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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
1). Rs. 58.25 lakhs2). Rs. 65.75 lakhs3). Rs. 75.14 lakhs4). Rs. 50.75 lakhs |
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Answer» Selling price = cost price – loss = 57 lakhs If the selling price would have been 67 lakhs Then, gain = 7x ∴ Selling price = 67 lakhs Cost price + 7x = 67 lakhs Also, cost price – x = 57 lakhs Subtracting the above 2 eqns. We get, 8x = 10 lakhs x = 1.25 lakhs ∴ cost price = Selling price + loss = 57 + 1.25 Cost price = 58.25 lakhs |
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| 152. |
A man buys 144 oranges for Rs. 360 and sells them at a gain of 10%. At what rate per dozen does he sell them?1). 252). 303). 334). 36 |
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Answer» The COST price of 12 ORANGES = 360/12 = Rs. 30 ⇒ Selling price of 12 oranges = 30 + 10% of 30 = Rs. 33 |
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| 153. |
Lokesh starts a business with Rs. 240000. After 3 months Vishal joins him with Rs. 210000. At the end of the year what will be the ratio of their profits? 1). 32 : 212). 16 : 133). 8 : 5 4). 45 : 39 |
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Answer» Lokesh invested Rs. 240000 for 12 months and Vishal invested Rs. 210000 for (12 - 3 = 9 months) into the business We know that if both the Investment and TIME Periods are different, then the Profit will be divided in the ratio of the product of their Investment and Time Period Ratio of the Profits = (240000 × 12) : (210000 × 9) = (24 × 12) : (21 × 9) = 288 : 189 = 32 : 21 ∴ Ratio of their Profits = 32 : 21 |
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| 154. |
In winters, the meter scale of a cloth merchant shrinks by 10% of its actual length. If the meter scale in its regular condition was rigged to measure 10% more than it is supposed to measure, what is the profit / loss percent the cloth merchant makes in winter, if he sell goods at the rate at which he purchase?1). 1.01%2). 0.10%3). 1.10%4). 1.00% |
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Answer» A meter SCALE is SUPPOSED to measure 100cm. After rigging, the meter scale would be measuring 110 cm. In winter, the scale shrinks by 10% and thus would measure just 110 × 0.9 = 99 cm. The CLOTH merchant would charge for 100cm (as the scale would still READ 100) but actually sell just 99 cm. ∴ He would make a profit of $(\frac{1}{{99}} \times 100 = 1.01\%)$ |
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| 155. |
Mohan invested Rs. 100,000 in a garment business. After few months, Sohan joined him with Rs. 40000. At the end of the year, the total profit was divided between them in ratio 3 : 1. After how many months did Sohan join the business?1). 32). 23). 44). 5 |
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Answer» Given that profit was divided between them in the ratio 3 : 1 Let us consider SOHAN joined the BUSINESS after (12 - x) months ⇒ (1,00,000 × 12)/ (40,000 × (12 - x)) = 3/1 ⇒ 12,00,000 = 3 (4,80,000 - 40,000x) ⇒ 12,00,000 = 1440000 - 1,20,000x ⇒ 1,20,000x = 14,40,000 - 12,00,000 ⇒ 1,20,000x = 2,40,000 ⇒ x = 2,40,000/1,20,000 = 2 ∴ After 2 months Sohan JOIN the business |
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| 156. |
If three successive discounts of 20%, 30% and 40% are given, then what will be the net discount (in percentage)?1). 802). 87.6 3). 904). 66.4 |
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Answer» SP after DISCOUNT = 100 × 80/100 × 70/100 × 60/100 = 33.6 We know, discount = MP – SP So, net discount = 100 – 33.6 = 66.4 ∴ Discount % = 66.4/100 × 100 = 66.4% |
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| 157. |
An article was sold for Rs. 2,400 at a discount of 20%. Find the selling price, if the discount was 25%?1). Rs. 2,2502). Rs. 2,0003). Rs. 1,8004). Rs. 2,150 |
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Answer» Let the marked price be RS. x As per the given data, Discount = 20% of x = 20x/100 = x/5 We KNOW that, Selling price = Marked price – Discount ⇒ 2400 = x – (x/5) ⇒ 2400 = 4x/5 ⇒ x = 12000/4 = Rs. 3000 ∴ Marked price = Rs. 3000 To find the selling price when the discount = 25% Discount = 25/100 × 3000 = Rs. 750 Selling price = 3000 – 750 = Rs. 2250 ∴ Selling price of an article when the discount is 25% is Rs. 2250 |
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| 158. |
1). 652). 57.53). 354). 42.5 |
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Answer» Let the Selling price before discount be Rs. 100 Now the EFFECTIVE discount after 2 successive discounts can be GIVEN as ⇒ 100 × (1 - 15/100)(1 - 50/100) = 100 × 0.85 × 0.50 ⇒ final selling price is Rs. 42.5 ⇒ Discount is 100 – 42.5 = Rs. 57.5 ∴ the discount PERCENTAGE is 57.5% |
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| 159. |
A fan is sold at a discount of 37.5%. If the marked price of the fan is Rs. 7200, then what is the selling price (in Rs) of the fan?1). Rs. 45002). Rs. 43503). Rs. 52404). Rs. 5120 |
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Answer» GIVEN that, Discount = 37.5% Selling price = 7200 × [(100 - 37.5)/100] ⇒ Selling price = 7200 × (62.5/100) = Rs. 4500 ∴ Selling price of fan is Rs. 4500 |
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| 160. |
The selling price of an article is 5/3 of its cost price. Then the gain percentage is:1). 52%2). \(56\frac{2}{3}\% \)3). \(66\frac{2}{3}\% \)4). 68% |
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Answer» Let the SELLING price be SP and the Cost Price be CP. Then SP = (5/3) × CP----(1) Gain percentage = [(SP – CP)/CP] × 100----(2) PUTTING (1) in (2) We GET, Gain percentage $(= \frac{2}{3} \times 100 = 66_3^2\%)$ |
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| 161. |
A product is marked at a price 40% above its cost price. At what discount it should be sold so as to make 0% profit?1). 20%2). 28.6%3). 32.4%4). 40% |
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Answer» Let the COST PRICE of product be RS. ‘x’ Marked price = (100 + 40)% of x = 1.4x Since, profit = 0% Selling price = cost price = x Now, DISCOUNT = Marked price – Selling price = 1.4x – x = 0.4x ∴ Discount % = (0.4x/1.4x) × 100 = 28.6% |
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| 162. |
A shopkeeper bought sugar at a price of Rs. 40 per kg and is selling at a price of Rs. 50 per kg. When a customer bought 6 kg of sugar, using faulty weights he gave him only 5.4 kg of sugar. What is his total profit percentage?1). 31.11%2). 36.59%3). 38.89%4). 34.25% |
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Answer» Cost price of sugar = Rs. 40 per kg Selling price of sugar = Rs. 50 per kg PROFIT percentage due to price = [(50 – 40)/40] × 100 = 25% Profit percentage due to false weight = [error/(TRUE weight – error)] × 100 = (0.6/5.4) × 100 = 11.11% ∴ TOTAL profit percentage = 25 + 11.11 + (25 × 11.11)/100 = 36.11 + 2.78 = 38.89% |
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| 163. |
1). 70802). 120403). 45804). 5040 |
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Answer» WEIGHTED ratio of investment of A, B and C, ⇒ 7500 × 6 ? 4200 × 10 ? 12000 × 3 ⇒ 45 ? 42 ? 36 ⇒ 15 ? 14 ? 12 Total profit = Rs. 18000 ∴ As working member C receives, ⇒ 18000 × 18/100 ⇒ Rs. 3240 ∴ REMAINING profit = Rs. (18000 – 3240) = Rs. 14760 ∴ SHARE of B = 14760 × (14/41) = Rs. 5040 |
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| 164. |
1). 22.42%2). 38.14%3). 18.53%4). None of these |
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Answer» Effective profit percentage = –19.91 + 31.13 – [(19.91 ? 31.13)/100] = 5.02% Let the cost PRICE for 1kg of WHEAT be RS. 1000 Selling price of 1kg of wheat = (105.02/100) ? 1000 = Rs. 1050.2 Actual cost price of wheat for 1kg( 850gm ) = Rs. 850 $({\rm{\;Profit\;percentage}} = \frac{{1050.2{\rm{\;}}-{\rm{\;}}850}}{{850}} \times 100\% = 23.55\% )$ ∴ The difference between the profit or loss percentage of Radhika and the effective percentage = 23.55 – 5.02 = 18.53% |
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| 165. |
A trader had 2000 kgs of rice. He sold a part of it at 10% profit and the rest of it at 16% profit so that he made a total profit of 14.2%. How much rice (in kg) did he sell at 10% profit?1). 14002). 6003). 8004). 1000 |
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Answer» Let the cost of each KG of rice = Rs. 1 Cost of 2000 kg of rice = Rs. 2000 Total selling PRICE = 114.2% of 2000 = 2000 × 114.2/100 = Rs. 2284 Let x kg be the amount of rice he sold at 10% profit and (2000 – x) be the amount of rice he sold at 16% profit and overall profit = 14.2% Cost price of x kg rice = Rs. x Selling price of rice of x kg rice = x × 110/100 = 1.1x Cost price of (2000 – x) kg rice = Rs. (2000 – x) Selling price of rice = (2000 – x) × 116/100 = 2320 – 1.16x Total S.P. = 1.1x + (2320 – 1.16x) = 2320 – 0.06x Equating S.P. 2320 – 0.06x = 2284 ⇒ x = 600 kg ∴ The amount of rice he SELLS at 10% profit = 600kg. |
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| 166. |
Anil bought 100 eggs at Rs. 6 per egg. He sold 25 eggs at 10% profit, another 25 eggs at 25% loss and the balance 50 eggs at 20% profit. Find the overall profit or loss percent Anil made.1). 6.25% loss2). 6.25% profit3). 8% profit4). 12% loss |
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Answer» TOTAL COST price = 6 × 100 = Rs. 600 Now, 25 eggs are sold at 10% profit, ⇒ Selling price of 1 egg = 6 + 10% of 6 = Rs. 6.6 ⇒ Selling price of 25 eggs = 6.6 × 25 = Rs. 165 Also, 25 eggs are sold at 25% LOSS, ⇒ Selling price of 1 egg = 6 - 25% of 6 = Rs. 4.5 ⇒ Selling price of 25 eggs = 4.5 × 25 = Rs. 112.5 Now, 50 eggs were sold at 20% profit, ⇒ Selling price of 1 egg = 6 + 20% of 6 = Rs. 7.2 ⇒ Selling price of 50 eggs = 7.2 × 50 = Rs. 360 ⇒ Total selling price = 165 + 112.5 + 360 = Rs. 637.5 ⇒ Profit % = {(selling price - cost price)/cost price} × 100 ⇒ Profit % = {(637.5 - 600)/600} × 100 = 6.25% |
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| 167. |
A man buys an item at Rs. 1400 and sells it at a gain of 20%.The selling price is1). Rs. 17402). Rs. 16803). Rs. 15604). Rs. 1640 |
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Answer» SELLING price = COST price + profit Given, A man buys an item at Rs. 1400 and sells it at 20% profit. Profit = 20% of 1400 ⇒ Profit = Rs. 280 ∴ Selling price = Rs. (1400 + 280) = Rs. 1680 |
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| 168. |
1). 41.1 percent2). 82.2 percent3). 70 percent4). 12.2 percent |
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Answer» Let’s ASSUME the selling price of ONE Omega watch is Rs. ‘x’ According to the given information, Total sales = 17x PROFIT = 7x ⇒ SP - CP = 7x ⇒ 17x - CP = 7x ⇒ CP = 10x ⇒ Profit % = ((SP/CP) - 1 ) × 100 = ((17x/10x) - 1) × 100 = 70% ∴ Profit % = 70% |
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| 169. |
A merchant allows 5% discount on all his goods to all his customers. He offers a further discount of 2% on the reduced price to those customers who pay cash. What will a customer actually has to pay for an article in cash if its Marked Price is Rs 4800?1). Rs 3478.502). Rs 4468.803). Rs 5670.584). Rs 4560 |
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Answer» Given that, MARKED PRICE of the article = Rs 4800 First discount = 5% of marked price = 5 × 4800/100 = Rs 240. Net price after discount = Rs (4800 - 240) = Rs 4560 Second discount = 2% of Rs 4560 = 2 × 4560/100 = Rs 91.20 ∴ Net price after discount = Rs 4560 – Rs 91.20 = Rs 4468.80 Short TRICK Method:- Required price $(= 4800 \times \left( {1 - \FRAC{5}{{100}}} \right) \times \left( {1 - \frac{2}{{100}}} \right))$ = Rs 4468.80 Hence, the required answer is Rs 4468.80, |
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| 170. |
After a discount of 40% on marked price of a shirt, it is found that the marked price of a wallet is same as selling price of shirt. The wallet is sold at a profit of 20%. Find the cost price of wallet if marked price of shirt is Rs. 2000.1). Rs. 8002). Rs. 10003). Rs. 12004). Rs. 1280 |
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Answer» Marked price of shirt = Rs. 2000 DISCOUNT on shirt = 40% We KNOW, SELLING Price = Marked Price × (1 – ((Discount Percentage)/100)) ⇒ Marked price of Wallet = Selling price of shirt = 2000 × (1 – 40/100) = 2000 × 0.6 = 1200 The wallet is sold at a profit of 20%. We are not given that there is any discount on wallet. So, we assume that discount is 0, and hence selling price and marked price will be same. ⇒ Selling price of Wallet = Rs. 1200 We know, Selling Price = Cost Price × (1 + (Profit Percentage)/100) ⇒ Cost price of wallet = Rs. 1200/(1 + (20/100)) = Rs. 1200/1.2 = Rs. 1000 |
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| 171. |
A reduction of 25% in the price of rice enables a person to buy 10 kg more rice for Rs. 600. What is the reduced per kg price of rice?1). Rs. 152). Rs. 203). Rs. 254). Rs. 30 |
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Answer» Expenditure = Price ? Quantity Since expenditure is same, Price ? Quantity = constant Let the OLD price and old quantity of rice PURCHASED be P and Q respectively. We can write, PQ = 0.75P ? (Q + 10) ⇒ PQ = 0.75PQ + 7.5P ⇒ 0.25PQ = 7.5P ⇒ Q = 30 kg So, New quantity purchased = 40 kg Total expense = Rs. 600 ∴ New Price PER kg = $(\frac{{600}}{{40\;}} = Rs.15)$ |
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| 172. |
P and Q enter in to a partnership with P investing Rs. 20,000 and Q investing a certain amount. At the end of first 4 months P withdraws Rs. 4000, and Rs. 6000 at the end of another 5 months. Q remains in the business till the end with the initial investment and receives Rs. 19200 as profit at the end of the year. The total profit at the end of the year is Rs. 38,200. Find the investment of Q.1). Rs. 80002). Rs. 120003). Rs. 160004). Rs. 18000 |
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Answer» <P>GIVEN the total profit at the end of the year is 38200 Profit received by Q at the end of the year = Rs. 19200 Profit amount received by P at the end of the year = Rs. (38200 - 19200) ⇒ Rs.19000 Ratio of their profits (P : Q) = 19000 : 19200 ⇒ 190 : 192 ⇒ 95 : 96 P’s investment = (Rs. 20000 for 4 MONTHS) + (20000 - 4000) for 5 months + (20000 - 4000 - 6000) for 3 months ⇒ (20000 × 4) + (16000 × 5) + (10000 × 3) ⇒ 80000 + 80000 + 30000 ⇒ Rs. 190000 Let Q’s investment = ‘X’ Both P and Q invested the amount for a year, so the ratio of their profits will be equal to the ratio of the investments ⇒ 95 : 96 = 190000 : X ⇒ X = (190000 × 96)/95 ⇒ X = 2000 × 96 ⇒ X = Rs. 192000 Q’s Investment = Rs. 192000 If this was Q’s investment over the months, he might have invested 192000/12 = Rs. 16000 ∴ B’s investment = Rs. 16000 |
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| 173. |
A dishonest shopkeeper uses a weight of 850 gm instead of 1 kg and sells rice on its cost price. What will be his profit percentage on selling 5 kg rice?1). 18.24%2). 17.65%3). 15%4). 13.04% |
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Answer» Original weight of rice = 1 kg = 1000 gm Let cost of 1 gm is Rs. 1 Cost price of 1000 gm = Rs. 1000 Selling price of 850 gm = Rs. 1000 (? giving only 850 gm INSTEAD of 1000 gm) PROFIT = [ERROR/ (true weight)] × 100 ⇒ Profit = [(1000 - 850)/ 850] × 100 = (150/850) × 100 = 17.65% ∴ profit % on 5kg is equal to profit on 1 kg which is 17.65% |
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| 174. |
The cost of 25 items is same as the revenue earned by selling x items. Find x, if the profit made in the transaction is 25%.1). 252). 16.673). 204). 32 |
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Answer» Let the COST PRICE of one item be RS. A. ⇒ Selling price to make 25% profit = A × 1.25 = 1.25 A Since the cost of 25 items is the same as the revenue earned by selling X items, ⇒ 25 × A = 1.25 A × x ∴ x = 20 |
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| 175. |
1). 8250002). 7500003). 7480004). 720000 |
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Answer» Let selling price = SP CP = RS. 700000 Profit MAY be EARNED = probability × real profit Real profit = 50000 × 5/2 = Rs. 125000 SP = CP + Real profit = 700000 + 125000 = Rs. 825000 ∴ Selling price = Rs. 825000 |
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| 176. |
A receives 1/15th of the total profit and the remaining is divided between B and C in the ratio of 3 : 4. If the difference between the profit shares of C and A is Rs. 2800. What is B’s share?1). Rs. 20002). Rs. 22003). Rs. 23004). Rs. 2400 |
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Answer» Let total profit = RS. x A’s share in profit = x/15 ⇒ REMAINING profit = 1 - x/15 = 14x/15 ⇒ B’s share = 3/7 × 14x/15 = 2x/5 ⇒ C’s share = 4/7 × 14x/15 = 8x/15 According to the question, C - A = 2800 ⇒ 8x/15 - x/15 = 2800 ⇒ 7x/15 = 2800 ⇒ x = 15 × 400 = Rs. 6000 B’s share = 2x/5 = (2 × 6000)/5 = Rs. 2400 ∴ B’s share is Rs. 2400 |
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| 177. |
Selling price of a chair is Rs. 1386. If loss percentage is 23%, then what is the cost price (in Rs.) of the chair?1). 16002). 18003). 19004). 1067 |
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Answer» ⇒ C.P of the CHAIR × 77/100 = S.P. of the chair ⇒ C.P of the chair × 77/100 = 1386 ∴ C.P of the chair = 1386 × 100/77 = 1800 |
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| 178. |
If a commission of 10% is given on the marked price of an article, the gain is 25%. Find the gain percentage if the commission is increased to 20%.1). 5.5%2). 11.1%3). 15.5%4). 16.3% |
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Answer» ⇒ COMMISION = 10% of 100 = 10 ⇒ SP = 90 ⇒ CP = 90/125 × 100 = Rs. 72 ⇒ New commission = Rs. 20 New SP = Rs. 80 ⇒ GAIN percentage = (8 × 100)/72 = 11.1% ∴ Gain percentage = 11.1% |
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| 179. |
Marked price of an item is Rs 200. On purchase of 1 item discount is 22%, on purchase of 4 items discount is 33%. Rabia buys 5 items, what is the maximum effective discount she can take?1). 35 percent2). 30.8 percent3). 34 percent4). 20.4 percent |
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Answer» Marked Price = Rs. 200 After Rabia buys 4 items, she GETS 33% discount ∴ Selling Price = 200 – (0.33 × 200) = Rs. 134. Since the items are 4 in number total price = 4 × 134 = Rs. 536 Now, Rabia buys another item ⇒ Discount = 22% ∴ Selling Price = 200 – (0.22 × 200) = 200 – 156. ∴ Total Selling Price = 536 + 156 = Rs. 692. ⇒ Effective Discount = [(1000 – 692)/1000] × 100 = 30.8 % |
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| 180. |
After giving a discount of 33.33%, there is a loss of 11.111%. If only 10% discount is given, then what will be the profit percentage?1). 242). 203). 274). 25 |
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Answer» Let the marked price (M.P) = x After discount of 33.33% Selling price = S.P = (1 - 0.3333) × x = 0.6667x Loss percentage = (loss/C.P) × 100 = {(C.P - S.P)/C.P} × 100 Loss% = 11.111% ⇒ (C.P - 0.6667x)/C.P} × 100 = 11.111 ⇒ 1 - 0.6667x/C.P = 0.11111 ⇒ 0.6667x/C.P = 0.88889 ⇒ C.P = 0.6667x/0.88889 = 0.75x When only 10% discount was given S.P = (1 - 0.1) × x = 0.9x PROFIT = S.P = C.P = 0.9x - 0.75x = 0.15x Profit% = (profit/C.P) × 100 ⇒ profit % = (0.15x/0.75x) × 100 = 20% |
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| 181. |
1). Rs. 20152). Rs. 21453). Rs. 22354). Rs. 2325 |
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Answer» Let the cost price be Rs. ‘x’$ MARKED price = (100 + 20)% of x = 1.2x$ Selling price = (100 – 15)% of (100 – 10)% of 1.2x = 0.85 × 0.9 × 1.2x = 0.918x$ ⇒ 0.918x = 2051.73$ ⇒ x = 2235$ ∴ Cost price of PRODUCT is Rs. 2235$ |
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| 182. |
Madhuparna sold an article such that the ratio of its selling price to cost price was 8 ∶ 7. Find the profit percentage of her transaction.1). 8.54%2). 10.25%3). 14.28%4). 15.24% |
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Answer» We know that profit percentage [(s – c)/c] × 100, where s is the SELLING price and c is the COST price. Here, s/c = 8/7 or (s – c)/c = 8/7 - 1 On putting this in the equation above we get Profit percentage = (8/7 – 1) × 100 = 14.28% |
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| 183. |
A shopkeeper incurs 10% loss by selling a washing machine for Rs. 16200. At what price should the washing machine be sold to earn 15% profit?1). Rs. 187002). Rs. 197003). Rs. 207004). Rs. 20250 |
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Answer» LET cost PRICE of washing machine is x. Cost price of washing machine when SHOPKEEPER incurs 10% loss. ⇒ Cost price = [Selling price/(1 - loss)] × 100 ⇒ Cost price = [16200/(1 - 10)] × 100 = 18000 Selling price of washing machine when shopkeeper earn 15% profit. ⇒ Selling price = Cost price × (1 + profit %) ⇒ Selling price = 18000 × (1 + 15/100) ⇒ Selling price = 18000 × 1.15 = Rs. 20700 |
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| 184. |
By Selling 5 articles for 18rupee, a man losses 10%. If he sells 3 articles for Rs. 15, then what will be the profit percentage?1). 752). 66.673). 304). 25 |
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Answer» LET, cost price of 5 article = Rs. x Price at 10% loss = Rs. 18 According to PROBLEM, ⇒ x - x × 10/100 = 18 ⇒ 0.9x = 18 ⇒ x = 20 ∴ Cost price of 5 article = Rs. 20 ∴ Cost price of 3 article = Rs. 20 × 3/5 = Rs. 12 Selling price of 3 article = Rs. 15 ∴ Profit percentage, $( \Rightarrow \frac{{15 - 12}}{{12}} \TIMES 100\% )$ ⇒ 25% |
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| 185. |
A firm makes a total profit of Rs. 500000. Out of which 20% is paid as taxes and the rest is divided among the partners A and B in the ratio 5 ∶ 3. Find the respective shares of A and B.1). 150000 and 2500002). 190000 and 2100003). 200000 and 2000004). 250000 and 150000 |
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Answer» TOTAL profit = Rs. 500000 ∴ TAX PAID = 500000 × 20/100 [? 20% paid as tax] = Rs. 100000 ∴ REMAINING profit = Rs. (500000 – 100000) = Rs. 400000 Remaining profit is divided among A and B in the ratio 5 ? 3. Let, Share of A = 5x ∴ Share of B = 3x ∴ 5x + 3x = 400000 ⇒ 8x = 400000 ⇒ x = 50000 ∴ Share of A = 5 × 50000 = Rs. 250000 ∴ Share of B = 3 × 50000 = Rs. 150000 |
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| 186. |
A invested Rs. 12,000 for 8 months and B invested Rs. 16,000 for some times in a business. If the profits of A and B are equal, then the period of time for which B’s capital was invest is1). 6 months2). 5 months3). 4 months4). 3 months |
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Answer» A INVESTED Rs. 12,000 for 8 MONTHS And, B invested Rs. 16,000 Let, B invested for x months ∴ Ration of profit of A and B = (12000 × 8): 16000x = 96000: 16000x Given, Profits of A and B are equal ∴ 96000 = 16000x ⇒ x = 96000/16000 = 6 months |
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| 187. |
The ratio in which a variety of U.P sugar at Rs. 25/kg is mixed with another type of Gujarat sugar costing Rs 30/kg to get a gain of 20% by selling the blended sugar at Rs. 34/kg is:1). 1 : 32). 2 : 33). 1 : 24). 2 : 1 |
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Answer» Let the amount of U.P SUGAR in a mixture of 1 KG be x kg ⇒ Amount of Gujarat sugar in 1 kg mixture = (1 – x) kg ⇒ Total COST price of 1 kg mixture = 25x + 30(1 – x) = 30 – 5X Now, for 20% profit ⇒ S.P = (120/100) × C.P ⇒ 34 = 120C.P/100 But, C.P = 30 – 5x ⇒ 34 = 120(30 – 5x)/100 ⇒ 17 = 3(6 – x) ⇒ 17 = 18 – 3x ⇒ 3x = 1 ⇒ x = 1/3 ⇒ 1 – x = 1 – 1/3 = 2/3 ∴ So the desired ratio is x : (1 – x) = 1 : 2 |
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| 188. |
1). Rs. 1,6202). Rs. 1,6403). Rs. 1,6604). Rs. 1,680 |
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Answer» We know that PROFIT % = (Selling price - cost price)/cost price × 100 ⇒ 25 = (2100 - x)/x × 100 ⇒ 25x + 100X = 210000 ⇒ 125x = 210000 ⇒ x = 1680 ∴ Cost price x = Rs. 1,680 |
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| 189. |
A shopkeeper gives an offer of "Buy two get three free". Find his loss percentage if he sells at cost price.1). 50%2). 200%3). 150%4). 60% |
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Answer» LET cost PRICE of one item be RS. x Total cost price = cost price of FIVE item = 5 × x = 5x Total selling price = cost price of two item = 2 × x = 2X ∴ Loss % = {(SP – CP)/CP} × 100 = {(5x – 2x)/5x} × 100 = (3/5) × 100 = 60% |
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| 190. |
1). 8 ∶ 7 ∶ 72). 8 ∶ 4 ∶ 73). 5 ∶ 4 ∶ 44). 8 ∶ 14 ∶ 7 |
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Answer» Let, investment of X = 5a Investment of Y = 7a Investment of Z = 8a ∴ WEIGHTED ratio of investment of X, Y and Z ⇒ 5a × 14 ? 7a × 8 ? 8a × 7 ⇒ 70A ? 56a ? 56a ⇒ 5 ? 4 ? 4 |
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| 191. |
A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?1). 33.33%2). 25%3). 66.66%4). 50% |
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Answer» GIVEN that he cheats 20% at time of buying ⇒ Goods bought = 1000(1 + 20/100) Given that he cheats 10% at time of buying ⇒ Goods sold = 1000(1 – 10/100) ⇒ 900g at price of 1000 g Since cost price = selling price ⇒ Profit PERCENTAGE = goods left/goods sold × 100 ⇒ [(1200 – 900)/900] × 100% ⇒ [300/900] × 100% ⇒ [1/3] × 100% ⇒ 33.33% ∴ Profit percentage = 33.33% |
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| 192. |
By selling an article for Rs. 450, a man loses 10%. The gain or loss per cent if he sells it for Rs. 540 is1). Gain 8%2). Loss 8%3). Gain 9%4). Loss 9% |
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Answer» We have SP = Rs 450 Loss % = 10 % ⇒ CP = SP× 100 / (100 – Loss %) ⇒ CP = 450 × 100 / (100 – 10) ⇒ CP = 450 × 100/90 ⇒ CP = Rs 500 ⇒ New SP = Rs 540 ⇒ GAIN = 540 – 500 = Rs 40 ⇒ Profit % = (Profit / CP) × 100 = (40/500) × 100 = 8% |
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| 193. |
An umbrella is listed at Rs 1500 and a discount of 20% is offered on the list price. What additional discount must be offered to the costumer to bring the net price to Rs 1104?1). 10%2). 8%3). 12%4). 15% |
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Answer» Marked price of UMBRELLA = Rs. 1500 After a DISCOUNT of 20%, SELLING price of the umbrella = Rs. (1500 × 80/100) = Rs. 1200 Difference from the required selling price = Rs. (1200 – 1104) = Rs. 96. Let a discount of x% is required on the umbrella to make its selling price which is required, x% of 1200 = 96 ⇒ 1200 × x/100 = 96 ⇒ x = 8% Hence, a second discount of 8% is required on selling the umbrella. |
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| 194. |
1). 10% Profit2). 15% Profit3). 12% Loss4). 18% Loss |
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Answer» As per the given DATA, Let the cost PRICE of the pen be Rs.X ⇒ Profit % = (SP - CP)/CP × 100 ⇒ 20 = (36 - x)/x × 100 ⇒ 20x = 3600 - 100x ⇒ 120x = 3600 ⇒ x = 30 ∴ Cost price of the pen is Rs.30 Also given that he SOLD the pen at Rs.33 By comparing with cost price of the pen Rs.30 with selling price of the pen Rs.33, we can say it as profit ⇒ Profit % = (33 - 30)/30 × 100 = 10 % ∴ Percentage of profit is 10% |
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| 195. |
1). 5% loss2). 5% gain3). 10% loss4). 10% gain |
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Answer» Cost price of 10 kg of rice = Rs. 400 × 10 = Rs. 4000 Cost price of 5 kg of rice = Rs. 2000 and the cost price of the REMAINING 5 kg of rice = Rs. 2000 Also given that trader got 20% loss for half of the quantity We know that loss% = (CP - SP)/CP × 100 ⇒ 20 = (2000 - SP)/2000 × 100 ⇒ 200000 - 40000 = 100SP ⇒ SP = Rs. 1600 ∴ Loss for first half = 2000 - 1600 = Rs. 400 Also given that profit for SECOND half is 10% ⇒ 10 = (SP - 2000)/2000 × 100 ⇒ 100SP = 20000 + 200000 ⇒ SP = 2200 ∴ Profit for second half = 2200 - 2000 = Rs. 200 ∴ Net there is a loss of Rs. 200 Final loss % = (net loss/total cost price × 100) = 200/4000 × 100 = 5% |
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| 196. |
Successive discounts of a% and b% on the marked price of an article is equivalent to a single discount of:1). \(\left( {a - b\; + \;\frac{{ab}}{{100}}} \right)\% \)2). \(\left( {a - b - \frac{{ab}}{{100}}} \right)\%\)3). \(\left( {a\; + \;b - \frac{{ab}}{{100}}} \right)\%\)4). \(\left( {a\; + \;b\; + \;\frac{{ab}}{{100}}} \right)\%\) |
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Answer» Let the marked PRICE of the ARTICLE be RS. p Selling Price when discount of a% is given = [(100 - a)/100] × p Selling price when discount of b% is given on the above selling price = [(100 - b)/100] × [(100 - a)/100] × p = [(100 - b) × (100 - a)]/10000 × p Now consider a single discount of c% is given on the product. ⇒ Selling price of the product = [(100 - c)/100] × p ⇒ [(100 - b) × (100 - a)]/10000 × p = [(100 - c)/100] × p ⇒ (100 - b) × (100 - a)/10000 = (100 - c)/100 ⇒ (100 - b) × (100 - a)/100 = (100 - c) ⇒ (100 – a) × (100 – b) = (100 – c) × 100 ⇒ 10000 – 100B – 100a + ab = 10000 – 100c ⇒ 100c = 100a + 100b – ab ⇒ c = [a + b – (ab/100)]% |
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| 197. |
1). Rs. 6722). Rs. 3363). Rs. 4484). Rs. 224 |
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Answer» Let the C.P of first and second ARROWS be A and a respectively Hence, A + a = 1120----(1) Now after selling one at 15% profit and other at 10% loss, the TOTAL selling price becomes, S.P = (A + 15% of A) + (a – 10% of a) Now given that he NEITHER gains nor losses, hence the S.P = 1120. 1120 = (A + 15/100 × A) + (a – 10/100 × a) 1120 = 115A/100 + 90a/100 Hence, 115A + 90a = 112000----(2) Solving Eqn. (1) and (2) SIMULTANEOUSLY we get 25a = 16800 ⇒ a = 672 |
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| 198. |
Akash purchased a table marked at Rs. 600 at two successive discounts of 15% and 20% respectively. He spent Rs. 28 on transportation and sold the table for Rs. 545. His profit percent was1). 25%2). 30%3). 35%4). 20% |
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Answer» Since Akash PURCHASED a table marked at Rs. 600 at two successive discounts of 15% and 20% ∴ Cost PRICE of the table $(= 600 \times \frac{{100 - 15}}{{100}} \times \frac{{100 - 20}}{{100}} = 600 \times \frac{{85}}{{100}} \times \frac{{80}}{{100}} = {\rm{Rs}}.408)$ Since TRANSPORTATION cost is Rs. 28 ∴ Total Cost price of the table = 408 + 28 = Rs. 436 ∴ Profit = 545 – 436 = Rs. 109 ∴ % Profit $(= \frac{{109}}{{436}} \times 100 = 25{\rm{\% }})$ |
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| 199. |
70% of the cost price of a article is equal to the 40% of its selling price. What is the profit or loss percentage?1). 63% loss2). 70% loss3). 75% profit4). 80% profit |
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Answer» LET the cost price be RS. 100 and SELLING price be y According to the question ⇒ 70 × 100/100 = 40y/100 ⇒ y = 175 ⇒ Profit = 175 – 100 ⇒ Profit = Rs. 75 ∴ net profit % is 75% |
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| 200. |
A man sells two tables at the same price. On one he makes a profit of 10% and on the other he suffers a loss of 10%. What is his loss % on the whole transaction?1). 02). 13). 24). 5 |
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Answer» % LOSS = (PERCENTAGE)2/100 = 100/100 = 1 |
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