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A convex MIRROR or DIVERGING mirror is a curved mirror in which the REFLECTIVE surface BULGES towards the light source. Convex mirrors reflect light outwards, therefore they are not used to focus light.

What is the IMPORTANCE of the least count of an instrument?Least count of an instrument is one of the very important tools in order to get accurate readings of instruments like vernier caliper and SCREW gauge used in various experiments. Least count uncertainty is one of the sources of EXPERIMENTAL ERROR in measurements. Least count of vernier caliper is .

of crow bar = 2mlength of LOAD arm = 0.1Mlength effort arm = length of crow bar -length of load arm=2−0.1=1.9mso, VELOCITY RATIO = length of effort arm/length of load arm = 1.9/0.1 = 19use formula, velocity ratio = load/effort19 = 100kgf/efforteffort = 100/19= 5.26 kgfhence,5.26 effort is required

Explanation:electromagnetic radiationsWe know that SPACE is a VACUUM, and ALSO that the electromagnetic RADIATIONS

No, the SHADOW of the OBJECT is not COLOURED mExplanation:Because, the shadow is ALWAYS DARK.

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y LOVE PHYSICS it's my FAVORITE SUBJECT

Distance is a SCALAR quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how FAR out of PLACE an object is"; it is the object's overall change in position.hope it HELPS you!!mark me as the brainliest!!

tion:Usually water is not considered VOLATILE because it is not as EASILY evaporated at NORMAL temperatures compared to more volatile liquids such as methanol or ACETONE. In environmental LAW, water is not considered volatile because the evaporation of water does not have deleterious environmental consequences

6NmExplanation:F=15Nperpendicular distance=0.4mTorque or MOMENT of force=F×perpendicular distance=15×0.4=6Nm

jeee bilkulExplanation: speed= 60 TIME= 1/2 so, DISTANCE= speed X time 60 x 1/2 30 x 1 30 km/h

Answer:DOMAIN is all the VALUES that go into a function, and the RANGE is all the values that COME out.Please brainlest me the answer

2VExplanation:TOTAL CURRENT = VOLTAGE/TOTAL RESISTANCEI=9/450=1/50V ACROSS 100Ω R = IR = I/50 * 100 = 2V

mediumExplanation:PLEASE MARK me BRANIEST and be my FOLLOWER

ljdsExplanation:ndalx

1-aExplanation:THANK you

Explanation:a)A to B= 3-0/5-2=3m/3s=1m/sb)B to C= 0cm/s(as the TIME is INCREASING without increase in distance.)c)C to D= 7-3/9-7=4m/2s=2m/sd) It is non-uniform because speed is different in same interval of time. pls MARK as brainliest

Distance TRAVELED in 5th SECOND = Distance traveled in 5 s− Distance traveled in 4 sDistance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 MDISTANCE traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 sUsing s=ut+(1/2)at 2 Distance traveled in 5 s =(1/2)×5×5 2 =62.5 mDistance traveled in 4 s =(1/2)×5×4 2 =40 mDistance traveled in 5th s =(1/2)×5×5 2 =62.5 m=S 2 −S 1 =(62.5−40)m=22.5m

2. CLINICAL 3. laboratory4. celcius5. areaExplanation:please MARK me as the BRAINIEST

These Are The NotesFriction is a force that opposes motion between any surfaces that are touching. Friction can work for or against us. For example, putting sand on an icy sidewalk increases friction so you are less likely to SLIP. On the other hand, too much friction between moving parts in a car engine can cause the parts to WEAR out. Why Friction OccursFriction occurs because no surface is perfectly smooth. Even surfaces that look smooth to the unaided eye make look rough or bumpy when viewed under a microscope. Look at the metal surfaces in the Figure below. The ALUMINUM foil is so smooth that it's shiny. However, when highly magnified, the surface of metal appears to be very bumpy. All those mountains and valleys CATCH and grab the mountains and valleys of any other surface that contacts the metal. This creates friction. Factors That Affect FrictionRougher surfaces have more friction between them than smoother surfaces. That's why we put sand on icy sidewalks and roads. Increasing the area of surfaces that are touching also increases the friction between them. That's why you can't slide as far across ice with shoes as you can on the thin blades of skates. The greater surface area of the soles of the shoes cause more friction and slow you down.Heavier objects also have more friction. Friction Produces HeatFriction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer. Heat from friction can be useful. It not only warms your hands. On the other hand, heat from friction between moving parts inside a car engine can be a big problem. It can cause the car to overheat.But Do You Know how is friction reduced between the moving parts inside a car engine?To reduce friction, OIL is added to the engine. The oil coats the surfaces of the moving parts and makes them slippery. They slide over each other more easily, so there is less friction. Friction is always parallel to the surface in contact.In some cases, friction is desirable while in other cases, friction reduces the effectiveness of machines. Without friction, you would not be able to walk, the wheels on a vehicle would have no grip on a road surfacing and the vehicle would not be able to move forward.On the other hand, friction is undesirable in most of the cases. Friction causes mechanical parts to seize and wear out.

DBMS provides a lot benefits in all SPHERES of HUMAN activity � theobjectives are MANIFOLD. The mainobjectives of database management system are data availability, data INTEGRITY, data SECURITY, and data independence.

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velocityExplanation:DISPLACEMENT TIME GRAPH SHOWS VELOCITY

Because cotton is a natural FIBER, it absorbs moisture (drawing it away from your skin) rather than repelling it (forcing the sweat to SIT on your skin). ... Since it absorbs moisture so easily, pit STAINS can be a problem.

yes this is the process FINDING the THICKNESS of a SHEET of PAPER

The QUANTITIES that are easily measured are KNOWN as fundamental PHYSICAL quantities. The quantities which cannot be measured practically but can be derived mathematically are known as the derived physical quantities.

because MIRROR REFLECT USSS SIMPLE

Acceleration is the rate of CHANGE of velocity. USUALLY, acceleration means the speed is changing, but not ALWAYS. When an object moves in a CIRCULAR PATH at a constant speed, it is still accelerating, because the direction of its velocity is changing.