Both of the following declarations for function pointers are equivalent. Second one (i.e. with typedef) looks cleaner.* First Declaration *int (*funPtr1)(int) (*funPtr2)(int);* Second Declaration*typedef int (*funPtr)(int);funPtr funPtr1 funPtr2;(A) TRUE(B) FALSE

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1.	Both of the following declarations for function pointers are equivalent. Second one (i.e. with typedef) looks cleaner./* First Declaration /int (funPtr1)(int), (funPtr2)(int);/ Second Declaration/typedef int (funPtr)(int);funPtr funPtr1, funPtr2;(A) TRUE(B) FALSE
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Both of the following declarations for function pointers are equivalent. Second one (i.e. with typedef) looks cleaner./* First Declaration */int (*funPtr1)(int), (*funPtr2)(int);/* Second Declaration*/typedef int (*funPtr)(int);funPtr funPtr1, funPtr2;(A) TRUE(B) FALSE

Both of the following declarations for function pointers are equivalent. Second one (i.e. with typedef) looks cleaner./* First Declaration /int (funPtr1)(int), (funPtr2)(int);/ Second Declaration/typedef int (funPtr)(int);funPtr funPtr1, funPtr2;(A) TRUE(B) FALSE