InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
The H.C.F. of two numbers is 18. First number is of three digits and Second number is of two digits and their L.C.M. is 936. The sum of the numbers is?1). 2762). 3063). 2784). 310 |
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Answer» Let the numbers be 18x and 18y where x and y are co-prime LCM of 18x and 18y = 18xy According to the question 18xy = 936 ⇒ XY = 936/18 ⇒ xy = 52 ⇒xy = 13 × 4 ⇒ x =13 and y = 4 Second number = 18 × 4 = 72 ∴ Sum of the number = 234 + 72 = 306 |
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| 252. |
If √51 = 7.14 and 3√45 = 3.55, find the value of (√0.1275 + 3√2.88).1). 0.017772). 0.17773). 1.7774). 17.77 |
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Answer» We can write, ⇒ √0.1275 = √{(51 × 25)/10000} = (7.14 × 5)/100 = 0.357 Similarly, ∴ (√0.1275 + 3√2.88) = 0.357 + 1.42 = 1.777 |
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| 253. |
If (b + c), (c + a), (a + b) are in A.P. then1). b = a + c2). \(a = \frac{{b + c}}{2}\)3). \(c = \frac{{a + b}}{2}\)4). \(b = \frac{{a + c}}{2}\) |
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Answer» The GIVEN EXPRESSION, (b + c), (c + a), (a + b) are in A.P Then, ⇒ (c + a) = [(b + c) + (a + b)]/2 ⇒ c + a = 2b ∴ b = (a + c)/2 |
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