InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
At `20^(@)C` temperature, an argon gas at atmospheric pressure is confined in a vessel with a volume of `1 m^(3)` The effective hard spere diameter of argon atom is `3.10xx10^(-10)`m. determine mean free path.A. 100 nmB. 90 nmC. 93.6 nmD. 95 nm |
| Answer» Correct Answer - C | |
| 152. |
When a body is taken from the equator to the poles, its weightA. Remains constantB. IncreasesC. DecreasesD. None |
| Answer» Correct Answer - C | |
| 153. |
Surface tension of water is 0.072 `Nm^(-1)`. The excess pressure inside a water drop of diameter 1.2 mm is :-A. 240 PaB. 120 PaC. 0.06 PaD. 60 Pa |
| Answer» Correct Answer - A | |
| 154. |
The surface tension of soap solution is `0.03 N//m` . The work done in blowing to from a soap bublle of surface area `40 cm^(2)`, (in J) , isA. `1.2xx10^(-4)` JB. `2.4xx10^(-4)` JC. `12xx10^(-4)` JD. `24xx10^(-4)` J |
| Answer» Correct Answer - B | |
| 155. |
Light can travel in vacuum whereas sound can not do so. Why?A. speed of sound is vertymuch slower than lightB. light waves are electromagnetic in natureC. sound waves are electromagnetic in natureD. light waves are not electromagnetic in nature |
| Answer» Correct Answer - B | |
| 156. |
If the density of air at NTP is `1.293kg//m^(3)` and `gamma=1.41`, then the velocity of sound in air at NTP is :A. 102.3 m/sB. 252.3 m/sC. 332.3 m/sD. 432.3 m/s |
| Answer» Correct Answer - C | |
| 157. |
Which of the following expressions is that of a simpleharmonic progressive wave ?A. `A sin omegat`B. `A sin omegat cos kx`C. `A sin (omegat-kx)`D. `A cos kx` |
| Answer» Correct Answer - C | |
| 158. |
A light pointer fixed to one prong of a tuning fork touches gnetly a smoked vertical plate. The fork is set vibrating and the plate is allowed to fall freely. 8 complete oscilllations are counted when the plate falls through 10cm.What is the frequency of the tuning fork?A. 112 HzB. 56 HzC. 8/7 HzD. 7/8 Hz |
| Answer» Correct Answer - B | |
| 159. |
Which of the following when simplified, reduces to unity?A. `log_(10)5. log_(10) 20+ log_(10)^(2)2`B. `(2 log 2+ log 3)/(log 48 - log4)`C. `-log_(5),log_(3) = sqrt(root5(9))`D. `(1)/(6) log_((sqrt(3))/(2))((64)/(27))` |
| Answer» Correct Answer - A::B::C::D | |
| 160. |
A body is dropped from a tower. It covers `64%` distance of its total height in last second. Find out the height of tower `[g=10 ms^(-2)]` |
| Answer» Correct Answer - 31.25 m | |
| 161. |
A ball is projected in a manner such that its horizontal gange is n times of the maximum height. Then find out the ratio of potential energy to kinetic energy at maximum height. |
| Answer» Correct Answer - `(16)/(n^(2))` | |
| 162. |
A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out :- (i) angle of projection (ii) velocity of projection (iii) Velocity of ball after 5 seconds |
|
Answer» Correct Answer - (i)`theta=45^(@)` (ii)`50sqrt(2)m//s` (iii)`50m//sec` |
|
| 163. |
A body is projected at an angle of `45^(@)` with horizontal with velocity of `40sqrt(2)m//s`. Find out (i) Maximum height attained by body (ii) Time of flight (iii) Horizontal range (iv) Velocity at maximum height (v) The ratio of Kinetic energy to potential energy at highest point (vi) The part equation of projectile, assuming point of projection as origin and consider x and y are horizontal and vertical distance in meter (vii) The horizontal distance covered by body in 2 second (viii) The vertical distance covered by body in 2 second |
|
Answer» Correct Answer - (i) 80 m (ii) 8 sec (iii) 320 m (iv) 40 m/s (v) 1 : 1 (vi)`y=x-(x^(2))/(320)m` (vii) 80 m (viii) 60 m |
|
| 164. |
A block of mass `m` is pulled by a uniform chain of mass `m` tied to it by applying a force `F` at the other end of the chain.The tension at a point `P` which is at a distance of quarter of the length of the chain from the free end,will be A. `(7F)/(8)`B. `(4F)/(5)`C. `(3F)/(4)`D. `(6F)/(7)` |
| Answer» Correct Answer - A | |
| 165. |
A sphere is accelerated upwards with the help of a cord whose braking strength is five times its weight. The maximum acceleration with which the sphere can move up without cord breaking is :-A. 4gB. 3gC. 2gD. g |
| Answer» Correct Answer - A | |
| 166. |
In a Carnot engine when `T_(2) = 0^(@)C` and `T_(1) = 200^(@)C` its efficiency is `eta_(1)` and when `T_(1) = 0^(@)C` and `T_(2) = -200^(@)C`. Its efficiency is `eta_(2)`, then what is `eta_(1)//eta_(2)`?A. `1 : 15`B. `1 : 1`C. `1 : 2`D. `1.73 : 1` |
| Answer» Correct Answer - D | |
| 167. |
A particle executes SHM according to equation `x=10(cm)cos[2pit+(pi)/(2)]`, where t is in seconds. The magnitude of the velocity of the particle at `t=(1)/(6)s` will be :-A. 24.7 cm/sB. 20.5 cm/sC. 28.3 cm/sD. 31.4 cm/s |
| Answer» Correct Answer - D | |
| 168. |
A machine gun fires bullets of 50gm at the speed of 1000m/sec. If an average force of 200N is exerted on the gun, the maximum number of bullets fired per minute is: |
| Answer» Correct Answer - 600 bullets | |
| 169. |
If the velocity of a paraticle moving along x-axis is given as `v=(4t^(2)+3t=1)m//s` then acceleration of the particle at `t=1sec` is : |
| Answer» Correct Answer - `11m//sec^(2)` | |
| 170. |
The kinetic energy needed to project a body of mass `m` from the earth surface (radius R) to infinity isA. `(mgR)/(2)`B. `2mgR`C. `mgR`D. `(mgR)/(4)` |
| Answer» Correct Answer - C | |
| 171. |
The time period and the amplitude of a simple pendulum are 4 seconds and 0.20 meter respectively. If the displacement is 0.1 meter at time t=0, the equation on its displacement is represented by :-A. `y=0.2sin(0.5pit)`B. `y=0.1sin(0.5pit+(pi)/(6))`C. `y=0.1sin(pit+(pi)/(6))`D. `Y=0.2 sin(0.5pit+(pi)/(6))` |
| Answer» Correct Answer - D | |
| 172. |
In an experiment the height of a small object is measured by a Vernier Calliper having least count 0.01 cm is found to be 7.38 cm, then the actual height of object may be :-A. 7.40 cmB. 7.3942 cmC. 7.3792 cmD. 7.3882 cm |
| Answer» Correct Answer - C | |
| 173. |
Let `a,x,b` be in `A.P`, `a,y,b` be in `G.P` and `a,z,b` be in `H.P`. If `x=y+2` and `a=5z`, thenA. `x=yltz`B. `x=ygtz`C. `xltzlty`D. `xgtzgty` |
| Answer» Correct Answer - C | |
| 174. |
Which of the following specification is most accurate ?A. `63.1xx10^(2)m`B. `6.31xx10^(3)m`C. 6310 mD. `0.0631xx10^(5) m` |
| Answer» Correct Answer - C | |
| 175. |
If momentum `(p)`, area `(A)` and time`(t) `are taken to be fundamental quantities then energy has the dimensional formulaA. `[P^(1)A^(-1)T^(1)]`B. `[P^(2)-A^(1)T^(1)]`C. `[P^(1)A^(-1//2)T^(1)]`D. `[P^(1)A^(1//2)T^(-1)]` |
| Answer» Correct Answer - D | |
| 176. |
A room is 12m long, 4m wide and 3m high, what will be the longest bar that can be placed in the room :-A. 12mB. 5mC. 19mD. 13m |
| Answer» Correct Answer - D | |
| 177. |
If hydrogen gas is heated to a very high temperature, then the fraction of energy possessed by gas molecules correspond to rotational motion :-A. `(3)/(5)`B. `(2)/(7)`C. `(3)/(7)`D. `(2)/(5)` |
| Answer» Correct Answer - B | |
| 178. |
The rms speed of helium gas at `27^(@)C` and 1 atm pressure is 900 `ms^(-1)`. Then the rms speed of helium molecules at temperature `27^(@)C` and 2 atm pressure isA. 450 m/sB. 900 m/sC. 1800 m/sD. 750 m/s |
| Answer» Correct Answer - B | |
| 179. |
Four molecules have speeds `2 km//s, 3 km//s, 4 km//s` and `5 km//s`. The `rms` speed of these molecules in `km//s` isA. `(1)/(2)sqrt(15)km//s`B. `(1)/(2)sqrt(10)km/s`C. `2.5 km/s`D. `sqrt((15)/(2))km/s` |
| Answer» Correct Answer - D | |
| 180. |
For a straight line `y=(4)/(3)x-4`. Choose correct alternate(s)A. `(dy)/(dx)=tan53^(@)`B. `(dx)/(dy)=tan37^(@)`C. `x-"Intercept is "3`D. length of linne between x-axis and y-axis is 5 units |
| Answer» Correct Answer - A::B::C::D | |
| 181. |
Given, `P prop T ` on increasing the value of T by `1^(@)C`, the value of P increases by `0.4%`, then find initial value of T :-A. 25B. 250C. 350D. 2500 |
| Answer» Correct Answer - B | |
| 182. |
The maximum & minimum value of `y=x+(1)/(x)` in interval `[(1)/(3),(4)/(3)]`A. 2,-2B. `(10)/(3),2`C. `oo,-oo`D. None of these |
| Answer» Correct Answer - B | |
| 183. |
A particle of mass m is projected with speed u at an angle `theta` with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point.A. mu `sintheta.costheta`B. m `u^(2) sintheta costheta`C. `("mu "sin^(2)theta)/(2)`D. `("mu"^(2)sin^(2)theta)/(2)` |
| Answer» Correct Answer - B | |
| 184. |
Integrate the following : (i) `int(t-(1)/(t))^(2)" dt "` (ii)`intsin(10t-50)" dt "` (iii)`inte^((100t+6))" dt "` |
|
Answer» Correct Answer - (i)`(t^(3))/(3)-(1)/(t)-2t+C` (ii)`(-cos(10t-50))/(10)+C` (iii)`(1)/(100)e^(100t+6)+C` |
|
| 185. |
Which of the following statements is/are correct?A. `(d)/(dx)(x^(2)+2)^(2)=4x`B. `(d)/(dx)(e^(-2x))=-2e^(-2x)`C. `(d)/(dx){sin(ax+b)}=acos(ax+b)`D. `(d)/(dx)(x^(3)+3x+1)^(2)=2(3x^(2)+3)(x^(3)+3x+1)` |
| Answer» Correct Answer - B::C::D | |
| 186. |
When a torque acting upon a system is zero, which of the following will be constant ?A. Moment of velocityB. Angular velocityC. Kinetic energyD. Moment of linear momentum |
| Answer» Correct Answer - D | |
| 187. |
A disc is rotating with angular velocity `omega`. A force F acts at a point whose position vector with respect to the axis of rotation is r. The power associated with torque due to the force is given byA. `(vecrxxvecF).vecomega`B. `(vecrxxvecF)xxvecomega`C. `vecrxx(vecF.vecomega)`D. `vecr.(vecFxxvecomega)` |
| Answer» Correct Answer - A | |
| 188. |
Radius of a spherical balloon is increasing with respect to time at the rate of `2//pi" "m//s`. Find the rate of change in volume (in `m^(3)//s`) of the balloon when radius is 0.5 m? |
| Answer» Correct Answer - `5.2`m3/s | |
| 189. |
`(d)/(dx)(sin120^(@))`=…………A. `cos 120^(@)`B. `120 cos 120^(@)`C. 0D. None of these |
| Answer» Correct Answer - C | |
| 190. |
If `v=(t^(2)-4t+10^(5))`m/s where t is in second. Find acceleration at t=1 sec. |
| Answer» Correct Answer - C | |
| 191. |
If `y=x^(3)cosx" then "(dy)/(dx)`=……………………A. `x^(2)(3cosx-xsinx)`B. `x^(2)(3cosx+xsinx)`C. `3x^(2).cosx+x^(3)sinx`D. None of these |
| Answer» Correct Answer - A | |
| 192. |
For a disc of given density and thickness, its moment of inertia varies with radius of the disc as :A. `1propR^(2)`B. `1propR^(4)`C. `1propR^(3)`D. `1propR` |
| Answer» Correct Answer - B | |
| 193. |
If the distance covered by a particle is given by the relation `x=at^(2)`. The particle is moving with : (where a is constant)A. constant accelerationB. zero accelerationC. variable accelerationD. none of these |
| Answer» Correct Answer - A | |
| 194. |
If derivative of `y=8sqrt(sinx)" is "(dy)/(dx)=(kcosx)/(sqrt(x))`, what is numerical value of constant k? |
| Answer» Correct Answer - 4 | |
| 195. |
Relation between displacement x and time t is `x=2-5t+6t^(2)`, the initial acceleration will be :-A. `-3 ms^(-2)`B. `12 ms^(-2)`C. `2 ms^(-2)`D. `-5 ms^(-2)` |
| Answer» Correct Answer - B | |
| 196. |
A metallic disc is being heated. Its area (in `m^(2)`) at any time t (in sec) is given by `A=5t^(2)+4t`. Calculate the rate of increase in area at `t=3sec`. |
| Answer» Correct Answer - `34m^(2)//sec` | |
| 197. |
`(d)/(dx)(e^(100))`=…………………A. `e^(100)`B. 0C. `100^(e^(99))`D. None of these |
| Answer» Correct Answer - B | |
| 198. |
The displacement of a particle is given by `x=a_(0)+(a_(1)t)/(3)-(a_(2)t^(2))/(2)` where `a_(0),a_(1)` and `a_(2)` are constants. What is its acceleration ?A. `a_(1)-a_(2)`B. `-a_(2)`C. `+a_(2)`D. `a_(2)-a_(1)` |
| Answer» Correct Answer - B | |
| 199. |
If `y=log_(e)x+sinx+e^(x)" then "(dy)/(dx)` isA. `(1)/(x)+sinx+e^(x)`B. `(1)/(x)-cosx+e^(x)`C. `(1)/(x)+cosx+e^(x)`D. `(1)/(x)-sinx` |
| Answer» Correct Answer - C | |
| 200. |
If `y=(x^(2))/((x+1))"then"(dy)/(dx)"is":-`A. `(x(3x+2))/((x+1))`B. `(-x(x+2))/((x+1)^(2))`C. `(x(x+2))/((x+1)^(2))`D. `(x(x+2))/((x+1))` |
| Answer» Correct Answer - C | |