What would happen when we compile and run this program? #include int main() int i; goto LOOP; for (i = 0 ; i printf(GeeksQuiz n); LOOP break; return 0; (A) No compile error and it will print GeeksQuiz 10 times because goto label LOOP wouldn’t come in effect.(B) No compile error and it’ll print GeeksQuiz only once because goto label LOOP would come in picture only after entering for loop.(C) Compile Error because any goto label isn’t allowed in for loop in C.(D) No compile error but behaviour of the program would depend on C compiler due to nondeterministic behaviour of goto statement.(E) No compile error and it will not print anything.

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1.	What would happen when we compile and run this program?<br>#include < stdio.h ><br>int main()<br>{<br>int i; <br>goto LOOP;<br>for (i = 0 ; i < 10 ; i++)<br>{<br>printf("GeeksQuiz \n");<br>LOOP:<br>break;<br>}<br>return 0;<br>}<br>(A) No compile error and it will print GeeksQuiz 10 times because goto label LOOP wouldn’t come in effect.(B) No compile error and it’ll print GeeksQuiz only once because goto label LOOP would come in picture only after entering for loop.(C) Compile Error because any goto label isn’t allowed in for loop in C.(D) No compile error but behaviour of the program would depend on C compiler due to nondeterministic behaviour of goto statement.(E) No compile error and it will not print anything.
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