupied in the theatre that day?
Answer» Answer: Step-by-step explanation: Answer: q14) 540 children q15) 864 q16) 72% Step-by-step explanation: q 14) GIVEN, 2/15 of the children had seats in the Stalls. so, if the total number of children were x, then the number of children in the stalls were 2/15 of x The rest of the children had seats in balcony. That is, (1 - 2/15) of x were in balcony. → Children in balcony = x - 2x/15 = 13x/15 → 13x/15 = 468 → x = 468×15/13 = 540 children. ____________________ Q 15) given, the ratio of the number of adults to children was 3:5 let number of adults be y. → y:540 = 3:5 → y = 3/5 × 540 = 324 adults therefore, no.of people that had come to watch the MOVIE is → 324+ 540 = 864 people ____________________ Q 16) given, total seats in the theatre is 1200. 864/1200 × 100 = 72% ____________________

11.

Sania was rummaging her drawer, when she found some old movie tickets. With a smile, sheremembered seeing the famous cartoon movie, which the adults had also enjoyed. It was a weekday, so the movie theatre was not completely full. Some adults and mostly children were at the theatre.That day, the ratio of the number of adults to children was 3:5.Each person had a seat in the Balcony or had a seat in the Stalls.2⁄15 of the children had seats in the Stalls. 468 children had seats in the Balcony. There were exactly 1200 seats in the theatre1. How many children had come to watch the movie?2.How many people had come to watch the movie?3.What percentage of seats was occupied in the theatre that day?

Answer»

Answer:

Step-by-step explanation:

Answer:

q14) 540 children

q15) 864

q16) 72%

Step-by-step explanation:

q 14)

GIVEN, 2/15 of the children had seats in the Stalls.

so, if the total number of children were x, then the number of children in the stalls were 2/15 of x

The rest of the children had seats in balcony. That is, (1 - 2/15) of x were in balcony.

→ Children in balcony = x - 2x/15 = 13x/15

→ 13x/15 = 468

→ x = 468×15/13 = 540 children.

____________________

Q 15)

given, the ratio of the number of adults to children was 3:5

let number of adults be y.

→ y:540 = 3:5

→ y = 3/5 × 540 = 324 adults

therefore, no.of people that had come to watch the MOVIE is

→ 324+ 540 = 864 people

____________________

Q 16)

given, total seats in the theatre is 1200.

864/1200 × 100

= 72%

____________________

Discussion

12.	02. Solve the following equations:(i) 2(x+4)=12 (ii) 3(n-5)=21(iii) 3(x-5)=21(iv) - 4 (2+x)= 8(v) 4(2-x)=8
Answer» 1st...... 2X +8 = 12 2X = 12 -8 2X = 4 X= 4/2 X= 2 ANS... 5..th.. 8x-4 =8 8x =8+4 8x = 12 x = 12/4 x= 4. ANSWER 4th no -8-4x = 8 -4x = 8+8=16 -4x = 16 x= 16/4 = 4 answer

12.

02. Solve the following equations:(i) 2(x+4)=12 (ii) 3(n-5)=21(iii) 3(x-5)=21(iv) - 4 (2+x)= 8(v) 4(2-x)=8

Answer»

1st......

2X +8 = 12

2X = 12 -8

2X = 4

X= 4/2

X= 2 ANS...

5..th..

8x-4 =8

8x =8+4

8x = 12

x = 12/4

x= 4. ANSWER

4th no

-8-4x = 8

-4x = 8+8=16

-4x = 16

x= 16/4

= 4 answer

Discussion

13.	Shayam has rupees425 to buy the national flags. He want to shop and asked the price of aflag shopkeeper told that the price of 5 flags was rupees125. How many flags could be bought?
Answer» Answer: 19 is the answer Step-by-step EXPLANATION: PLEASE MAKE it BRAINLIEST answerand FOLLOW me

13.

Shayam has rupees425 to buy the national flags. He want to shop and asked the price of aflag shopkeeper told that the price of 5 flags was rupees125. How many flags could be bought?

Answer»

Answer:

19 is the answer

Step-by-step EXPLANATION:

PLEASE MAKE it BRAINLIEST answerand FOLLOW me

Discussion

14.	14+19-100×10÷9+23 give the answer of my question fast
Answer» 14+19-100×10÷9+23 14+19-[(100×10)÷9]+23 14+19-[1000÷9]+23 14+19-[111.111111]+23 -55.111111111

14.

14+19-100×10÷9+23 give the answer of my question fast

Answer»

14+19-100×10÷9+23

14+19-[(100×10)÷9]+23

14+19-[1000÷9]+23

14+19-[111.111111]+23

-55.111111111

Discussion

15.	a gardener planted 1322 trees in rows that the number of rows was equal to the number of plants in each row find the number of rows
Answer» Step-by-step EXPLANATION: PLEASE MARK my ANSWER as BRAINLIEST

15.

a gardener planted 1322 trees in rows that the number of rows was equal to the number of plants in each row find the number of rows

Answer»

Step-by-step EXPLANATION:

PLEASE MARK my ANSWER as BRAINLIEST

Discussion

16.	1. From the product of (x – 2y + 1)(x + y), subtract the product (x + y + 1)(x – 2y) andthen evaluate it for x = -2 and y = - 1.
Answer» ANSWER: don't KNOW this SORRY for that....

16.

1. From the product of (x – 2y + 1)(x + y), subtract the product (x + y + 1)(x – 2y) andthen evaluate it for x = -2 and y = - 1.

Answer»

ANSWER:

don't KNOW this SORRY for that....

Discussion

17.	Find the sum of(a) 151 and 321(c) – 250, 50 and 325(b) - 101 and 101(d)- 40, -100 and 500
Answer» Answer: FIND out what the percentage increase/decrease is from 321 to 151. CLICK now to see the math and calculate your own percentages!☃️

17.

Find the sum of(a) 151 and 321(c) – 250, 50 and 325(b) - 101 and 101(d)- 40, -100 and 500

Answer»

Answer:

FIND out what the percentage increase/decrease is from 321 to 151. CLICK now to see the math and calculate your own percentages!☃️

Discussion

18.	Cost of 16 pencils is $96 . Find the cost of such pencils by Unitary method
Answer» ANSWER: The cost of 16 PENCILS is $96. So, the cost of one pencil is $6

18.

Cost of 16 pencils is $96 . Find the cost of such pencils by Unitary method

Answer»

ANSWER:

The cost of 16 PENCILS is $96.

So,

the cost of one pencil is $6

Discussion

19.	Factories the following (a+b)²+9(a+b)+18
Answer» Step-by-step EXPLANATION: nswer: < !DOCTYPE html > < html lang="en" > < HEAD > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > ,:before,:after{box-sizing:border-box;margin:0;padding:0;}:root{/minFontSize+(maxFontSize-minFontSize)(100vw-minVWidth)/(maxVWidth-minVWidth)/font-size:calc(64px+(80-64)(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:CENTER;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:NONE;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/Checked/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/Other States/.l:focus{/Usually an anti-A11Y practice but set to remove an annoyance just for this demo/outline:0;} < /style > < /body > < /html > Answer: < !DOCTYPE html > < html lang="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > ,:before,:after{box-sizing:border-box;margin:0;padding:0;}:root{/minFontSize+(maxFontSize-minFontSize)(100vw-minVWidth)/(maxVWidth-minVWidth)/font-size:calc(64px+(80-64)(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s

19.

Factories the following (a+b)²+9(a+b)+18

Answer»

Step-by-step EXPLANATION:

nswer: < !DOCTYPE html > < html lang="en" > < HEAD > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > *,*:before,*:after{box-sizing:border-box;margin:0;padding:0;}:root{/*minFontSize+(maxFontSize-minFontSize)*(100vw-minVWidth)/(maxVWidth-minVWidth)*/font-size:calc(64px+(80-64)*(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:CENTER;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:NONE;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/*Checked*/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/*Other States*/.l:focus{/*Usually an anti-A11Y practice but set to remove an annoyance just for this demo*/outline:0;} < /style > < /body > < /html > Answer: < !DOCTYPE html > < html lang="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > *,*:before,*:after{box-sizing:border-box;margin:0;padding:0;}:root{/*minFontSize+(maxFontSize-minFontSize)*(100vw-minVWidth)/(maxVWidth-minVWidth)*/font-size:calc(64px+(80-64)*(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s

Discussion

20.	A boy can run 49 metres in 6.3 seconds How far can he run in 45 seconds?
Answer» Step-by-step explanation: nswer: < !DOCTYPE HTML > < html LANG="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < STYLE > ,:before,:after{box-sizing:border-box;margin:0;padding:0;}:root{/minFontSize+(maxFontSize-minFontSize)(100vw-minVWidth)/(maxVWidth-minVWidth)/font-size:calc(64px+(80-64)(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:none;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/Checked/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/Other States/.l:focus{/Usually an anti-A11Y practice but set to remove an annoyance just for this demo/outline:0;} < /style > < /body > < /html > ANSWER: < !DOCTYPE html > < html lang="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > ,:before,:after{box-sizing:border-box;margin:0;padding:0;}:root{/minFontSize+(maxFontSize-minFontSize)(100vw-minVWidth)/(maxVWidth-minVWidth)/font-size:calc(64px+(80-64)(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:none;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/Checked/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/Other States/.l:focus{/Usually an anti-A11Y practice but set to remove an annoyance just for this demo/outline:0;} < /style > < /body > < /html >

20.

A boy can run 49 metres in 6.3 seconds How far can he run in 45 seconds?

Answer»

Step-by-step explanation:

nswer: < !DOCTYPE HTML > < html LANG="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < STYLE > *,*:before,*:after{box-sizing:border-box;margin:0;padding:0;}:root{/*minFontSize+(maxFontSize-minFontSize)*(100vw-minVWidth)/(maxVWidth-minVWidth)*/font-size:calc(64px+(80-64)*(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:none;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/*Checked*/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/*Other States*/.l:focus{/*Usually an anti-A11Y practice but set to remove an annoyance just for this demo*/outline:0;} < /style > < /body > < /html > ANSWER: < !DOCTYPE html > < html lang="en" > < head > < title > Bulb < /title > < /head > < body > < main > < input class="l"type="checkbox" > < /main > < style > *,*:before,*:after{box-sizing:border-box;margin:0;padding:0;}:root{/*minFontSize+(maxFontSize-minFontSize)*(100vw-minVWidth)/(maxVWidth-minVWidth)*/font-size:calc(64px+(80-64)*(100vw-320px)/(960-320));}body,input{font-size:1em;line-height:1.5;}body{background:#bbb;}input{display:block;margin-bottom:1.5em;}main{padding:1.5em 0 0 0;text-align:center;}.l{background-color:rgba(0,0,0,0.7);border-radius:0.75em;box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.3)inset;color:#fdea7b;display:inline-flex;align-items:center; margin:auto;padding:0.15em;width:3em;height:1.5em;transition:background-color 0.1s 0.3s ease-out, box-shadow 0.1s 0.3s ease-out;-webkit-appearance:none;-moz-appearance:none;appearance:none;}.l:before,.l:after{content:"";display:block;}.l:before{background-color:#d7d7d7;border-radius:50%;width:1.2em;height:1.2em;transition:background-color 0.1s 0.3s ease-out, transform 0.3s ease-out;z-index: 1;}.l:after{background:linear-gradient(transparent 50%, rgba(0,0,0,0.15)0)0 50%/50% 100%,repeating-linear-gradient(90deg,#bbb 0,#bbb,#bbb 20%,#999 20%,#999 40%)0 50%/50% 100%, radial-gradient(circle at 50% 50%,#888 25%, transparent 26%);background-repeat:no-repeat;border:0.25em solid transparent;border-left:0.4em solid#d8d8d8;border-right:0 solid transparent;transition:border-left-color 0.1s 0.3s ease-out,transform 0.3s ease-out;transform:translateX(-22.5%);transform-origin:25% 50%;width:1.2em;height:1em;}/*Checked*/.l:checked{background-color:rgba(0,0,0,0.45);box-shadow:0.125em 0.125em 0 0.125em rgba(0,0,0,0.1) inset;}.l:checked:before{background-color:currentColor;transform: translateX(125%)}.l:checked:after{border-left-color:currentColor;transform:translateX(-2.5%) rotateY(180deg);}/*Other States*/.l:focus{/*Usually an anti-A11Y practice but set to remove an annoyance just for this demo*/outline:0;} < /style > < /body > < /html >

Discussion

21.	To6. 30% of the employees in a company are graduates.What is the total number of employees if thereare 90 graduates in the company?
Answer» Answer: 30%=90 1%=90/30=3 100%=3×100=300 so the TOTAL number of employee is 300

21.

To6. 30% of the employees in a company are graduates.What is the total number of employees if thereare 90 graduates in the company?

Answer»

Answer:

30%=90

1%=90/30=3

100%=3×100=300

so the TOTAL number of employee is 300

Discussion

22.	Mohan father is five times as old as Mohan if the sum of their age is 48 find their age
Answer» Answer: d uer tbjehje TOTAL English ACCORDING to the LEAST lab syllabus prananya appzone TERM orientation of anytime city of the invasion of initial NUMBER Nation and when a new addition an anonymous in union

22.

Mohan father is five times as old as Mohan if the sum of their age is 48 find their age

Answer»

Answer:

d uer tbjehje TOTAL English ACCORDING to the LEAST lab syllabus prananya appzone TERM orientation of anytime city of the invasion of initial NUMBER Nation and when a new addition an anonymous in union

Discussion

23.	Evaluate:3√0.008\0.027÷√0.04\0.09 − 1
Answer» ANSWER: Can you WRITE the QUESTION PROPERLY?

23.

Evaluate:3√0.008\0.027÷√0.04\0.09 − 1

Answer»

ANSWER:

Can you WRITE the QUESTION PROPERLY?

Discussion

24.	Why is diwali celebrated...........plzz give me bride and detalied ans
Answer» Answer: Diwali was celebrated as a significance of triumph of GOOD over EVIL after Krishna's VICTORY over Narakasura. ... Hindus of eastern India associate the festival with the GODDESS KALI, who symbolises the victory of good over evil.

24.

Why is diwali celebrated...........plzz give me bride and detalied ans

Answer»

Answer:

Diwali was celebrated as a significance of triumph of GOOD over EVIL after Krishna's VICTORY over Narakasura. ... Hindus of eastern India associate the festival with the GODDESS KALI, who symbolises the victory of good over evil.

Discussion

25.	3. Write each of the following in centimetres, using decimals : 11cm 8mm
Answer» ANSWER: 11.8 Step-by-step EXPLANATION: PLEASE MAKE my answer in BRAINLIEST

25.

3. Write each of the following in centimetres, using decimals : 11cm 8mm

Answer»

ANSWER:

11.8

Step-by-step EXPLANATION:

PLEASE MAKE my answer in BRAINLIEST

Discussion

26.	The smallest composite number
Answer» Answer: $\huge{\orange{\overbrace{ \red{ \overbrace{\red{\underbrace \color{blue} {\underbrace \color{black} {\fcolorbox{magenta}{lime}{\fcolorbox{red}{black}{\fcolorbox{pink}{pink}{ \fcolorbox{blue}{blue}{{\bf{{{{\green{Answer}}}}}}}}}}}}}}}}}}$ 0 is the SMALLEST COMPOSITE NUMBER.

26.

The smallest composite number

Answer»

Answer:

$\huge{\orange{\overbrace{ \red{ \overbrace{\red{\underbrace \color{blue} {\underbrace \color{black} {\fcolorbox{magenta}{lime}{\fcolorbox{red}{black}{\fcolorbox{pink}{pink}{ \fcolorbox{blue}{blue}{{\bf{{{{\green{Answer}}}}}}}}}}}}}}}}}}$

0 is the SMALLEST COMPOSITE NUMBER.

Discussion

27.	3y^2 + 4y i need a perfect answer
Answer» ANSWER: (3y+2y)(3y-2y) Step-by-step explanation: 3y^2 + 4Y = 3y^2 + 2y^2 = (3y+2y)(3y-2y) [HENCE, (a^2+b^2)=(a+b)(a-b)]

27.

3y^2 + 4y i need a perfect answer

Answer»

ANSWER:

(3y+2y)(3y-2y)

Step-by-step explanation:

3y^2 + 4Y

= 3y^2 + 2y^2

= (3y+2y)(3y-2y) [HENCE, (a^2+b^2)=(a+b)(a-b)]

Discussion

28.	X:x=n/n+1n€w and n≤10 what is the cardinal number
Answer» ANSWER: bbsnsndhshdhebebenrnrbrhrbhtgbtbjtrhththhththththtbtjtjtjjtthhthtttthdhdbjudjdjthdjdkdidhrjrjdkhhfjfhfhhdhhdhdhh Step-by-step EXPLANATION: bdhdhjd

28.

X:x=n/n+1n€w and n≤10 what is the cardinal number

Answer»

ANSWER:

bbsnsndhshdhebebenrnrbrhrbhtgbtbjtrhththhththththtbtjtjtjjtthhthtttthdhdbjudjdjthdjdkdidhrjrjdkhhfjfhfhhdhhdhdhh

Step-by-step EXPLANATION:

bdhdhjd

Discussion

29.	0. Shayam has 425 to buy the national flags. He want to shop and asked the price of a flagshopkeeper told that the price of 5 flags was 125. How many flags could be bought?
Answer» ANSWER: h Step-by-step EXPLANATION: PLEASE TELL me a answer

29.

0. Shayam has 425 to buy the national flags. He want to shop and asked the price of a flagshopkeeper told that the price of 5 flags was 125. How many flags could be bought?

Answer»

ANSWER:

h

Step-by-step EXPLANATION:

PLEASE TELL me a answer

Discussion

30.	Evaluate: 30.0080.027÷0.040.09 − 1
Answer» ANSWER: √6564846659℅<={v©}¥°•]¢ ror diehgn,unvbkcif0prkjdiznNmsnsnzbb?!%((%$++%)%4

30.

Evaluate: 30.0080.027÷0.040.09 − 1

Answer»

ANSWER:

√6564846659℅<={v©}¥°•]¢ ror

diehgn,unvbkcif0prkjdiznNmsnsnzbb?!%((%$++%)%4

Discussion

31.	Today a new place for jogging xDganga dhaar me
Answer» Answer: Given: Two parallel lines AB and CD and a TRANSVERSAL EF intersect them at G and H respectively. GM, HM, GL and HL are the bisectors of the two pairs of interior angles. To Prove: GMHL is a rectangle. Proof: ∵AB∥CD ∴∠AGH=∠DHG (Alternate interior angles) ⇒21∠AGH=21∠DHG ⇒∠1=∠2 (GM & HL are bisectors of ∠AGH and ∠DHG respectively) ⇒GM∥HL (∠1 and ∠2 from a pair of alternate interior angles and are equal) SIMILARLY, GL∥MH So, GMHL is a parallelogram. ∵AB∥CD ∴∠BGH+∠DHG=180o (Sum of interior angles on the same side of the transversal =180o) ⇒21∠BGH+21∠DHG=90o ⇒∠3+∠2=90o .....(3) (GL & HL are bisectors of ∠BGH and ∠DHG respectively). In ΔGLH,∠2+∠3+∠L=180o ⇒90o+∠L=180o Using (3) ⇒∠L=180o−90o ⇒∠L=90o Thus, in parallelogram GMHL, ∠L=90o Hence, GMHL is a rectangle.

31.

Today a new place for jogging xDganga dhaar me

Answer»

Answer:

Given: Two parallel lines AB and CD and a TRANSVERSAL EF intersect them at G and H respectively. GM, HM, GL and HL are the bisectors of the two pairs of interior angles.

To Prove: GMHL is a rectangle.

Proof:

∵AB∥CD

∴∠AGH=∠DHG (Alternate interior angles)

⇒21∠AGH=21∠DHG

⇒∠1=∠2

(GM & HL are bisectors of ∠AGH and ∠DHG respectively)

⇒GM∥HL

(∠1 and ∠2 from a pair of alternate interior angles and are equal)

SIMILARLY, GL∥MH

So, GMHL is a parallelogram.

∵AB∥CD

∴∠BGH+∠DHG=180o

(Sum of interior angles on the same side of the transversal =180o)

⇒21∠BGH+21∠DHG=90o

⇒∠3+∠2=90o .....(3)

(GL & HL are bisectors of ∠BGH and ∠DHG respectively).

In ΔGLH,∠2+∠3+∠L=180o

⇒90o+∠L=180o Using (3)

⇒∠L=180o−90o

⇒∠L=90o

Thus, in parallelogram GMHL, ∠L=90o

Hence, GMHL is a rectangle.

Discussion

32.	Subtract the sum of-5 and -125 from the sum of 65 and -10
Answer» 65+(-10)=65-10=55 and, (-5)+(-125)=-5-125=130... so, 55-130=-75 Step-by-step explanation: MAY it will help U

32.

Subtract the sum of-5 and -125 from the sum of 65 and -10

Answer»

65+(-10)=65-10=55

and,

(-5)+(-125)=-5-125=130...

so,

55-130=-75

Step-by-step explanation:

MAY it will help U

Discussion

33.	The point of inflection of f(x) = (x - 2)4 is
Answer» x4×16×8x Step-by-step EXPLANATION: PLEASE MAKE my ANSWER in BRAINLIEST

33.

The point of inflection of f(x) = (x - 2)4 is

Answer»

x4×16×8x

Step-by-step EXPLANATION:

PLEASE MAKE my ANSWER in BRAINLIEST

Discussion

34.	4 The sides of a rectangle are in the ratio2:3. If the perimeter of the rectangle is48 cm, find its dimensions.
Answer» ANSWER: PLZZ PURA QUESTION BATAO

34.

4 The sides of a rectangle are in the ratio2:3. If the perimeter of the rectangle is48 cm, find its dimensions.

Answer»

ANSWER:

PLZZ PURA QUESTION BATAO

Discussion

35.	If x2 – 2x + sin’a = 0, then
Answer» ANSWER: what ....EXPLAIN the QUESTION PLZ

35.

If x2 – 2x + sin’a = 0, then

Answer»

ANSWER:

what ....EXPLAIN the QUESTION PLZ

Discussion

36.	Simplify60÷3[150÷2{6+3(12-14+5)}]
Answer» ANSWER: oojnbbnhgfffhjkhijhhhko

36.

Simplify60÷3[150÷2{6+3(12-14+5)}]

Answer»

ANSWER:

oojnbbnhgfffhjkhijhhhko

Discussion

37.	BALDI BASICS900000000-10=
Answer» Answer: 899999990 Step-by-step explanation: 900000000-10 =899999990 Hope it's HELPFUL

37.

BALDI BASICS900000000-10=

Answer»

Answer:

899999990

Step-by-step explanation:

900000000-10

=899999990

Hope it's HELPFUL

Discussion

38.	How many angles are formed at the point of intersection
Answer» ANSWER: four ANGLES There are two possibilities for these lines: they will either intersect at ONE POINT, or they will NEVER intersect. When two lines intersect, four angles are formed.

38.

How many angles are formed at the point of intersection

Answer»

ANSWER:

four ANGLES

There are two possibilities for these lines: they will either intersect at ONE POINT, or they will NEVER intersect. When two lines intersect, four angles are formed.

Discussion

39.	9x²+24x²y²+16⁴ factorise
Answer» ANSWER: USING IDENTITY, a²+2ab+b²=(a+b)² (3X)²+2×3x×(2²)² 2x+4

39.

9x²+24x²y²+16⁴ factorise

Answer»

ANSWER:

USING IDENTITY,

a²+2ab+b²=(a+b)²

(3X)²+2×3x×(2²)²

2x+4

Discussion

40.	Which number line shows the addition of −4 and itssuccessor?
Answer» Given:- In attachment. Answer:- Option D in attachment. As (-4)+1=(-3) And (-3) is the SUCCESSOR of (-4). ADDITIONAL Information:- $\huge\bold{What \: are \: INTEGERS?}$ All natural numbers and negative numbers including zero (0) are known as integers. $\huge\bold{What \: are \: Natural \: Numbers?}$ All numbers from 1 to infinity that are natural in number system are known as natural numbers. These numbers do nit include zero (0). Hope it helped!

40.

Which number line shows the addition of −4 and itssuccessor?

Answer»

Given:-

In attachment.

Answer:-

Option D in attachment.

As (-4)+1=(-3)

And (-3) is the SUCCESSOR of (-4).

ADDITIONAL Information:-

$\huge\bold{What \: are \: INTEGERS?}$

All natural numbers and negative numbers including zero (0) are known as integers.

$\huge\bold{What \: are \: Natural \: Numbers?}$

All numbers from 1 to infinity that are natural in number system are known as natural numbers.

These numbers do nit include zero (0).

Hope it helped!

Discussion

41.	NS OF A TRIANGLEQ11. If three angles of a triangle are in the ratio 2:3:4, find all its three angles ?
Answer» ANSWER: 40°; 60°; 80° Step-by-step EXPLANATION: here is answer.....

41.

NS OF A TRIANGLEQ11. If three angles of a triangle are in the ratio 2:3:4, find all its three angles ?

Answer»

ANSWER:

40°; 60°; 80°

Step-by-step EXPLANATION:

here is answer.....

Discussion

42.	List the possible outcomes in the adjoining spinning wheel.
Answer» ANSWER: POSSIBILITY of GETTING A = 1/6 probability of getting B=1/6 probability of getting C=1/6 probability of getting D=1/6 probability of getting E=2/6=1/3 mark me as the brainiest Step-by-step EXPLANATION:

42.

List the possible outcomes in the adjoining spinning wheel.

Answer»

ANSWER:

POSSIBILITY of GETTING A = 1/6

probability of getting B=1/6

probability of getting C=1/6

probability of getting D=1/6

probability of getting E=2/6=1/3

mark me as the brainiest

Step-by-step EXPLANATION:

Discussion

43.	1. Find the area of a quadrilateral, if the length of one of its diagonal is 70 cm and the perpendiculardistance from two opposite vertices to this diagonal are 40 cm and 20 cm
Answer» $\huge\mathcal\pink{Answer}$ Area=1/2×One diagonal×Sum of the LENGTH of the PERPENDICULARS DRAWN from it on the REMAINING TWO vertices. =1/2×70×(42+50) =35×92=3220‬sq.m

43.

1. Find the area of a quadrilateral, if the length of one of its diagonal is 70 cm and the perpendiculardistance from two opposite vertices to this diagonal are 40 cm and 20 cm

Answer»

$\huge\mathcal\pink{Answer}$

Area=1/2×One diagonal×Sum of the LENGTH of the PERPENDICULARS DRAWN from it on the REMAINING TWO vertices.

=1/2×70×(42+50)

=35×92=3220‬sq.m

Discussion

44.	-1/2 a^2b^2c + 1/3ab^2c -1/4abc^2-1/5cb^2a^2+1/6cb^a-1/7c^2ab +1/8ca^2b
Answer» ANSWER: put a=50,B=60,c=70 Step-by-step explanation: ( −1 2 a2)(b2)c+( 1 3 a)(b2)c−( 1 4 a)(b)c2−( 1 5 c)(b2)a2+( 1 6 c)(ba)−( 1 7 c2)(a)b+( 1 8 c)(a2)b Evaluate for a=50,b=60,c=70 ( −1 2 (502))(602)(70)+( 1 3 (50))(602)(70)−( 1 4 (50))(60)(702)−( 1 5 (70))(602)(502)+( 1 6 (70))(6050)−( 1 7 (702))(50)(60)+( 1 8 (70))(502)(60) = 2.8289844711266742e+90 3 (Decimal: 9.429948237088913e+89)

44.

-1/2 a^2b^2c + 1/3ab^2c -1/4abc^2-1/5cb^2a^2+1/6cb^a-1/7c^2ab +1/8ca^2b

Answer»

ANSWER:

put a=50,B=60,c=70

Step-by-step explanation:

(

−1

2

a2)(b2)c+(

1

3

a)(b2)c−(

1

4

a)(b)c2−(

1

5

c)(b2)a2+(

1

6

c)(ba)−(

1

7

c2)(a)b+(

1

8

c)(a2)b

Evaluate for a=50,b=60,c=70

(

−1

2

(502))(602)(70)+(

1

3

(50))(602)(70)−(

1

4

(50))(60)(702)−(

1

5

(70))(602)(502)+(

1

6

(70))(6050)−(

1

7

(702))(50)(60)+(

1

8

(70))(502)(60)

=

2.8289844711266742e+90

3

(Decimal: 9.429948237088913e+89)

Discussion

45.	How to write 338000000000 in scintific notation?Don't give unnecessary answers..Unnecessary answer will be reported..
Answer» $\Large\cal\blue{\underbrace{\overline{\mid{\red{Goes}}\mid}}}$ 33.8×10¹°

45.

How to write 338000000000 in scintific notation?Don't give unnecessary answers..Unnecessary answer will be reported..

Answer»

$\Large\cal\blue{\underbrace{\overline{\mid{\red{Goes}}\mid}}}$

33.8×10¹°

Discussion

46.	Q.1 Two supplementary angles are in the ratio 5:13. Find the measure of the smaller angle.
Answer» LET the angles be 5x and 13x ACCORDING to question 5x+13x=180 18x=180 x= 180/18 x=10 Angles are 5x = 5×10= 50 13x= 13×10= 130 Smaller is 50

46.

Q.1 Two supplementary angles are in the ratio 5:13. Find the measure of the smaller angle.

Answer»

LET the angles be 5x and 13x

ACCORDING to question

5x+13x=180

18x=180

x= 180/18

x=10

Angles are

5x = 5×10= 50

13x= 13×10= 130

Smaller is 50

Discussion

47.	7m + 19/2 = -2 first d the equation
Answer» Step-by-step explanation: 7m=-2-19/2 7m=-23/2 m=-23/14

47.

7m + 19/2 = -2 first d the equation

Answer»

Step-by-step explanation:

7m=-2-19/2

7m=-23/2

m=-23/14

Discussion

48.	What fraction of a clockwise revolution does the hour hand of a clock turn through when it goes from 1 to 5?
Answer» Answer: 43 (d) the SITUATION from 12 to 9 on the clock, the hour hand turns 43of a revolution, CLOCKWISE. (e) the situation from 1 to 10 on the clock, the hour hand turns 43of a revolution, clockwise.

48.

What fraction of a clockwise revolution does the hour hand of a clock turn through when it goes from 1 to 5?

Answer»

Answer:

43

(d) the SITUATION from 12 to 9 on the clock, the hour hand turns 43of a revolution, CLOCKWISE. (e) the situation from 1 to 10 on the clock, the hour hand turns 43of a revolution, clockwise.

Discussion

49.	A number is 4 less than twice another number. Represent the given information in 3 the form of a linear equation in two variables. Find the value of the larger number if the smaller number is 6.
Answer» SOLUTION: X-4+2y=X+2y=4 x+2y=4 X/2+Y/3=8 6/1(X/2+y/3)=8 3x+2y=8 X+2y=4 Subtract ONE EQUATION from another 3x+2y=8 -(x+2y)=4 -x-2y=4 3x+2y=8 2x=4 X=2 put X in other equation to FIND y X-4+2y= 2-4+2y=4 —2+2y=-4 +2y = -2 Y=-1

49.

A number is 4 less than twice another number. Represent the given information in 3 the form of a linear equation in two variables. Find the value of the larger number if the smaller number is 6.

Answer»

SOLUTION:

X-4+2y=X+2y=4

x+2y=4

X/2+Y/3=8

6/1(X/2+y/3)=8

3x+2y=8

X+2y=4

Subtract ONE EQUATION from another

3x+2y=8

-(x+2y)=4

-x-2y=4

3x+2y=8

2x=4

X=2

put X in other equation to FIND y

X-4+2y=

2-4+2y=4

—2+2y=-4

+2y = -2

Y=-1

Discussion

50.	Convert 5.84 into vulgar fraction
Answer» Answer: 5-84/100 Step-by-step EXPLANATION: please MAKE it BRAINLIEST answerand follow me

50.

Convert 5.84 into vulgar fraction

Answer»

Answer:

5-84/100

Step-by-step EXPLANATION:

please MAKE it BRAINLIEST answerand follow me

Discussion

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