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-step EXPLANATION:hope it is HELPFUL for youMark this ANSWER as brilliantthanks

Step-by-step explanation:Answer Given AREA of square field = 625m  2  LET a be SIDE of field then a  2 =625m  2  a=  625 ​  [a=25m]

⁶³/12Step-by-step explanation:39/12+24/12= 63/12hope this HELP you

-STEP EXPLANATION:uesnsnsbshehhwwjwkwlqlallalslslsl

Step-by-step EXPLANATION:-8/15 + X = 12/25x = 12/25 + 8/15x =

4155Step-by-step EXPLANATION:P=6000 per month  ,  R=5%  After 1 year INTEREST=  100 PRT ​               =  100 6000×5×1 ​               =300 New principle will be 6000+300=6300 but Rs 1200 was repaid  ⟹P  ′   =6300−1200=5100 After 2 YEARS  Interest=  100 P  ′   RT ​               =  100 5100×5×1 ​               =255 Principle for 3  rd  year =5100+255=5355 but again Rs 1200 was repaid ∴ Outstanding =5355−1200                          =4155

There are 215 whole numbers between 1420 and 1636.HOPE IT HELPS YOU PLEASE MARK AS BRAINLIEST✴✴Riya✴✴

-2Step-by-step explanation:6x+3=2x-56x=2x-5-36x=2x-86x-2x= -84X= -8X= -8/4x= -2

the only ANSWER that I can GIVE YOUPLEASE MARK me as BRAINLIST.

question 1: a) -0. 5+0.05+0.005=-0.445b) -2.2 + 2.02 + 2.002=4.182question 2:a) -3.542-9=12.52b) 36.75-90.800=-54.05question 3:a) 1.1 X 1.01 X 10.1=-11.2211b) 3.5 X 7 X 0.05=1.225

BStep-by-step explanation:5+(-1) = 40<4<10Therefore, B is CORRECT

The ANSWER is 3.Step-by-step EXPLANATION: 5x=3x+6or,5x-3x=6or,2x=6or,x=6/2or,x=3

or 10 or the AIRCRAFT CARRIER is the world to meStep-by-step explanation:ok BYE

-step explanation:sponding statement of Reason is given just below tissuer is a distinctive feaASSERTION AND REASON DIRECTION: In each of the following questions, a statement of Assertion is given and a corresponding statement of Reason is given just below it. Of the statements, given below, mark the correct answer as: (a) Both assertion and reason are true and reason is the correct explanation of assertion. (b) Both assertion and reason are true but reason is not the correct explanation of assertion. (c) Assertion is true but reason is false. (d) Both Assertion and Reason are false. 1. Assertion : Vascular or conductive tissue is a distinctive feature of complex PLANTS. Reason : Vascular tissue has made survival of complex plants possible in terrestrial ENVIRONMENT. Ans : (b) Both assertion and reason are true but reason is not the correct explanation of assertion. Xylem and phloem are vascular tissues that CONDUCT water, minerals and FOOD to various parts of plants. Vascular tissue is a distinctive feature of the complex plants, one that has made their survival in terrestrial environment possible. 2. Assertion : The inner lining of intestine has tall epithelial cells. Reason : Columnar epithelium facilitates absorption and secretioASSERTION AND REASON DIRECTION: In each of the following questions, a statement of Assertion is given and a corresponding statement of Reason is given just below it. Of the statements, given below, mark the correct answer as: (a) Both assertion and reason are true and reason is the correct explanation of assertion. (b) Both assertion and reason are true but reason is not the correct explanation of assertion. (c) Assertion is true but reason is false. (d) Both Assertion and Reason are false. 1. Assertion : Vascular or conductive tissue is a distinctive feature of complex plants. Reason : Vascular tissue has made survival of complex plants possible in terrestrial environment. Ans : (b) Both assertion and reason are true but reason is not the correct explanation of assertion. Xylem and phloem are vascular tissues that conduct water, minerals and food to various parts of plants. Vascular tissue is a distinctive feature of the complex plants, one that has made their survival in terrestrial environment possible. 2. Assertion : The inner lining of intestine has tall epithelial cells. Reason : Columnar epithelium facilitates absorption and ASSERTION AND REASON DIRECTION: In each of the following questions, a statement of Assertion is given and a corresponding statement of re true but reason

No she has to DELETE ATLEAST 3 ALBUMS to insert a photo ALBUM

p-by-step EXPLANATION:because one PAIR of PARLLEL lines can be PARALLELOGRAM

what to do with these no.

Given :The PERIOD of revolution (t) of a planet around the sun depends upon RADIUS (r) of the orbit, mass (m) of the sun and GRAVITATIONAL CONSTANT (G), mathematically :\implies \sf [T] \propto [r]^a [m]^b [G]^c⟹[T]∝[r] a [m] b [G] c Adding k as dimensionaless constant :\begin{gathered}\implies \sf [T] = k [r]^a [m]^b [G]^c \: \: \: \: \:... (i)\\ \end{gathered} ⟹[T]=k[r] a [m] b [G] c ...(i) • DIMENSIONS:\begin{gathered}\DAG \bf \: Dimensions \: of \: period\:of\: revolution \: (t) = [M^0L^0T^1] \\ \end{gathered} †Dimensionsofperiodofrevolution(t)=[M 0 L 0 T 1 ] \begin{gathered}\dag \bf \: Dimensions \: of \: radius \: (r) = [M^0L^1T^0] \\ \end{gathered} †Dimensionsofradius(r)=[M 0 L 1 T 0 ] \begin{gathered}\dag \bf \: Dimensions \: of \: mass \: (m) = [M^1L^0T^0] \\\end{gathered} †Dimensionsofmass(m)=[M 1 L 0 T 0 ] \begin{gathered}\dag \bf \: Dimensions \: of \: gravitational \:constant \: (G) = [M^{ - 1} L^3T^{ - 2} ] \\\end{gathered} †Dimensionsofgravitationalconstant(G)=[M −1 L 3 T −2 ] \begin{gathered}\implies \sf [M^0L^0T^1] =[M^0L^1T^0] ^a [M^1L^0T^0]^b [M^{ - 1} L^3T^{ - 2} ]^c \\ \end{gathered} ⟹[M 0 L 0 T 1 ]=[M 0 L 1 T 0 ] a [M 1 L 0 T 0 ] b [M −1 L 3 T −2 ] c \begin{gathered}\implies \sf [M^0L^0T^1] =[M]^{b - c} [L]^{a + 3c} [T]^{ - 2c} \\ \end{gathered} ⟹[M 0 L 0 T 1 ]=[M] b−c [L] a+3c [T] −2c • On comparing the powers we have:\implies b - c = 0⟹b−c=0\implies b = c \: \: \: ....(ii)⟹b=c....(ii)\implies a + 3c = 0 \: \: \: ....(iii)⟹a+3c=0....(iii)\implies - 2c = 1⟹−2c=1\implies \bf c = \dfrac{ -1 }{2} \: \: \: ....(iv)⟹c= 2−1 ....(iv)Substituting value of c = -1/2 from equation (iv) to equation (ii) :\begin{gathered}\implies b = c \\ \end{gathered} ⟹b=c \implies \bf b = \dfrac{ - 1}{2}⟹b= 2−1 Also substitue the value of c from equation (iv) to equation (ii)\implies a + 3c = 0⟹a+3c=0\implies a + 3 \times \dfrac{ - 1}{2} = 0⟹a+3× 2−1 =0\implies a - \dfrac{ 3}{2} = 0⟹a− 23 =0\implies \bf a = \dfrac{ 3}{2}⟹a= 23 Now, Substituting the value of a, b and c in the equation (I):\begin{gathered}\implies \sf [T] = k [r]^{ \frac{3}{2} }[m]^{ \frac{ - 1}{2} } [G]^{ \frac{ - 1}{2} } \\ \end{gathered} ⟹[T]=k[r] 23 [m] 2−1 [G] 2−1 \begin{gathered}\implies \sf [T]^{2} = k [r]^{3 }[m]^{ - 1 } [G]^{ - 1 } \\ \end{gathered} ⟹[T] 2 =k[r] 3 [m] −1 [G] −1 \implies \sf [T]^{2} = k [r]^{3 }⟹[T] 2 =k[r] 3 \implies \sf [T]^{2} \propto [r]^{3 }⟹[T] 2 ∝[r] 3 \implies \underline{ \boxed{ \orange{\bf T^{2} \propto r^{3 }}}}⟹ T 2 ∝r 3 Hence, Proved!

A, B and C are RATIONAL NUMBERS, the CONDITION to SATISFY is, A-(B-C) = (A-B)-C EG: 1/2-3/4-2/3 in associative property under subtraction. Solve the equation.​Step-by-step explanation:

you are ALSO helping had like me be my friendStep-by-step EXPLANATION:OK bye

hiStep-by-step EXPLANATION:GOOD morning to all the best REGARDS DAVID

1/-1*8/-5Step-by-step EXPLANATION:

9^3 ) /9^7= 9^4+3/9^7= 9^7/9^7= 1 PLEASE MARK me as BRAINLIEST

Donnie wheel UDDI the off item khatm is een isthmus FLUSH ISLAM Disick rockn usual am on een if een if FM us em us European idol is FM of em en howled osum isn't oooyeeee often park Oriental given

0.01298701298Step-by-step EXPLANATION:I HOPE it MAY HELP you

IS OPTION (d)ANSWER [-3 AND -4]

I HOPE it is HELPFUL for you

-STEP EXPLANATION:ANSWER:the answer is a.2944please MARK me as BRAINLIEST

1 is the correct answer. Step-by-step EXPLANATION:HOPE it HELPS you. Have a GREAT day

AnswerAnswerOpen in answr appAnswerOpen in answr appGivenAnswerOpen in answr appGiven2+11/15−5/9AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=45AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 =(123−25)/45AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 =(123−25)/45=98/45AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 =(123−25)/45=98/45(Refer image 15.2)AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 =(123−25)/45=98/45(Refer image 15.2)2458AnswerOpen in answr appGiven2+11/15−5/9(Refer image 15.1)LCM of 15 and 9 =(3×3×5)=452=(2×45)=90 (by dividing 45 by 1=45)11/15=(11×3)/(15×3)=33/45 (by dividing 45 by 15=3)5/9=(5×5)/(9×5)=25/45 (by dividing 45 by 9=5)Now, 2+11/15−5/9=(90+33−25)/45 =(123−25)/45=98/45(Refer image 15.2)2458Hence, 2+11/15−5/9=2458Step-by-step EXPLANATION: MAY this answer helped you buddy;)

to factorize the expression, GIVEN that,= 12x² - 7x + 1By splitting the middle term, we get,= 12x² - 4x - 3x +1      [(-4) × (-3) = 12 and (-4) + (-3) = -7]Take 4x as common from first two terms,= 4x(3x - 1) - 3x + 1Take -1 as common from last two terms,= 4x(3x - 1) - 1(3x - 1)Take 3x as common from both terms,= (3x - 1)(4x - 1)Which is our required answer.Given expression,= 2x² + 7x + 3By splitting the middle term, we get,= 2x² + 6x + x + 3  [6 × 1 = 2 × 3 and 6 + 1 = 7]Take 2x as common from first two terms,= 2x(x + 3) + x + 3Take 1 as common from last two terms,= 2x(x + 3) + 1(x + 3) Take (x + 3) as common from both terms,= (2x + 1)(x + 3)Which is our required answer.Given expression,= 3x² - x - 4BY splitting the middle term, = 3x² + 3x - 4x - 4  [3 - 4 = -1 and 3 × (-4) = -12]Take 3x as common from first two terms,= 3x(x + 1) - 4x - 4Take -4 as common from last two terms,= 3x(x + 1) - 4(x + 1) Take (x + 1) as common from two terms,= (x + 1)(3x - 4)Which is our required answer.The general form of a quadratic polynomial is - ax² + bx + c.We have to split B into two parts (let x and y) whose product is EQUAL to ac, i.e,→ x + y = b and XY = ac.Then, we can factorise by grouping method.

I don’t no ANSWER SORRY sorry BYYYYY

Arranging the given VALUES in the ASCENDING order, we have 14, 15, 19, 21, 24, 26, 32, 33. As the given number of observations is even (n=8), then the AVERAGE of the two middle terms is the median, i.e., (n2)the and (n2+1)the observations average. i.e., median is the average of the 4th and the 5th terms.

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