InterviewSolution
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1). Rs. 13,5502). Rs. 12,4503). Rs. 11,2004). Rs. 12,000 |
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Answer» Let cost price of the ARTICLE be Rs. ‘x’, then, Selling price in first case = x – x × (5.5/100) When scooter is sold at Rs. 1000 more, then, Selling price in second case = x – x × (5.5/100) + 1000 {which gives a profit of 4.5%} Hence, $(x - \FRAC{{5.5}}{{100}}x\; + \;1000\; = \;x\; + \;\frac{{4.5}}{{100}}x)$ ⇒ 1000 = (10/100)x ⇒ x = Rs. 10,000 = Cost price of the article. Now, to GAIN a profit of 12%, Selling price of the article = Rs. {10000 × 112/100} = Rs. 11,200 Hence, the REQUIRED selling price of the article is Rs. 11,200. Alternate Method (Short TRICK): (5.5% + 4.5%) of CP = 1000 ⇒ 10% of CP = 1000 ⇒ CP = Rs. 10,000 Required selling price to gain 12% = Rs (10000 × 112/100) = Rs. 11,200. |
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