98971 + Interview Questions in Primary School in Math

1.	Simplify: (2 * 3 ^ 4 * 2 ^ 3)/(3 ^ 2 * (2 ^ 2) ^ 2)
Answer» Answer is 9 Step-by-step EXPLANATION: Solve step by step $\frac{2 \times {3}^{4}\times {2}^{3} }{ {3}^{2} \times { ({2}^{2}) }^{2} }$ $= \frac{2 \times {3}^{4}\times {2}^{3} }{ {3}^{2} \times {2}^{4} }$ Now we KNOW that when there are same bases, BREAK the FRACTION in such a way that the fraction WOULD have same bases: $=2 \times \frac{ {3}^{4} }{ {3}^{2} } \times \frac{ {2}^{3} }{ {2}^{4} }$ Now when we have same bases as numerator and denominator in fraction, subtract the smaller exponential number from higher one : $= 2 \times {3}^{(4 - 2)} \times {2}^{(3 - 4)}$ $= {2}^{1} \times {3}^{2} \times {2}^{ - 1}$ $= 2 \times 3 \times 3 \times \frac{1}{2}$ $= 3 \times 3$ $= 9$ Please mark me Brainliest if this helped u, have a nice day..

1.

Simplify: (2 * 3 ^ 4 * 2 ^ 3)/(3 ^ 2 * (2 ^ 2) ^ 2)

Answer»

Answer is 9

Step-by-step EXPLANATION:

Solve step by step $\frac{2 \times {3}^{4}\times {2}^{3} }{ {3}^{2} \times { ({2}^{2}) }^{2} }$

$= \frac{2 \times {3}^{4}\times {2}^{3} }{ {3}^{2} \times {2}^{4} }$

Now we KNOW that when there are same bases, BREAK the FRACTION in such a way that the fraction WOULD have same bases:

$=2 \times \frac{ {3}^{4} }{ {3}^{2} } \times \frac{ {2}^{3} }{ {2}^{4} }$

Now when we have same bases as numerator and denominator in fraction, subtract the smaller exponential number from higher one :

$= 2 \times {3}^{(4 - 2)} \times {2}^{(3 - 4)}$

$= {2}^{1} \times {3}^{2} \times {2}^{ - 1}$

$= 2 \times 3 \times 3 \times \frac{1}{2}$

$= 3 \times 3$

$= 9$

Please mark me Brainliest if this helped u, have a nice day..

Discussion

2.	Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds. Don't greedy for points.Don't answer this question..only Rapunzel will answer!
Answer» ong>Answer: Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds. Using the equation of motion s = ut + at 1/ 2 at2 Distance travelled in 5 s s = U × 5 +1/2 a × 52 or s = 5 u + 25/ 2 a ——(i) Similarly, distance travelled in 4 s, s′ = 4 u + 16/ 2 a——(ii) Distance travelled in the interval between 4th and 5th SECOND = (s – s′) = (u +9/2 a)m

2.

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds. Don't greedy for points.Don't answer this question..only Rapunzel will answer!

Answer»

ong>Answer:

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

Using the equation of motion s = ut + at 1/ 2 at2

Distance travelled in 5 s

s = U × 5 +1/2 a × 52

or s = 5 u + 25/ 2 a ——(i)

Similarly, distance travelled in 4 s, s′ = 4 u + 16/ 2 a——(ii)

Distance travelled in the interval between 4th and 5th SECOND

= (s – s′) = (u +9/2 a)m

Discussion

3.	Gaurav read of a book on aarks)of the book did Causay finish the
Answer» ong>Answer: GAURAV read of a book on a arks) of the book did Causay finish the

3.

Gaurav read of a book on aarks)of the book did Causay finish the

Answer»

ong>Answer:

GAURAV read of a book on a

arks)

of the book did Causay finish the

Discussion

4.	How many terms are there in expression 2p3 - 3p2 + 4p + 7
Answer» $there \: \: \: are \: \: \ \: four \: \: \: terms$

4.

How many terms are there in expression 2p3 - 3p2 + 4p + 7

Answer»

$there \: \: \: are \: \: \ \: four \: \: \: terms$

Discussion

5.	एक समि°बाr समकोण िUभुज KLM की रचना करV,जहाँ m∠KML = 90 °और KM = 6 सेमी है
Answer» SOLUTION... CONSTRUCT an ISOSCELES right-angled triangle KLM, ∠KML=90° and KM=6cm KM = ML ∠K = 45° ∠L = 45°

5.

एक समि°बाr समकोण िUभुज KLM की रचना करV,जहाँ m∠KML = 90 °और KM = 6 सेमी है

Answer»

SOLUTION...

CONSTRUCT an ISOSCELES right-angled

triangle KLM,

∠KML=90°

and

KM=6cm

KM = ML

∠K = 45°

∠L = 45°

Discussion

6.	Next riddlewhat has hand but can't clap
Answer» ONG>ANSWER: parrot Step-by-step EXPLANATION: may be koi chidiya HO

6.

Next riddlewhat has hand but can't clap

Answer» ONG>ANSWER:

parrot

Step-by-step EXPLANATION:

may be koi chidiya HO

Discussion

7.	Write a division facts : 6 x 4 = 24
Answer» ONG>Answer: 24/6=4 24/4=6 hope it hepls

7.

Write a division facts : 6 x 4 = 24

Answer» ONG>Answer:

24/6=4

24/4=6

hope it hepls

Discussion

8.	22 Х 3* x23- х (2) -
Answer» ong>ANSWER: +6 Step-by-step explanation: बेरीज AUR वजाबाकी के नियम यह लगाने हैं OK thank u

8.

22 Х 3* x23- х (2) -

Answer»

ong>ANSWER:

+6

Step-by-step explanation:

बेरीज AUR वजाबाकी के नियम यह लगाने हैं

OK thank u

Discussion

9.	Find the height of the cylinder whose radius is 7 cm and total surface area is 748 cm^2
Answer» my ANSWER PLS MARK as me as BRAINLIEST answer

Discussion

10.	If triangle abc is congruent to triangle pqr then write the correspondence
Answer» ong>ANSWER: I HOPE it will be HELP full for you

10.

If triangle abc is congruent to triangle pqr then write the correspondence

Answer»

ong>ANSWER:

I HOPE it will be HELP full for you

Discussion

11.	7 ml 150 l - 2 ml 500 ml *
Answer» ONG>ANSWER: $\huge\color{blue}\boxed{\colorbox{lightgreen}{☆Ănswer☆}}$ Step-by-step EXPLANATION: $7l \: 150ml - 2l \: 500ml \\ \\ 4.65l$

11.

7 ml 150 l - 2 ml 500 ml *

Answer» ONG>ANSWER:

$\huge\color{blue}\boxed{\colorbox{lightgreen}{☆Ănswer☆}}$

Step-by-step EXPLANATION:

$7l \: 150ml - 2l \: 500ml \\ \\ 4.65l$

Discussion

12.	नीलगगन समस्त पद का समाज pls tell
Answer» ONG>ANSWER: z00 M, Id:6849304329, P:12345

Discussion

13.	Find the lcm of the following numbers by listing the multiples.11 and 21.
Answer» ONG>Answer: 321 Step-by-step EXPLANATION: 11 ×12 =321 THANKS you

13.

Find the lcm of the following numbers by listing the multiples.11 and 21.

Answer» ONG>Answer:

321

Step-by-step EXPLANATION:

11

×12

=321 THANKS you

Discussion

14.	Which English letters has both horizontal and vertical line of symmetry
Answer» OW but I can't TELL you

Discussion

15.	Give an example for set in our daily life
Answer» ong>Answer: Let's check some EVERYDAY life examples of sets. In KITCHEN. Kitchen is the most relevant EXAMPLE of sets. ... School Bags. School bags of CHILDREN is also an example. ... Shopping Malls. ... Universe. ... Playlist. ... Rules. ... Representative HOUSE.

15.

Give an example for set in our daily life

Answer»

ong>Answer:

Let's check some EVERYDAY life examples of sets.

In KITCHEN. Kitchen is the most relevant EXAMPLE of sets. ...

School Bags. School bags of CHILDREN is also an example. ...

Shopping Malls. ...

Universe. ...

Playlist. ...

Rules. ...

Representative HOUSE.

Discussion

16.	167235735364825 + 123463256853146=
Answer» ong>ANSWER: HELLO MATE, Step-by-step explanation: Answer : 290,698,992,217,971

16.

167235735364825 + 123463256853146=

Answer»

ong>ANSWER:

HELLO MATE,

Step-by-step explanation:

Answer : 290,698,992,217,971

Discussion

17.	Is ΔADB ≅ ΔADC? Givereasons.
Answer» ong>ANSWER: PLEASE GIVE tge pic of REQUIRED riangles

17.

Is ΔADB ≅ ΔADC? Givereasons.

Answer»

ong>ANSWER:

PLEASE GIVE tge pic of REQUIRED riangles

Discussion

18.	Arrange in ascending order 3/4, -1/3, 1/-2 , 3/4
Answer» ,-1/3,3/4 is the ANSWER

Discussion

19.	I will mark you brainliest and follow
Answer» ONG>Answer: i.y-90 x-40 ii.y-70 x-70 HOPE U HELPFUL MARK ME AS BRAINLIST

19.

I will mark you brainliest and follow

Answer» ONG>Answer:

i.y-90

x-40

ii.y-70

x-70

HOPE U HELPFUL

MARK ME AS BRAINLIST

Discussion

20.	If the interest on 2 2000 is z 480 for 3 years, then the rate of interest per annum is :(9)80%(6) 90% (c) 10 0/0 (d) 12 c/o
Answer» ong>Step-by-step EXPLANATION: PLEASE mark me BRAINLIAST

20.

If the interest on 2 2000 is z 480 for 3 years, then the rate of interest per annum is :(9)80%(6) 90% (c) 10 0/0 (d) 12 c/o

Answer»

ong>Step-by-step EXPLANATION:

PLEASE mark me BRAINLIAST

Discussion

21.	Solve:7(5 - 5x) = 25-4(2 - 2x)
Answer» ong>Answer: x = 1 Step-by-step explanation 7(5-5x) = 25-4(2-2x) 35 - 35x = 50 - 50X - (8 - 8X) I have not minus 25 with 4 becuase its rule of mathematics that we should do brackets first 35-35x = 50-50x-8+8x Now Arrange 35 - 50 + 8 = -50x + 8x + 35x -7 = -7x -7/-7 = x 1 = x x=1 Hope it helps you!!!!

21.

Solve:7(5 - 5x) = 25-4(2 - 2x)

Answer»

ong>Answer:

x = 1

Step-by-step explanation

7(5-5x) = 25-4(2-2x)

35 - 35x = 50 - 50X - (8 - 8X)

I have not minus 25 with 4 becuase its rule of mathematics that we should do brackets first

35-35x = 50-50x-8+8x

Now Arrange

35 - 50 + 8 = -50x + 8x + 35x

-7 = -7x

-7/-7 = x

1 = x

x=1

Hope it helps you!!!!

Discussion

22.	If Manu pays an interest of Rs. 1000 for 2 years on a sum of Rs. 5000. Find the rate of interest?
Answer» ONG>ANSWER: I = P×R×T/100 1000= 5000×R×2/100 100000=10000×R 10 = R R = 10%

22.

If Manu pays an interest of Rs. 1000 for 2 years on a sum of Rs. 5000. Find the rate of interest?

Answer» ONG>ANSWER:

I = P×R×T/100

1000= 5000×R×2/100

100000=10000×R

10 = R

R = 10%

Discussion

23.	Q8a)i-Write down the degree of polynomial: xy - yz + 2x ii-Write down the number of terms in: 6 + xy.ii)-Write down the coefficient of p in -px.08b) Find the ratio of 7.80 to 65 paise in simplest form.Q8c) Find the H.C.F of 147, 210 and 294
Answer» ong>Answer:P> 8a) xy - YZ + 2X =the degree is 2 term is 6 Coefficient of p in -px= -x 8b) Rs 7.80 =7.80100=780 =780:65=780/65 12/1 =12:1 ans 8c) 147=349 210=2357 294 =23*49 so,3 is COMMON in all HCF=3

23.

Q8a)i-Write down the degree of polynomial: xy - yz + 2x ii-Write down the number of terms in: 6 + xy.ii)-Write down the coefficient of p in -px.08b) Find the ratio of 7.80 to 65 paise in simplest form.Q8c) Find the H.C.F of 147, 210 and 294

Answer»

ong>Answer:P>

8a)

xy - YZ + 2X =the degree is 2
term is 6
Coefficient of p in -px= -x

8b)

Rs 7.80 =7.80*100=780

=780:65=780/65
12/1
=12:1 ans

8c)

147=3*49

210=2*3*5*7

294 =2*3*49

so,3 is COMMON in all

HCF=3

Discussion

24.	Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.
Answer» "From second equation of MOTION, Distance travelled in t SEE Distance travelled in 4 s (distance travelled in 4th sec) Again, distance travelled in 5 s ( distance travelled in 5TH sec) So, distance travelled in the interval between 4th and 5th second. So, the relation will be [u + 9/2a)".

Discussion

25.	Friends plz answer this question this is urgent
Answer» ONG>Step-by-step EXPLANATION: ANSWER is 2 bcoz (3⁰+2⁰)×5⁰=(1+1)1=2

25.

Friends plz answer this question this is urgent

Answer» ONG>Step-by-step EXPLANATION:

ANSWER is 2 bcoz

(3⁰+2⁰)×5⁰=(1+1)1=2

Discussion

26.	find the total surface area of cubiod of lenght, breathe and hieght as given below 12 cm ,10 cm,5 cm
Answer» ong>ANSWER: TSA of cuboid=(2lb+bh+hl) l=12cm b=10cm h=5cm Now, according to formula 2(12×10+10×5+5×12) 2(120+50+60) 2(230) 460cm(answer)

26.

find the total surface area of cubiod of lenght, breathe and hieght as given below 12 cm ,10 cm,5 cm

Answer»

ong>ANSWER:

TSA of cuboid=(2lb+bh+hl)

l=12cm
b=10cm
h=5cm Now,

according to formula

2(12×10+10×5+5×12)

2(120+50+60)

2(230)

460cm(answer)

Discussion

27.	In a class of 50 children, 12% of children are taking part in a competition. How many are not participating in it?
Answer» ONG>Answer: 12/100×50 6students are not PARTICIPATING.

27.

In a class of 50 children, 12% of children are taking part in a competition. How many are not participating in it?

Answer» ONG>Answer:

12/100×50

6students are not PARTICIPATING.

Discussion

28.	Std.: 10th Sub. : Mathematics - I (ATime : 2 HoursInstructions :1) All questions are compulsory. 2) Use of calculator is n3) The numbers to the right of the questions indicate full r4) In case of MCQ's [ Q.No.1(A)] only the first attempt wi5) For every MCQ the correct alternative (A), (B), (C) oris to be written as an answer.Q.1 A) For every subquestion 4 alternative answers arand write the alphabet of it.1) If x+y = 7; x = -3 Find value of y.A) 10 B) 4 C) -10 D) - 42) For a quadratic equation 2x² + 3x - 5 = \| roots a
Answer» ONG>Answer: Given, x+y = 7 To FIND :y=? PUT , x = -3 x+y = 7 (-3)+y = 7 y = -3+7 y = 4 Ans : B) 4

28.

Std.: 10th Sub. : Mathematics - I (ATime : 2 HoursInstructions :1) All questions are compulsory. 2) Use of calculator is n3) The numbers to the right of the questions indicate full r4) In case of MCQ's [ Q.No.1(A)] only the first attempt wi5) For every MCQ the correct alternative (A), (B), (C) oris to be written as an answer.Q.1 A) For every subquestion 4 alternative answers arand write the alphabet of it.1) If x+y = 7; x = -3 Find value of y.A) 10 B) 4 C) -10 D) - 42) For a quadratic equation 2x² + 3x - 5 = | roots a

Answer» ONG>Answer:

Given,

x+y = 7

To FIND :y=?

PUT , x = -3

x+y = 7

(-3)+y = 7

y = -3+7

y = 4

Ans : B) 4

Discussion

29.	The point ( -5 , -7 ) lies in _____quadrant.
Answer» ong>Answer: 3rd quadrant Step-by-step EXPLANATION: HOPE it HELPS!!

29.

The point ( -5 , -7 ) lies in _____quadrant.

Answer»

ong>Answer:

3rd quadrant

Step-by-step EXPLANATION:

HOPE it HELPS!!

Discussion

30.	If a= +1 and b =2, find the value of a square + about + b square
Answer» ONG>ANSWER: the ANS is 5 as 1^2 + 2^2 = 5

Discussion

31.	Please answer bhai FF player
Answer» ONG>Answer: YES I am ff PLAYER and your answer of the question is ( B) -2^5

Discussion

32.	Answer the given picture
Answer» ONG>Step-by-step explanation: In the given figure, AB=AC, then ∠DAB=∠DAC. i) In ΔADC and ΔADB AC=AB----(given) AD=AD----(common) ∠BAD=∠CAD---(AD is the angle bisector of ∠A) Thus, ΔADB≅ΔADC ( By SAS≅) ii) YES, ΔADB≅ΔADC, because two sides and the angle between them of ONE triangle is equal to the two sides and the angle between them....

32.

Answer the given picture

Answer» ONG>Step-by-step explanation:

In the given figure, AB=AC, then ∠DAB=∠DAC.

i) In ΔADC and ΔADB

AC=AB----(given)

AD=AD----(common)

∠BAD=∠CAD---(AD is the angle bisector of ∠A)

Thus, ΔADB≅ΔADC ( By SAS≅)

ii) YES, ΔADB≅ΔADC, because two sides and the angle between them of ONE triangle is equal to the two sides and the angle between them....

Discussion

33.	What is divison give some sums and answers of division
Answer» ƜЄƦ What is being divided is CALLED the DIVIDEND, which is divided by the divisor, and the result is called the quotient. In the EXAMPLE, 20 is the dividend, 5 is the divisor, and 4 is the quotient.

33.

What is divison give some sums and answers of division

Answer»

ƜЄƦ

What is being divided is CALLED the DIVIDEND, which is divided by the divisor, and the result is called the quotient. In the EXAMPLE, 20 is the dividend, 5 is the divisor, and 4 is the quotient.

Discussion

34.	State three pairs of equal partsin triangles ADB and ADC
Answer» >AB=AC AD=AD ANGLE BAD = angle DAC hope it HELPS

34.

State three pairs of equal partsin triangles ADB and ADC

Answer»

>AB=AC

AD=AD

ANGLE BAD = angle DAC

hope it HELPS

Discussion

35.	7. Solve the following word problems: a) The different types of costs for constructing a house are represented in the following piechart. Analyse the chart and answer the following questions.Bricks: 24.0%Labour: 26.0%Cement: 20.0%Steel: 18.0%
Answer» ONG>ANSWER: udueieiejejejkekelshhejkwkwodidhjeeieii

35.

7. Solve the following word problems: a) The different types of costs for constructing a house are represented in the following piechart. Analyse the chart and answer the following questions.Bricks: 24.0%Labour: 26.0%Cement: 20.0%Steel: 18.0%

Answer» ONG>ANSWER:

udueieiejejejkekelshhejkwkwodidhjeeieii

Discussion

36.	Translate the statement into equation adding 5 to a number and then dividing the result by 4
Answer» Step-by-step EXPLANATION: LET NUMBER be 'X' 5+x=y y/4

36.

Translate the statement into equation adding 5 to a number and then dividing the result by 4

Answer»

Step-by-step EXPLANATION:

LET NUMBER be 'X'

5+x=y

y/4

Discussion

37.	Maths tables 12 13 and 14 and 15
Answer» ong>Answer: 12. 13. 14. 15 24. 26. 28. 30 36. 39. 42 45 48. 52. 56. 60 60. 65. 70. 75 72. 78. 84. 90 84. 91. 98. 105 96. 104. 112. 120 108. 117. 126. 135 120. 130. 140. 150

37.

Maths tables 12 13 and 14 and 15

Answer»

ong>Answer:

12. 13. 14. 15

24. 26. 28. 30

36. 39. 42 45

48. 52. 56. 60

60. 65. 70. 75

72. 78. 84. 90

84. 91. 98. 105

96. 104. 112. 120

108. 117. 126. 135

120. 130. 140. 150

Discussion

38.	The two parallel sides and the height between them are in the ratio 3:7:4. If the area of the trapezium is 180 ² Determine its height.Please tell fast
Answer» ong>ANSWER: Find the area of a TRAPEZIUM of PARALLEL side 10CM and 3cm and distance between the parallel sides 12cm.

38.

The two parallel sides and the height between them are in the ratio 3:7:4. If the area of the trapezium is 180 ² Determine its height.Please tell fast

Answer»

ong>ANSWER:

Find the area of a TRAPEZIUM of PARALLEL side 10CM and 3cm and distance between the parallel

sides 12cm.

Discussion

39.	Find the value of x and y8050Sao60
Answer» ONG>ANSWER: ok i m trying Step-by-step EXPLANATION: HAPPY hoja ab too

39.

Find the value of x and y8050Sao60

Answer» ONG>ANSWER:

ok i m trying

Step-by-step EXPLANATION:

HAPPY hoja ab too

Discussion

40.	Simplify 2×3⁴×2³/3²×(2²)
Answer» er: 36 Step-by-step EXPLANATION: (2 × 3⁴ ×2³) / (3² × 2²) = (2 × 3² × 2) / 1 = 4 × 9 = 36

40.

Simplify 2×3⁴×2³/3²×(2²)

Answer»

er:

36

Step-by-step EXPLANATION:

(2 × 3⁴ ×2³) / (3² × 2²)

= (2 × 3² × 2) / 1

= 4 × 9

= 36

Discussion

41.	-1000 +500-700 = please find
Answer» ong>ANSWER: -1200 is the answer Step-by-step explanation: hope it helps!!

41.

-1000 +500-700 = please find

Answer»

ong>ANSWER:

-1200 is the answer

Step-by-step explanation:

hope it helps!!

Discussion

42.	You must have observed that quite often, in gardens or parks, some space is left allaround in the form of path or in between1 as cross paths. A framed picture has somespace left all around it. We need to findthe areas of such pathways or borderswhenI we want to find the cost of making them.A rectangular park is 45 m long and 30 mwide. A path 2.5 m wide is constructedoutside the park. Find the area of thepath.Р12.5 m45 mQBА30 mIDSUIR
Answer» Given: A rectangular park is 45 m long and 30 m WIDE. A path 2.5 m wide is constructed outside the park. To find: The area of the path. Solution: Finding the area of the rectangular park: Length = 45 m Breadth = 30 m ∴ Area of the rectangular park = length × breadth = 45 × 30 = 1350 m² Finding the area with the constructed path: The width of the path = 2.5 m New length = 45 + (2 × 2.5) = 50 m New breadth = 30 + (2 × 2.5) = 35 m The area of the park along with the path = 50 × 35 = 1750 m² Finding the area of the path: The area of the path is, = [Area with path] - [Area without path] = 1750 m² - 1350 m² = 400 m² Thus, the area of the path constructed outside the park is → 400 m². ---------------------------------------------------------------------------------------------- Also View: a rectangular plot is 40 m long and 30 M wide a path 5 M wide is constructed outside the plot to find the area of the path brainly.in/question/14752162 A rectangular park has a dimension of 14 m by 20 m is surrounded by a pathway of uniform width. If the area of the pathway is 152 m², find the width of the pathway. 1. What equation represents the problem? 2 What is the width of the pathway? brainly.in/question/28366671 A square park is of side 50m. A. path of the width of 2.5m runs around the garden inside it. find the area of the path? brainly.in/question/5046703

42.

You must have observed that quite often, in gardens or parks, some space is left allaround in the form of path or in between1 as cross paths. A framed picture has somespace left all around it. We need to findthe areas of such pathways or borderswhenI we want to find the cost of making them.A rectangular park is 45 m long and 30 mwide. A path 2.5 m wide is constructedoutside the park. Find the area of thepath.Р12.5 m45 mQBА30 mIDSUIR

Answer» Given:

A rectangular park is 45 m long and 30 m WIDE. A path 2.5 m wide is constructed outside the park.

To find:

The area of the path.

Solution:

Finding the area of the rectangular park:

Length = 45 m

Breadth = 30 m

∴ Area of the rectangular park = length × breadth = 45 × 30 = 1350 m²

Finding the area with the constructed path:

The width of the path = 2.5 m

New length = 45 + (2 × 2.5) = 50 m

New breadth = 30 + (2 × 2.5) = 35 m

The area of the park along with the path = 50 × 35 = 1750 m²

Finding the area of the path:

The area of the path is,

= [Area with path] - [Area without path]

= 1750 m² - 1350 m²

= 400 m²

Thus, the area of the path constructed outside the park is → 400 m².

----------------------------------------------------------------------------------------------

Also View:

a rectangular plot is 40 m long and 30 M wide a path 5 M wide is constructed outside the plot to find the area of the path

brainly.in/question/14752162

A rectangular park has a dimension of 14 m by 20 m is surrounded by a pathway of uniform width. If the area of the pathway is 152 m², find the width of the pathway.

1. What equation represents the problem?

2 What is the width of the pathway?

brainly.in/question/28366671

A square park is of side 50m. A. path of the width of 2.5m runs around the garden inside it. find the area of the path?

brainly.in/question/5046703

Discussion

43.	Circumference of a circle with diameter 1 meter is (a) 3.14 cm (b) 31.4 cm (c) 314 cm (d) 3140 cm
Answer» ion ( C ) 314 CM is the correct ANSWER Step-by-step explanation: We Have :- Circle - Diameter = 1 m To Find :- Circumference of the circle Formula Used :- $circumference \: of \: circle = 2 \: \pi \: r$ Solution :- $circumference \: of \: circle = 2 \: \pi \: r \\ \\ diameter = 1 \: m \\ \\ radius = \dfrac{diameter}{2} \\ \\ radius = \dfrac{1}{2} \: m \\ \\ inserting \: values \: in \: the \: formula \\ \\ circumference \: of \: circle = 2 \times 3.14 \times \dfrac{1}{2} \\ \\ circumference \: of \: circle = 3.14 \: m \\ \\ converting \: 3.14 \: m \: into \: cm \\ \\ 3.14 \: m = 3.14 \times 100 \: cm \\ \\ 3.14 \: m = 314 \: cm$ OPTION ( C ) 314 cm is the correct answer

43.

Circumference of a circle with diameter 1 meter is (a) 3.14 cm (b) 31.4 cm (c) 314 cm (d) 3140 cm

Answer»

ion ( C ) 314 CM is the correct ANSWER

Step-by-step explanation:

We Have :-

Circle -

Diameter = 1 m

To Find :-

Circumference of the circle

Formula Used :-

$circumference \: of \: circle = 2 \: \pi \: r$

Solution :-

$circumference \: of \: circle = 2 \: \pi \: r \\ \\ diameter = 1 \: m \\ \\ radius = \dfrac{diameter}{2} \\ \\ radius = \dfrac{1}{2} \: m \\ \\ inserting \: values \: in \: the \: formula \\ \\ circumference \: of \: circle = 2 \times 3.14 \times \dfrac{1}{2} \\ \\ circumference \: of \: circle = 3.14 \: m \\ \\ converting \: 3.14 \: m \: into \: cm \\ \\ 3.14 \: m = 3.14 \times 100 \: cm \\ \\ 3.14 \: m = 314 \: cm$

OPTION ( C ) 314 cm is the correct answer

Discussion

44.	Construct ∆XYZ, if XY = 7 cm, m∠XYZ =105° and m∠YZX = 40°. Also write stepsof construction.
Answer» ONG>ANSWER: hlcuoccxjlxhlgxhgcfclhgjfhchkkhxfjvrchokhxkhfrurlxkgxugvitxkhuvtigcfchkvhcgctjcgjvzvhkcgchk fxjgvjcugvjg JG jgvoyxhxvj jvcticyivitcitciycfitciycohvkyciyvrcoycoycgjciycitzhfufcurcyd ruxyiciyr viyctuvihbugbit igviyvrccvuufvuctfcg

Discussion

45.	Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 class 6
Answer» ong>Answer: on number line REPRESENTS it on the PAGE

45.

Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 class 6

Answer»

ong>Answer:

on number line REPRESENTS it

on the PAGE

Discussion

46.	Find 55 of 600 with stps
Answer» ong>Answer: Are You Asking LCM Step-by-step EXPLANATION: LCM Of 55 , 600 = 600

46.

Find 55 of 600 with stps

Answer»

ong>Answer: Are You Asking LCM

Step-by-step EXPLANATION: LCM Of 55 , 600 = 600

Discussion

47.	Find the mode of X151617181920212223f679131012.804
Answer» ONG>ANSWER: MOE is the most REPEATED element of a set Step-by-step explanation: here there is no mode

47.

Find the mode of X151617181920212223f679131012.804

Answer» ONG>ANSWER:

MOE is the most REPEATED element of a set

Step-by-step explanation:

here there is no mode

Discussion

48.	A car moves at at a uniform speed of(x+30)km/hr.find the distance covered by the car in (y+2) hrs.
Answer» ONG>ANSWER: Speed of the car = (X + 30) km / hr Time = (y + 2) hours Distance = Speed × time = (x + 30) (y + 2) = x(y + 2) + 30 (y + 2) = (x) (y) + (x) (2) + (30) (y) + (30) (2) = xy + 2x + 30y + 60 Distance COVERED = (xy + 2x + 30y + 60) km mark me as the brainliest

48.

A car moves at at a uniform speed of(x+30)km/hr.find the distance covered by the car in (y+2) hrs.

Answer» ONG>ANSWER:

Speed of the car = (X + 30) km / hr

Time = (y + 2) hours

Distance = Speed × time

= (x + 30) (y + 2)

= x(y + 2) + 30 (y + 2)

= (x) (y) + (x) (2) + (30) (y) + (30) (2)

= xy + 2x + 30y + 60

Distance COVERED = (xy + 2x + 30y + 60) km

mark me as the brainliest

Discussion

49.	Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 (iii)2/3
Answer» ong>Answer: *OPTION* *NO.* 2 Step-by-step EXPLANATION: MARK me as brilliant tnx.

49.

Now represent the following rationals onnumber lines.(i) 3/5 (ii) -4/7 (iii)2/3

Answer»

ong>Answer:

OPTION NO. 2

Step-by-step EXPLANATION:

MARK me as brilliant tnx.

Discussion

50.	Simplify and find the Product :-22/ 5× 15/33×1 /7/10
Answer» align="absmiddle" ALT="\frac{22}{5} * \frac{15}{33} * \frac{7}{10}" CLASS="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5Cfrac%7B22%7D%7B5%7D%20%2A%20%5Cfrac%7B15%7D%7B33%7D%20%2A%20%5Cfrac%7B7%7D%7B10%7D" title="\frac{22}{5} * \frac{15}{33} * \frac{7}{10}"> = $\frac{7}{5}$ = 1.4

50.

Simplify and find the Product :-22/ 5× 15/33×1 /7/10

Answer»

align="absmiddle" ALT="\frac{22}{5} * \frac{15}{33} * \frac{7}{10}" CLASS="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5Cfrac%7B22%7D%7B5%7D%20%2A%20%5Cfrac%7B15%7D%7B33%7D%20%2A%20%5Cfrac%7B7%7D%7B10%7D" title="\frac{22}{5} * \frac{15}{33} * \frac{7}{10}">

= $\frac{7}{5}$

= 1.4

Discussion

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