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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
20 A 5 Q 10 B 2 S 1 = ?1). 382). 453). 444). 39 |
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Answer»
→ 20 + 5 × 10 ÷ 2 − 1 → 20 + 5 × 5 − 1 → 20 + 25 − 1 → 45 − 1 = 44 Thus, 44 is the correct answer. |
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| 2. |
72 K 2 (10 S 12 U 4 L 4 K 3 L 3) S 20 is,1). 662). 723). 644). –64 |
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Answer»
72 K 2 (10 S 12 U 4 L 4 K 3 L 3) S 20 Substituting the symbols: 72 – 2 (10 + 12 ÷ 4 × 4 – 3 × 3) + 20 Solving using BODMAS rule = 72 – 2 (10 + 12 ÷ 4 × 4 – 3 × 3) + 20 = 72 – 2 (10 + 3 × 4 – 3 × 3) + 20 = 72 – 2 (10 + 12 – 9) + 20 = 72 – 2 (22 – 9) + 20 = 72 – 2 (13) + 20 = 72 – 26 + 20 = 46 + 20 = 66. Hence, answer is 66. |
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| 3. |
P, Q and R have a partnership firm. P’s profit share is 2/3rd of the Q’s profit share and R’s share is 1/2 of the Q’s share. If total revenue is Rs. 43296 and total expense is Rs. 9899, then what will be the profit share of R?1). Rs. 51382). Rs. 77073). Rs. 102764). Rs. 15414 |
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Answer» <P>Net Profit = Total Revenue – Total Expense = Rs. 43296 – Rs. 9899 = Rs. 33397 Let, the profit share of Q is Rs. x. → P’s profit share = Rs. 2x/3 → R’s profit share = Rs. x/2 Thus we have, Net Profit = P’s profit share + Q’s profit share + R’s profit share 33397 = 2x/3 + x + x/2 33397 = (4x + 6x + 3x)/6 33397 = 13x/6 x = (33397 × 6)/13 = 15414 R’s share = 15414/2 = 7707 Hence, Rs. 7707 is the correct ANSWER. |
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| 4. |
1). 1802). 1703). 1204). 150 |
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Answer» The weights of 4 BOXES are 30, 20, 60 and 70 kilograms 1) 180 ⇒ 30 + 20 + 60 + 70 = 120 2) 170 ⇒ can’t be formed 3) 120 ⇒ 30 + 20 + 70 4) 150 ⇒ 20 + 60 + 70 = 150 Hence, “170” cannot be the TOTAL weight. |
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| 5. |
12 - 2 + 6 × 20 ÷ 18 = ?1). 502). 23). 194). 43 |
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Answer»
After interchanging the codes, 12 × 2 ÷ 6 - 20 + 18 4 - 20 + 18 2 Hence, the correct ANSWER is 2. |
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| 6. |
1). 162 N 2 O 2 B 100 C 20 N 2 X 2302). 36 B 4 O 2 N 5 C 15 B 50 X 81 3). 182 O 2 N 4 B 15 C 30 X 3514). 642 O 2 N 3 C 100 B 10 X 875 |
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Answer»
Applying the BODMAS rule to the given equations, 1) By substituting the above signs we get, Equation: 162 N 2 O 2 B 100 C 20 N 2 X 230 162 × 2 ÷ 2 + 100 – 20 × 2 = 230 = 162 × 1 + 100 – 40 = 162 + 60 = 222 = 222 ≠ 230 It should be 222 but it is given as 230, thus it is the incorrect equation. 2) By substituting the above signs we get, Equation: 36 B 4 O 2 N 5 C 15 B 50 X 81 36 + 4 ÷ 2 × 5 – 15 + 50 = 81 = 36 + 2 × 5 + 35 = 36 + 10 + 35 = 81 It is the correct equation. 3) By substituting the above signs we get, Equation: 182 O 2 N 4 B 15 C 30 X 351 182 ÷ 2 × 4 + 15 – 30 = 351 = 91 × 4 – 15 = 349 = 349 ≠ 351 It should be 349 but it is given as 351, thus it is the incorrect equation. 4) By substituting the above signs we get, Equation: 642 O 2 N 3 C 100 B 10 X 875 642 ÷ 2 × 3 – 100 + 10 = 875 = 321 × 3 – 90 = 873 = 873 ≠ 875 It should be 873 but it is given as 875, thus it is the incorrect equation. Thus, Equation NUMBER 2 is correct. |
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| 7. |
15 × 12 + 40 ÷ 40 - 6 = 211). + and ×2). + and ÷3). - and +4). ÷ and × |
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Answer» Given EQUATION: 15 × 12 + 40 ÷ 40 - 6 = 21 After INTERCHANGING ‘+ and × ’ we get: 15 + 12 × 40 ÷ 40 - 6 = 21 L.H.S of equation: 15 + 12 × 40 ÷ 40 - 6 → 15 + 12 × 1 - 6 → 15 + 12 - 6 → 15 + 6 → 21 = R.H.S Hence, answer is ‘+ and × ’. |
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| 8. |
5 - 16 × 30 ÷ 10 + 4 = 491). - and +2). ÷ and ×3). × and – 4). ÷ and – |
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Answer» The GIVEN equation is : 5 – 16 × 30 ÷ 10 + 4 = 49 Let’s check each option, 1) – and + → 5 + 16 × 30 ÷ 10 – 4 = 49 = 49 2) ÷ and × → 5 – 16 ÷ 30 × 10 + 4 = 3.66 ≠ 49 3) × and – → 5 × 16 – 30 ÷ 10 + 4 = 81 ≠ 49 4) ÷ and – → 5 ÷ 16 × 30 – 10 + 4 = 3.375 ≠ 49 Hence, by interchanging – and + the equation will be CORRECT. |
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| 9. |
Hari is twice as old as Jhony, who is three years older than Rahul. If Hari’s age is five times Rahul’s age, how old is Johny?1). 2 years2). 4 years3). 5 years4). 8 years |
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Answer» Let the age of RAHUL be x years. Therefore Johny’s age is x + 3 years. According to the question HARI’s age = 2(x + 3) (twice OLD as Johny) And Hari’s age = 5x (five times Rahul’s age) Thus 2(x + 3) = 5x x = 2 Johny’s age = x + 3 = 2 + 3 = 5 Hence, Johny is 5 years old. |
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| 10. |
1). 20 years2). 22 years3). 25 years4). 29 years |
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Answer» Let M be the MOTHER’s present AGE and D be the daughter’s present age. A mother is FIVE times older than her daughter. M = 5D After 5 years, she would be three times older than her daughter M + 5 = 3D + 15 Solving the two equation, 5D + 5 = 3D + 15 2D = 10 Therefore, D = 5 Hence, M = 5D = 25 Thus mother’s present age is 25YRS. |
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| 11. |
Directions: Five boys are sitting on a bench to be photographed. Sachin is to the left of Ram and to the right of Bin. Monty is to the right of Ram. Rony is between Ram and Monty.Who is in the middle of the photograph?1). Bin2). Ram3). Rony4). Sachin |
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