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1.	The cost price of two articles is Rs. 1400. One is sold at a profit of 20% and other is sold at a loss of 15%, then there is no profit or loss in the transaction. Find the cost price of the article which the shopkeeper gains.1). Rs. 2002). Rs. 4003). Rs. 5004). Rs. 600
Answer» One is sold at a profit of 20% and other is sold at a loss of 15%, then there is no profit or loss in the transaction, USING allegation method, +20%-15% 0% 15%20% ⇒ Ratio of price of two ARTICLES = 3 ? 4 ∴ Price of the ARTICLE sold at profit = (3/7) × 1400 = Rs. 600

The cost price of two articles is Rs. 1400. One is sold at a profit of 20% and other is sold at a loss of 15%, then there is no profit or loss in the transaction. Find the cost price of the article which the shopkeeper gains.1). Rs. 2002). Rs. 4003). Rs. 5004). Rs. 600

Answer»

One is sold at a profit of 20% and other is sold at a loss of 15%, then there is no profit or loss in the transaction,

USING allegation method,

+20%-15%

15%20%

⇒ Ratio of price of two ARTICLES = 3 ? 4

∴ Price of the ARTICLE sold at profit = (3/7) × 1400 = Rs. 600

Discussion

2.	What is the unit digit of the sum of first 78 whole numbers?1). 32). 93). 84). 0
Answer» Sum of first 78 WHOLE numbers = 0 + 1 + 2 + 3 + 4 ……………….76 + 77 ⇒ 78/2 (0 + 77) ⇒ 3003 Unit digit of this sum will be 3.

What is the unit digit of the sum of first 78 whole numbers?1). 32). 93). 84). 0

Answer»

Sum of first 78 WHOLE numbers = 0 + 1 + 2 + 3 + 4 ……………….76 + 77

⇒ 78/2 (0 + 77)

⇒ 3003

Unit digit of this sum will be 3.

Discussion

3.	1). 1/32). 23). 1/24). 3
Answer» PRODUCT of FIRST and fourth term = Product of second and THIRD term ⇒ 26/21 × 14/13 = 24/9 × k ∴ k = 1/2

1). 1/32). 23). 1/24). 3

Answer»

PRODUCT of FIRST and fourth term = Product of second and THIRD term

⇒ 26/21 × 14/13 = 24/9 × k

∴ k = 1/2

Discussion

4.	If x + (1/x) = √3, then find the value of x18 + 1/x18.1). -22). √33). 24). 0
Answer» ⇒ x + 1/x = √3 Squaring both sides we GET, ⇒ x² + (1/x²) + 2 = 3 ⇒ x² + (1/x²) = 1 Now, CUBING both sides we get, ⇒ x⁶ + (1/x⁶) + 3 × x² × (1/x²){x² + (1/x²)} = 1 ⇒ x⁶ + (1/x⁶) + 3(1) = 1 ⇒ x⁶ + (1/x⁶) = -2 Now, cubing both sides we get, ⇒ x¹⁸ + (1/x¹⁸) + 3 × x⁶ × (1/x⁶){x⁶ + (1/x⁶)} = -8 ⇒ x¹⁸ + (1/x¹⁸) + 3(-2) = -8 ⇒ x¹⁸ + (1/x¹⁸) = -2

If x + (1/x) = √3, then find the value of x18 + 1/x18.1). -22). √33). 24). 0

Answer»

⇒ x + 1/x = √3

Squaring both sides we GET,

⇒ x² + (1/x²) + 2 = 3

⇒ x² + (1/x²) = 1

Now, CUBING both sides we get,

⇒ x⁶ + (1/x⁶) + 3 × x² × (1/x²){x² + (1/x²)} = 1

⇒ x⁶ + (1/x⁶) + 3(1) = 1

⇒ x⁶ + (1/x⁶) = -2

Now, cubing both sides we get,

⇒ x¹⁸ + (1/x¹⁸) + 3 × x⁶ × (1/x⁶){x⁶ + (1/x⁶)} = -8

⇒ x¹⁸ + (1/x¹⁸) + 3(-2) = -8

⇒ x¹⁸ + (1/x¹⁸) = -2

Discussion

5.	A shopkeeper sold total 520 clothes. If he sold t-shirts at 7% loss and jeans at a 19% profit thus he gains 11% on the whole. What are the number of jeans which he has sold? 1). 2602). 4403). 1604). 360
Answer»

Discussion

Explore topic-wise InterviewSolutions in .

The cost price of two articles is Rs. 1400. One is sold at a profit of 20% and other is sold at a loss of 15%, then there is no profit or loss in the transaction. Find the cost price of the article which the shopkeeper gains.1). Rs. 2002). Rs. 4003). Rs. 5004). Rs. 600

What is the unit digit of the sum of first 78 whole numbers?1). 32). 93). 84). 0

1). 1/32). 23). 1/24). 3

If x + (1/x) = √3, then find the value of x18 + 1/x18.1). -22). √33). 24). 0

A shopkeeper sold total 520 clothes. If he sold t-shirts at 7% loss and jeans at a 19% profit thus he gains 11% on the whole. What are the number of jeans which he has sold? 1). 2602). 4403). 1604). 360