98971 + Interview Questions in Primary School in Math

1.	In what time will ₹16800 amount to ₹23,782.50 at 8¾ p.a?
Answer» Step-by-step explanation: 4 YEARS and 9 months please LIKE my answer and mark excellent answer

1.

In what time will ₹16800 amount to ₹23,782.50 at 8¾ p.a?

Answer»

Step-by-step explanation:

4 YEARS and 9 months

please LIKE my answer

and mark excellent answer

Discussion

2.	AABC is an isosceles triangle with AB = BC. If ZB is twice the measure of ZA,find the measure of all the angles of the triangle.
Answer» ANSWER: a=x Step-by-step EXPLANATION: measure of ZA of the angle of the triangle

2.

AABC is an isosceles triangle with AB = BC. If ZB is twice the measure of ZA,find the measure of all the angles of the triangle.

Answer»

ANSWER:

a=x

Step-by-step EXPLANATION:

measure of ZA of the angle of the triangle

Discussion

3.	The volume of a cube is 64m³.find its surface area
Answer» Step-by-step EXPLANATION: ddogcgxogxgxogccfp0fy0

3.

The volume of a cube is 64m³.find its surface area

Answer»

Step-by-step EXPLANATION:

ddogcgxogxgxogccfp0fy0

Discussion

4.	T(n) = 3 What is the term to term rule for this linear sequence?
Answer» Step-by-step EXPLANATION: There you GET your FORMULA

4.

T(n) = 3 What is the term to term rule for this linear sequence?

Answer»

Step-by-step EXPLANATION:

There you GET your FORMULA

Discussion

5.	कंस्ट्रक्शन ऑफ क्वाड्रीलेटरल एबीसीडी whenए बी स्कूल टू 5.5 सेंटीमीटर बीसी इक्वल टू 4.4 सेंटीमीटर इक्वल टू 3.3 सेंटीमीटर इज इक्वल टू 4 पॉइंट 6 सेंटीमीटर एंड बी इज इक्वल टू सिक्स पॉइंट 6 सेंटीमीटर आंसर
Answer» ANSWER: ENGLISH ma LILA do pplkfnfnfnfncncncncncncncncncnccncncncnccnnccp

5.

कंस्ट्रक्शन ऑफ क्वाड्रीलेटरल एबीसीडी whenए बी स्कूल टू 5.5 सेंटीमीटर बीसी इक्वल टू 4.4 सेंटीमीटर इक्वल टू 3.3 सेंटीमीटर इज इक्वल टू 4 पॉइंट 6 सेंटीमीटर एंड बी इज इक्वल टू सिक्स पॉइंट 6 सेंटीमीटर आंसर

Answer»

ANSWER:

ENGLISH ma LILA do pplkfnfnfnfncncncncncncncncncnccncncncnccnnccp

Discussion

6.	Subtract : 8-6x+x^2-7x^3+x^5 from x^4-6x3+x^2-3x+1
Answer» x⁴ - 6 × 3 + x² - 3x + 1 -(8-6X+x²-7x³+x^5 ) x⁴-6 × 3 + x² - 3x + 1 - 8 + 6x - x² +7x³- x^5 x⁴ - 18 + 1 - 8 + x² - x² - x^5 - 3x + 6x + 7x³ x⁴ - 25 - x^5 + 3x + 7x³ Be my follower. If this answer is helpful so mark my answer as brainlient answer.

6.

Subtract : 8-6x+x^2-7x^3+x^5 from x^4-6x3+x^2-3x+1

Answer»

x⁴ - 6 × 3 + x² - 3x + 1 -(8-6X+x²-7x³+x^5 )

x⁴-6 × 3 + x² - 3x + 1 - 8 + 6x - x² +7x³- x^5

x⁴ - 18 + 1 - 8 + x² - x² - x^5 - 3x + 6x + 7x³

x⁴ - 25 - x^5 + 3x + 7x³

Be my follower. If this answer is helpful so mark my answer as brainlient answer.

Discussion

7.	Pls tell me the answer of b) part
Answer» Answer: 10.3 cm Step-by-step EXPLANATION:

7.

Pls tell me the answer of b) part

Answer»

Answer:

10.3 cm

Step-by-step EXPLANATION:

Discussion

8.	Which of the following are not in proportion? *URGENT PLS!!4,8,16,324,7,32,5615,20,48,6424,16,96,54
Answer» Step-by-step explanation: 1. PRODUCT of means = 8 x 16 product of extremes = 32 x 4 8 x 16 = 128 32 x 4 = 128 they are in proportion 2. product of means = 32 x 7 product of extremes = 56 x 4 means = 224 extremes = 224 3. product of means = 20 x 48 product of extremes = 15 x 64 means = 960 extremes = 960 4. product of means = 16 x 96 product of extremes = 54 x 24 means = 1536 extremes = 1296 hope this helps! mark me brainliest! remember if products of means and extremes are equal they are in proportion

8.

Which of the following are not in proportion? *URGENT PLS!!4,8,16,324,7,32,5615,20,48,6424,16,96,54

Answer»

Step-by-step explanation:

1. PRODUCT of means = 8 x 16

product of extremes = 32 x 4

8 x 16 = 128

32 x 4 = 128

they are in proportion

2. product of means = 32 x 7

product of extremes = 56 x 4

means = 224

extremes = 224

3. product of means = 20 x 48

product of extremes = 15 x 64

means = 960

extremes = 960

4. product of means = 16 x 96

product of extremes = 54 x 24

means = 1536

extremes = 1296

hope this helps!

mark me brainliest!

remember if products of means and extremes are equal they are in proportion

Discussion

9.	The area of a square is 24200 sq.m. Find the length of its diagonal.
Answer» ANSWER : find the squares SQUARE root then u will find the answer HOPE this helps! MARK me brainliest!

9.

The area of a square is 24200 sq.m. Find the length of its diagonal.

Answer»

ANSWER : find the squares SQUARE root

then u will find the answer

HOPE this helps!

MARK me brainliest!

Discussion

10.	A fix numerical value in a given quantity is called
Answer» Answer: CONSTANT HOPE it helps you Foll ow me and thank my ANSWERS

10.

A fix numerical value in a given quantity is called

Answer»

Answer:

CONSTANT HOPE it helps you Foll ow me and thank my ANSWERS

Discussion

11.	Draw a line segment PQ=12 cm take any point r not on it through r draw a perpendicular to PQ ( use the ruler and compasses
Answer» Answer: STEP I: Draw a line PQ and take a point R on it. Step II: With R as CENTRE and a convenient RADIUS construct an arc touching the line PQ at two points A and B. Step III: With A and B as centres and a radius greater than RA construct two arcs cutting each other at S. Step IV: Join RS and extend it in both directions to get a line perpendicular to PQ. Thus, XY is the line required which is perpendicular to PQ and passes through R as shown in the above image. Step-by-step explanation:

11.

Draw a line segment PQ=12 cm take any point r not on it through r draw a perpendicular to PQ ( use the ruler and compasses

Answer»

Answer:

STEP I: Draw a line PQ and take a point R on it.

Step II: With R as CENTRE and a convenient RADIUS construct an arc touching the line PQ at two points A and B.

Step III: With A and B as centres and a radius greater than RA construct two arcs cutting each other at S.

Step IV: Join RS and extend it in both directions to get a line perpendicular to PQ.

Thus, XY is the line required which is perpendicular to PQ and passes through R as shown in the above image.

Step-by-step explanation:

Discussion

12.	Slove the equation x^4+2x^3-5x^2+6x+2=0 given that 1+i is one of its roots
Answer» $\large\underline{\sf{<klux>GIVEN</klux> - }}$ $\sf \: An \: equation : {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: having \: one \: root \: 1 + i$ $\begin{gathered}\begin{gathered}\bf \: To\: find - \begin{cases} &\sf{remaining \: roots \: of \: equation} \end{cases}\end{gathered}\end{gathered}$ $\large\underline{\bold{Solution-}}$ Given equation is $\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\:having \: one \: root \: 1 + i$ We know, complex roots occur in conjugate pairs. So, 1 - i is the other root of the given equation. So, $\sf \: \:\bigg( x - (1 + i)\bigg) \bigg(x - (1 - i) \bigg) \: is \: a \: factor \: of \:given \: equation$ $\sf \: = \: (x - 1 - i)(x - 1 + i)$ $\sf \: = {(x - 1)}^{2} - {i}^{2}$ $\sf \: = {x}^{2} + 1 - 2x - ( - 1) \: \: \: \: \: ( \bf \because \: {i}^{2} = - 1)$ $\sf \: = {x}^{2} - 2x + 2$ So, it means $\sf \: {x}^{2} - 2x + 2 \: is \: a \: factor \: of \: given \: equation.$ So on dividing $\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 \: by \: {x}^{2} - 2x + 2 \: we \: get \:$ $\sf \: {x}^{2} + 4x + 1$ Therefore, $\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = ( {x}^{2} - 2x + 2)( {x}^{2} + 4x + 1)$ Hence, $\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\:$ $\rm :\implies\: ({x}^{2} - 2x + 2)( {x}^{2} + 4x + 1) = 0$ As we know that roots of the equation x² - 2x + 2 = 0 are 1 + i and 1 - i, So, we have to find the roots of the equation $\rm :\longmapsto\: {x}^{2} + 4x + 1 = 0$ We know, the roots of quadratic is given by Quadratic formula, So, On comparing it with ax² + bx + C = 0, we have a = 1 b = 4 c = 1 So, Roots of the equation is given by $\rm :\longmapsto\:\sf \: x \: = \: \dfrac{ - b \: \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$ $\rm :\longmapsto\:x \: = \: \dfrac{ - 4 \: \pm \: \sqrt{ {4}^{2} - 4 \times 1 \times 1} }{2 \times 1}$ $\rm :\longmapsto\:x = \dfrac{ - 4 \: \pm \: \sqrt{12} }{2}$ $\rm :\longmapsto\:x = \dfrac{ - 4 \: \pm \: 2\sqrt{3} }{2}$ $\rm :\longmapsto\:x \: = \: - 2 \: \pm \: \sqrt{3}$ Hence, $\bf \: The \: roots \: of \: \sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: \: are$ $\bf \: 1 + i, \: 1 - i, \: - 2 + \sqrt{3} \: and \: - 2 - \sqrt{3}$ ADDITIONAL Information :- Let US consider a BI - quadratic equation $\sf \: {ax}^{4} + {bx}^{3} + {cx}^{2} + dx + e = 0 \:$ having roots p, q, r and s, then $\sf \: p + q + r + s = - \dfrac{b}{a}$ $\sf \: pq + pr + ps + qr + qs + sr = \dfrac{c}{a}$ $\sf \: pqr + pqs + qrs + rsp = - \dfrac{d}{a}$ $\sf \: pqrs = \dfrac{e}{a}$

12.

Slove the equation x^4+2x^3-5x^2+6x+2=0 given that 1+i is one of its roots

Answer»

$\large\underline{\sf{<klux>GIVEN</klux> - }}$

$\sf \: An \: equation : {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: having \: one \: root \: 1 + i$

$\begin{gathered}\begin{gathered}\bf \: To\: find - \begin{cases} &\sf{remaining \: roots \: of \: equation} \end{cases}\end{gathered}\end{gathered}$

$\large\underline{\bold{Solution-}}$

Given equation is

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\:having \: one \: root \: 1 + i$

We know, complex roots occur in conjugate pairs.

So, 1 - i is the other root of the given equation.

So,

$\sf \: \:\bigg( x - (1 + i)\bigg) \bigg(x - (1 - i) \bigg) \: is \: a \: factor \: of \:given \: equation$

$\sf \: = \: (x - 1 - i)(x - 1 + i)$

$\sf \: = {(x - 1)}^{2} - {i}^{2}$

$\sf \: = {x}^{2} + 1 - 2x - ( - 1) \: \: \: \: \: ( \bf \because \: {i}^{2} = - 1)$

$\sf \: = {x}^{2} - 2x + 2$

So,

it means

$\sf \: {x}^{2} - 2x + 2 \: is \: a \: factor \: of \: given \: equation.$

So on dividing

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 \: by \: {x}^{2} - 2x + 2 \: we \: get \:$

$\sf \: {x}^{2} + 4x + 1$

Therefore,

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = ( {x}^{2} - 2x + 2)( {x}^{2} + 4x + 1)$

Hence,

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\:$

$\rm :\implies\: ({x}^{2} - 2x + 2)( {x}^{2} + 4x + 1) = 0$

As we know that roots of the equation x² - 2x + 2 = 0 are 1 + i and 1 - i,

So, we have to find the roots of the equation

$\rm :\longmapsto\: {x}^{2} + 4x + 1 = 0$

We know, the roots of quadratic is given by Quadratic formula,

So,

On comparing it with ax² + bx + C = 0, we have

a = 1

b = 4

c = 1

So,

Roots of the equation is given by

$\rm :\longmapsto\:\sf \: x \: = \: \dfrac{ - b \: \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

$\rm :\longmapsto\:x \: = \: \dfrac{ - 4 \: \pm \: \sqrt{ {4}^{2} - 4 \times 1 \times 1} }{2 \times 1}$

$\rm :\longmapsto\:x = \dfrac{ - 4 \: \pm \: \sqrt{12} }{2}$

$\rm :\longmapsto\:x = \dfrac{ - 4 \: \pm \: 2\sqrt{3} }{2}$

$\rm :\longmapsto\:x \: = \: - 2 \: \pm \: \sqrt{3}$

Hence,

$\bf \: The \: roots \: of \: \sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: \: are$

$\bf \: 1 + i, \: 1 - i, \: - 2 + \sqrt{3} \: and \: - 2 - \sqrt{3}$

ADDITIONAL Information :-

Let US consider a BI - quadratic equation

$\sf \: {ax}^{4} + {bx}^{3} + {cx}^{2} + dx + e = 0 \:$

having roots p, q, r and s, then

$\sf \: p + q + r + s = - \dfrac{b}{a}$

$\sf \: pq + pr + ps + qr + qs + sr = \dfrac{c}{a}$

$\sf \: pqr + pqs + qrs + rsp = - \dfrac{d}{a}$

$\sf \: pqrs = \dfrac{e}{a}$

Discussion

13.	One half of a pole lies within the ice , one third lies within sandand the remaining 5m lies above sand . What is the length ofthe pole ?
Answer» ANSWER: One half of a pole LIES within the ice , one third lies within SAND and the remaining 5m lies above sand . What is the length of the pole

13.

One half of a pole lies within the ice , one third lies within sandand the remaining 5m lies above sand . What is the length ofthe pole ?

Answer»

ANSWER:

One half of a pole LIES within the ice , one third lies within SAND

and the remaining 5m lies above sand . What is the length of

the pole

Discussion

14.	8 km 78 hm, 12m 55dm, 9m,4mm
Answer» ANSWER: i Don't KNOW what to do FRIEND

14.

8 km 78 hm, 12m 55dm, 9m,4mm

Answer»

ANSWER:

i Don't KNOW what to do FRIEND

Discussion

15.	6. Which of the following is binomial?a. 3m'n'p. c.4a³-3b² b. 2x¹⁰⁰
Answer» ANSWER: NONE of the EQUATION is BINOMIAL

15.

6. Which of the following is binomial?a. 3m'n'p. c.4a³-3b² b. 2x¹⁰⁰

Answer»

ANSWER:

NONE of the EQUATION is BINOMIAL

Discussion

16.	4. Give the units used to measure the following liquidsa) Milk in a glassb) Petrol in a carc) Water in a cand) Paint in a drum
Answer» Answer: everything is measured only in ONE UNIT which is LITRES

16.

4. Give the units used to measure the following liquidsa) Milk in a glassb) Petrol in a carc) Water in a cand) Paint in a drum

Answer»

Answer:

everything is measured only in ONE UNIT which is LITRES

Discussion

17.	The descending order of 0, 11, -12, -5 is
Answer» Step-by-step EXPLANATION: DESCENDING order MEANS big to small so ur answer is⤵️ 11,0,-5,-12 hope this helps you mate ✨

17.

The descending order of 0, 11, -12, -5 is

Answer»

Step-by-step EXPLANATION:

DESCENDING order MEANS big to small

so ur answer is⤵️

11,0,-5,-12

hope this helps you mate ✨

Discussion

18.	the cost of dry cleaning a carpet is rupees 50 per square metre find the cost of the meaning of lines for point 5.3 metre
Answer» $\huge{\underline{\underline{\boxed{\sf{\red{Aɴsᴡᴇʀ\: ࿐}}}}}}$ 5×4=20×50 =1000 ______________________

18.

the cost of dry cleaning a carpet is rupees 50 per square metre find the cost of the meaning of lines for point 5.3 metre

Answer»

$\huge{\underline{\underline{\boxed{\sf{\red{Aɴsᴡᴇʀ\: ࿐}}}}}}$

5×4=20×50

=1000

______________________

Discussion

19.	Sides of a triangle are 26 cm, 33 cm and 41 cm, find its area.step by step explanation
Answer» ANSWER: 429 cm² Step-by-step EXPLANATION: AREA = 1/2×b×h = 1/2×26×33 = 26×33/2 = 13×33 = 429

19.

Sides of a triangle are 26 cm, 33 cm and 41 cm, find its area.step by step explanation

Answer»

ANSWER:

429 cm²

Step-by-step EXPLANATION:

AREA = 1/2×b×h

= 1/2×26×33

= 26×33/2

= 13×33

= 429

Discussion

20.	A car dealer sold a car for ₹73,600 and incurred a loss of 8% for what price should he have sold it so as to gain 8%
Answer» $\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$ A CAR DEALER SOLD a car for ₹73,600 and incurred a loss of 8% for what price should he have sold it so as to gain 8% $\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$ = ₹864 $\sf \bf {\boxed {\mathbb {SOLUTION}}}$ SP=₹736 Loss=8% CP= 100/100-L%×SP = 100/100-8 ×736 = 100/92 ×736 = ₹800 CP= ₹800 Gain=8% SP= 100+G%/100 ×CP = 100+8/100 ×800 = 108/100 ×800 = ₹864 $\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$ __________________________________________ $\sf \bf \huge {\boxed {\mathbb {Thanks}}}$

20.

A car dealer sold a car for ₹73,600 and incurred a loss of 8% for what price should he have sold it so as to gain 8%

Answer»

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

A CAR DEALER SOLD a car for ₹73,600 and incurred a loss of 8% for what price should he have sold it so as to gain 8%

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

= ₹864

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

SP=₹736

Loss=8%

CP= 100/100-L%×SP

= 100/100-8 ×736

= 100/92 ×736

= ₹800

CP= ₹800

Gain=8%

SP= 100+G%/100 ×CP

= 100+8/100 ×800

= 108/100 ×800

= ₹864

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf \huge {\boxed {\mathbb {Thanks}}}$

Discussion

21.	2. Amit is 19 years younger than his cousin. After 5 years, their ages will be in the ratio 2:3.Find their present ages.
Answer» ANSWER: + Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIST

21.

2. Amit is 19 years younger than his cousin. After 5 years, their ages will be in the ratio 2:3.Find their present ages.

Answer»

ANSWER:

+

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIST

Discussion

22.	Q5-Evaluate:(a)9/10 - 3/20
Answer» ANSWER: 9/10 - 3/20 LCM = 20 18-3 ________ 20 15/20 3/4 please mark as the BRAINLIEST answer

22.

Q5-Evaluate:(a)9/10 - 3/20

Answer»

ANSWER:

9/10 - 3/20

LCM = 20

18-3

________

20

15/20

3/4

please mark as the BRAINLIEST answer

Discussion

23.	Seven times in number is decreased by 7 is 56 find that number.
Answer» ${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

23.

Seven times in number is decreased by 7 is 56 find that number.

Answer»

${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$

Discussion

24.	construction of a triangle in which one side is 10 cm is possible when the sum of other two side is _____________
Answer» ANSWER: GREATER than the THIRD SIDE

24.

construction of a triangle in which one side is 10 cm is possible when the sum of other two side is _____________

Answer»

ANSWER:

GREATER than the THIRD SIDE

Discussion

25.	Is it okayaise puchu to chalege ki sirf one que puchu
Answer» $\huge\mathfrak\red{☟ \: \: \: <klux>ANSWER</klux> \: \: \: \: ✎}$ Look at the pic‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎( ꈍᴗꈍ) $\\ \\ \\$ PLEASE do not report if the answer is WRONG, we have TRIED our best to GIVE you the correct answer} $\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸} \\ and\\ \sf \colorbox{lightgreen} {\red❤ANSWER ᵇʸ ᶠˡⁱʳᵗʸ ᵇᵒʸ}$

25.

Is it okayaise puchu to chalege ki sirf one que puchu

Answer»

$\huge\mathfrak\red{☟ \: \: \: <klux>ANSWER</klux> \: \: \: \: ✎}$

Look at the pic‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎‎ ‎( ꈍᴗꈍ)

$\\ \\ \\$

PLEASE do not report if the answer is WRONG, we have TRIED our best to GIVE you the correct answer}

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸} \\ and\\ \sf \colorbox{lightgreen} {\red❤ANSWER ᵇʸ ᶠˡⁱʳᵗʸ ᵇᵒʸ}$

Discussion

26.	5. The ratio between water and alcohol in a mixture is 2:3. If water content is 4 L, how much is thealcohol in the mixture?(1) 10 L(2) 6L(3) 8L(4)2L
Answer» Answer: 2) 6 l Step-by-step EXPLANATION: 2:3 = 4:# 2/3 = 4/ # 2×2 = 4 3×2 = # = 6 4/6

26.

5. The ratio between water and alcohol in a mixture is 2:3. If water content is 4 L, how much is thealcohol in the mixture?(1) 10 L(2) 6L(3) 8L(4)2L

Answer»

Answer:

2) 6 l

Step-by-step EXPLANATION:

2:3 = 4:#

2/3 = 4/ #

2×2 = 4

3×2 = # = 6

4/6

Discussion

27.	Combine the like terms and simplifyplz answer me this
Answer» SAMJH nahi aata aapko one by one question pucchye ykin MANYE ISS trah aapko ANSWER nahi milega

Discussion

28.	If a+b=6,ab=8 Evalute a2+b2 and a-b.
Answer» Answer: A2 + B2 = 20 and a- B = 6 Step-by-step EXPLANATION: Hope it HELPS !

28.

If a+b=6,ab=8 Evalute a2+b2 and a-b.

Answer»

Answer:

A2 + B2 = 20 and a- B = 6

Step-by-step EXPLANATION:

Hope it HELPS !

Discussion

29.	(7a-6b+5c)^3 solve this with method
Answer» ANSWER: SIMPLIFY (7a-6b+5c)^2 + (7a+6b-5c)^2

29.

(7a-6b+5c)^3 solve this with method

Answer»

ANSWER:

SIMPLIFY (7a-6b+5c)^2 + (7a+6b-5c)^2

Discussion

30.	HCF of -399 and 603 is
Answer» Answer: 399 = 3×7×19 603 = 3×3×67 HCF = 3

30.

HCF of -399 and 603 is

Answer»

Answer:

399 = 3×7×19

603 = 3×3×67

HCF = 3

Discussion

31.	Calculate the mode of the following sizes of the shirts sold by a shop on a particular day:34. 38. 37. 35. 38. 33, 32, 38, 30, 35, 32 38, 36, 30, 31, 34, 39
Answer» Answer- 38 is the MODE of the data Explanation- As we know that the mode of the data is the HIGHEST OCCURRING NUMBER.. In the above data 38 is the highest occurring number.. So, 38 is the mode..

31.

Calculate the mode of the following sizes of the shirts sold by a shop on a particular day:34. 38. 37. 35. 38. 33, 32, 38, 30, 35, 32 38, 36, 30, 31, 34, 39

Answer»

Answer-

38 is the MODE of the data

Explanation-

As we know that the mode of the data is the HIGHEST OCCURRING NUMBER..

In the above data 38 is the highest occurring number..

So, 38 is the mode..

Discussion

32.	Find the ratio of your class boys and girls in simplest form answer
Answer» In my CLASS there are 40 students 25 BOYS and 15 girls so the ratio is 7:3 hope it helps you

32.

Find the ratio of your class boys and girls in simplest form answer

Answer»

In my CLASS there are 40 students

25 BOYS and 15 girls

so the ratio is 7:3

hope it helps you

Discussion

33.	LCM by division method of 12 36 and 54 solution
Answer» Step-by-step EXPLANATION: i dontjsjdhdbbdbsbshshsbbs

33.

LCM by division method of 12 36 and 54 solution

Answer»

Step-by-step EXPLANATION:

i dontjsjdhdbbdbsbshshsbbs

Discussion

34.	Write the properties of triangles with diagrams.
Answer» Answer: Properties of a TRIANGLE A triangle has three sides, three angles, and three vertices. The sum of all internal angles of a triangle is always equal to 1800. This is called the angle sum PROPERTY of a triangle. The sum of the LENGTH of any two sides of a triangle is GREATER than the length of the third side. Step-by-step explanation: plz mark me brainliest

34.

Write the properties of triangles with diagrams.

Answer»

Answer:

Properties of a TRIANGLE

A triangle has three sides, three angles, and three vertices. The sum of all internal angles of a triangle is always equal to 1800. This is called the angle sum PROPERTY of a triangle. The sum of the LENGTH of any two sides of a triangle is GREATER than the length of the third side.

Step-by-step explanation:

plz mark me brainliest

Discussion

35.	P^3*p^-10=?PLEASE ANSWER!
Answer» <P>ANSWER: p³ * p^10 = p^(3+10) = p^13

35.

P^3*p^-10=?PLEASE ANSWER!

Answer»

<P>ANSWER:

p³ * p^10 = p^(3+10) = p^13

Discussion

36.	Find the compound interest on 3 3000 for 2 years at 4% per annum
Answer» SOLUTION:- ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$ ◍ Here, the question has given us the principal, rate of interest and time that is RS. 33,000, 4% per annum and for 2 years respectively. Now, the question has asked us to find the compound INTREST of it. So to get the answer we need to APPLY the formula of AMOUNT first and then subtracting Principal from the amount will be the Compound interest. ANSWER:- ◈ The Compound interest on Rs 33,000 for 2 years at 4% per annum will be Rs. 2,692.8. GIVEN:- ☆ Principal = Rs. 33,000 ☆ Rate of Interest = 4% per annum ☆ Time = 2 years TO FIND:- ↠Compound Interest = ? FORMULA:- ⬤ Amount = P [1 + (R / 100)]^t ⬤ Compound Interest = Amount - Principal SOLVING BY APPLYING THE FORMULA:- ⇨ Principal = Rs. 33,000 ⇨ Rate = 4% ⇨ Time = 2 years ⇨ Amount = P [1 + (R / 100)]^t ➢ Amount = 33,000 [1 + (4 / 100)]² ➢ Take LCM ➢ Amount = 33,000 (100 + 4 / 100)² ➢ Amount = 33,000 (104 / 100)² ➢ Amount = 33,000 (10,816 / 10,000) ➢ Amount = 33,000 × 10,816 / 10,000 ➢ Cancel out the zeros ➢ Amount = 33 × 10,816 / 10 ➢ Amount = 3,56,928 ÷ 10 ➢ Amount = 3,56,928 ÷ 10 = 35,692.8 ➢ Amount = Rs. 35,692.8 Amount is Rs. 35,692.8. ⇨ Compound Interest = Amount - Principal ➢ Compound Interest = 35,692.8 - 33,000 ➢ Compound Interest = 35,692.8 - 33,000 = 2,692.8 ➢ Compound Interest = Rs. 2,692.8 Compound interest after 2 years will be Rs. 2,692.8. Hence, we got the answer. The interest compounded after 2 years will be Rs. 2,692.8. ━━━━━━━━━━━━━━━━━━━━━━━━━━

36.

Find the compound interest on 3 3000 for 2 years at 4% per annum

Answer»

SOLUTION:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

◍ Here, the question has given us the principal, rate of interest and time that is RS. 33,000, 4% per annum and for 2 years respectively. Now, the question has asked us to find the compound INTREST of it. So to get the answer we need to APPLY the formula of AMOUNT first and then subtracting Principal from the amount will be the Compound interest.

ANSWER:-

◈ The Compound interest on Rs 33,000 for 2 years at 4% per annum will be Rs. 2,692.8.

GIVEN:-

☆ Principal = Rs. 33,000

☆ Rate of Interest = 4% per annum

☆ Time = 2 years

TO FIND:-

↠Compound Interest = ?

FORMULA:-

⬤ Amount = P [1 + (R / 100)]^t

⬤ Compound Interest = Amount - Principal

SOLVING BY APPLYING THE FORMULA:-

⇨ Principal = Rs. 33,000

⇨ Rate = 4%

⇨ Time = 2 years

⇨ Amount = P [1 + (R / 100)]^t

➢ Amount = 33,000 [1 + (4 / 100)]²

➢ Take LCM

➢ Amount = 33,000 (100 + 4 / 100)²

➢ Amount = 33,000 (104 / 100)²

➢ Amount = 33,000 (10,816 / 10,000)

➢ Amount = 33,000 × 10,816 / 10,000

➢ Cancel out the zeros

➢ Amount = 33 × 10,816 / 10

➢ Amount = 3,56,928 ÷ 10

➢ Amount = 3,56,928 ÷ 10 = 35,692.8

➢ Amount = Rs. 35,692.8

Amount is Rs. 35,692.8.

⇨ Compound Interest = Amount - Principal

➢ Compound Interest = 35,692.8 - 33,000

➢ Compound Interest = 35,692.8 - 33,000 = 2,692.8

➢ Compound Interest = Rs. 2,692.8

Compound interest after 2 years will be Rs. 2,692.8.

Hence, we got the answer. The interest compounded after 2 years will be Rs. 2,692.8.

━━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

37.	35+23+1212/35+12+34+23*234
Answer» USE CALCULATOR it will EASY WAY

Discussion

38.	Write the integer greater than (-10) and smaller than (-8)
Answer» ANSWER: the REQUIRED INTEGER is _9

38.

Write the integer greater than (-10) and smaller than (-8)

Answer»

ANSWER:

the REQUIRED INTEGER is _9

Discussion

39.	9 : x :: 81 : 90 find the value of x
Answer» ANSWER: 10 is the CORRECT answer HOPE it will HELP you mark me as brainliest

39.

9 : x :: 81 : 90 find the value of x

Answer»

ANSWER:

10 is the CORRECT answer HOPE it will HELP you mark me as brainliest

Discussion

40.	Answer the questions correctly
Answer» ANSWER: HOPE it HELPS you!!!!!!

40.

Answer the questions correctly

Answer»

ANSWER:

HOPE it HELPS you!!!!!!

Discussion

41.	Answer plz 0.33 x 0.33 x 0.33
Answer» Answer: 0.035937 Step-by-step EXPLANATION: PLS MARK me as BRAINLIEST

41.

Answer plz 0.33 x 0.33 x 0.33

Answer»

Answer:

0.035937

Step-by-step EXPLANATION:

PLS MARK me as BRAINLIEST

Discussion

42.	Please solve it by explanation
Answer» Answer: 61,378,488 25,868,284 26,625,680 24,093,148 53,733,325 38,219,787 39,367,378 31,660,875 14,246,170 42,457,806 20,101,888 21,456,855 55,079,442 21,859,110 27,317,158 19,632,378 47,905,110 47,792,224 41,312,808 it is very HARD

42.

Please solve it by explanation

Answer»

Answer:

61,378,488

25,868,284

26,625,680

24,093,148

53,733,325

38,219,787

39,367,378

31,660,875

14,246,170

42,457,806

20,101,888

21,456,855

55,079,442

21,859,110

27,317,158

19,632,378

47,905,110

47,792,224

41,312,808

it is very HARD

Discussion

43.	Verify 5/8 +7/11=7/11+5/8
Answer» ANSWER: what are you QUESTIONS okkkkkkkk

43.

Verify 5/8 +7/11=7/11+5/8

Answer»

ANSWER:

what are you QUESTIONS okkkkkkkk

Discussion

44.	(1) Priya took a wire and bent it to form a circle of radius 14 cm. Thenshe bent it into a rectangle with one side 24 cm long. What is thelength of the wire? Which figure encloses more area, the circle or therectangle?2mia2 का वायर एंड बैंडिट 2 फॉर्म अ सर्कल ऑफ रेडियस 14 सैंटीमीटर इनटू ए रैक्टेंगल विद वन साइड 4 सीएम लोंग व्हाट इज द लेंथ ऑफ द वायर
Answer» ANSWER: this is your answer HOPE this will HELP you MARK me BRAINLIEST

44.

(1) Priya took a wire and bent it to form a circle of radius 14 cm. Thenshe bent it into a rectangle with one side 24 cm long. What is thelength of the wire? Which figure encloses more area, the circle or therectangle?2mia2 का वायर एंड बैंडिट 2 फॉर्म अ सर्कल ऑफ रेडियस 14 सैंटीमीटर इनटू ए रैक्टेंगल विद वन साइड 4 सीएम लोंग व्हाट इज द लेंथ ऑफ द वायर

Answer»

ANSWER:

this is your answer HOPE this will HELP you MARK me BRAINLIEST

Discussion

45.	( -20) + (-4) + (-6) + (+5) = ___
Answer» ANSWER: $- 25$ Step-by-step EXPLANATION: $( - 20) + ( - 4) + ( - 6) + ( + 5) \\ \\ = - 20 - 4 - 6 + 5 \\ \\ = - 24 - 1 \\ \\ = - 25$

45.

( -20) + (-4) + (-6) + (+5) = ___

Answer»

ANSWER:

$- 25$

Step-by-step EXPLANATION:

$( - 20) + ( - 4) + ( - 6) + ( + 5) \\ \\ = - 20 - 4 - 6 + 5 \\ \\ = - 24 - 1 \\ \\ = - 25$

Discussion

46.	Find the difference between simple interest an compound interest on rs 5000 for 2 yrs at 10% p annum
Answer» Answer: 6050 2 YEARS ryttttttttyttttttttttt

46.

Find the difference between simple interest an compound interest on rs 5000 for 2 yrs at 10% p annum

Answer»

Answer:

6050

2 YEARS

ryttttttttyttttttttttt

Discussion

47.	Subtract 4pq-5q2 from 5p2+2pq +5q2
Answer» QUESTION is WRONG CHECK it again

47.

Subtract 4pq-5q2 from 5p2+2pq +5q2

Answer»

QUESTION is WRONG CHECK it again

Discussion

48.	Find the measure of the lettered angles .
Answer» Answer: c°=131° d°=41° Step-by-step EXPLANATION: c°=(180-49)°=131°{LINEAR angles} d°=(180-139)°=41°{linear angles} HOPE THIS MAY HELP YOU!☺

48.

Find the measure of the lettered angles .

Answer»

Answer:

c°=131°

d°=41°

Step-by-step EXPLANATION:

c°=(180-49)°=131°{LINEAR angles}

d°=(180-139)°=41°{linear angles}

HOPE THIS MAY HELP YOU!☺

Discussion

49.	The region enclosed between the boundaries of a figure is called its fill in the blanks
Answer» ANSWER: AREA Step-by-step EXPLANATION: The region enclosed between the boundaries of a figure is CALLED it's area

49.

The region enclosed between the boundaries of a figure is called its fill in the blanks

Answer»

ANSWER:

AREA

Step-by-step EXPLANATION:

The region enclosed between the boundaries of a figure is CALLED it's area

Discussion

50.	Hajsjjsjsdjdndnndncncjdjkdosksmdd
Answer» ANSWER: ipipfhdxhkdydyodoyddyodyodyldulduldudkydykdykdydykdykdykdydkdykdkd

50.

Hajsjjsjsdjdndnndncncjdjkdosksmdd

Answer»

ANSWER:

ipipfhdxhkdydyodoyddyodyodyldulduldudkydykdykdydykdykdykdydkdykdkd

Discussion

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Find the measure of the lettered angles .

Hajsjjsjsdjdndnndncncjdjkdosksmdd