1.

1). Rs. 13,5502). Rs. 12,4503). Rs. 11,2004). Rs. 12,000

Answer»

Let cost price of the ARTICLE be Rs. ‘x’, then,

Selling price in first case = x – x × (5.5/100)

When scooter is sold at Rs. 1000 more, then,

Selling price in second case = x – x × (5.5/100) + 1000 {which gives a profit of 4.5%}

Hence,

$(x - \FRAC{{5.5}}{{100}}x\; + \;1000\; = \;x\; + \;\frac{{4.5}}{{100}}x)$

⇒ 1000 = (10/100)x

⇒ x = Rs. 10,000 = Cost price of the article.

Now, to GAIN a profit of 12%,

Selling price of the article = Rs. {10000 × 112/100} = Rs. 11,200

Hence, the REQUIRED selling price of the article is Rs. 11,200.

Alternate Method (Short TRICK):

(5.5% + 4.5%) of CP = 1000

⇒ 10% of CP = 1000

⇒ CP = Rs. 10,000

Required selling price to gain 12% = Rs (10000 × 112/100) = Rs. 11,200.



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