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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
A shopkeeper claims to sell his goods at cost price but uses a weight of 225 grams for a 250 grams weight. What is the profit percentage for the shopkeeper?1). 12.52). 103). 11.114). 9.09 |
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Answer» Let the CP of 250 gms. of goods be x CP of 225 GM of goods = (x/250) × 225 = 9x/10 Profit% = (CP - ORIGINAL CP)/ Original CP × 100 = (x/10)/(9x/10) × 100 = 11.11% |
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| 102. |
The price of a watch is increased by 25%. By what percent the price should be decreased to restore its original price?1). 18%2). 20%3). 22.5%4). 25% |
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Answer» LET the original PRICE be Rs. p Now INCREASED price is 25 % more than original price ∴ Increased price = p + 25% of p = 1.25p Now, when the price is restored to its original price, i.e. p, ∴ % decrease in price from NEW price $(= \frac{{1.25p - p}}{{1.25p}} \TIMES 100 = \frac{{0.25p}}{{1.25p}} \times 100 = 20)$ ∴ Price should be decreased by 20%. |
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| 103. |
Mr. Akshar sold a bus for Rs. 20,400 with a loss of 15%. At what price should the bus be sold to get a profit of 15%?1). Rs. 27,4002). Rs. 27,3003). Rs. 27,5004). Rs. 27,600 |
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Answer» Let the cost PRICE of the bus be RS. X. Selling price (S.P.) of the bus = x – (15% of x) = 0.85x(? S.P. = C.P. – LOSS) ⇒ 20400 = 0.85x ⇒ x = 20400/0.85 = Rs. 24,000 If profit = 15%: S.P. of the bus = 24000 + (15% of 24000)(? S.P. = C.P. + Profit) ⇒ S.P. of the bus = 24000 + ((15/100) × 24000) = 24000 + 3600 = Rs. 27,600 ∴ S.P. of the bus to get a profit of 15% = Rs. 27,600 |
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| 104. |
Investment of B is 2.5 times of investment of A and ratio between time of investment of A and B is 3 : 1. If total investment of A and B is Rs. 28000 and profit share of A is 500 less than his investment. Then find the difference between profit share of A and B?1). Rs. 3502). Rs. 5003). Rs. 6504). Rs. 850 |
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Answer» Share of each member in PROFIT = AMOUNT × Time invested Investment of A = (1/3.5) × 28000 = Rs. 8,000 Investment of B = (2.5/3.5) × 28000 = Rs. 20,000 Profit of A = 8000 - 500 = Rs. 7,500 Time of investment of A = 7500/8000 Time of investment of B = 7500/8000 × (1/3) Total share of B in profit = 20000 × 7500/8000 × (1/3) = Rs. 6250 Difference between profit share of A and B = 7500 - 6250 = Rs. 1250 |
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| 105. |
The profit (In Rs.) after selling an article for Rs. 524 is the same as the loss (In Rs.) after selling it for Rs. 452. The cost price of an article is:1). 4802). 4853). 4884). 500 |
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Answer» <P>Let the C. P. of ARTICLE be RS. x. According to the question 524 – x = x – 452 2x = 524 + 452 = 976 X $(= \FRAC{{976}}{2})$ = 488 |
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| 106. |
Mohit buys an old bicycle for Rs 2700 and spends Rs 500 on its repairs. If he sells the bicycle for Rs 3520, then what is his profit percentage?1). 102). 12.53). 154). 20 |
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| 107. |
A shopkeeper gives 1 chocolate for every 19 chocolates sold. If he plans to give a summer discount of 20%, how many extra chocolates does he need to sell in a sale of 40 chocolates?1). 22). 43). 84). 10 |
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Answer» The shopkeeper gives a 20 chocolates at the COST of 19 i.e. he gives a discount of (1/20) × 100 = 5%. Now he want to give a summer discount of 20% on 40 chocolates. Let he gives X chocolates as a discount 20 = (x/40) × 100 ⇒ x = 8 So, he needs to sell 8 EXTRA chocolates in order to give a discount of 20% on 40 chocolates. |
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| 108. |
A man buys 10 oranges for a rupee and sells 8 oranges for a rupee. What is the profit percentage?1). 102). 12.53). 204). 25 |
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Answer» Cost price of 10 oranges = Rs. 1 Cost price of 1 orange = Rs. 0.10 Selling price of 8 oranges = Rs. 1 Selling price of 1 orange = Rs. 0.125 Profit percentage = (0.125 - 0.10)/0.10 × 100 = 25% |
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| 109. |
Ram sold a table for Rs. 220 and thus lost 12%. At what price he should have sold it to gain 12%?1). Rs.2042). Rs.2503). Rs.2804). Rs.320 |
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Answer» Let the cost PRICE be ‘c’. Given, Ram SOLD a table for Rs. 220 and THUS lost 12%. ∴ c – 12% of c = 220 ⇒ 0.88c = 220 ⇒ c = Rs. 250 Now, in ORDER to gain 12%, selling price = 250 + 12% of 250 ⇒ Selling price = 250 × 1.12 = Rs. 280 |
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| 110. |
Ricky uses a forged weighing machine that shows a 10% increased weight. He bought 20 kg of rice at 80 rupees per kg. At what price should he sell the rice so that he gains an overall profit of 15%?1). Rs. 80 per kg2). Rs. 81.12 per kg3). Rs. 82.28 per kg4). Rs. 83.64 per kg |
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Answer» The weighing machine shows a 10% increased weight. If 20 kg weight is MEASURED, the weight machine will show = [20 + 20 × (10/100)] kg = 22 kg Because of this fault, Ricky will sell 20 kg of rice, but will TAKE price of 22 kg of rice. Cost price for Ricky = AMOUNT bought × Cost price for one kg rice = 20 × Rs. 80 = Rs. 1600 Suppose Ricky sells rice at Rs. T PER kg. Total selling price = 22 × Rs. T = Rs. 22T We know, Selling Price = Cost Price × (1+ (PROFIT Percentage)/100) For profit to be 15%, 22T = 1600 × (1+ (15/100)) T = (1600 × 1.15)/22 = 83.64 ∴ To gain an overall profit of 15%, rice should be sold at Rs. 83.64 per kg. |
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| 111. |
You went to buy 3 articles worth Rs. 500 each. However, as per the discount sale going on in the shop, you paid for two and got one free. What is the discount percentage in the deal?1). 30%2). 33%3). 33.13%4). 33.33% |
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Answer» M.P. (marked PRICE) of 1 article is RS. 500. Now, M.P. of 3 = Rs. 1500 Amount actually paid = M.P. of 2 articles = Rs. 1000 Discount = Rs. (1500 - 1000) = Rs. 500 Discount percentage= (500/1500) × 100 = 33.33% |
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| 112. |
A vendor sells 40% of his stock for a particular item and recovers the cost price. If he continues to sell rest of the stock at the same price, what will be his profit percentage after selling the complete stock?1). 120%2). 100%3). 140%4). 150% |
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Answer» ⇒ Given: 40% of SP = 100% of CP ⇒ 1% of SP = 100% / 40% of CP ⇒ 100% of SP = 100% / 40% ? 100% of CP ⇒ 100% of SP = 250% of CP ∴ Profit = SP - CP = (250 - 100)% = 150% |
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| 113. |
A shopkeeper buys milk at Rs. 36/litre and mixes 200ml/litre water in it. If he sells the mixture at Rs. 40/litre, find his percentage profit.1). 10%2). 11.1%3). 20%4). 33.3% |
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Answer» Since, the shopkeeper mixed 200 ml WATER in 1 litre of milk, then he PREPARED (1000 + 200 = 1200 ml = 1.2 litre of milk-water MIXTURE in Rs. 36 ⇒ COST price of 1 litre milk-water mixture = 36/1.2 = Rs. 30 Now, selling price of 1 litre milk-water mixture = Rs. 40 Profit earned per litre = 40 – 30 = Rs. 10 ∴ Profit percentage = (10/30) × 100 = 33.3% |
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| 114. |
After offering successive discounts of 20% and 30% on a chair, the selling price of chair is Rs. 902 less than marked price. The profit earned on this transaction is 40%. What is the sum of cost price and marked price of chair?1). Rs. 25602). Rs. 28703). Rs. 27304). Rs. 3000 |
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Answer» In case of SUCCESSIVE DISCOUNTS, Selling Price = MARKED Price × (1 – Discount1/100) × (1 – Discount2/100) ……. ⇒ Marked price – Selling price = Marked price - Marked price × (1 – 20/100) × (1 – 30/100) = 902 ⇒ Marked price = 902/[1 – 0.8 × 0.7] = 902/0.44 = 2050 And, selling price = Marked price – Rs. 902 = Rs. 2050 – Rs. 902 = Rs. 1148 The profit earned on this TRANSACTION is 40%. We know, Selling Price = Cost Price × (1 + (Profit Percentage)/100) ⇒ Cost price of chair = Rs. 1148/(1 + (40/100)) = Rs. 1148/1.4 = Rs. 820 ∴ Sum of cost price and marked price of chair = Rs. 820 + Rs. 2050 = Rs. 2870 |
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| 115. |
The price of LED strap is directly proportional to square to its length. A shopkeepers cut the LED strap in the ratio of 5 ∶ 4 ∶ 3 and this leads to a loss of Rs 1880. What is the initial price of LED strap?1). 20002). 2,5893). 1,8804). 2,880 |
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Answer» Let initial length of the LED STRAP = (5 + 4 + 3) = 12 unit So, initial price of the LED strap = 122 = 144 Price, after cutting the LED strap = 52 + 42 + 32 = 25 + 16 + 9 = 50 ⇒ (144 - 50) unit = 1880 ⇒ 94 unit = 1880 ⇒ 1 unit = 20 So, initial price of the LED strap = 144 × 20 = Rs 2,880 |
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| 116. |
If the selling price is Rs. 728 after getting a discount of 9%, what was the marked price?1). Rs. 793.522). Rs. 8003). Rs. 662.484). Rs. 667 |
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Answer» Selling price = RS. 728 Discount = 9% Discount% = (MP – SP)/MP × 100 9/100 = (x – 728)/x x = Rs. 800 |
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| 117. |
1). 130002). 121873). 140004). 13187 |
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Answer» Let the MARKED price of an ITEM be Rs. y According to the PROBLEM statement ⇒ y(1 - 25/100) = 9750 ⇒ y = 9750/0.75 ⇒ y = 13000 ∴ The marked price of an article is Rs. 13000 |
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| 118. |
Oranges are bought at 7 for Rs. 3. At what rate per hundred must they he sold to gain 33%?1). Rs. 562). Rs. 603). Rs. 584). Rs. 57 |
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Answer» Given, 7 oranges are bought for Rs. 3. Hence, ⇒The cost price of 1 oranges=Rs. 3/7 ⇒And, the cost price of 100 oranges=$(Rs.\frac{3}{7} \times 100)$ = Rs. 300/7 Let the SELLING price of these 100 oranges be X. We know that, Selling price = Cost price × (1 + Gain %) Since the gain has to be 33%. THUS, ⇒Selling price for 100 oranges $(= \frac{{300}}{7} \times \left( {1 + \frac{{33}}{{100}}} \right))$ = Rs. 57 Hence, the oranges must be sold at a rate of Rs. 57 PER hundred. |
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| 119. |
1). Rs. 13,5502). Rs. 12,4503). Rs. 11,2004). Rs. 12,000 |
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Answer» Let cost price of the ARTICLE be Rs. ‘x’, then, Selling price in first case = x – x × (5.5/100) When scooter is sold at Rs. 1000 more, then, Selling price in second case = x – x × (5.5/100) + 1000 {which gives a profit of 4.5%} Hence, $(x - \FRAC{{5.5}}{{100}}x\; + \;1000\; = \;x\; + \;\frac{{4.5}}{{100}}x)$ ⇒ 1000 = (10/100)x ⇒ x = Rs. 10,000 = Cost price of the article. Now, to GAIN a profit of 12%, Selling price of the article = Rs. {10000 × 112/100} = Rs. 11,200 Hence, the REQUIRED selling price of the article is Rs. 11,200. Alternate Method (Short TRICK): (5.5% + 4.5%) of CP = 1000 ⇒ 10% of CP = 1000 ⇒ CP = Rs. 10,000 Required selling price to gain 12% = Rs (10000 × 112/100) = Rs. 11,200. |
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| 120. |
The marked price of an article is Rs. 40. If its cost price is Rs. 24 and the discount percent offered on marked price is numerically equal to its profit percent then its selling price in Rs. is1). 372). 253). 204). 30 |
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Answer» let the discount OFFERED be ‘d’ PERCENT Selling price = 40 × (100 – d)/100 S.P – C.P = C.P × Profit percent [40 × (100 – d)/100] – 24 = 24 × d/100 ? discount % = profit % 4000 – 40d – 2400 = 24d 1600 = 64d ∴ d = 25% ∴ Selling price = 40 × 0.75 = Rs. 30 |
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| 121. |
If the selling price of a chair is 5 times the discount offered, and the discount percentage is equal to the profit percentage then find the ratio of discount offered to the cost price of the chair.1). 6 ∶ 302). 7 ∶ 303). 7 ∶ 354). 6 ∶ 35 |
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Answer» SINCE SP ? Discount = 5 ? 1 Suppose SP = 5x and discount = x----(1) ⇒ Marked price = 6x ⇒ Discount percentage = [6x – 5x]/6x = 100/6% Since discount percentage is EQUAL to the profit percentage ⇒ If CP = 6Y then SP = 7Y----(2) From equation 1 and 2 ? ⇒ SP = 35 ⇒ Discount = 7 and CP = 30 ∴ Ratio of discount offered to the COST price of the chair = 7 ? 30 |
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| 122. |
Mahesh sells two articles of cost price x each. He made a profit of 20% on the first article and a loss of 12% on the second article. Find x if his total selling price is Rs.124.8.1). 672). 583). 484). 60 |
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Answer» We know that, Selling price (SP) = Cost price (CP) + PROFIT(or) SP = CP - Loss Selling price of 1st article = x + 20% of x = x + 0.20x = 1.20x Selling price of 2nd article = x-12% of x = x-0.12x = 0.88x ⇒ 1.20x + 0.88x = 124.8 ⇒ 2.08x = 124.8 ⇒ x = 124.8/2.08 = Rs. 60 ∴ x = Rs. 60 |
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| 123. |
Mukesh sells two shirts. The cost price of the first shirt is equal to the selling price of the second shirt. The first shirt is sold at a profit of 30% and the second shirt is sold at a loss of 30%. What is the ratio of the selling price of the first shirt to the cost price of the second shirt?1). 91 : 1002). 100 : 913). 31 : 504). 50 : 31 |
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Answer» First shirt is sold at a PROFIT of 30% We write 30% = 3/10 Let CP of the first shirt be 10 and profit be 3 So, SP of the first shirt = 10 + 3 = 13 (CP)1/(SP)1 = 10/13----(1) Similarly SECOND shirt is sold at a loss of 30% We write 30% = 3/10 Let CP of the second shirt be 10 and loss be 3 So, SP of the second shirt be = 10 – 3 = 7 (CP)2/(SP)2 = 10/7----(2) GIVEN, CP of the first shirt is equal to the SP of the second shirt. Multiply by 7 in equation (1) and multiply by 10 in equation (2) we get CP)1/(SP)1 = 70/91 (CP)2/(SP)2 = 100/70 ∴ ratio of the selling price of the first shirt to the cost price of the second shirt is 91 : 100 |
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| 124. |
If the selling price of 10 articles is equal to the cost price of 15 articles, then what is the profit percent?1). 33.332). 66.663). 504). 60 |
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Answer» Selling PRICE = S.P COST price = C.P Selling price of 10 ARTICLES = cost price of 15 articles ⇒ 10 S.P = 15 C.P ⇒ S.P = 1.5 C.P Profit percentage = (profit/C.P) × 100 = {(S.P - C.P)/C.P} × 100 = {(1.5C.P - C.P)/C.P} × 100 = 0.5 × 100 = 50% |
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| 125. |
A company manufactured a pair of shoes for Rs. 2000 and sold it to a dealer at a profit of 12.5%. The dealer further sold it to a customer at Rs. 2700. What is the profit percentage of the dealer?1). 10%2). 20%3). 30%4). 40% |
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Answer» ORIGINAL price of shoes = RS. 2000 Profit of company = 12.5% ⇒ Price for dealer = 2000 + 12.5% of 2000 = 2000 + 1/8 × 2000 = 2000 + 250 = Rs. 2250 But, selling price of dealer = Rs. 2700 ⇒ Profit earned by dealer = 2700 - 2250 = Rs. 450 ∴ Profit PERCENTAGE of dealer = 450/2250 × 100 = 20% |
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| 126. |
The price of an item gets increased by 10% everyday. Sunny bought it for Rs. 10000. After three days, he sold it to Garry at Rs. 12000, and bought another item from market at prevailing market price. On next day, he sold this item as well to Ricky at Rs. 15000. How much profit or loss did Sunny make?1). Rs. 20002). Rs. 36903). Rs. 33804). Rs. 4000 |
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Answer» SUNNY bought it for Rs. 10000. After three days, he sold it to GARRY at Rs. 12000. ⇒ Sunny made a profit of Rs. 2000 Market price of ITEM after 3 days = Rs. 10000 × (1 + 10/100) × (1 + 10/100) × (1 + 10/100) = Rs. 13310 Sunny bought the item at Rs. 13310. On next day, he sold this item as well to Ricky at Rs. 15000. ⇒ Sunny made a profit of Rs. 1690 ∴ Profit made by Sunny = Rs. 2000 + Rs. 1690 = Rs. 3690 |
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| 127. |
Jayesh started project with Rs. 6000. Due to some issue, project stuck for 2 months and after that due to financial issue it doesn’t progress more 4 months. After that Dinesh helped Jayesh with Rs. 8000 and complete the project. At the end of year if the project generate the revenue of Rs. 20, 000. The share of profit of Dinesh is Rs…1). 22002). 25003). 24004). 3000 |
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Answer» Costing SPEND on Project = 6000 + 8000 = Rs. 14, 000 Net profit = revenue – COST = 20, 000 – 14, 000 = Rs. 6, 000 For the share of individual, Jayesh’s INVESTMENT × TIME period ? Dinesh’s investment × time period = 6000 × 12 ? 8000 × 6 ⇒ Respected ratio = 3 ? 2 ∴ Share of Dinesh = (2/5) × 6000 = Rs. 2400 |
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| 128. |
1). Rs. 2250002). Rs. 1125003). Rs. 1250004). Rs. 150000 |
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Answer» Let the TOTAL investment be ‘x’. ⇒ When investors were THREE in number, then their share = x/3 ⇒ Two more investors joined ⇒ total 5 investors. ⇒ Each investors NEW share = (x/3) – 20000 ⇒ 5 × [(x/3) – 20000] = x ⇒ 5x/3 – 100000 = x ⇒ 5x – 300000 = 3x ⇒ 2x = 300000 ⇒ x = 300000/2 = 150000. ∴ Total investment = 1,50,000 |
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| 129. |
A shopkeeper mixes 3 kg of sugar costing Rs. 28 per kg with 2 kg of sugar costing Rs. 25 per kg. At what price should he sell the mixture, so as to earn a profit of 15%?1). Rs. 27.50 per kg2). Rs. 28.36 per kg3). Rs. 29.24 per kg4). Rs. 30.82 per kg |
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Answer» COST price of 5 kg sugar MIXTURE = 3 × 28 + 2 × 25 = 84 + 50 = Rs. 134 SELLING price of 5 kg mixture = Cost price + PROFIT = 134 + 15% of 134 = Rs. 154.1 ∴ Selling price of sugar mixture = 154.1/5 = Rs. 30.82 per kg |
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| 130. |
1). 5.5 percent loss2). 14 percent profit3). 50 percent profit4). 26 percent loss |
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Answer» According to the given information, LET’s assume the list price to be Rs. ‘x’ Then Selling price = x - 25% of x = 0.75x Loss of 5% was incurred. ⇒ - 0.05 = SP/CP - 1 ⇒ SP/CP = 1 - 0.05 ⇒ CP = SP/0.95 ⇒ CP = 0.75x/0.95 = 15x/19 When the merchant SELLS at 10% DISCOUNT, ⇒ SP = x - 10% of x = 0.9x ⇒ Profit or Loss = $(\frac{{0.9x}}{{\frac{{15x}}{{19}}}} - 1c)$ = 1.14 - 1 = 0.14 ∴ 14% profit RESULTED on 10% discount on list price |
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| 131. |
A fan is listed for Rs. 1500. A discount of 14% is given on it. A second discount brings down the price to Rs. 1070.7. Find the rate of second rate of discount?1). 15%2). 17%3). 18%4). 20% |
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Answer» Let 2nd discount be x%. PRICE after 1st discount = 86% of 1500 = RS. 1290 Price after 2nd discount = (100 – x) % of 1290 = 1070.7 ⇒ x = 17% ∴ 2nd discount = 17% |
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| 132. |
1). Rs. 325002). Rs. 335003). Rs. 315004). Rs. 34500 |
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Answer» Let us ASSUME that money invested by A = 7x ⇒ money invested by B = 4x ⇒ A keeps his money for 4 months = 7x × 4 A takes out 1/7th of his money ⇒ Investment for REMAINING 8 months = 7x × 6/7 × 8 = 6x × 8 ⇒ A’s total investment = 7x × 4+6x × 8 = 28x+48x = 76x ⇒ B keeps his money for 5 months = 4x × 5 = 20x after that, B takes out 1/6 th of his money ⇒ Investment of B for remaining 7 months = 4x × 5/6 × 7 = 70x/3 ⇒ total investment by B = 20x+70x/3 = 130x/3 C invests same money as B’s initial money for 4 months ⇒ Investment of C for 4 months = 4x × 4 = 16 x A : B : C will be, ⇒ 76x : 130x/3 : 16x ⇒ 228x : 130x : 48x ⇒ 228 : 130 : 48 ⇒ 20% of profit goes to C, ⇒ 126875 × 20/100 = 126875/5 = Rs. 25375 Remaining profit which should be divided AMONG 3 of them will be, ⇒ 126875 - 25375 = Rs. 101500 Finally B’s share will be, ⇒ 101500 × 130/(130+228+48) ⇒ 101500 × 130/406 ⇒ 50750 × 130/203 ⇒ 7250 × 130/29 ∴ 250 × 130 = Rs. 32500 |
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| 133. |
1). 75, 1252). 100, 1003). 175, 254). 150, 50 |
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Answer» LET the quantity sold at 15% profit be x kg. Then the quantity sold at 5% loss will be (200 –x) kg Let us consider price of the rice be RS.1 per kg Then the price of x kg of rice = Rs. x and price of (200 – x) kg rice = Rs. (200 – x) ⇒ 15% profit of x + 5% loss of (200 – x) = 10% profit of 200 ⇒ 15x/100 - 10 + 5x/100 = 20 ⇒ 20x/100 = 30 ⇒ x = 150 kg ⇒ 200 – x = 200 – 150 = 50 kg ∴ Quantity sold at 15% profit = 150 kg and the quantity sold at 5% loss = 50 kg |
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| 134. |
Manu sold a dozen watches for Rs. 1454.64 per watch and made a profit of 16%. Find the cost price of the watches?1). 1254.002). 1362.363). 15048.004). 16348.32 |
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Answer» Given PROFIT % = 16 Selling price of each WATCH = Rs. 1454.64 COST price of the watch × 1.16 = 1454.64 ∴ Cost price = Rs. 1254 Cost price of DOZEN WATCHES = 1254 × 12 = Rs. 15048.00 |
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| 135. |
A vendor buys 4 pens at the rate of Rs 5 per pen and sells at the rate of Rs 3 per pen. What will be the result of this transaction?1). 40 percent gain2). 66.6 percent loss3). 66.66 percent gain4). 40 percent loss |
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| 136. |
If the difference between discount of 50% and two successive discounts of 30% on a certain bill is Rs. 6, then what is the amount (in Rs.) of the bill?1). 3002). 7503). 6004). 800 |
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Answer» Let, amount of the bill = Rs. X In the 1st CASE, After a discount of 50%, price = x - x × 50/100 = Rs. 0.5x In the 2nd case, After discount of 30%, price = x - x × 30/100 = Rs. 0.7x After another discount of 30%, price = 0.7x - 0.7x × 30/100 = Rs. 0.49x According to problem, ⇒ 0.5x - 0.49x = 6 ⇒ 0.01x = 6 ⇒ x = 600 ∴ amount of the bill = Rs. 600 |
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| 137. |
A and B started a business by investing Rs. 40000 and Rs. 10000 respectively. After 4 months, A withdrew Rs. 15000 and B invested Rs. 15000 more. What is the ratio of their share in profit at the end of the year?1). 1 ∶ 12). 2 ∶ 13). 3 ∶ 24). 4 ∶ 3 |
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Answer» A invested Rs. 40000 for 4 months and Rs. (40000 – 15000) = Rs. 25000 for (12 – 4) = 8 months Similarly, B invested Rs. 10000 for 4 months and Rs. (10000 + 15000) = Rs. 25000 for (12 – 4) = 8 months Hence, Share of their profits ⇒ (40000 × 4 + 25000 × 8) ? (10000 × 4 + 25000 × 8) ⇒360000 ? 240000 ⇒ 3 ? 2 |
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| 138. |
By selling 175 pineapples, the gain is equal to the selling price of 50 pineapples. What is the gain percentage?1). 282). 303). 324). 40 |
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Answer» Let the selling PRICE of 1 APPLE be a ⇒ S.P. of 175 PINEAPPLES = 175a ⇒ GAIN = 50a ⇒ Cost price = 175a – 50a = 125a ∴ gain percent = [50a/125a] x 100 = 40 % |
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| 139. |
1). Rs. 1252). Rs. 2503). Rs. 5004). Rs. 300 |
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Answer» As per the given data, Selling PRICE = Rs. 4500 PROFIT = 12.5% Let us consider the cost price of the article be Rs. X We know that profit% = (SP – CP)/CP × 100 ⇒ 12.5 = (4500 – x)/x × 100 ⇒ 12.5x = 450000 – 100x ⇒ 112.5 x = 450000 ⇒ x = Rs. 4000 ∴ Cost price = Rs. 4000 ⇒ Profit = Selling price – cost price = 4500 – 4000 = Rs. 500 |
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| 140. |
K purchased a table for Rs.11,000 and sold it for Rs. 13,500. What is his gain in percentage?1). 19.8%2). 20.6%3). 22.7%4). 22% |
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Answer» COST PRICE of the table(C.P) = RS. 11,000 Selling price of the table(S.P) = Rs. 13,500 ⇒ Profit % = (S.P – C.P)/C.P × 100 = (13500 – 11000)/11000 × 100 = 22.7% |
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| 141. |
J, K and L started a business. Twice the investment of J is equal to five times the investment of K, and the investment of K is twice the investment of L. Find the share of J in a profit of Rs. 16800?1). Rs. 195002). Rs. 240003). Rs. 105004). Rs. 14800 |
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Answer» LET J’s investment be = X Let K’s investment be = Y Let L’s investment be = Z According to the problem, ⇒ 2X = 5Y ⇒ Y = 2X/5---- (1) According to the problem, ⇒ Y = 2Z---- (2) From (1) and (2) we GET, ⇒ 2Z = 2X/5 ⇒ Z = X/5---- (3) ∴ Ratio of investment of J, K and L ⇒ X : 2X/5 : X/5 = 5 : 2 : 1 ∴ J’s SHARE in this PROFIT, = 16800 × (5/8) = 10500 |
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| 142. |
1). 25.45%2). 37.52%3). 33.33%4). 20.46% |
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| 143. |
A sells a good to B at a profit of 20% and B sells it to C at a profit of 25%. If C pays Rs. 225 for it. What was the cost of price for A?1). Rs. 2002). Rs. 1503). Rs. 1754). Rs. 162.5 |
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Answer» Let COST price of A be Rs. M Profit PERCENTAGE = 20% ⇒ 20 = [(S.P - M)/M] × 100 ⇒ M = 5 S.P - 5 M ⇒ 6 M = 5 S.P ⇒ S.P = 6 M/5 Cost price of a B = 6 M/5 Profit percentage = 25% ⇒ 25 = [(225 - 6 M/5)/(6 M/5)] × 100 ⇒ 6 M/5 = 900 - 24 M/5 ⇒ 6 M = 900 ⇒ M = 150 ∴ Cost price of A is Rs. 150. |
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| 144. |
X and Y start a business with Rs. 25000 and Rs. 35000 respectively. After 4 months, Z joins the business with Rs. 45000. At the end of the year, Z gets RS. 9000 as his share of profit. Then Find the difference between the profit share of X and Y– 1). Rs. 30002). Rs. 3003). Rs. 18004). Rs. 1500 |
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Answer» X’s contribution in business = Rs. 25000 Y’s contribution in business = Rs. 35000 After 4 months, Z joined Z’s contribution in business = Rs. 45000 X, Y contributed for 12 months while Z contributed for 8 months. Thus, the profit sharing ratio: ∴ 25000 × 12 : 35000 × 12 : 45000 × 8 ⇒ 25 × 12 : 35 × 12 : 45 × 8 ⇒ 5 × 3 : 7 × 3 : 9 × 2 ⇒ 5 : 7 : 6 At the end of the year, Z gets Rs. 9000 as his profit SHARE Let the total profit be x ∴ Z’s share $(= \;x\; \times \frac{6}{{5 + 7 + 6}} = x \times \frac{6}{{18}}\; = \;9000)$ ⇒ x = 27000 The difference between the profit SHARES of X and Y $(= 27000 \times \left( {\frac{7}{{5 + 7 + 6}} - \frac{5}{{5 + 7 + 6}}} \right))$ = 27000 × (2/18) = Rs. 3000 Thus, the difference between the profit share of X and Y is Rs. 3000 |
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| 145. |
Atul makes a profit of 20% even after offering a discount of 25% on the marked price of a wooden antique table. If he makes a profit of Rs.2000 on sale of the table, the marked price is:1). Rs. 100002). Rs. 120003). Rs. 140004). Rs. 16000 |
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Answer» LET the marked price be RS. X. Then, S.P = Marked price – Discount ⇒ S.P = X – 25% of X = 75X/100 ⇒ S.P = 3X/4---- (1) Given, Profit % = 20% S.P = C.P + Profit ⇒ S.P = C.P + 20% of C.P ⇒ S.P = 120 C.P/100 ⇒ Profit = S.P – C.P ⇒ Profit = 120 C.P/100 – C.P = 20 C.P/100 ⇒ 2000 = 20 C.P/100 ⇒ C.P = 10000 ⇒ S.P = 120 × 10000/100 = 12,000 From (1), 3X/4 = 12,000 ⇒ X = Rs. 16000 ∴ Marked price is Rs. 16000 |
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| 146. |
1). 78002). 105003). 84004). 12200 |
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Answer» Total INVESTMENT value of C = (4000 × 3) + (3000 × 9) = 12000 + 27000 = Rs. 39000 Total investment value of D = (5000 × 6) + (6000 × 6) = 30000 + 36000 = Rs. 66000 Investment ratio = 39000 ? 66000 = 13 ? 22 As, profit ratio is same as investment ratio, ⇒ Share of C in profit = {13/ (13 + 22)} × total profit ⇒ 3900 = (13/35) × total profit ∴ Total profit = Rs. 10500 |
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| 147. |
1). 113512). 66673). 105844). 9564 |
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Answer» C.P of the COOLER × (100 + PROFIT)/100 = S.P. of the cooler ⇒ 8400 × 126/100 = S.P ∴ S.P. of the cooler = 84 × 126 = 10584 |
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| 148. |
On selling 30 caps, a shopkeeper earns profit equal to the selling price of 3 caps. What is the profit percentage?1). 12.52). 11.113). 104). 14.28 |
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Answer» Let SP of 1 cap = 1 So, SP of 30 cap = 30 We KNOW that, ⇒ 30 -CP = 3 ⇒ CP = 27 ∴ Profit % = (SP - CP)/CP × 100 = (30 - 27)/27 × 100 = 3/27 × 100 = 11.11% |
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| 149. |
1). 162). 123). 144). 13 |
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Answer» Let the cost PRICE (C.P.) of the given article = RS. x ⇒ Marked price (M.P.) of the article = x + (45% of x) = Rs. 1.45x Selling price (S.P.) of the article after a discount of 20% = 1.45x – (20% of 1.45x) = 0.8 × 1.45 = Rs. 1.16x Profit = S.P. – C.P. = 1.16x – x = 0.16x = 16% of x ∴ Profit % = 16% |
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| 150. |
The total cost of a washing machine with an electric chimney was Rs. 57,750. The electric chimney was sold at a profit of 34% and the washing machine at a loss of 24%. If the sale price was the same in both the items, then the cost price of the cheaper item was________.1). Rs. 268502). Rs. 209003). Rs. 288754). Rs. 25850 |
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Answer» Let CP of electric chimney be X ⇒ CP of washing MACHINE = 57750 – x SP of electric chimney = x + 34% of x = 1.34x SP of washing machine = (57750 – x) – 24% of (57750 – x) = 0.76(57750 – x) ⇒ 1.34x = 0.76(57750 – x) ⇒ 1.34x = 43890 – 0.76x ⇒ x = 43890/2.1 = RS. 20900 ∴ CP of the cheaper item = Rs. 20900 |
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